This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 96801. |
The door ______ unless you ______. A) won’t open / push B) doesn’t open / will push C) won’t open / will push D) isn’t open / push |
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Answer» Correct option is A) won’t open / push |
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| 96802. |
Junko Tabei -JAPNESE MOUNTANIER |
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Answer» Junko Tabei, first woman to climb Mount Everest. Junko Tabei became the First Woman in 1975 to climb the Mt. Everest. |
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| 96803. |
Don’t worry about the baby. I’ll look _____ her while you’re out. A) for B) with C) to D) after |
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Answer» Correct option is D) after |
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| 96804. |
Who is father of biology? |
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Answer» The Fathers of Biology is Aristotle. In the 4th century BC the Greek philosopher Aristotle traveled to Lesvos, an island in the Aegean teeming, then as now, with wildlife. His fascination with what he found there, and his painstaking study of it, led to the birth of a new science i.e., Biology. Biology is one of the three major branches of natural science. Biology is the study of life, living things and evolution of life. Living things like animals, plants, fungi, microorganisms, etc. This branch of science is related to the study of life and its processes. Biology is further divided into many branches, the father of most of the biology branches are discussed below. FATHER OF BIOLOGY IS ARISTOTLE |
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| 96805. |
Why does thermionic emission take place from a metal surface only? |
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Answer» Cause-A lot of free electrons are present in metals but elections in non metals require maximum energy for emission,work function is reduced or decreased by giving oxide layer on the metal.For good thermionic emission tungston is coated by stransium oxide. |
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| 96806. |
I’ll ________ the children for you while you are out. A) look after B) look for C) look on D) look out E) look over |
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Answer» Correct option is A) look after |
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| 96807. |
Teresa ______ to the theatre, but Jack doesn’t. A) want to go B) wants to go C) can go D) wanted to go |
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Answer» Correct option is B) wants to go |
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| 96808. |
I don’t think he ______ pass. A) won’t B) doesn’t C) would D) will |
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Answer» Correct option is D) will |
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| 96809. |
1st pm of india |
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Answer» Jawaharlal Nehru was the first Prime Minister of India. JAWAHARLAL NEHRU WAS THE FIRST PM OF INDIAHE WAS ELECTED AS PM AT 15-AUG-1947 HE WORKED AS PM UNTI 27 MAY 1964 |
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| 96810. |
I wish I could ________ smoking. A) give away B) give from C) give off D) give out E) give up |
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Answer» Correct option is E) give up |
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| 96811. |
Does she ______ some ice ? A) wanted B) want C) wants D) to want |
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Answer» Correct option is B) want |
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| 96812. |
How many more times have I got to tell you not to ______ here without knocking? A) burst out B) burst on C) burst in D) burst off |
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Answer» Correct option is C) burst in |
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| 96813. |
Who ______ play tennis with me ? A) wants B) want to C) wants to D) to want |
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Answer» Correct option is C) wants to |
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| 96814. |
If you don, t ______ smoking, you’ ll never regain your health? A) give of B) give away C) give up D) give off |
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Answer» Correct option is C) give up |
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| 96815. |
The children ______ play with them. A) want that I B) want me to C) want me for D) want my |
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Answer» Correct option is B) want me to |
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| 96816. |
The ______ makes bread. A) cook B) shopkeeper C) baker D) actor |
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Answer» Correct option is C) baker |
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| 96817. |
Send him to the baker’ s ______ some bread. A) to buy B) for buying C) in order that D) for I buy |
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Answer» Correct option is A) to buy |
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| 96818. |
Read the extracts given below and answering the questions:The baker or bread-seller of those days had a peculiar dress known as the kabai. It was a single piece long frock reaching down to the knees. In our childhood we saw bakers wearing shirt and trousers which were shorter than full-length ones and longer than half pants. Even today, anyone who wears a half pant which reaches just below the knees invites the comment that he is dressed like a pader!i. Choose the answer that lists the correct option about the recording of the baker’s monthly accounts.a) Option (1) b) Option (2) c) Option (3) d) Option (4)ii. When the writer says, ‘Baking was indeed a profitable profession in the old days.’, he means that a) baking isn’t as popular in Goa currently. b) bakers have chosen to adopt other professions. c) baking, as a job, isn’t as gainful as it used to be. d) bakers’ goods were of a better quality in earlier times. iii. The statement that is TRUE about payment collection, according to the passage is: a) The baker received payment on a daily basis. b) The baker was paid for his services at the end of the month. c) The baker insisted that customers pay before the month-end. d) The baker chose to receive payment any day of the month. iv. The kabai was a ‘peculiar’ outfit as it was a) a tight-fitting apparel. b) too colourful. c) made of unsuitable materials. d) a dress-like attire.v. The extract uses the phrase, ‘invites (the) comments’. Which of the following expressions is incorrect with respect to the word ‘invites’ ?a) Option (1) b) Option (2) c) Option (3) d) Option (4) |
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Answer» i. c) Option (3) ii. c) baking, as a job, isn’t as gainful as it used to be. iii. b) The baker was paid for his services at the end of the month. iv. d) it was a dress-like attire. v. b) Option (2) |
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| 96819. |
neruda suggest that |
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Answer» Instead of indulging in wars, the people must come out in their best dresses with then- brothers. They should go out for a walk under the shady trees and enjoy themselves doing nothing. This would bring the feeling of togetherness among them. |
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| 96820. |
What different kinds of bread did the baker delivered? |
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Answer» Different varieties of bread are – bol, cakes and bolinhas. Every variety of bread is associated with different occasions. The sweet bread, bol is used as a marriage gift. The sandwiches are made on engagements. |
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| 96821. |
I think it’s a lot more difficult to ______ children nowadays than it used to be. A) bring out B) bring off C) bring on D) bring up |
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Answer» Correct option is D) bring up |
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| 96822. |
the poet uses the word let s to |
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Answer» It initiates the poet to begin a story or a poem |
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| 96823. |
Write of characteristics sketch of astrologer |
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Answer» In "An Astrologer's Day," the main character is the astrologer. He is an ordinary man who practices to be a genuine astrologer. At midday, he begins his job by seeking out people who need to know more about their futures. Punctually at midday he opened his bag and spread out his professional equipment, which consisted of a dozen cowrie shells, a square piece of cloth with obscure mystic charts on it, a notebook, and a bundle of palmyra writing. In a prophetic like glare, he seeks out customers. They take his mysterious stare as being genuine in that he knows something about the future. His forehead was resplendent with sacred ash and vermilion, and his eyes sparkled with a sharp abnormal gleam which was really an outcome of a continual searching look for customers, but which his simple clients took to be a prophetic light and felt comforted. The astrologer worked in an area that had poor lighting. At night, he used the light of the neighboring vendors who sold nuts, fruits, and ice cream to name a few things being sold. He did what had he had to do to earn a living. When a client would sit down, he would allow the client to talk for ten minutes. By this time, the astrologer had enough information to go on. He was a good judge of character. He could read people very well. His job was one of guess work for "he knew no more of what was going to happen to others than he knew what was going to happen to himself the next minute." |
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| 96824. |
options:a) no coagulation will occur at any electrode b) coagulation will occur at cathodec) coagulation will occur at anoded) coagulation will occur at both electrode |
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Answer» b) coagulation will occur at cathode |
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| 96825. |
A tube of sugar solution 20 cm long is placed between crossed nicols and illuminated with light of wavelength `6xx10^(-5)` cm If the optical rotation produced is `13^(@)` and the specific rotation is `65^(@)` determine the strength of the solutionA. `0.1g//cc`B. `0.2g//cc`C. `0.9g//cc`D. `1.0g//cc` |
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Answer» Correct Answer - A The specific totation `alpha` of a solution is given by `alpha=(theta)/(lxxC)` where `theta` is the optical rotation in degrees, I is the length of the tube in dicimeter and c the strength of the solution in `gm//cc` `therefore C=(theta)/(Ixxalpha)` Here `theta =13^(@),I=20cm=2.0 decimeter and alpha=65^(@)` `therefore c=(13^(@))/(2xx65^(@))=0.1g//cc` |
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| 96826. |
I got 95.87 percentile in jee mains 2020 january attempt. And my category is general girl. So pls suggest which nit or iiit can i get and with which branch?? |
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Answer» You have scored a decent percentile. Your JEE Main All India rank will be approx 20k - 21k. For getting seat In NITs your score should be —
For getting Seat in top 10 NITs ( in CSE, IT or ECE )
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| 96827. |
A long wire having a semi-circular loop of radius r carries a current I, as shown in Fig. Find the magnetic field due to entire wire. A. `(mu_(0)I)/(4r)`B. `(mu_(0)I^(2))/(4r)`C. `(mu_(0)I)/(4r^(2))`D. None of these |
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Answer» Correct Answer - A According to Biot savart Law, the magnetic induction at a point to a current carrying elemnet i `delta` l is given by `deltaB=(mu_(0))/(4pi)(ideltalxxr)/(r^(3))or B=(mu_(0))/(4pi)(ideltalsintheta)/(r^(2))` Directed normal to plane containing `deltal` and r theta being angle between `delta`l and r r `theta` being angle between `delta` l and r Magnetic field due to linear portions of wire If we consider anuy element of lenth `deltal` of either linear portion ab or de, the angle between `delta` l and r is 0 or `pi` therefore. `sintheta=0` Hence, magnetic induction due to both linear portins of wire is `(mu_(0))/(4pi)(ideltalsintheta)/(r)=0` Field due to semi circular are Now angle between a current element `delta` l of semi circular arc and the radius vector of the elment to point c is `pi//2` Therefoe the magnitude of magnetic induction B at O due to this element is `deltaB=(mu_(0))/(4pi)(ideltalsinpi//2)/(r^(2))=(mu_(0)ideltal)/(4pir^(2))` Hence magnetic indution due to whole semi circular loop is `B=Sigma(mu_(0))/(4pi)(ideltal)/(r^(2))=(mu_(0))/(4pir^(2))=(mu_(0))/(4pi)(i)/(i^(2))Sigmadeltai=(mu_(0)i)/(4piR^(2))(pir)=(mu_(0)i)/(4r)` |
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| 96828. |
A conductor lies along the ` z`-axis at ` -1.5 le z lt 1.5 m` and carries a fixed current of `10.0 A` in `- hat(a)_(z)` direction ( see figure). For a field `vec(B) = 3.0 xx 10^(-4) e^(-0.2x) hat(a)_(y) T`, find the power required to move the conductor at constant speed to `x = 2.0 m , y = 0 m ` in `5xx 10^(-3)s` . Assume parallel motion along the ` x-axis`. A. 1.57 WB. 2.97 WC. 4.45 WD. 9.87 W |
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Answer» Correct Answer - B Force exerted on curretn carrying conductor (F)=BII Given ,`B =3xx10^(4)e^(0.2x)ay,I=10.0 A` `Average power=(Work done)/(Time taken)` `P=(1)/(5xx10^(-3)intoverset(2)underset(0)int3xx10^(-4)e^(-0.2x)xx10xx3dx` `=9[1-e^(-0.4)]=9[1-(1)/(e^(0.4))]=2.967 W=2.97 W` |
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| 96829. |
Which of the following patterns do not withstand rough handling?(a) Aluminium(b) Cast iron(c) Brass(d) Steel |
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Answer» Correct choice is (a) Aluminium Best explanation: It is one of the limitation of aluminium pattern that, it cannot withstand rough handling, while all other metal and alloy patterns can withstand it. Aluminium is the lightest metal known. |
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| 96830. |
Refer to Q5 and, calculate: An error is made determining the steady-state oxygen level which, instead of 78%, is taken as 70%. What is the percentage error in kLa resulting from this 10% error in (ar{C_{AL}})?(a) 50%(b) 25%(c) 75%(d) 100% |
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Answer» Right option is (d) 100% For explanation I would say: If (ar{C_{AL}}) is taken to be 70% air saturation: The error in kLa is almost 100%. |
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| 96831. |
An air column in a pipe, when is closed at one end, is in resonance with a vibrating tuning fork of frequency `264 H_(Z)`. If `upsilon = 330 m//s`, the length of the column in cm is (are)A. `31.25`B. `62.5`C. `93.75`D. `125` |
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Answer» Correct Answer - A::C `n_(1)=(V)/(4l)impliesl=(V)/(4n_(1))`, `n_(2)=3n_(1)` |
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| 96832. |
In a resonance apparatus, the first and second resonating lengths of air column are `15cm` and `48cm` respectively. The end correction for this apparatus isA. `6cm`B. `3cm`C. `1.5cm`D. `2cm` |
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Answer» Correct Answer - C `e=(l_(2)-2l_(1))/(2)` |
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| 96833. |
Number of mole of KMnO4 is required to react completely with 1 mole of Fe2(C2O4)3 in acidic medium is equal to(1) 6/5(2) 1.2(3) 5(4) Both 1 & 2 |
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Answer» Correct option is (A) 6/5 In acidic medium- \(M_n{O_4}^- \longrightarrow Mn^{+2}\) or \(Mn{O_4}^- + 8H^+ + 5e^- \longrightarrow Mn^{+2} + 4H_2O\) ....(i) \([C_2{O_4}^{-2} \longrightarrow 2CO_2 + 2e^-]\) ......(ii) Applying 5 x (ii) + 2 x (i), we get ⇒ \(2Mn{O_4}^- + 16H^+ + 5C_2 {O_4}^{-2} \longrightarrow 10CO_2 + 2Mn^{+2} + 8H_2O\) or \(2KMnO_4 + 8H_2SO_4+ \frac 53 Fe_2(C_2O_4)_3 \longrightarrow 10CO_2 + 2MnSO_4 + K_2SO_4 + \frac 53Fe_2(SO_4)_3\) \(\because \frac 53\) mole Fe2(C2O4)3 react with 2 mole of KMnO4. \(\therefore\) 1 mole of Fe2(C2O4)3 react with = \(\frac 2{5/3}\) mole of KMnO4 \(= \frac{2\times 3}5\) \(= \frac 65\) mole of KMnO4 |
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| 96834. |
Sum of the paired electrons present in the orbital with l=2 in all the species Fe2+, Co2+ and Ni2+ are2nd one |
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Answer» Answer: l = 2 means d orbitals So the sum of paired electrons is 2+4+6=12 |
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| 96835. |
26. In which of the following compounds, an element exhibits two different oxidation states?(a) \( NH _{2} OH \)(c) \( N _{2} H _{4} \)(b) \( NH _{4} NO _{3} \)(d) \( N _{ S } H \) |
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Answer» Answer: NH4NO3 In NH2OH oxidation of N is -1 NH4NO3 exists as NH4+ .NO3− , thus the oxidation state of N in NH4+ is -3 while in NO3− is +5. In N2H4 oxidation of N is -2 In N3H oxidation of N is −1/3 |
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| 96836. |
If one doubles the tension in a violin string, the fundamental frequency of that string will increase by a factor of? |
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Answer» Fundamental frequency of violin string f = 1/2l \(\sqrt{T/\mu}\) If tension increase one double then fundamental frequency increase by \(\sqrt2\) factor f = 1/2l \(\sqrt{2T/\mu}\) f = \(\sqrt2\) 1/2l \(\sqrt{T/\mu}\) |
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| 96837. |
8.4 MG nahco3 powder was slowly added to 10 ml of 0.03 m HCL in a 50 ml breaker steering after effervescent seized |
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Answer» We have given, weight of NaHCO3 = 8.4 mg molecular weight of NaHCO3 = 84 g/mol Number of moles of NaHCO3 \(=\frac{0.0084\,g}{84\,g/mol}\) = 0.0001 mol Concentration of HCl = 0.03 M Volume of HCl = 10 mL ∴ moles of HCl = 0.03 M x 0.01 L = 0.0003 mol NaHCO3 + HCl → NaCl + H2O + CO2 ↑ ∵ 1 mole of NaHCO3 reacts with 1 mol. of HCl and give 1 mol NaCl, 1 mol H2O and 1 mol CO2 gas. ∴ 0.0001 mol, NaHCO3 reacts with 0.0001 mol HCl So, left HCl = 0.0002 mol ∴ Concentration of HCl = 0.0002/10 x 1000 = 0.02 M HCl |
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| 96838. |
Option nlmA31+1B31-1C. bothD. None |
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Answer» Yes, answer is correct, the values will be n=3, l=1, m=1(or)-1 |
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| 96839. |
A body dropped from the top of tower covers a distance 9 x in the last second of its journey, where x is the distance covered in the first second. How much time does it take to reach the ground.A. 5 sB. 4 sC. 3 sD. 6 s |
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Answer» Correct Answer - A `9x=(9)/(2)(2n-1)` .(1) `x=(1)/(2)g(1)^(2)` .(2) from (1) and (2) `n=5` |
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| 96840. |
Which of the following quantities is/are always non-negative in a simple harmonic motion along a straight line?A. `vec(F).vec(a)`B. `vec(v).vec(r)`C. `vec(a).vec(r)`D. `vec(F).vec(r)` |
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Answer» Correct Answer - A `vec(F).vec(a)=mvec(a).vec(a)` [ it is always non-negative] |
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| 96841. |
The Vander wall equation for 1 mole of a real gas is `(P+ (a/V^2))(V-b) =RT` where P is the pressure, V is the volume, T is the absolute temperature, R is the molar gas constant and a, b are Vander waal constants. The dimensions of a is the same as those ofA. PvB. `PV^(2)`C. `P^(2)V`D. `P//V` |
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Answer» Correct Answer - B `[P] =[a/(V^(2))] rArr [a] =[P] [V^(2)]` |
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| 96842. |
A compound sphere is made by joining a hemispherical shell and a solid hemisphere of same radius `R` and same mass as shown in figure. This system is kept between two smooth parallel walls and a smooth floor with the hollow hemisphere on the top as shown in figure. The maximum angular velocity of the compound shere when the system is slightly disturbed is `(` all surfaces are smooth `)` A. `sqrt((15g)/(64R))`B. `sqrt((15g)/(32R))`C. `sqrt((15g)/(16R))`D. `sqrt((15g)/(8R))` |
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Answer» Correct Answer - B Change in `PE=` Increase in `K.E.` `Mg[(R)/(2)2-(3R)/(8)2]=(1)/(2)[(2)/(5)MR^(2)+(2)/(3)MR^(2)]omega^(2)(g)/(4)` `=(2)/(2)[(1)/(5)+(1)/(3)]Romega^(2) sqrt((15g)/(32R))=omega` |
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| 96843. |
`int2sin(x)dx` is equal to:A. `-2cos x + C`B. `2 cosx +C`C. `-2 cos x`D. `2 cosx` |
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Answer» Correct Answer - A `int2sin(x)dx=-2cosx+C` |
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| 96844. |
`intx^3dx` is equal to …A. `3x^(2)`B. `(x^(4))/(4)+C`C. `(x^(4))/(4)`D. `4X^(3)` |
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Answer» Correct Answer - B `intx^(3)dx=(x^(4))/(4)+C` |
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| 96845. |
Given `: vec(A)rarr=2hat(i)-3hat(j)` is The magnitude of `(vec(A)+vec(B))` is `:`A. `sqrt(120)units`B. `sqrt(130)units`C. `sqrt(58)units`D. `sqrt(65)units` |
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Answer» Correct Answer - B `(vec(A)+vec(B))=7hat(i)-9hat(j)` `:. |vec(A)+vec(B)|=sqrt(49+81)=sqrt(130)` |
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| 96846. |
A particle moves `21m` along the vector `6hat(i)+2hat(j)+3hat(k)` , then `14 m` along the vector `3hat(i)-2hat(j)+6hat(k)`. Its total displacement (in meters) isA. `15hat(i)+2hat(j)+12hat(k)`B. `9hat(i)+12hat(k)`C. `9hat(i)+6hat(j)`D. `24hat(i)+2hat(j)+21hat(k)` |
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Answer» Correct Answer - D Total displacement `=21((6hat(i)+2hat(j)+3hat(k))/(7))+14((3hat(i)-2hat(j)+6hat(k))/(7))` `=18hat(i)+6hat(j)+9hat(k)+6hat(i)-4hat(j)+12hat(k)` `=(24hat(i)+2hat(j)+21hat(k))m` |
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| 96847. |
Unit vector along `3hat(i)+3hat(j)` isA. `(hat(i)+hat(j))/(sqrt(2))`B. `(3hat(i)+3hat(j))/(2)`C. `hat(i)+hat(j)`D. `(hat(i)+hat(j))/(sqrt(3))` |
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Answer» Correct Answer - A unit vector `=(3hat(i)+3hat(j))/(sqrt(3^(2)+3^(2)))=(hat(i)+hat(j))/(sqrt(2))` |
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| 96848. |
What made the family change over to their fourth residence? What precaution did they take before building it? |
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Answer» Dibal precaution that live together till your program to your family always do not hide anything to your family this Pakistan can make your family better than every family |
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| 96849. |
For the figure shown .A. `vec(A)+vec(B)=vec(C)`B. `vec(B)+vec(C)=vec(A)`C. `vec(C)+vec(A)=vec(B)`D. `vec(A)+vec(B)+vec(C)=0` |
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Answer» Correct Answer - C Apply triangle law of vector addition. |
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| 96850. |
If `vec(A)` and `vec(B)` are two non`-`zero vectors such that `|vec(A)+vec(B)|=(|vec(A)-vec(B)|)/(2)` and `|vec(A)|=2|vec(B)|` then the angle between `vec(A)` and `vec(B)` is `:`A. `37^(@)`B. `53^(@)`C. `cos^(-1)(-3//4)`D. `cos^(-1)(-4//3)` |
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Answer» Correct Answer - C `(A^(2)+B^(2)+2AB cos theta)=(1)/(4)(A^(2)+B^(2)-2ABcos theta)` `rArr 3A^(2)+3B^(2)+10ABcos theta=0` or `12B^(2)+3B^(2)+10(2B)(B) cos theta=0` `15B^(2)+20B^(2)cos theta=0` `cos theta=-(3)/(4)` |
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