InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
Yesterday when Tom ___ the lesson___ . A) comes / already begins B) came / had already begun C) came / already began D) will come / already begins E) came / already begins |
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Answer» Correct option is B) came / had already begun correct option is B. |
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| 152. |
Would you approve if I had this article _____? A) to be copied B) to copy C) been copied D) copied |
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Answer» Correct option is D) copied |
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| 153. |
I _____ a shower every morning. A) am having B) have C) having D) had |
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Answer» Correct option is B) have |
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| 154. |
It’s never too late ___ . A) being learned B) not to learn C) learned D) learning E) to learn |
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Answer» Correct option is E) to learn |
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| 155. |
We can go out now. It ___ . A) don’t rain B) rains C) didn’t rain D) has rained E) isn’t raining |
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Answer» Correct option is E) isn’t raining |
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| 156. |
When he ___ in London, it ___ heavily. A) arrive / rains B) arrives / rained C) arrived / was raining D) will arrive / rains E) arrived / is raining |
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Answer» Correct option is C) arrived / was raining |
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| 157. |
Take your umbrella. It ___ . A) was raining B) rained C) rains D) is raining E) would be raining |
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Answer» Correct option is D) is raining |
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| 158. |
Last Monday when I ___ the house it ___ heavily. A) leave / rain B) left / was raining C) left / had rained D) was leaving / rained E) leave / rains |
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Answer» Correct option is B) left / was raining correct answer B) |
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| 159. |
When fully _____ the men cut off all the lower branches. A) growing B) to grow C) had grown D) grown |
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Answer» Correct option is D) grown |
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| 160. |
The weather is awful, it ___ all day. A) rains B) is raining C) rained D) has rained E) has been raining |
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Answer» Correct option is E) has been raining |
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| 161. |
I’m _____ gum. A) chew B) chewing C) chews D) chewed |
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Answer» Correct option is B) chewing |
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| 162. |
I always _____ _____ credit card. A) pay / by B) am paying / with C) ’m paying / by D) pay / with |
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Answer» Correct option is A) pay / by |
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| 163. |
............is not used for making payment. a. Debit card b. Credit card c. Pay –in-slip d. Cash |
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Answer» c. Pay –in-slip |
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| 164. |
A: Why do we go to school? B: _____. A) To learn B) Learning C) Learned D) Learn |
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Answer» Correct option is A) To learn |
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| 165. |
___ the language he couldn’t understand the question. A) know B) knows C) not to know D) known E) not knowing |
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Answer» Correct option is E) not knowing |
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| 166. |
We expect him ___ tomorrow. A) arrived B) to arrive C) to have arrived D) to be arrived E) having arrived |
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Answer» Correct option is B) to arrive |
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| 167. |
It is _____ . A) rains B) to rain C) raining D) rained |
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Answer» Correct option is C) raining |
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| 168. |
We were made _____ still with our arms folded. A) sat B) to sit C) sitting D) to sitting |
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Answer» Correct option is B) to sit |
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| 169. |
I always pay _____ credit card. A) in B) on C) at D) by |
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Answer» Correct option is D) by |
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| 170. |
Let’s _____ in the sun. A) sitting B) to sit C) sat D) sit |
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Answer» Correct option is D) sit |
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| 171. |
Which of these four young men ___ by the fire is your son? A) sitting B) sitC) will sit D) sits E) sat |
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Answer» Correct option is A) sitting |
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| 172. |
Who ______ next to you now? A) sits B) is sitting C) sit D) sitting |
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Answer» Correct option is B) is sitting |
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| 173. |
He’s _____ down. A) sit B) sitting C) sits D) sat |
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Answer» Correct option is B) sitting |
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| 174. |
The boy _____ in the dentist’s chair has got toothache. A) sitting B) sat C) sit D) sits |
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Answer» Correct option is A) sitting |
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| 175. |
A: Where’s Helen? B: She ______ in the office A) is sitting B) sit C) sitting D) sits |
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Answer» \Correct option is A) is sitting |
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| 176. |
A standing wave having 3 nodes and 2 antinodes is formed between two atoms having a distance 1.21Å between them. The wavelength of the standing wave isA. `3.63Å`B. `6.05Å`C. `1.12Å`D. `2.42 Å` |
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Answer» Correct Answer - C Two loops contains 3 nodes and 2 antinodes (with node at end) `p((lambda)/(2)) = L or 2 xx (lambda)/(2) = L` `lambda = 1.21 Å` |
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| 177. |
Oh, someone _____ in my seat! A) is sitting B) sits C) will sit D) sit |
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Answer» Correct option is A) is sitting |
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| 178. |
The height of T.V. tower is 125 m if its range is doubled for signal, find the new height:(1) 125 m (2) 250 m(3) 500 m(4) 300 m |
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Answer» Correct option is (3) 500 m d = \(\sqrt{2hR}\) 2d = \(\sqrt{2h'R}\) h' = 4h = 4 x 125 = 500 m |
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| 179. |
If the input x & y of a logic gate is shown and its output A is also shown then the type of gate is(1) OR(2) NOR(3) AND(4) NAND |
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Answer» Correct option is (3) AND It is AND GATE |
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| 180. |
A tower of height 100 m on earth can send signal on earth to particular range. If range is to be increased to 3 times find the new height of tower required.(1) 300(2) 500(3) 900(4) 700 |
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Answer» Correct option is (3) 900 \(d = \sqrt{2Rh}\) \(d^2 \propto h\) New height is 900 m |
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| 181. |
A conductor of length 3m moving in a uniform magnetic field of strength 100 T. It covers a distance of 70 m in 5 sec. Its plane of motion makes an angle of 30° with direction of magnetic field. Calculate the emf induced in it. |
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Answer» Given: l = 3m, B = 100T, d = 70 m, t = 5 sec, θ = 30°, e = ? e = BlVsinθ V = \(\frac{d}{t}\) = \(\frac{70}{5}\) = 14m/s V = 100 × 3 × 14 × sin 30° = 100 × 3 × 14 × \(\frac{1}{2}\) e = 2100 V |
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| 182. |
Figure shows a cubical block of side 10 cm and relative density 1.5 suspended by a wire of cross sectional area `10^(-6) m^(2)`. The breaking stress of the wire is `7 xx 10^(6) N//m^(2)`. The block is placed in a beaker of base area `200 cm^(2)` and initially i.e. at t = 0, the top surface of water & the block coincide. There is a pump at the bottom corner which ejects `2 cm^(3)` of water per sec. Find the time at which the wire will break. |
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Answer» Correct Answer - 100 sec Breaking force = Breaking stress `xx` area of wire `=7 xx 10^(6) xx 10^(-6) = 7N` weight of block = vol `xx` density `xx g` `=10^(-3) xx(1.5 xx10^(3)) xx10 = 15 N` The upthrust when the liquid level has decended by `xx` cm `100 (10-x)10^(-6)10^(3)10=10-x` Newton `:.` Net downward force on the block `= 15 -(10 -x)=5 + x` = Tension T `:.` The wire will break when `5 + x = 7` i.e. when x = 2 cm Let the level descends by 2 cm in t time then `2t =(200-100) 2 t = 100 sec`. |
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| 183. |
When 4x3 - 3x2 + 2x - 1 is divided by (x + 2), then remainder is1. 482. 493. - 494. - 48 |
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Answer» Correct Answer - Option 3 : - 49 Concept: If a function is divisible by another function (x + a), then we can put the value of x from x + a = 0, in the function to get the remainder Calculation: According to the question: Put the value of x = - 2 in the function 4x3 - 3x2 + 2x - 1 ⇒ 4(- 2)3 - 3(- 22) + 2(- 2) - 1 ⇒ - 32 - 12 - 4 - 1 ⇒ - 49 ∴ When 4x3 - 3x2 + 2x - 1 is divided by (x + 2), then remainder = - 49 |
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| 184. |
Two concentric rings of radii `R_(1) = sqrt(6) m` and `R_(2) = 4m` are placed in y-z plane with their centres at origin. They have uniform charge -q and `+ Q = 2 sqrt(2) q` on the inner and outer rings respectively. Consider the electrostatic potential to be zero at infinity. Then A. The electric potential is zero at originB. The electric field intensity is zero at r = 2mC. A positive charged particle disturbed from origin along the x-axis will restore back to origin.D. Where potential is maximum on the x-axis, field intensity is zero |
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Answer» Correct Answer - B::C::D V at origin `ne =` `E=(r=2 m)=(K(-q)r)/((R_(1)^(2)+r^(2))^(3//2))+(K.Q.r)/((R_(2)^(2)+r^(2))^(3//2))` `=K.rq[-(1)/(10^(3//2))+(2 sqrt(2))/(2^(3//2)10^(3//2))]=0` From origin to r=2, field is towards origin. |
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| 185. |
For what values of k, can the quadratic polynomial, kx2 – 8x + k can be factored into real linear factors?1. 0 ≤ k ≤ 42. – 4 ≤ k ≤ 43. k = 44. k = – 4 |
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Answer» Correct Answer - Option 2 : – 4 ≤ k ≤ 4 Given: kx2 – 8x + k Concept Used: ax2 – bx + c = 0 has real liner factors when, b2 – 4ac = 0 Calculation: Comparing the given equation with ax2 + bx + c = 0, We get a = k, b = 8, and c = k ⇒ (8)2 – 4(k)(k) = 0 ⇒ 64 – 4k2 = 0 ⇒ 4k2 = 64 ⇒ k2 = 16 ⇒ k = √16 ⇒ k = +/– 4 ∴ The value of k is – 4 ≤ k ≤ + 4. |
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| 186. |
Two concentric rings of radii `R_(1) = sqrt(6) m` and `R_(2) = 4m` are placed in y-z plane with their centres at origin. They have uniform charge -q and `+ Q = 2 sqrt(2) q` on the inner and outer rings respectively. Consider the electrostatic potential to be zero at infinity. Then A. The electric potential is zero at originB. The electric field intensity is zero at a distance `x=2m` from origin on axis of ring.C. A positive charged particle disturbed from origin along the x-axis will restore back to origin for any value of displacementD. Where potential is maximum on the x-axis, field intensity is zero. |
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Answer» Correct Answer - B::D `V_(0)=(k(-q))/(sqrt(6))+(k(2sqrt(2)q))/(4)ne0` `E=(-kqx)/((R_(1)^(2)+x^(2))^(3//2))+(k2sqrt(2)q)/((R_(2)^(2)+x^(2))^(3//2))` |
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| 187. |
What is the average horizontal force acting on a ball when it elestically bounces off a wall, assuming the collision times is 0.1 s and the momentum of the ball before the the bounce was 2kg. m/s, perpendicular to the wall ?A. 0.2 NB. 0.4 NC. 40 ND. 20 N |
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Answer» Correct Answer - C `F=(DeltaP)/(Deltat) =4/0.1=40 N` |
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| 188. |
When a force accelerates a body immersed in a fluid, some of the fluid must also be accelerated, since it must be pushed out of the way of the body, but also the inertia of the fluid pushed out of the way. It can be shown that for a spherical body completely immersed in a nonviscous fluid, the extra inertia is that of a mass of fluid half as large as the fluid displaced by the body. The acceleration of a small spherical air bubble in water is nearlyA. zeroB. gC. `g//2`D. `2g` |
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Answer» Correct Answer - D If m be the mass of water displaced, the buouant force is mg. while the mass of the extra water that has to be pushed "out of the way" is effectively `m//2` |
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| 189. |
A pendulum of length `1 m` hangs from an inclined wall. Suppose that this pendulum is released at an initial angle of `10^(@)` and it bounces off the wall elastically when it reaches an angle of `-5^(@)` as shown in the figure. Take `g = pi^(2) m//s^(2)`. The period of this pendulum is (in second) A. `2//3`B. `3//2`C. `3//4`D. `4//3` |
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Answer» Correct Answer - D We take `theta = (10^(@)) cos (pit)`, calculate t when `theta = -5^(@)`. This gives `t = 2//3 (s)`. The period is 2 times this. |
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| 190. |
A thin plano-convex lens fits exactly into a thin plano-concave lens. Their plane surfaces are parallel to each other. The lenses are made of different material of refractive indices `mu_(1)` and `mu_(2)` and R is the radius of curvature of the curved surfaces of the lenses, if rays are incident parallel to principal axis on lens of refractive index.A. `mu_(1)` then the focal length of the combination is `(R)/(mu_(1)-mu_(2))`B. `mu_(2)` then the focal length of combination is `(2R)/(mu_(2)mu_(1))`C. `mu_(1)` then the focal length of the combination is `(R)/(2(mu_(1)-mu_(2)))`D. `mu_(2)` then the focal length of the combination is `(R)/((mu_(2)-mu_(1)))` |
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Answer» Correct Answer - A::D `(1)/(f_(1))=(mu_(1)-1)/(R)` `(1)/(f_(2))=(mu_(2)-1)/(-R)` `(1)/(f_(eq))=(1)/(f_(1))+(1)/(f_(2))=(mu_(1)-mu_(2))/(R)` |
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| 191. |
Which of the following orbital of central atom is not involved in bonding in `XeO_(3) F_(2)` molecule :-A. `d_(zx)`B. `d_(yz)`C. `d_(xy)`D. `d_(x^(2)-y^(2))` |
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Answer» Correct Answer - D In `XeO_(3)F_(2),d_(z^(2))` used in hybridisation and `d_(xy)d_(yz) and d_(zx)` is used in `pi-` bond formation. |
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| 192. |
A block of mass `2 kg` is given a push for a moment horizontally and then the block starts sliding over a horizontal plane. The graph shows the velocity`-` time of the motion. The co`-` efficient of sliding friction between the plane and the block is `:` A. `0.02`B. `0.20`C. `0.04`D. `0.40` |
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Answer» Correct Answer - B The magnitude of declaration from graph is `a=(8-0)/(4-0)=2m//s^(2)` The declaration of block is `a=mug :. Mu=(a)/(g)=0.2` |
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| 193. |
Under what conditoin of temperature and pressur the formation of atomic hydrogen from molecular hydrogen will be favoured most ?A. High temperatured and high pressureB. Low temperature and low pressureC. High temperature and low pressureD. Low temperature and high pressure |
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Answer» Correct Answer - C `H_(2)(g)to2H_((g)` As temperature increase and pressure decreases, formation of atomic H increases. |
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| 194. |
Under what conditions for temperature and pressure the formation of atomic oxygem from molecular oxygen will be favoured most?A. high temperature and high pressureB. low temperature and low pressureC. high temperature and low pressureD. low temperature and high pressure |
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Answer» `O_(2)(g)hArr2O(g)` `DeltaH_(g)gt0` so `Q alpha(1)/(V)rArr` on P decreaes `rArrV` increases `rArrQltK` forward favour endo in forwad direction so on increasing temperature forward favour |
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| 195. |
One mole gas is first colled from `300 K` to `150 K` at constant volume and then heated from `150K` to `300 K` at constant pressure. The net heat absorbeed by the gas isA. zeroB. `150 R`C. `300 R`D. `450 R` |
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Answer» Correct Answer - B |
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| 196. |
Which one of the following sets of ions represents the collection of isoelectronic species?A. `K^(+), Cr, Mg^(2+), Sc^(3+)`B. `Na^(+), Ca^(2+), Sc^(3+), F^(-)`C. `K^(+), Ca^(2+), Sc^(3+), CI^(-)`D. `Na^(+), Mg^(2+), AI^(3+), CI^(-)` |
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Answer» Correct Answer - C Which one of the following ……….. Atomic number of K, Ca, Sc and CI are 19, 20, 21 and 17 respectively. `K^(+) = 18e, Ca^(2+) = 18e, Sc^(3+)= 18e, Cr = 18e` |
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| 197. |
A particle moves on x-axis such that its KE varies as a relation KE=`3t^(2)` then the average kinetic energy of a particle in 0 to 2 sec is given by :A. 6 jouleB. 8 jouleC. 4 jouleD. 16 joule |
| Answer» Correct Answer - A | |
| 198. |
A particle of mass 1 kg moves in a circular path of radius 1 m such that its speed varies with time as per equation `v=3t^(2)m//s` where time t is in seconds. The power delivered by the force acting on the paritcle at `t=1s`, is `:-`A. 36 WB. 20 WC. 18 WD. zero |
| Answer» Correct Answer - A | |
| 199. |
The position of a particle moving in XY-plane varies with time t as `x=t, y=3t-5`. (i) What is the path traced by the particle? (ii) When does the particle cross-x-axis? |
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Answer» (i) `x=t, y=3t-5` By eliminating t from above two equations `y=3x-5` This is the equation of a straight line. (ii) The particle crosses x-axis when `y=0`. So `0=3t-5 rArr t=5/3` |
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| 200. |
Two particles A and B move along the straight lines `x+2y+3=0` and `2x+y-3=0` respectively. Their positive vector, at the time of meeting will beA. `3hat(i)+3hat(j)`B. `3hat(i)-3hat(j)`C. `(hat(i))/3-(hat(j))/3`D. Particles never meet |
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Answer» Correct Answer - B The particles meet at the point intersection of lines. By solving them `x=3, y=-3`, So position vector of meeting point will be `3hat(i)-3hat(j)` |
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