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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 99501. |
Arrange the following solutions is the decreasing order of pOH : (A) 0.01 M HC1 (B) 0.01 M NaOH (C) 0.01 M CH 3COONa (D) 0.01 M NaCl(1) (B) > (C) > (D) > (A) (2) (A) > (C) > (D) > (B) (3) (B) > (D) > (C) > (A) (4) (A) > (D) > (Q > (B) |
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Answer» Correct answer is (4) (A) > (D) > (Q > (B) |
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| 99502. |
Gypsum on heating at 393K produces (1) dead burnt plaster (2) Anhydrous CaSO4(3) Ca SO4 . 1/2 H2O(4) CaSO4. 5H2O |
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Answer» Answer: (3) Ca SO4 . 1/2 H2O |
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| 99503. |
Assertion: Superoxide ion is paramagnetic whereas peroxide ion is diamagnetic. Reason: Superoxide ion `[O=O]^(-)` has one unpaired electron whereas peroxide ion `[O=O]^(-)` has no unpaired electron.A. If both assertion and reason are true and the reason is the correct explanation of the assertionB. If both assertion and reason are true but reason is not the correct explanation of the assertionC. If assertion is true but reason is falseD. If assertion is false but reason is true. |
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Answer» Correct Answer - A `[O=O]^(-)`has`M.Ogt`Configration `sigmals^(2)sigma**ls^(2),sigma2s^(2)sigma**2s^(2),sigma2p^(2)pi2p_(x)^(2)pi2p_(y)^(2)pi**2p_(x)^(2)pi**2p_(y)^(1)` ` [O=O]^(-)`has configuration `sigmals^(2)sigma**ls^(2),sigma2s^(2)sigma**2s^(2),sigma2p^(2)pi2p_(x)^(2)pi2p_(y)^(2)pi**2p_(x)^(2)pi**2p_(y)^(x)` |
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| 99504. |
A spherical tank of radius 0.35m is half filled with oil of relative density 0.8. if the tank is moving with a horizontal acceleration of `10(m)/(s^(2))`. The surface of oil is at rest with respect to sphere. The maximum gauge pressure of oil in the tank is `nxx10^(3)Pa`, the value of n is approximately equal to (take `g=10(m)/(s^(2))` |
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Answer» Correct Answer - 4 `tan=(a)/(g)=1` `impliestheta=45^(@)` `P_(max)=rhogh_(max)=rhogxxsqrt(2)R` `=4xx10^(3)(N)/(m^(2))` |
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| 99505. |
There are two concentric conducting shells of radius `R, 2R` respectively. Charge on each surface is as shown in the figure. Equivalent capacitance of this system is:A. `4piepsilon_(0)R`B. `8piepsilon_(0)R`C. `16piepsilon_(0)R`D. `12piepsilon_(0)R` |
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Answer» Correct Answer - A This is series combination of a spherical capacitor and an isolated sphere. Capacitance of spherical capacitor `=(4piepsilon_(0)2R^(2))/(2R-R)` `C_(1)=8piepsilon_(0)R` Capacitance of isolated sphere `C_(2)=8piepsilon_(0)R` Capacitance of system is `1/C=1/(C_(1))+1/(C_(2))` `1/C=1/(8piepsilon_(0)R)+1/(8piepsilon_(0)R)=1/(4piepsilon_(0)R)` |
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| 99506. |
A rod `AB` of mass `M` and length `L` lies on smooth horizontal table impulse `J` is applied to end `A` as shown in the figure immediately after imparting the impulse : A. The radius of curvature of trajectory of `A` as seen from the ground is `(8)/(9)L`.B. The radius of curvature of trajectory of `B` as seen from the ground is `(2)/(9)L`.C. The instantaneous axis of rotation is at a distance of `L//6` from the mid point of the rod.D. the mid point of the rod will move along a straight line. |
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Answer» `R=(v^(2))/(a_(c))` `v=(J)/(M)` `omega=((JL)/(2))/((MI^(2))/(12))=(6J)/(ML)` `rArr v_(A)=v+(omegaL)/(2)=(J)/(M)+(3J)/(M)=(4J)/(M)` `a_(c_(A))=(omega^(2)L)/(2)=(18J^(2))/(M^(2)L)` `rArrR_(A)=(v_(A)^(2))/(a_(c_(A)))=16(J^(2))/(M^(2)).(M^(2)L)/(18J^(2))=(8)/(9)L` `v_(B)=v-(omegaL)/(2)=(2J)/(M)` `rArrR_(B)=(4J^(2))/(M^(2)).(M^(2)L)/(18J^(2))=(2)/(9)L` |
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| 99507. |
A block of mass `m` is attached with a massless spring of force constant `k`. The block is placed over a fixed rought inclined surface for which the coefficient of friction is `mu=(3)/(4)` . The block of mass `m` is initially at rest . The block is mass `M` is released from rest with spring in unstretched state. The minimum value of `M` required to move the block up the plane is `(` neglect mass of string and pulley and friction in pulley `)` A. `(3)/(5)m`B. `(4)/(5)m`C. `(6)/(5)m`D. `(3)/(2)m` |
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Answer» Correct Answer - A As long as the block of mass `m` remains stationary, the block of mass `M` released from rest comes down by `(2Mg)/(K)(` before coming it rest momentanly again `)` . Thus the maximum extension in spring is `x=(2Mg)/(K) …….(1)` for block of mass `m` to just move up the incline `kx=mg sin theta + mu mg cos theta ........(2)` `2Mg=mgxx(3)/(5)+(3)/(4) mg xx(4)/(5)` or `M=(3)/(5) m Ans. ` |
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| 99508. |
Rain is falling with a velocity `(-4hat(i)+8hat(j)-10hat(k))`. A person is moving with a velocity of `(6hat(i)+8hat(j))` on the ground. The speed with the rain drops hit the person is `:`A. `10m//s`B. `10sqrt(2)m//s`C. `sqrt(180)m//s`D. `sqrt(360)m//s` |
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Answer» Correct Answer - B `vec(V)_(rm)=vec(V)_(r)-vec(V)_(m)=(-10hat(i)-10hat(k))` Ans. `(-10hat(i)-10hat(k))` rain appears to come `45^(@)` with `hat (j)` `V_(m)=sqrt(10^(2)+10^(2))=10sqrt(2)m //sec.` `W_(CL)|_("accelerated motion") =DeltaKE-W_("friction")` where `W_(CL)` is work down by camel on load. `=[(1)/(2)mv^(2)-0]-[-mu_(kk) mg . 50]=1000[(125)/(2)]` similarly, `W_(CL)|_("acceleration")=DeltaKE-W_(f r iction)[0-(1)/(2)mv^(2)]-[-mu_(k)mg.50]=100[(75)/(2)]` `:. (W_(CL)|_("acceleration motion"))/(W_(CL)|_("retarded motion"))` `=(125)/(75)=(5)/(3)` `rArr 5:3` |
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| 99509. |
Rain is falling with a velocity `(-4hat(i)+8hat(j)-10hat(k))`. A person is moving with a velocity of `(6hat(i)+8hat(j))` on the ground. Find the velocity of rain with respect to man and the direction from which the rain appears to be coming. |
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Answer» Correct Answer - `(-10hat(i)-10hat(k))` rain appears to come`45^(@)` with `hat(i)` `vec(V)_(rm)=vec(V)_(r)-vec(V)_(m)=(-10hat(i)-10hat(k))` Ans. `(-10hat(i)-10hat(k))` rain appears to come `45^(@)` with `hat (j)` `(A)W_(CL)+W_(t)=DeltaKE :. W_(CL)=DeltaKE-W_(f)` `(a)` During accelerated motion negative work is done against friction and there is also change is kinetic energy. Hencenetwork needed is `+ve.` `(b)` During uniform motion work is doen against friction only and that is `+ve`. `(c)` During retarded motion, the load has to be stopped in exactly 50 metres. If only friction is considered then then where it has to stop. Hence the camel has to apply some force so that the load stops in `50m gt (12.5m)`. Therefore the work done in this case is also `+ve`. |
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| 99510. |
The potential energy between two atoms in a molecule is given by `U=ax^(2)-bx^(2)` where `a` and `b` are positive constants and `x` is the distance between the atoms. The atom is in stable equilibrium when `x` is equal to `:-`A. `0`B. `(2b)/(3a)`C. `(3a)/(2b)`D. `(3b)/(2a)` |
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Answer» Correct Answer - B `U=ax^(3)-bx^(2)rArr(dU)/(dx)=3ax^(2)-2bx` and `(d^(2)U)/(dx^(2))=6ax-2b` For equilibrium `(dU)/(dx)=0rArr3ax^(2)-2bx=0` `rArrx=0,(2b)/(3a)` For `x=(2b)/(3a),(d^(2)U)/(dx^(2))=6axx(2b)/(3a)-2b=2bgt0` Therefore at `x=(2b)/(3a)`, potential energy is minimum. This is a condition of stable equilibrium. |
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| 99511. |
A particle is movbed from `(0, 0) to (a, a)` under a force `F =(x^(2)hati+y^(3)hatj)` from two paths. Path 1 si `OP` and Path 2 is `OQP`. Let `W_(1)` and `W_(2)` be the work done by this force in these two paths. Then A. `W_(1)=W_(2)`B. `W_(1)=2W_(2)`C. `W_(2)=2W_(2)`D. `W_(2)=4W_(1)` |
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Answer» Correct Answer - A A particle………… The force is constant and hence conservative `:. W_(1) = W_(2)` |
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| 99512. |
Which are the factors that affect the induced emf in electromagnetic induction? |
Answer»
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| 99513. |
The focal length of which of the following can not be obtained directly .A. convex mirror and convex lensB. convex mirror & concave lensC. convex lens and concave mirrorD. concave lensd and concave mirror |
| Answer» Correct Answer - B | |
| 99514. |
An electron moving with a velocity `v` along the positive `x`-axis approaches a circular current carrying loop as shown in the fig. the magnitude of magnetic force on electron at this instant is A. `(mu_(0) eviR^(2))/(2(x^(2)+R^(2))^(3//2))`B. `mu_(0)=(eviR^(2)x)/((x^(2)+R^(2))^(3//2))`C. `(mu_(0) eviR^(2)x)/(4pi(x^(2)+R^(2))^(3//2))`D. 0 |
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Answer» Correct Answer - D `F=q[v(+hati)]xxB(-hati)]=0` Because B as well as v is are along axis of circular CN. |
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| 99515. |
If the ratio of time periods of circular motion of two charged particles in magnetic field in `1//2`, then the ratio of their kinetic energies must be :A. `1:sqrt(2)`B. `sqrt(2):1`C. `2:1`D. it can have any value |
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Answer» Correct Answer - D `(T_(1))/(T_(2))=(1)/(2)=((2pim_(1))/(q_(1)B_(1)))/((2pim_(2))/(q_(2)B_(2)))=((m_(1))/(q_(1)B_(1)))((q_(2)B_(2))/(m_(2)))` |
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| 99516. |
A unitless quantity(a) never has a nonzero dimension,(b) always has a nonzero dimension,(c) may have a nonzero dimension,(d) does not exist. |
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Answer» (a) never has a nonzero dimension, Explanation: A unitless quantity never has a non-zero dimension. |
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| 99517. |
A bullet is fired from a rifle recoils freely, then K.E of the rifle is (1) less than that of bullet (2) equal to that of bullet (3) greater than that of bullet (4) none of these. |
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Answer» Answer is (1) less than that of bullet E = (1/2) mν2 = p2/2m ⇒ E ∝ 1/m |
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| 99518. |
The resistance `R = V//i`, where `V = 100 +- 5 V and I = 10+- 0.2 A`. What is the total error in `R`?A. `5%`B. `7%`C. `5.2%`D. `(5)/(2)%` |
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Answer» Correct Answer - 2 `(/_R)/(R)=(/_V)/(V)+(/_I)/(I)=(5)/(100)+(0.2)/(10)` `(/_R)/(R)xx100=7%` |
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| 99519. |
The period of oscillation of a simple pendulum in the experiment is recorded as `2.63 s , 2.56 s , 2.42 s , 2.71 s , and 2.80 s`. Find the average absolute error.A. 0.1 sB. 0.11 sC. 1.0 sD. 0.01 s |
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Answer» Correct Answer - 2 `"Average value"=(2.63+2.56+2.42+2.71+2.80)/(5)` `=2.62 sec.` `"Now " |/_T_(1)|=2.63-2.62=0.01` `|/_T_(2)|=2.62-2.56=0.06` `|/_T_(3)|=2.62-2.42=0.20` `|/_T_(4)|=2.71-2.62=0.09` `|/_T_(5)|=2.80-2.62=0.18` Mean absolute error `/_T=(|/_T_(1)|+|/_T_(2)|+|/_T_(3)|+|/_T_(4)|+|/_T_(5)|)/(5)` `/_T=(0.54)/(5)=0.108=0.11sec.` |
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| 99520. |
A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity `v m//s`. If it is to climb the inclined surface then `v` should be : A. `sqrt(10/7gh)`B. `gesqrt(2gh)`C. `2gh`D. `10/7gh` |
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Answer» Correct Answer - A `1/2MV^(2)+1/2Iomega^(2)geM"gh"` `Vgesqrt(10/7"gh")` |
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| 99521. |
A thin diamagnetic rod is placed vertically between the poles of an electromagnet. When the current in the electromagnetic is switched on, then the diamagnetic rod is pushed up, out of the horizontal magnetic field. Hence the rod gains horizontal potential energy. the work required to do this comes fromA. The lattice structure of the material of the rodB. the magnetic fieldC. the current sourceD. the induced electric field du to the changing magnetic field |
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Answer» Correct Answer - C c) As the sourceof current is switched on, a magnetic field sets up in between the poles of the electromagnet. As we know that a diamagnetic substances when placed in a magnetic field acquires a feeble magnetism opposite to the direction of the magnetic field. Also, in the presence of the field (non-uniform), these substances are attracted towards the weaker field, i.e. they move from stronger to weaker magnetic field. Due to these reasons, the rod is repelled by the field produced to the current source. Hence, it is pushed up, out of horizontal field and gains gravitational potential energy. |
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| 99522. |
If the mass of the sun were ten times smaller and the universal gravitational constant were ten times larger in magnitude, which of the following is not correct?A. Times period of a simple pendulum on the Earth wourld decreaseB. Walking on the ground would become more difficultC. Raindrops will fall fasterD. `g` on the Earth will not change |
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Answer» Correct Answer - D |
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| 99523. |
The kinetic energies of a planet in an elliptical orbit about the Sun, at positions `A,B` and `C` are `K_(A),K_(B)` and `K_(C)` respectively. AC is the major axis and `SB` is perpendicular to `AC` at the position of the sun as shown in the figure. Then A. `K_(B)ltK_(A)ltK_(C)`B. `K_(A)gtK_(B)gtK_(C)`C. `K_(A)ltK_(B)ltK_(C)`D. `K_(B)gtK_(A)gtK_(C)` |
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Answer» Correct Answer - B |
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| 99524. |
How does the game of hockey start? |
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Answer» The game of hockey starts when a player passes over the ball under certain rules to another player of his side from the centre line. |
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| 99525. |
How many players are there in a hockey team? |
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Answer» There are 16 players in the game of hockey. Eleven of these players play the game while 5 players are substitutes. |
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| 99526. |
Saltatory conduction A. Occurs only in myelinated fibres. B. Does not depend on depolarization of the nerve membrane. C. Has a slower velocity in cold than in warm conditions. D. Is faster than non-saltatory conduction in nerve fibres with diameters around 10 μm. E. Transmits impulses with a velocity proportional to fibre diameter. |
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Answer» A. True Excitation leaps from node to node across the myelinated segments. B. False The membrane does depolarize at the nodes. C. True Cooling slows sodium conductance at the nodes. D. True Theoretically, saltatory conduction becomes the slower in nerve fibres with diameters less than 1 μm. E. True And to the distance between nodes. |
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| 99527. |
An action potential in a nerve fibre A. Occurs when its membrane potential is hyperpolarized to a critical level. B. Is associated with a transient increase in membrane permeability to sodium. C. Is associated with a transient decrease in membrane permeability to potassium. D. Induces local electrical currents in adjacent segments of the fibre. E. Has an amplitude which varies directly with the strength of stimulus. |
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Answer» A. False It occurs when the membrane potential is reduced to its threshold for firing. B. True This leads to rapid depolarization towards the sodium equilibrium potential. C. False Permeability to K+ increases and the resulting K+ efflux contributes to membrane repolarization. D. True This depolarizes the adjacent axon and leads to propagation of the impulse. E. False Because of the ‘all or none’ law, impulse configuration is independent of stimulus strength. |
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| 99528. |
Resting nerve cell membranes are more permeable to A. Organic anions than to Cl- anions. B. K+ ions than to Cl- ions. C. Na+ ions than to K+ ions. D. Oxygen molecules than to glucose molecules. E. Water molecules than to H+ ions. |
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Answer» A. False Organic anions cannot cross the membrane readily. B. False The permeability to Cl- is about twice that to K+. C. False K+ permeability is about 100 times that of Na+. D. True O2, being a small, nonpolar, lipophilic molecule dissolves in the membrane lipid and crosses more easily than the larger glucose molecule. E. True The bilipid layer is more permeable to water than to the charged hydrogen ion. |
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| 99529. |
Loss of pain sensation in the A. Feet may lead to skin ulceration. B. Knee may lead to joint damage. C. Ears and fingers usually precedes frostbite.D. Leg follows surgical division of the spinocerebellar tracts in the spinal cord. E. Face follows surgical division of the facial nerve. |
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Answer» A. True Probably because of failure to protect the foot and letting minor injury persist without attention. B. True Again due to loss of the protective effects of pain. C. True Nerve fibres stop conducting near freezing point so there is no further warning when freezing causes tissue damage. D. False Pain sensation is blocked by surgical division of the spinothalamic tracts. E. False It is lost following division of the sensory root of the trigeminal nerve. |
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| 99530. |
Intracranial pressure tends to rise when A. Cerebral venous pressure rises. B. Forced expiration is made against a closed glottis. C. There is a bout of coughing. D. Cerebral blood flow increases. E. Arterial PCO2 falls below normal. |
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Answer» A. True This distends intracranial veins and hence raises pressure within the cranium. B. True This (Valsalva) manoeuvre raises cerebral venous pressure. C. True This also raises cerebral venous pressure. D. True The vasodilation raises the volume of blood within the cranium. E. False This constricts cerebral vessels and reduces cerebral blood volume. |
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| 99531. |
At every hour on the radio there are six ______ so that people can check the precise time. A) squeaks B) pops C) pips D) cracks |
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Answer» Correct option is C) pips |
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| 99532. |
Sleep is associated with A. An alpha rhythm in the electroencephalogram. B. Increased activity in the reticular activating system. C. A high level of vagal tone to the heart. D. Grinding movements of the teeth. E. A rise in central body temperature. |
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Answer» A. False The alpha rhythm disappears during sleep. B. False Activity decreases; increased activity is associated with alertness. C. True This maintains a slow heart rate during sleep. D. True Teeth-grinding is associated with REM sleep and is called bruxism. E. False This tends to drop during the early hours of sleep. |
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| 99533. |
α (alpha) adrenoceptors A. Are located on myofilaments in smooth muscle cells. B. Are distinguishable from (beta) receptors using electron microscopy. C. Can be stimulated by both adrenaline and noradrenaline. D. Are involved in the vasoconstrictor responses in skin to adrenaline. E. Are involved in the heart rate responses to noradrenaline. |
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Answer» A. False They are located in the cell membranes. B. False They cannot be visualized; chemical evidence suggests their structure is similar. C. True Also by drugs such as ephedrine which has a similar structure. D. True Alpha receptors predominate in skin arterioles. E. False Cardiac adrenoceptors are predominantly beta receptors. |
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| 99534. |
When a nerve cell membrane is depolarized by 5 mV A. Its permeability to sodium increases. B. Sodium ions move into the cell to cause further depolarization. C. Potassium ions move outwards down their electro chemical gradient. D. Chloride ions move inwards down their electro chemical gradient. E. An action potential is generated. |
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Answer» A. True Depolarization opens sodium channels in the membrane. B. True Positively charged sodium ions move down their electro chemical gradient making the inside of the fibre more positive. C. True The fall in membrane potential increases the outward electro chemical gradient for the positively charged potassium ions; their exit tends to stabilize the membrane potential. D. True The fall in membrane potential increases the inward electro chemical gradient for chloride; this again tends to restore the resting membrane potential. E. False Not unless it reaches the threshold for firing. |
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| 99535. |
Damage to the cerebral cortex may cause loss of A. Pain sensation on the opposite side of the body. B. Reflex thermoregulatory activity. C. Skilled movements in the absence of paralysis. D. Ability to identify an object by its tactile characteristics. E. Vision in one eye only. |
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Answer» A. False The cerebral cortex is not involved in the conscious appreciation of pain. B. False Reflex thermoregulation is organized in the hypothalamus. C. True Such loss of skilled movements is called ‘apraxia’. D. True This ‘asteriognosia’ results from parietal cortex damage. E. False Damage to the visual cortex causes loss of part of the visual field in both eyes. |
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| 99536. |
In the spinal cord A. Pain impulse traffic may be modulated in the posterior horn.B. Autonomic motor neurones arise in the lateral horn. C. Gamma-aminobutyric acid may act as an excitatory neurotransmitter. D. Reflex centres are normally inhibited by descending impulses from supra-spinal centres. E. Post-synaptic excitation may be mediated by amino acid derivatives acting as neurotransmitters. |
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Answer» A. True In the substantia gelatinosa; endorphins may inhibit pain impulse transmission. B. True These are the preganglionic autonomic motor neurones. C. False It is an inhibitory transmitter thought to be responsible for IPSPs at post-synaptic membranes. D. False Loss of supraspinal facilitation is responsible for the areflexia in spinal shock. E. True Glutamate and aspartate are thought to be responsible for much of excitatory transmission in the CNS. |
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| 99537. |
Generalized sympathetic activity is characterized by A. Contraction of the radial muscle in the iris. B. Increased urinary excretion of catecholamines. C. Lipolysis in adipose tissue. D. Decreased conduction rate in the atrio-ventricular bundle. E. Relaxation of sphincteric smooth muscle in the alimentary tract. |
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Answer» A. True This dilates the pupil. B. True Derived from activity in the adrenal medulla and sympathetic nerve endings. C. True This provides fatty acids for energy production. D. False It increases and the PR interval shortens; higher heart rates are made possible. E. False Sympathetic activity inhibits most smooth muscle in gut but contracts the sphincters. |
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| 99538. |
Numerical problems.1. A pendulum oscillates 50 times in 6 seconds. Calculate its time period and frequency. |
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Answer» The pendulum oscillates 50 times in 6 secs. so time taken to oscillate once= 6/50 secs = 0.12 secs so time period of the pendulum is 0.12 secs. frequency = 1/time period= 1/0.12 Hz = 8.33 Hz |
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| 99539. |
Delta (δ) wave activity in the electroencephalogram A. Is low in frequency and amplitude. B. Suggests that the patient is alert and concentrating. C. When unilateral suggests a brain abnormality. D. Is a feature of petitmal epilepsy. E. Is more common in children than in adults while they are awake. |
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Answer» A. False Delta waves have slow frequency and large amplitude. B. False It is associated with deep sleep. C. True Delta waves may indicate brain damage as well as deep sleep. D. False This produces a characteristic spike and wave pattern in the EEG. E. True Delta wave activity is seen occasionally in the EEGs of normal awake children. |
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| 99540. |
Atropine (which blocks muscarinic receptors) causes A. Paralysis of accommodation for near vision in the eye. B. Constriction of the pupil. C. Constriction of the bronchi. D. Diarrhoea. E. Difficulty with micturition. |
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Answer» A. True By paralysing the ciliary muscles. B. False It causes pupillary dilatation by paralysing circular muscle in the iris. C. False It tends to dilate the bronchi by blocking vagal effects. D. False It causes constipation by suppressing bowel activity. E. True Micturition depends on cholinergic nerves. |
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| 99541. |
Disease of the extrapyramidal motor system in Parkinsonism causes A. Tremor which is more obvious when the patient is performing skilled movements. B. Muscle paralysis. C. Increased muscle tone throughout the range of passive movement. D. Increased involuntary facial movements during speech. E. An unusual gait with small fast regular steps. |
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Answer» A. False Parkinsonism causes tremor which is more obvious when the patient is at rest. B. False Paralysis is not a feature of the condition. C. True This is ‘cogwheel’ or ‘lead pipe’ rigidity. D. False The face is mask-like; there is poverty of facial movements. E. True The body’s centre of gravity is shifted forward. |
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| 99542. |
Aphasia A. Is an impairment of language skills without motor paralysis, loss of hearing or vision. B. Implies impairment of consciousness. C. Is called motor aphasia if the patient understands what the speech sounds and symbols mean but lacks the higher motor skills needed to express them. D. Is called sensory aphasia if the patient does not understand the meaning of the words he hears, sees and uses. E. Usually results from right-sided cortical damage. |
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Answer» A. True It is a cortical dysfunction. B. False Level of consciousness is an independent entity. C. True It may start with an inability to say the names of familiar objects but end up with loss of virtually all verbal communication skills. D. True Patients with sensory aphasia tend to talk rubbish since they are unaware of the errors in their use of language. E. False Language skills are carried in the left hemisphere in right and some left-handed people. |
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| 99543. |
Consider the following statements and select the correct option (A) The endomembrane system includes plasma membrane, ER, Golgi complex, lysosomes and vacuoles (B) ER helps in the transparent of substances, synthesis of proteins, lipoproteins and glycogen (C) Ribosomes are involved in protein synthesis (D) Mitochondria help in oxidative phosphorylation and generation of ATPA. B, C and D are correctB. A along is correctC. B alone is correctD. C alone is correct |
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Answer» Correct Answer - A |
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| 99544. |
Jhumming : The 'slash and burn' agriculture is known as 'Milpa' in Mexico and Central America, 'Conuco' in Venezuela, 'Roca' in Brazil, 'Masole' in Central Africa, 'Ladang' in Indonesia, 'Ray' in Vietnam.In India, this primitive form of cultivation is called 'Bewar' or 'Dahiya' in Madhya Pradesh, 'Podu' or 'Penda' in Andhra Pradesh, 'Pama Dabi' or 'Koman' or 'Bringa' in Odisha, 'Kumari' in Western Ghats, 'Valre' or 'Waltre' in South-eastern Rajasthan, 'Khil' in the Himalayan belt, 'Kuruwa' in Jharkhand and 'Jhumming' in the North-eastern region.The 'slash and burn' agriculture is known as 'Roca' in which one of the following countries?(a) Mexico(b) Indonesia (c) Brazil(d) Venezuela |
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Answer» Answer is : (c) Brazil |
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| 99545. |
Aestivation of petals in the flower of cotton is correctly shown inA. B. C. D. |
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Answer» Correct Answer - D |
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| 99546. |
ASSERTION (A): The elderly villagers occupied the back benches on the last day of French lesson. REASON (R): This fact surprised Franz the most. (a) Both, A and R, are true and R is the correct explanation of A (b) Both, A and R, are true but R is not the correct explanation of A (c) A is true but R is false (d) A is false but R is true |
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Answer» (b) Both, A and R, are true but R is not the correct explanation of A |
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| 99547. |
ASSERTION (A): The elderly people occupied the back benches. REASON (R): They were present for thanking M Hamel, for being sorry too for not going to school more, for showing their respect towards the country that was theirs no more. (a) Both, A and R, are true and R is the correct explanation of A (b) Both, A and R, are true but R is not the correct explanation of A (c) A is true but R is false (d) A is false but R is true |
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Answer» (a) Both, A and R, are true and R is the correct explanation of A |
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| 99548. |
A uniform cylinder of radius R originally had weight of 80N. It weigths 65N, after an off axis cylinderical hoole at `(2R)/(3)` was drilled through n. The axis of the two cylinders are parallel and at same height A force T is applied to the top of the cylinder horizontally to keep the cylinder at rest about the axis of the original cylinder passing through O. The value of force should be A. 1NB. 3NC. 5ND. 10N |
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Answer» `15xx(2R)/(3)=65x` `TR=65x=15xx(2R)/(3)` `T=10` N |
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| 99549. |
X and Y are two elements which form `X_(2)Y_(3)` and `X_(3)Y_(4)`. If `0.20` mol of `X_(2)Y_(3)` weight `32.0g` and `0.4mol` of `X_(3)Y_(4)` weigths `92.8g`, the atomic weights of X and Y are respectivelyA. `16.0` and `56.0`B. `8.0` and `28.0`C. `56.0` and `16.0`D. `28.0` and `8.0` |
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Answer» Correct Answer - 3 `(32)/(2x+3y)=0.2," "(92.8)/(3x+4y)=0.4`.Hence `: x=56 & y=16` |
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| 99550. |
In the reaction `4A+2B+3C rarr A_(4)B_(2)C_(3)` what will bw the number of moles of product formed. Starting from 2 moles of `A, 1.2` moles of `B & 1.44` moles of `C :`A. `0.5`B. `0.6`C. `0.48`D. `4.64` |
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Answer» Correct Answer - 3 `{:(,4A,+,2B,+,3C,rarr,A_(4)B_(2)C_(3)),("Initial mole",2,,1.2,,1.44,,0),("final mole",,,,,0,,0.48):}` C is limiting reagent. `:.` moles of `A_(4)B_(2)C_(3)` is `0.48`, |
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