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95801.

It is advantageous to connect electric devices in parallel instead of connecting them in series. Why?

Answer»

(i) The appliances connected in series need currents of widely different values to operate properly.

(ii) In a series circuit, if one component fails, the circuit is broken and none of the components work.

(iii) But in a parallel circuit current divides through the electrical gadgets.

(iv) This is helpful particularly when each gadget had different resistance and requires different current to operate properly.

95802.

A battery of emf `E_(0) = 12 V` is connected across a `4 m` long uniform wire having resistance `(4 Omega)/(m)`. The cells of small emfs `epsilon_(1) = 2 V` and `epsilon_(2) - 4 V` having internal resistance `2 Omega` and `6 Omega` respectively, are connected as shown in the figure. If galvanometer shows no deflection at the point `N`, the distance of point `N` from teh point `A` is equal to A. `(1)/(6)m`B. `(1)/(3)m`C. `25cm`D. `50cm`

Answer» Correct Answer - C
`4xxl(12)/(24)=(epsilon_(1)r_(2)-r_(1)epsilon_(2))/(r_(1)+r_(2))`
95803.

How does the hydrostatic lubrication differ from hydrodynamic type?

Answer»

In hydrostatic lubrication which is used in slow speed turbines, the lubricating oil is pressurised externally whereas in hydrodynamic system it forms oil film by its speed which pushes the lubrication oil to form film.  

95804.

What are the functions of dearator? 

Answer»

Dearator removes non-condensable gases (O2), which gets added in the steam and it, mixes steam with the condensed water for feed water heating. This is a contact type feed water heater.

95805.

Define capacity factor.

Answer»

Capacity factor can be defined as net power produced by the plant divided by perfect net power that can be produced in the plant. 

Capacity factor = Net power produced / Perfect net power produced. 

95806.

What are the methods of removing moisture from turbine? 

Answer»

The methods of removing moisture from turbine are.

a. External method by moisture separator and reheater, which separates the moisture and reheates the steam. 

b. Internally by stainless steel mesh, which reduces moisture (water particles) to 1%. 

c. By main steam reheat.  

95807.

Why non-return valves are provided in the steam extraction lines?

Answer»

Non-return valves are provided because when the turbine trips there will be an instant drop in pressure inside the turbine. But there will be steam in feed water heaters, which is at high pressure. These will rush in to the turbine and overspeed will be there in turbine. So non-return valves are provided in steam extraction lines to prevent overspeeding of turbine. 

95808.

What is the function of the steam traps?

Answer»

During startup the steam traps will bypass turbine drains.

95809.

Explain the principle of working of impulse steam turbine.

Answer»

When steam enters the turbine it suffers a change in direction and momentum, which gives rise to the rotation of the turbine. There will be no drop in pressure in impulse steam turbine. 

95810.

How turbine oil purification is achieved? 

Answer»

Oil purification is achieved by centrifugal operation.

95811.

How dearator pressure is maintained after turbine trip?

Answer»

Pegging steam is used to maintain dearator pressure after turbine trip.

95812.

What is the use of vacuum breaker? 

Answer»

In case of loss of seal oil to generator seals vacuum breaker is used to bring TG to rest very quickly. 

95813.

Why exhaust sprays are provided?

Answer»

Over heating of last stage LP blades is avoided by exhaust sprays by CEP. 

95814.

Why morpholine is used?

Answer»

Morpholine is used for pH control.

95815.

How gland-sealing steam is supplied? 

Answer»

Gland sealing speed is supplied from main steam line.  

95816.

What is the function of speeder gear? 

Answer»

Speed raising beyond governor takeover speed upto full speed is achieved by raising and lowering the speeder gear.  

95817.

By which material condenser tubes are made?

Answer»

Condenser tubes are made up of aluminium brass.

95818.

In Exercises 7.3 and 7.4, what is the net power absorbed by each circuit over a complete cycle. Explain your answer.

Answer»

In the inductive circuit,
Rms value of current, I = 15.92 A
Rms value of voltage, V = 220 V
Hence, the net power absorbed can be obtained by the relation,

P=VI cosϕ

Where,
ϕ= Phase difference between V and I.

For a pure inductive circuit, the phase difference between alternating voltage and current is 90° i.e., ϕ= 90°.
Hence, P = 0 i.e., the net power is zero.
In the capacitive circuit,
rms value of current, I = 2.49 A
rms value of voltage, V = 110 V
Hence, the net power absorbed can be obtained as: 

P=VI cosϕ 

For a pure capacitive circuit, the phase difference between alternating voltage and current is 90° i.e., ϕ= 90°. 

Hence, P = 0 i.e., the net power is zero.

95819.

A cavity of radius b is made in a disc of mass M, radius R, as ahown in fig. Find the new COM- A. `(-b^(2))/(R+b)`B. `(-b^(2))/(R-b)`C. `(-R)/(2R+b)`D. `(-R)/(3R+b)`

Answer» Correct Answer - A
`x_(CM)=(M(0)-(Mb^(2))/(R^(2))(R-b))/(M-(Mb^(2))/R^(2))`
`=-(b^(2))/(R+b)`
95820.

Name the type of mirror used in the following situations.(a) Headlights of a car.(b) Side/rear-view mirror of a vehicle.(c) Solar furnace.

Answer»

(a) In headlights of a car, type of mirror used is concave as the light of the lamp, under goes divergence from reflector surface and cover a large area in the front.
(b) Side/rear-view mirror of a vehicle is a convex mirror as it gives a diminished, Virtual and an erect image of the side or rear with wider field of view . A convex mirrors enable the driver to view much larger area than would be possible with a plane mirror
(c) Solar furnace is a concave mirror as Sun rays after reflection from its surface, get converged at focus with much intense heat.

95821.

A pipe of length `l_(1)`, closed at one end is kept in a chamber of gas of density `rho_(1)`. A second pipe open at both ends is placed in a second chamber of gas of density `rho_(2)`. The compressibility of both the gases is equal. Calculate the length of the second pipe if frquency of first overtone in both the cases is equal.A. `(4)/(3) l_1 sqrt((rho_2)/(rho_(1))`B. `(4)/(3) l_1 sqrt(rho_1)/(rho_(2))`C. `l_1 sqrt((rho_2)/(rho_(1))`D. `l_1 sqrt(rho_1)/(rho_(2))`

Answer» Correct Answer - B
Frequency of first overtone in closed pipe,
`v = (3)/(4l_(1)) sqrt((B)/(rho_(1)))`…(i)
Frequency of the first overtone in open pipe,
`v = (1)/(l_(2)) sqrt((B)/(rho_(2))) rArr l_(2) =(4)/(3) l_(1) sqrt((rho_(1))/(rho_(2)))`….(ii).
95822.

Which transition metal oxide has appearance and conductivity like that of copper

Answer» `ReO_(3)` (Rhenium oxide)
95823.

Two monomers in maltose are : (1) α-D-glucose and β-D-glucose (2) α-D-glucose and  α-D-Fructose(3) α-D-glucose and α-D-glucose(4) α-D-glucose and α-D-galactose

Answer»

Answer is (3)

Two monomers in maltose are α- D-glucose & α-D-glucose.

Answer is (3)

Maltose on hydrolysis gives 2 molecule of α–D–glucose.

95824.

Hydrolysis of starch forms a)Dextrin maltose and then glucose at the end of hydrolysis b)Glucose after complete hydrolysis c)a and b d)No answer

Answer»

Answer: c) a and b

95825.

The anesthesia applied directly to the skin is ___________(a) Topical Anesthesia(b) Caudal Anesthesia(c) Local Blocks(d) General Anesthesia

Answer» The correct option is (a) Topical Anesthesia

Easy explanation: When anything is applied externally on the skin, it is called a topical application. Thus, the anesthesia that is applied directly on the skin is called as topical anesthesia. It numbs a certain region of the skin and allows surgical procedures to happen.
95826.

_______ is the most commonly used material for vapourizer.(a) Steel(b) Cast iron(c) copper(d) Brass

Answer» Correct choice is (c) copper

The best I can explain: A vapourizer is a machine that heats water and converts it into steam. This instrument is used to maintain the humidity of the room and is often used to give steam to a patient. Of all the three materials, copper has the best conductivity for heat and it helps the water heat up faster. Thus, copper coils or copper based vessel is used in a vapourizer.
95827.

One of the methods to measure changes in the levels of consciousness during anesthesia is ________(a) Auditory Evoked Potential(b) Visual Evoked Potential(c) Tactile Evoked Potential(d) Speech Evoked Potential

Answer» The correct option is (a) Auditory Evoked Potential

Best explanation: One of the methods to measure changes in the levels of consciousness during anesthesia is Auditory Evoked Potential (AEP) which is a neuro-physiological indicator of the changes in the level of consciousness during anesthesia. In this, the person is given an auditory stimulus and the EEG response of the person is noted. This allows the doctor to realize the level of consciousness of the person.
95828.

How many orders will be visible if the wavelength of incident radiation is 5000 nm and the number of lines on the grating is 2620 per inch? 

Answer»

Given :

d = \(\cfrac1{2620}\) per inch

d = \(\cfrac{1}{\cfrac{2620}{0.0284}}\)

d = \(\cfrac1{10314}\) per meter.

using n\(\lambda\) = d sin θ 

θ  = 90°

n\(\lambda\) = d

n = \(\cfrac d{\lambda}\)

n = \(\cfrac1{5000\times10^{-9}\times10314}\)

n = \(\cfrac{1000000}{51570}\)

n = 19.39

95829.

In which of these sub cutaneous infiltration with a desensitizing agent is done?(a) Saddle Blocks(b) Epidural Blocks(c) Local Blocks(d) General Anesthesia

Answer» Correct answer is (c) Local Blocks

Explanation: In a local anesthesia, the anesthetic or the desensitizing agent is injected in the sub cutaneous region of the skin. This allows a certain region of the body to become numb and the doctors are able to perform the operation. This is done when the area of operation is small or the time needed for the operation is small.
95830.

Define the terms :(a) Helmholtz electrical double layer(b) Zeta potential

Answer»

[Hint : (a) The combination of the two layers of opposite charges around the colloidal particles. E.g., AgI/I-K+.
(b) The potential difference between the xed layer and diffused layer of opposite charges is called zeta potential.]

95831.

Define fecundity.

Answer»

The capacity of a women bear children.

95832.

Explain briefly how an XXY individual is produced in humans.

Answer»

XXY individuals can arise due to non-disjunction of XX chromozomes at meiosis during the formation of female gamatos. Non-seperation of homologous chromosomes during meiosis is termed as non-disjunction. In human, non-disjunction of X-chromosome in female parent result in the egg with autosomes and two sex chromosomes (22 + XX). In such an egg is fertilized by an endosoperm (22 + X), the zygote will have (44 + XXY). It develops into klinefelter syndrome with 47 chromozomes.

95833.

What do you mean by the term 'pathogen'?

Answer»

Pathogen:-

Disease causing micro-organism such as bacteria, protozoans, worms etc. called pathogen.

95834.

What is aminocentesis?

Answer»

Amniocentesis:-

Transapdominal aspiration of liquid from the amriotic sac of the foetus is called amniocentesis.

Amniocentesis is a parental dignostic technique to determine the genetic disorders, if any, and sex of the foetus.

95835.

Which of the following types of tendering should be resorted to only in case of an emergency requirements?1. Spot tendering2. Proprietary tendering3. Open tendering4. Global tendering

Answer» Correct Answer - Option 1 : Spot tendering

The Tender open officials shall  prepare on the spot report for tendering in the case of Emergency.

  1. Tenders which can be participated by companies from any country of the world, generally known as global tenders.
  2. Open tendering is the main tendering procedures employed by both the government and private sector. open tendering allows anyone to submit  a tender to supply goods or services required and offers an equal oppurtunity to any organisation to submit tender.
  3. proprietary tendering is only for patented material ,specification or process that can be obtained only from one manufacturer.
95836.

Which gas is evolved in the given diagram of experiment ? How can this gas be tested for confirmation?

Answer»

(i) Oxygen gas is evolved in this experiment. 

(ii) If the burning splinter is kept near the mouth of the test tube, it burns brightly.

95837.

How do grasses reproduce?

Answer»

Grass can reproduce asexually via spreading root systems, but they can also spread sexually via flowers. Those fluffy tops you see when you don't cut the lawn are grass flowers. They don't look much because they are wind pollinated and do not need to attract insects. Once those fluffy tops have been pollinated, they grow into seed heads. We usually don't see any of this because we keep our lawns mowed.

95838.

Prepare two slogans on protecting non-renewable resources.

Answer»

(1) Use Biofuel – Reduce Fossil Fuel. 

(2) Use alternative resources – Save the environment.

95839.

Study the given paragraph and answer the questions.The organ 'A' of a person has been damaged completely due to a poisonous waste material 'B' has started accumulation in his blood, making it dirty. In order to save this person's life, the blood from an artery in the person's arm is made to flow into long tubes made of substance 'E' which are kept in coiled form in a tank containing solution 'F'. This solution contains three materials 'G', 'H' and 'I' and similar proportions to those in normal blood. As the person's blood passes through long tubes of substance 'E', most of the wastes present in it go into solution 'F'. The clean blood is then put back into a vein in the person for circulation.(A)What are organs A & B ? (B)What are G, H and I ?

Answer»

(A)Kidney, Nitrogenous waste substance. 

(B)Waste molecules, nutrient molecules and water

95840.

Write any four slogans on the conservation of natural resources. 

Answer»

(1) Save paper – Save the planet. 

(2) Tree plantation is the best option against pollution.

(3) Reduce, Reuse and Recycle. 

(4) Prevent environmental health hazards.

95841.

Why continued inbreeding should be avoided in plants?

Answer»

Continued inbreeding results in inbreeding depression which decreases fertility and productivity of plants.

95842.

Observe the pyramid of number which is given below and answer the questions.(i) As per the number of organisms in the tropic level, which group of organisms are more in number and which are less in number ? (ii) What happens if secondary consumers disappear ?

Answer»

(i) If producers are more in number, then tertiary consumers are less in number. 

(ii) If secondary consumers disappear the primary consumers increase in number and the tertiary consumers found no food to live. It leads to death.

95843.

Explain five effects of water pollution.

Answer»

1. Sewage discharge, pollutes the water and makes it unfit for human use, decomposers in the aquatic ecosystem, decompose these pollutants and makes the water foul smelling. 

2. The organic substances present in sewage are decomposed by decomposers aerobically as a result the oxygen content of the water decreases. This leads to biochemical oxygen demand (BOD). It kills large number of aquatic organisms. 

3. Agricultural runoff Or excess wash from agricultural fields, carry pesticides and fertilizers to water bodies like lakes. The nutrient enrichment of lakes promotes the enormous growth of algae. This is called algal bloom; it blocks the free flow of water and O2 content and eventual death of aquatic organisms. 

4. Industrial effluents discharged into ponds or lakes contain toxic substances, like mercury, DDT, etc. It is neither excreted nor metabolized, gradually they tend to accumulate in organisms through food chain. This is called biomagnification. Biomagnifieation of DDT disturbs calcium metabolism in birds, which lay eggs with thin egg shell, it results in premature breaking and decline in bird population. 

5. Oil slicks formed as a result of leakage of oils from ships carrying huge quantities of crude oil via sea routes, spread to several kilometers. It does not allow oxygen to penetrate into water and causes mass death of aquatic organisms. 

6. The hot water discharged from thermal power stations or nuclear power stations into water bodies, increases the temperature; this results in evaporation of oxygen from the water surface leading to death of aquatic animals like fishes. 

7. Sewage water contains many undesirable pathogenic microorganisms, when this water is discharged into nearby water bodies without proper treatment may cause outbreak of serious diseases like Jaundice, cholera, dysentery, typhoid, etc. 

8. Industrial effluents released into surrounding land or into pits, percolate along with its chemicals into soil and contaminate ground water.

95844.

Write the mechanism of photosynthesis in plants.

Answer»

(1) There are two major phases found in photosynthesis. They are light reaction and dark reaction. 

(2) Light reaction : The light reaction takes place in chlorophyll containing thylakoids called grana of chloroplasts. 

(3) The chlorophyll on exposure to light energy becomes activated by absorbing photons. 

(4) The energy is used in splitting the water molecule into its two component ions. 

H2O → H+ + OH-

This is known as photolysis of water

(5) OH ions through a series of steps produce water and oxygen. 

(6) ATP and NADPH are formed at the end of the light reaction are called assimilatory powers. 

(7) Dark reaction : Dark reactions do not depend on light. These reactions occur in stroma of chloroplast. 

(8) H+ ions produced in photolysis are immediately picked up by special compound NADP to form NADPH. 

(9) In the dark phase, the hydrogen of the NADPH is used to combine it with CO2 by utilising ATP energy and to ultimately produce glucose. 

(10) The synthesis of glucose occurs in number of steps using certain special intermediate compounds (mainly ribulose biphosphate) and enzymes. 

(11) Finally the glucose is converted to starch.

95845.

Explain the changes involved in the formation of seed from Ovule.

Answer»

Process of double fertilization : 

(1) At the time of fertilization there will be a total of 7 cells arranged in three groups in a mature embryo sac. 

(2) They are one egg (female gamet) two synergids, one central cell (secondary or polar nucleus) and three antipodals. 

(3) While all the cells are in haploid (n) condition only the polar nucleus is diploid (2n). This is due to the fusion of two nuclei. 

(4) The synergids are also known as helper cells. 

(5) After pollination pollen grain received by the stigma, germinate and give rise to pollen tubes. The pollen tube has two male nuclei. 

(6) Usually the pollen tube enters the ovule through microphyle and discharges the two male gametes into the embryo sac. 

(7) One male nucleus (gamet) approaches the egg and fuses with it to form diploid (2n) zygote this is called first fertilization. 

(8) The other male nucleus reaches the secondary nucleus (2n) (polar nucleus) and fuses with it to form endosperm nucleus which will be triploid. This is second fertilization. Thus double fertilization occurs in embryosac.

Changes after double fertilization : 

(9) After double fertilization, the ovule increases in size rapidly as a result of formation of endosperm tissue by mitosis and the development of new embryo. 

(10) The embryo consists of cotyledons an epicotyl and a hypocotyl. The cotyledons become greatly enlarged because of stored food for the seedling. 

(11) The zygote divides several times to form an embryo within the ovule. The ovule develops a tough coat and is converted into a seed. The ovary grows to form a fruit.

95846.

Explain the application of tissue culture in any three fields.

Answer»

Applications of tissues are : 

1. Micropropagation: 

It is used for the propagation/production of a large number of plants in short durations. Micropropagation produces somaclones (plants genetically identical to the original/parent plant). 

2. Virus – free plants

Meristems of plants are grown by tissue culture to get virus – free plants. By this method, healthly plants can be recovered from diseased plants. 

3. Somatic hybridization: 

Somatic hybrids obtained from somatic hybridization (fusion of naked protoplasts isolated from two different varieties og plants) can be further grown to form new plants by tissue culture.

95847.

What are Mendel's laws of inheritance ? What are the reasons to choose pea plant for his experiment ?

Answer»

(1) Law of Dominance : Among a pair of closely related 'alleles' or factors, only one expresses itself. In the first generation as one of the allele is dominant over the other. This is called as Mendel's Law of dominance. 

(2) Law of Seggregation : The law of seggregation states that every individual possesses a pair of alleles for any particular trait that each parent possess a randomly selected copy only one of these to its off - spring. 

(3) Law of Independent assortment : In the inheritance of more than one pair of characters (traits), the factors for each pair of characters assort independently of the other pairs. This is known as 'Law of Independent assortment'. 

Mendel has chosen garden pea as material for his experiment because :

(i) It has well developed characters. 

(ii) It is a bisexual flower. 

(iii) Predominently self pollinating. 

(iv) Suitable for cross pollination. 

(v) It is an annual plant.

95848.

The correct order of bond angle is `A. `PF_(3) lt PCl_(3) lt PI_(3) lt PBr_(3)`B. `PF_(3) lt PCl_(3) lt PBr_(3) lt PI_(3)`C. `PF_(2) lt PCl_(3) lt PBr_(3) lt PI_(3)`D. `PCl_(3) lt PF_(3) lt PBr_(3) lt PI_(3)`

Answer» Correct Answer - 2
`underset(larr)(PF_(3) lt PCl_(3) lt PBr_(3) lt PI_(3))`
(i) Electronegative of halogens increases
(ii) Bond angle decreases
95849.

A volatile subsatnces A has density of liquid =2 gm/ml at its boiling point & density of vapours =0.001 gm/ml at the same condition. What will be the volume occupied by liquid in a 10 l sample of vapour at boiling point.A. 0.5 mlB. 5 mlC. 50 mlD. 1 ml

Answer» Correct Answer - 1
`d_(L)=2, d_(g)=0.0001 gm//ml`
`m/10000=0.0001`
m=1 gm
`d_(L)=2 =1/v`
`v_(L)=0.5 ml`
95850.

Which of the following is not the correct arrangements according to the property indicated againsts it ?A. `Li lt Na lt K lt Cs` (metallic radius )B. `I lt Br lt F lt Cl` (electron affinity)C. `B lt C lt N lt O` (first ionisation energy)D. `Al^(3+) lt Mg^(2+) lt Na^(+) lt F^(-)` (ionic radius )

Answer» Correct Answer - 3
`{:(B, lt, C,lt,O,lt,N" " "(First ionisation energy)"),(2s^(2)2p^(1),,2s^(2)2p^(2),,2s^(2)2p^(4),,2s^(2)2p^(3)),(,,,,,,"(Half filled stable)"):}`