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96601.

A capillary tube with inner cross-section in the form of a square of side a is dipped vertically in a liquid of density `rho` and surface tension `rho` which wet the surface of capillary tube with angle of contact `theta` . The approximate height to which liquid will be raised in the tube is : (Neglect the effect of surface tension at the corners of capillary tube)A. `(2sigma cos theta)/(arhog)`B. `(4sigma cos theta)/(arhog)`C. `(8sigma cos theta)/(arhog)`D. None of these

Answer» Upward force by capilary tube on top surface of liquid is
`f_(up)=4 sigma a cos theta`
If liquid is raised to a height h then we use
`4 sigma cos theta=ha^(2) rhog` or `h=(4sigma cos theta)/(arhog)` Ans.
96602.

Who discovered Rhesus blood group system? a) Land Steiner and Wiener b) Thompson c) Charles Darwin

Answer»

a) Land Steiner and Wiener

Land Steiner and Wiener discovered Rhesus blood group system.

96603.

Why Young Modulus (Y) is greater than Shear Modulus (G)? And proof the relation G = Y/3.

Answer»

Shear Modulus is smaller than Young’s Modulus due to the fact that shear stress is not uniformly distributed over the entire cross section of the member while axial stress is generally more uniformly distributed over the cross section. In other words, any member will carry axial stress in a more efficient manner than shear stress.

96604.

Who discovered Rhesus blood group system?

Answer»

Land Steiner and Wiener

96605.

Name the study of cells that have been shed or removed from the epithelial or mesothelial linings.

Answer»

Exfoliative cytology

96606.

Describe how to properly bleed the hydraulic brake system.

Answer»

Bleeding of Hydraulic brake systems Materials and instruments required: 

  1.  Glass jar, fresh hydraulic fluid, flexible plastic pipe of 1/2 meter length which can be fixed to the bleeding nipple. 
  2.  Double ended spanner of size 10 mm 
  3.  Dry cotton waste. 

Important points 

1 If the bleeding nipple is provided with the master cylinder that should be bled first before proceeding to bleed other wheels. 

2 The sequences of bleeding points for right hand drive vehicle are as follows: 

(a) Master Cylinder (if bleeding nipple provided) 

(b) Left rear wheel 

(c) Right rear wheel 

(d) Left front wheel 

(e) Right front wheel 

(i.e., the farthest wheel from the master cylinder to be bled, after cylinder bleeding and nearest to be bled at last) 

Procedure of bleeding 

(i) Park the vehicle on hard level ground put the hand brake (parking brake) pulled. 

(ii) Start the engine and run it for some line to build up the air pressure if the hydraulic brake system is assisted by compressed air(air assisted hydraulic) 

(iii) Let one person sit on the driver's seat to operate brake pedal and let other person carry out the bleeding operation of different points one by one according to the sequence of mentioned above. 

(iv) Connect the flexible pipe of the bleeding nipple and other end of the pipe should be placed in glass jar to preserve the bled fluid while bleeding air from the system. 

(v) Ask the person who is sitting on the driver's seat to pump the brakes pedal numbers of times till it becomes hard to press but the brakes pedal to be kept in fully pressed position. 

(vi) Loosen the bleeding screw and you will be find air bubbles coming out through bleeding nipple. 

(vii) Number of times same procedure may be repeated till fresh flow of fluid at a pressure coming through the nipple. 

(viii) During every repetition the bleeding nipple should be closed and opened when the signal comes from the driver that he pumped and pressed. 

(ix) After every operation of bleeding, check the level of brake fluid in the reservoir. 

(x) Run the vehicle and check the brake effectiveness.

96607.

Write down the full form of FNAC.

Answer»

Fine needle aspiration cytology

96608.

How the FNAC process can play important role in diagnostic purpose?

Answer»

Fine needle aspiration cytology includes aspiration done by the pathologist or the clinician as well as guided aspiration done by the radiologists and aspirations. It is a diagnostic procedure used to investigate pathological lesions in organs that do not shed cells spontaneously. In this technique, a thin, hollow needle is inserted into the lesion (usually a lump or a swelling) to obtain cells and tissue fragments, which, after being stained, are examined under a microscope.

96609.

Blood grouping is very important procedure in medical field. Why is it important.

Answer»

The importance of blood grouping: 

1. Safe blood transfusion 

2. Organ transplant especially liver, heart, and kidney 

3. Medicolegal and forensic, paternity disputes 

4. Immunology and genetics

96610.

The initial and final temperature of water as recorded by an observer are `(40.6 pm 0.2)^(@)C` and `(78.3 pm 0.3)^(@)C`. Calculate the rise in temperature.

Answer» Given `theta_(1)=(40.6+-0.2)^(@)C` and `theta_(2)=(78.3+-0.3)^(@)C`
Rise in temp. `theta=theta_(2)-theta_(1)=78.3-40.6=37.7^(@)C`.
`Deltatheta=+-(Deltatheta_(1)+Deltatheta_(2))=+-(0.2+0.3)=+-0.5^(@)C`
`therefore` rise in temperature `=(37.7+-0.5)^(@)C`
96611.

Following observations were taken with a vernier callipers while measuring the length of a cylinder : `3.29 cm,3.28 cm,3.31 cm,3.28 cm,3.27 cm,3.29 cm,3.20 cm`. Then find : (a) Most accurate length of the cylinder (b) Absolute error in each observation (c) Mean absolute error (d) Relative error (e) Percentage error Express the result in terms absolute error and percentage error.

Answer» (a) Most accurate length of the cylinder will be the mean length `(vecl)`
`vecl=(3.29+3.28+3.29+3.31+3.28+3.27+3.29+3.30)/(8)=3.28875 cm "or" vecl=3.29cm`
(b) Absolute error in the first reading `=3.29-3.29=0.00cm`
Absolute error in the second reading =3.29-3.28=0.01cm
Absolute error in the thrid reading =2.29-3.29=0.00cm
Absolute error in the forth reading =3.39-3.31=-0.02cm
Absolute error in the fifith reading =3.29-3.28=0.01cm
Absolute error in the sixth reading =3.29-3.27=0.02cm
Absolute error in the seventh reading =3.29-3.29=0.00cm
Absolute error in the last reading =3.29-3.30=-0.01cm
(c) Mean absolute error `=vecDeltal=(0.00+0.01+0.00+0.02+0.01+0.02+0.00+0.01)/(8)=0.01 cm`
(d) Relative error in length `=(vecDeltal)/(l)=(0.01)/(3.29)=0.0030395=0.003`
(e) Percentage error `=(vecDeltal)/(vecl)xx100=0.003xx100=0.3%`
so length `l=3.29cm+-0.01cm` (in terms of absolute error)
or `t=3.29cm +- 0.30%` (in terms percentage error)
96612.

Round off the following numbers as indicated : (ii) 25.653 ot 3 digits (ii) 4.996xx10^5 to 3 digits (iii) 0.6995 to 1 digit (iv) 3.350 to 2 digits. (v) 3.450 to 2 digits.

Answer» (a) 25.7 (b) `5.00xx10^(5)` (c) `0.7` (d) 3.4 (e) 0.393 kg (f) `4.08xx10^(8)s`
96613.

A circular ring has inner and outer radii equal to `10 mm and 30 mm` respectively Mass of the ring is `m = 0.7` g. It gently pulled out vertically from a water surface by a sensitive spring. When the spring is stretched `3.4 cm` from its equilibrium position the ring is on verge of being pulled out from the water surface. If spring constant is `k = 0.7 Nm^(–1)` find the surface tension of water. A. `0.02 N//m`B. `0.07 N//m`C. `0.04 N//m`D. `0.09 N//m`

Answer» Correct Answer - B
When the ring is about to leave the water surface, surface tension force on it is
`F_(ST) = 2piRT + 2pirT = 2pi (R + r)T `
Spring force `F_(s) = kx`
`:. kx = 2pi(R+r)T + mg`
`:. T = (kx - mg)/(2pi(R + r)) = (0.73 xx 3.4 xx 10^(-2)-7 xx 10^(-4) xx 9.8)/(2xx 3.14 xx(30 + 10 xx 10^(-3))) =`
`0.076 Nm^(-1)`
96614.

A liquid is flowing through a horizontal channel. The speed of flow `(v)` depends on height `(y)` from the floor as `v = v_(0)[2((y)/(h))-((y)/(h))^(2)]`. Where `h` is the height of liquid in the channel and `v_(0)` is the speed of the top layer. Coefficient of viscosity is `eta`. Then the shear stress that the liquid exerts on the floor is. ` `A. `(2etav_(0))/(h)`B. `(3etav_(0))/(h)`C. `(4etav_(0))/(h)`D. `(2etav_(0))/(3h)`

Answer» Correct Answer - A
Shear stress is tangential force applied by the liquid on unit area of the floor:
Velocity gradient `= (dv)/(dy) = (2v_(0))/(h) - (2v_(0))/(h_(2))y`
At `y = 0, (dv)/(dy) = (2v_(0))/(h)`
`:.` Viscous force per unit area `= eta(dv)/(dy) = (2etav_(0))/(h)`
96615.

A particle is performing simple harmonic motion along the x axis about the origin. The amplitude of oscillation is a. A large number of photographs of the particle are shot at regular intervals of time with a high speed camera. It was found that photographs having the particle at `x_(1) + Deltax` were maximum in number and photographs having the particle at `x_(2) + Deltax` were least in number. What are values of `x_(1) " and " x_(2)`?A. `x_(1) = +- a, x_(2) = 0`B. `x_(1) = 0, x_(2) = +- a`C. `x_(1) = +- (a)/(2), x_(2) = 0`D. None of these

Answer» Correct Answer - A
96616.

Among the following structures the one which is not a resonating structure of other is : A. `IV`B. `II`C. `III`D. `I`

Answer» Correct Answer - B
96617.

Explain any three modes to open a file in C++.

Answer»

The file can be opened both for input and output operations using fstream class.
The syntax for opening a file with constructor is fstream object(“filename”, mode);
The syntax for opening a file with open() is fstream object.open(“filename”, mode);
Therefore, file can be opened using different modes. They are
ios::in opens file for reading only. For example, fstream fin(“te’xt.dat”, ios::in);
ios::out opens file for writing only. For example, fstream fout(“text.dat”, ios::out);
ios::app opens a file to append to end of file. For example, fstream
file.open(“text.dat”,ios::app);

96618.

A mixture contaning `1 mol` each of `CO` and `O_(2)` is exploded to produce `CO_(2)`. Which of the following is/are correct ?A. If `%` yield of reaction is `80%`, only `0.8` mole `CO_(2)` is formed.B. Oxygen is limiting reagent.C. Volume of final gaseous mixture is `33.6L` at `STP`, if `%` yield is `100%`D. `%` excess of excess reagent is `40%`, if `%` yield is `100%`

Answer» Correct Answer - A::C
`{:(2CO,+,O_(2)rarr,2CO_(2),),(,,CO is L.R. ,, O_(2) "is excess reagent"),(t=t,,1mol, 1mol),(t=t,o mol,1/2mol,mol("If % yield is 100%")):}`
Total gaseous moles `= 1 + (1)/(2) = 1.5 mol`
`:.` Volume of final mixture `1.5 xx 22.4 = 33.6L`
`%` excess of `O_(2) = (1//2"mol")/(1//2"mol") xx 100 = 100%`
If `%` yield `= 80`
`= ("Actual moles of" CO_(2) "formed")/("moles of" CO_(2) ("accoding to stoichiometry"))xx 100`
`80 = ("Moles of" CO_(2)"formed")/(1) xx 100`
`:.` Actual moles formed `= 0.8 mol`
96619.

In the balanced chemical reaction `IO_(3)^(ө)+al^(ө)+bH^(ө)rarrcH_(2)O+dI_(2)` `a, b,c`, and `d`, respectively, correspond toA. `a = 5`B. `c = 3`C. `d = 5`D. `b = 6`

Answer» Correct Answer - A::B::D
or `IO_(3^(-)) + 5I^(-) + 6H^(+) rarr 3I_(2) + H_(2)O`
96620.

Least active electrophile is :A. `CH_(3)-overset(O)overset(||)C-OCH_(3)`B. `CH_(3)-overset(O)overset(||)C-Cl`C. `CH_(3)-overset(O)overset(||)C-NMe_(2)`D. `CH_(3)-overset(O)overset(||)C-SCH_(3)`

Answer» Correct Answer - C
96621.

Mention database users.

Answer»

There are different types of database users. They are
1. Application programmers or Ordinary users:
These users write application programs to interact with the database. Application programs can be written in some programming language typically a SQL statement to DBMS.

2. End Users:
End users are the users, who use the applications developed. They just use the system to get their task done. End users are of two types:

  • Direct users
  • Indirect users.

3. Database Administrator (DBA):

Database Administrator (DBA) is the person which makes the strategic and policy decisions regarding the data of the enterprise, DBA is responsible for overall control of the system at a technical level.

4. System Analyst:
System Analyst determines the requirement of end-users, and develops specifications for transactions that meet these requirements. System Analyst plays a major role in database design, technical aspect, etc. of the system.

96622.

Which of the following alkyl halides is hydrolysed by `S_(N^(1))` mechanism?A. `CH_(3)Cl`B. `CH_(3)CH_(2)Cl`C. `CH_(3)CH_(2)CH_(2)Cl`D. `(CH_(3))_(3)"CCl"`

Answer» Correct Answer - D
96623.

The most easily hydrolysed molecule under `S_(N^(1))` condition is:A. allyl chlorideB. benzyl chlorideC. ethyl chlorideD. isopropyl chloride

Answer» Correct Answer - B
96624.

Give the services of e-commerce.

Answer»

Few services of eCommerce are:

  • Domain name purchasing.
  • Secure hosting.
  • Full integration with the payment gateway of your choice.
  • Web design.
  • Shopping cart system.
  • Marketing.
96625.

Explain any three HTML tags.

Answer»

1. The <p> tag is a paragraph tag.
Usage:
<p> HTML paragraphs </p>

2. The <table> tag is a table tag that creates a table in HTML.
Usage:
<table> </table>

3. The <tr> tag is a table row tag that creates a row in a table.
Usage: <tr> </tr>

96626.

What is the chemical composition of Nicol prism ?A. `AI_(2)O_(3)`B. `CaSO_(4)`C. `CaCO_(3)`D. `Na_(3)AIF_(6)`

Answer» Correct Answer - c
Nicol prism consists of a rhombohedral crytstal of iceland spn which is a variety of calcite i.e `CaCO_(3)` hence the composition is `CaCO_(3)`
96627.

The activation energies of two reactions are `E_(1)` & `E_(2)` with `E_(1)gtE_(2)`. If temperature of reacting system is increased from `T_(1)` (rate constant are `k_(1)` and `k_(2)`) to `T_(2)` (rate constant are `k_(1)^(1)` and `k_(2)^(1)`) predict which of the following alternative is incorrect.A. `(k_(1)^(1))/(k_(1))=(k_(2)^(1))/(k_(2))`B. `(k_(1)^(1))/(k_(1))gt(k_(2)^(1))/(k_(2))`C. `(k_(1)^(1))/(k_(1))lt(k_(2)^(1))/(k_(2))`D. `k_(1)^(1)ltk_(2)^(1)`

Answer» Correct Answer - B
Greater the activation energy of a reaction, greater is the temperature dependence of rate constant of reaction.
96628.

Identity the chiral molecule

Answer»

But in 1-chlorobutane, there is no carbon atom which is attached to four different atoms or groups. Hence the chiral compound is 2-chlorobutane.

96629.

Statement-1: Lithium is the most powerful reducing agent and sodium is the least powerful reducing agent amongst the alkali metals in aqueous solutions. Statement-2:Lithium has the highest hydration enthalpy and the sodium the least value.A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1C. Statement-1 is True, Statement-2 is False.D. Statement-1 is False, Statement-2 is True.

Answer» Correct Answer - C
(i)`E^0Li^(+)//Li= - 3.04 , Na^(+)//Na=-2.71` which is least among the alkali metals.
(ii)Hydration enthalpy /`KJ mol^(-1)`
Li= -506 , Na=-406 , Cs has the least `DeltaH_(hyd)=-276`
96630.

`NaHSO_3overset(NaCO_3)to(A)underset(Delta)overset("Element S")to(B)overset(I_2)to( C)` Find out the oxidation state of sulphur in the compound (A) to ( C).Give average value without sign, if the compound formed has more than one sulphur atoms. Does not consider the decimal.For example if the value is 3.5 than neglact the decimal and consider it as 35

Answer» Correct Answer - 4,2,2,5
(A)`Na_2SO_3`
(B)`Na_2S_2O_3`
(C )`Na_2S_4O_6`
`NaHSO_3+Na_2CO_3toNa_2SO_3(A)+H_2O+CO_2`
`Na_2SO_3+Soverset(Delta)toNa_2S_2O_3`(B)
`2Na_2S_2O_3+I_2toNa_2S_4O_6`(C )+2NaI
(A)`SO_3^(2-)`, x+3(-2)= -2
x=6-2=4
(B)`S_2O_3^(2-)`, 2x+3(-2)= -2
2x=6-2=4
x=2
(C )`S_4O_6^(2-)`, 4x+6(-2)= -2
4x=12-2=10
x=10/4 =2.5
96631.

Match each of the reactions given in column I with the corresponding products given in column II. `{:("Column I","Column II"),((A)Sn+conc.HNO_3,(p)"NO"),((B)Sn+dil.HNO_3,(q)NO_3 ),(( C)Ag+conc.HNO_3,(r)NH_4NO_3),((D)Ag+dil.HNO_3,(s)Sn(NO_3)_2),(,(t)AgNO_3):}`

Answer» Correct Answer - A-p ; B-r,s ; C-q,t ; D-p,t
(A)3Sn+`4HNO_3`(concssentrated ) + (x-2)`H_2Oto 4NO uarr + 3SnO_2 xH_2O`(metastrannic acid) (vogal)
(B)`4Sn+10^(+)+NO_3^(-)`(dilute)`to4Sn^(2+)+NH_4^(+)+3H_2O` (vogel)
(C )`Ag+2HNO_3` (concentrated) `toAgNO_3+NO_2+H_2O`
(D)`3Ag+4HNO_3`(dilute) `to 3AgNO_3 + NO + 2H_2O`
96632.

Match the compounds listed in colomn-I with characteristic(s) type of reactions listed in column-II. `{:("Column I","Column II"),((A)"Ionic hydrides",(p)B_2H_6","CH_4","H_2O","SiH_4),((B)"Covalent hydrides",(q)CuH","ZnH_2","CdH_2","HgH_2 ),(( C)"Metallic hydrides",(r)ScH_2","TiH_2","VH_2","ZrH_2),((D)"Intermediate hydrides",(s)NaH","KH","CaH_2","SrH_2):}`

Answer» Correct Answer - A`to`s ; B`to`p ; C`to`r ; D`to` q
(A)Ionic hydrides `to` (s)
(B)Covalent `to`(p)
(C )Metallic `to` ( r )
(D)Intermediate `to` (q)
96633.

If 1 litre aq. Solution of `H_(2)SO_(4)` ( `10%` by weight) with density 1.1 gm/ml, find th `pH` of solution.A. `-log2.244`B. `-log1.96`C. `-log1.86`D. `-log3.87`

Answer» Correct Answer - A
Let us take `100 gm` solution `implies 10 gm H_(2)SO_(4)` in `90 gm H_(2)O`
`100/1.1 ml` solution `=10/98="mol" H_(2)SO_(4)`
So, `M=(10xx1.1)/(98xx0.1)=110/98=1.122impliesN=2.244`
`pH=-log2.244`
96634.

In an ionic solid `r_(c)=1.6Å` and `r_(a)=1.86Å`. Find edge length of cubic unit cell is `Å`

Answer» Correct Answer - 4
`(r_(c))/(r_(a))=0.858`
From above ratio it is clear that cation occupy cubic void in simple cubic unit cell, hence
`sqrt(3)a=2(r_(c)+r_(a))`
`a=4`
96635.

In an ionic solid `r_((+)) = 1.6 Å and r_((-)) = 1.864 Å`. Use the radius ratio rule to determine the edge length of the cubic unit cell in `Å`A. 4B. `2sqrt3`C. `3sqrt3`D. `4/sqrt3`

Answer» Correct Answer - A
`r_+/r_(-) = 1.6/1.864=0.858`
So, It is CsCl type of unit cell
So `sqrt3 a=2(r_+ +r_-)`
So `a=(2(1.864+1.6))/sqrt3Å=2xx2Å=4Å`
96636.

The following curve shows the change of `pH` during the course of titration of weak acid `HA` with a strong base. At which point in the titration curve is the concentration of acid equal to that of its conjugate base. A. Point DB. Point EC. Point CD. Point B

Answer» Correct Answer - D
Point B represents exactly half neutralisation of acid. At this point concentration acid left and its conjugate base are equal.
96637.

1 cf at liquid of molar volume 100 mL is kept in an adiabatic container under a pressure of 1 bar.The pressure is steeply increased to 100 bar.Under this constant pressure of 100 bar, the volume of the liquid decreases by 1 mL.Calculate `DeltaU` of the process.

Answer» Correct Answer - `DeltaU=10 J`
`DeltaU=10J`
`DeltaU=DeltaQ+DeltaW`
for adiabatic process `DeltaQ=O`
`:. DeltaU=DeltaW=-PDeltaV= -100xx10^5(-10^(-6))=10 J`
96638.

The day before today was ______

Answer»

Correct answer is yesterday

96639.

Statement 1: KI molar conductivity increases steeply with increasing dilution.Statement 2: Carbonic molar conductivity increase/slowly with dilution.  (a) Both statement 1 and 2 are correct(b) Statement I is correct but statement 2 is incorrect(c) Statement 1 is incorrect but statement 2 is correct (d) Both statement 1 and 2 are incorrect.

Answer»

(d) Both statement 1 and 2 are incorrect.

The molar conductivity of KI increases slowly with dilution. Molar conductivity of carbonic acid increases steeply with dilution Therefore, both the statement are false

96640.

John Frantz is American. He has a wonderful lifestyle and he wants __(1)__ it with an English girl. He enjoys __(2)__ on exotic holidays, but he wouldn’t like __(3)__ outside the United States. He hopes __(4)__ an English wife through the English Rose dating agency. He’d like __(5)__ someone who likes __(6)__. 1. A) sharing B) share C) shared D) to share 2. A) to go B) went C) going D) to going 3. A) living B) to live C) live D) lives 4. A) to find B) found C) finding D) to be founded 5. A) meets B) to met C) meeting D) to meet 6. A) traveling B) traveled C) travel D) to traveling

Answer»

1 D) to share

2 C) going

3 B) to live

4 A) to find

5 D) to meet

6 A) traveling

96641.

The money used in Japan is ______

Answer»

Correct answer is yen

96642.

A bond formed by a shared pair of electrons, each bonding atom contributing one electron to the pair.

Answer»

Covalent bond

A covalent bond is formed by equal sharing of electrons from both the participating atoms. The pair of electrons participating in this type of bonding is called shared pair or bonding pair. The covalent bonds are also termed as molecular bonds. Sharing of bonding pairs will ensure that the atoms achieve stability in their outer shell which is similar to the atoms of noble gases.

96643.

The American English word for garden is ______

Answer»

Correct answer is yard

96644.

It takes this long for the earth to revolve around the sun. It’s a ______

Answer»

Correct option is year

96645.

"Razzle dazzle" is _____. A) a fancy display B) an unusual event C) something impossible

Answer»

Correct option is A) a fancy display

96646.

Of service" means to be _____. A) efficient B) useful C) desirable

Answer»

Correct option is B) useful

96647.

A shout caused by excitement or pain is a ______

Answer»

Correct option is yell

96648.

If something is "old hat", it _____. A) isn't new B) isn't popular C) well know

Answer»

Correct option is A) isn't new

96649.

They say that it takes smokers longer to ______ a cold than nonsmokers. A) get across B) get off C) get out of D) get over

Answer»

Correct option is D) get over

96650.

A short positive agreement in English is ______

Answer»

Correct option is yes