This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 96551. |
If initial velocity of an object is zero, then distance covered by it in time t and acceleration of 9.8 m s-2 would beA. 2.9 t2 B. 3 t2 C. 4 t2 D. 4.9 t2 |
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Answer» The Correct option is D. 4.9 t2 |
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| 96552. |
Projectile will attain its maximum range, if it is fired at an angle of A. 30° B. 47° C. 90° D. 45° |
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Answer» The Correct option is D. 45° |
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| 96553. |
Equation of motion can be used for A. straight line motion only B. curved motion only C. motion along the circular path D. all types of motion |
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Answer» A. straight line motion only |
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| 96554. |
When ball having a projectile motion is rising up, it A. decelerates B. accelerates C. rises up with constant acceleration D. acceleration becomes zero |
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Answer» A. decelerates |
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| 96555. |
Horizontal component of a bouncing ball is A. affected by gravity B. unaffected by gravity C. affected by weight D. affected by contact force |
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Answer» B. unaffected by gravity |
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| 96556. |
The value of 5 ʘ8 11, where ⨀ is multiplication modulo is (a) -1(b) 0(c) 7(d) 9 |
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Answer» Correct answer is: (c) 7 5 ʘ811 = (5 × 11) mod 8 = 55 mod 8 = 7 |
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| 96557. |
Only force acting on a bouncing ball is A. gravity B. weight of ball C. friction D. a and b both |
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Answer» D. a and b both |
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| 96558. |
For two distinct positive numbers (a) \(x+y> 2\sqrt{xy}\)(b) \(\cfrac{x+y}{2}>xy\)(c) \(\sqrt{xy}> \cfrac{x+y}{2}\)(d) \(\cfrac{2xy}{x+y}> \sqrt{xy}\) |
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Answer» Correct answer is: (a) \(x+y> 2\sqrt{xy}\) For distinct x, y > 0; AM > GM ⟹ \(\cfrac{x+y}{2}\) > \(\sqrt{xy}\) ⇒ x +y > 2\(\sqrt{xy}\) |
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| 96559. |
Accelerometer detects the A. small acceleration B. large acceleration C. small decelerationD. large acceleration and deceleration |
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Answer» D. large acceleration and deceleration |
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| 96560. |
A person can row in still water at the rate of 8 km/h. If it takes him thrice as long to row upstream as to row downstream then the speed of the stream is: (a) 2 km/h(b) 3 km/h(c) 4 km/h(d) 6 km/h |
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Answer» Correct answer is: (c) 4 km/h Let x be the speed of the stream \(\therefore\) 8 +x = 3 (8-x) \(\Rightarrow\) 4x = 16 \(\Rightarrow\) x = 4km/h |
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| 96561. |
If the gradient of a graph is negative, then the acceleration is A. positive B. negative C. zero D. 1 |
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Answer» B. negative. |
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| 96562. |
Gradient of line of velocity-time graph is tells us the A. velocity B. acceleration C. distance D. time |
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Answer» B. acceleration |
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| 96563. |
If x ≡ −4 ( 3), then a solution for is: (a) -2(b) 12(c)19(d) 35 |
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Answer» Correct answer is: (d) 35 Since 3|(x+ 4) is true for x = 35 |
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| 96564. |
If a student drops a stone from a cliff of height 30 m and the time it takes to reach the ground is 2.6 s, then the acceleration due to gravity isA. 9 m s-2 B. 10 m s-2 C. 4 m s-2 D. 8.8 m s-2 |
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Answer» D. 8.8 m s-2 |
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| 96565. |
In a 3 × 3 matrix A, value of a12c13 + a22c23 + a32c33, where c is the cofactor of a is(a) 0(b) -1(c) 1(d) |A| |
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Answer» Correct answer is: (a) 0 The summation of product of aij of 2nd column with corresponding cij of 3 column =0 |
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| 96566. |
If two square matrices A and B are such that |AB| = 12 and |B| = −4, then value of |A| is:(a) 8(b) -8(c) -3(d)16 |
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Answer» Correct answer is: (c) -3 |AB| = 12 ⟹ |A| |B| = 12 ⟹ −4|A| = 12 ⟹ |A| = −3 |
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| 96567. |
If solving a system of linear equations in 3 variables by Cramer’s rule, we get Δ= 0 and at least one of Δx, Δy, Δz is non-zero then the system of linear equations has(a) no solution(b) unique solution(c) infinitely many solutions(d) trivial solution |
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Answer» Correct answer is: (a) no solution If Δ= 0 and at least (one of Δx, Δy, Δz) \(\neq\) 0 The system of linear equations has no solution |
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| 96568. |
Differentiation of `2x^2+3x` w.r.t. x isA. `4x+3`B. `4x`C. `3`D. `4x+1` |
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Answer» Correct Answer - A `y=2x^(2)+3x` `(dy)/(dx)=4x+3` |
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| 96569. |
`y=4+5x7x^(3)`. Find `(dy)/(dx)` : |
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Answer» Correct Answer - `5+21x^(2)` `y=4+5x+7x^(2),(dy)/(dx)=5+21x^(2)` |
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| 96570. |
`y=x^(4)+3x^(2)+pi+2`. Find `(dy)/(dx)` : |
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Answer» Correct Answer - `4x^(3)+6x` `y=x^(4)+3x^(2)+pi +2, (dy)/(dx)=4x^(3)+6x` |
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| 96571. |
Equation of straight line is `2x + 3y =5`. Slope of the straight line is :A. `3//2`B. `2//3`C. `-2//3`D. `-3//2` |
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Answer» Correct Answer - C `y=-2//3+5//3rArr(dy)/(dx)=-2//3` Alter `:y=mx+c` `(` slope `)m=-2//3` |
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| 96572. |
One end of massless inextensible string of length `l` is fixed and other end is tied to a small ball of mass `m`. The ball is performing a circular motion in vertical plane. At the lowest position, speed of ball is `sqrt(20gl)`. Neglect any other forces on the ball except tension and gravitational force. Acceleration due to gravity is `g`. At the highest position of ball, tangential acceleration of ball is `-` |
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Answer» Correct Answer - A At the highest position of ball, tangential acceleration of ball is zero. |
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| 96573. |
One end of massless inextensible string of length `l` is fixed and other end is tied to a small ball of mass `m`. The ball is performing a circular motion in vertical plane. At the lowest position, speed of ball is `sqrt(20gl)`. Neglect any other forces on the ball except tension and gravitational force. Acceleration due to gravity is `g`. During circular motion, minimum value of tension in the string`-`A. zero only if `m_(1)=m_(2)`B. `mg`C. `10mg`D. `15mg` |
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Answer» Correct Answer - D Tension in the string is minimum when ball is at the highest position.By conservation of energy `(1)/(2)mv^(2)+mg (2l)=(1)/(2) m (20gl)` `v^(2)=16gl` where `v` is the velocity of ball at the highest point. So `T+ mg =(mv^(2))/(l)` `T=(m16gl)/(l)-mg=15mg` |
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| 96574. |
A bar of mass `M` and length `L` is in pure traslatory motion with its of mass velocity `V` . It collides with and sticks to a second identical bar which is initially at rest . `(` Assume that it bocomes one composite bar of length `2L)`. The angular velocity of the composite bar will be A. `(3)/(4)(V)/(L)` clockwiseB. `(4)/(3)(VL)/(L)` clockwiseC. `(3)/(4)(V)/(L)` counterclockwiseD. `(V)/(L)` counterclockwise |
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Answer» Correct Answer - C Cons. Of ang. Momentum about `P` gives `MV(L)/(2)=((2M)(2L)^(2))/(12)omega` `(V)/(2)=(2Lomega)/(3)` `omega=(3V)/(4L), ` counterclockwise `Ans . (C )` |
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| 96575. |
An aeroplane is flying in vertical plane at an angle of `30^(@)` with the horizontal (north) and wind is is blowing from west.A package is dropped from an aeroplane. The velocity of the wind if package hits a kite flying in the space with a position vector `vec(R) = (400 sqrt(3) hat(i) + 80 hat(j) + 200 hat(k))`m with respect to the point of dropping. (Here `hat(i)` and `hat(j)` are the unit vectors along north and vertically up respectively and `hat(k)` be the unit vector due east. Assume that the bag is light enough to get carried away by the wind)A. 50 m/secB. 25 m/secC. 20 m/secD. 10 m/sec |
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Answer» Correct Answer - B Let velocity of the aeroplane be `vec(v)_(P) = u cos 30^(0) hat(i) + u sin 30^(0) hat(j)` and velocity of the wind be v, then `u (sqrt3)/(2) t hat(i) + ((u)/(2) t - 5t^(2)) hat(j) + vt hat(k)` `= 400 sqrt(3 hat(i)) + 80hat(j) + 200 hat(k)` `rArr u(sqrt3)/(2)t = 400 sqrt3, (u)/(2) t - 5t^(2) = 80, vt = 200` `ut = 800` and `(u)/(2)t - 5t^(2) = 80` `rArr 400 - 5t^(2) = 80 rArr t^(2) = 64` `rArr t = 8 sec` `rArr v = (200)/(8) = 25 m//s` |
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| 96576. |
Haridas discounts a bill for Rs. 10,000 with his banker on 4th February, 2007. The bill was drawn on 1 January for Four months. The discount rate was 12%. p.a. write Journal entries in the book of Haridas. |
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Answer» Book of Haridas [Drawer] Journal
Note: Calculation of discount Discount = 10.000 × 12/100 × 3/12 = 300 It may be noted that discount has been charged for three months and not for 4 months because the bank will have to wait for 3 months to get the payment of bill on the due date. |
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| 96577. |
Syam sold goods to Anil on credit for Rs. 3,000, on 10th April 2003. He drew a bill on Anil for the amount at 3 months after date. Anil accepted the same and returned it to syam. At maturity, he met his obligation. Pass journal entries in the books of both parties. |
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Answer» Book of Syam (Drawer) Journal.
Book of Anil [Drawee] journal.
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| 96578. |
Who are the parties to a promissory note: |
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Answer» There are two parties to a promissory note. 1. The maker or the promisor: He is the person who makes or draws the promissory notable is the debtor. 2. The payee or the promisee: He is a person in whose favour the promissiory note is drawn. |
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| 96579. |
The exchange of data between two firms or individually comes undera. RFID b. EDI c. RIS d. UPC |
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Answer» Correct option: b. EDI |
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| 96580. |
Which of the following is the sequence of POS activity a. Scanning, Receiving payments, Printing bills, Cash drawer b. Receiving payments, Scanning, Printing bills, Cash drawer c. Printing bills, Cash drawer, Receiving payments, Scanning d. Cash drawer, Printing bills, Receiving Payments, Scanning |
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Answer» Correct option: a. Scanning, Receiving payments, Printing bills, Cash drawer |
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| 96581. |
Briefly explain the following terms :- (i) Drawer (ii) Drawee Or Briefly explain the following term :- (i) Payee (ii) Days of grace |
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Answer» (i) Drawer :- The party who issue the bill. Drawer is the maker of the bill of exchange. A seller/creditor who is entitled to receive money from the debtor can draw a bill of exchange upon the buyer/debtor (ii) Drawee :- The party, on whom the bill is being issued. Drawee is the person upon whom the bill of exchange is drawn. Drawee is the purchaser or debtor of the goods upon whom the bill of exchange is drawn. Or (i) Payee: - Payee is the person to whom the payment is to be made. The drawer of the bill himself will be the payee if he keeps the bill with him till the date of its payment. The payee can be bank if the bill is discounted with the bank. (ii) Days of grace: - number of days, usually three, allowed by law or custom for payment after a bill or note falls due. |
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| 96582. |
From the given specimen of Bill of exchange, identify: 1. Drawer 2. Drawee 3. Payee 4. Term of bill 5. Date of maturity 6. Consideration on the bill |
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| 96583. |
A gas is taken through an isochoric process it means that |
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| 96584. |
If anyone gets any cut in hand, then the blood gets clot. In this process which component further converts fibrinogen (soluble) into fibrin clot (insoluble)? a) Calcium b) Thrombin c) Prothrombin d) Blood |
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Answer» Correct option: b) Thrombin |
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| 96585. |
During the collection of blood in the vial anticoagulant is used to make it anticoagulated. For this purpose EDTA is used as an anticoagulant. Name the full form of EDTA. a) ethylenediaminetetra-amino acid b) ethyldiaminetetra-acetic acid c) ethylenediaminetetra- acetic acid d) ethylenediaminetetrameric-acetic acid |
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Answer» Correct option: c) ethylenediaminetetra- acetic acid |
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| 96586. |
During the process of Platelet counting, why does Excessive EDTA lead to a spuriously high platelet count? a) RBCs may swell and then disintegrate into fragments which are counted as platelets b) Reticulocytes may swell and then disintegrate into fragments which are counted as platelets c) WBCs may swell and then disintegrate into fragments which are counted as platelets d) Platelets may swell and then disintegrate into fragments which are counted as platelets |
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Answer» Correct option: d) Platelets may swell and then disintegrate into fragments which are counted as platelets |
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| 96587. |
Raju is working as lab technician and he has to study Coagulation Studies and ESR measurement with the blood sample. Which anticoagulant will be used by Raju? a) EDTA b) Trisodium citrate c) Heparin d) Double Oxalates |
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Answer» Correct option: b) Trisodium citrate |
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| 96588. |
Find the simple interest on Rs. 3000 at 6 1/4% per annum for the period from 4th Feb., 2005 to 18th April, 2005. |
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Answer» Time = (24+31+18)days = 73 days = 73/365 years = 1/5 years. P = Rs.3000 and R = 6 ¼ %p.a = 25/4%p.a S.I. = Rs.(3,000*(25/4)*(1/5)*(1/100)) = Rs.37.50. |
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| 96589. |
Find the simple interest on Rs. 68,000 at 16 2/3% per annum for 9 months. |
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Answer» P = Rs.68000,R = 50/3% p.a and T = 9/12 years = 3/4 years. S.I. = (P*R*T)/100 = Rs.(68,000*(50/3)*(3/4)*(1/100)) = Rs.8500 |
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| 96590. |
It should never be left for more than 1 minute. For prolonged application re- apply it after the site has been cleaned and just prior to insertion of needle. Name the procedure that is performed here. a) Tourniquet application b) Injection Push c) Disinfection d) Sanitization |
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Answer» Correct option: a) Tourniquet application |
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| 96591. |
Which one of the following helps in growth and repair of body- a) Carbohydrates b) Proteins c) Fats d) Vitamins and minerals |
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Answer» Correct answer is b) Proteins |
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| 96592. |
Mercuric chloride – 0.5gms – Prevents growth of bacteria and fungus.Sodium chloride – 1.0gms Sodium sulphate - 5.0gms Distilled water – 200mlThe fluid has to be renewed frequently to avoid RBC clumping. Name the diluting fluid. a) Dacie’s formol citrate Solutionb) Toisson’s fluid c) Hayem’s fluid d) Gower’s fluid |
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Answer» Correct option: c) Hayem’s fluid |
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| 96593. |
_______is defined as clumping of particles that have antigen on their surface and is brought about by anti-bodies. a) Agglutination b) Hemolysis c) Reaction |
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Answer» a) Agglutination Agglutination is defined as clumping of particles that have antigen on their surface and is brought about by anti-bodies. |
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| 96594. |
IgM antibody is found in- (a) Serum (b) Blood (c) Saliva (d) None of them |
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Answer» IgM antibody is found in Blood. |
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| 96595. |
Name two antigens of kidd blood group system. a) Jkd and Jke b) Jkm and Jkn c) Jka and Jkb |
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Answer» c) Jka and Jkb two antigens of kidd blood group system is Jka and Jkb. |
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| 96596. |
Figure shows a smooth cylindrical pulley of radius `R` with centre at origin of co-ordinates. An ideal thread is thrown over it on the two parts of ideal thread two identical masses are tied initially at rest with co-ordinates `(R,0)` and `(-R,-R)` respectively. If mass at `x-`axis is given slight upward jerk, it leaves contact with pulley at `(R cos phi, Rsinphi)`. Then find `phi//sinphi`. |
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Answer» `mgRphi-mgRsinphi=1//2(2m)v^(2)`……(`i`) `mv^(2)//R=mgsinphi`…..(`ii`) |
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| 96597. |
The titer of an antibody is usually determined by testing two fold serial dilution of the serum against selected _______cells. a) Red b) White c) Blue |
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Answer» a) Red The titre of an antibody is usually determined by testing two fold serial dilution of the serum against selected Red cells. |
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| 96598. |
A rod of length `1m` rotates about one of its end points with an angular velocity `2 rad//sec` in a plane perpendicular to the magnetic field `B=2T` as shown in the figure. Then find magnitude of electric field (in `SI` unit) at the mid point of the rod. |
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Answer» For a charge to be in equlibirum, `qE=qvBrArrE=omegaLB//2=BL omega//2=2` |
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| 96599. |
A large open tank is filled with water upto a height H. A small hole is made at the base of the tank. It takes `T_1` time to decrease the height of water to H/n(ngt1) and it takes `T_(2)` time to take out the remaining water. If `T_(1)=T_(2)`, then the value of n isA. 2B. 3C. 4D. `2sqrt(2)` |
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Answer» `-A(dy)/(dt)=asqrt(2gy)` `(2A)/(asqrt(2)g)(sqrt(H)-sqrt(H/n))=T_(1)` `(2A)/(asqrt(2)g)(sqrt(H/n)-0)=T_(2)` `T_(1)=T_(2)` n=4. |
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| 96600. |
Geyser has a rating 2 kva, 240 v a) What is the electrical energy consumed by (i) kwh (ii) joule if it is used for 90 minutes. b) If the cost of electricity is Rs 4.50 per commercial unit find the cost |
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Answer» Power rating of Geyser = 2kva = 2000W (because p=vi) Now, Power= 2Kw Time= 90minutes = 3/2hours Energy consumed = Pxt 2x3/2= 3Kwh or 3 units. Now cost of electricity = 3x 4.5Rs/- = 13.5Rs/-.
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