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Answer is : (d) Artificially acquired passive immunity

Antivenom injection provides artificial acquired passive immunity. Passive immunity is the transfer of active humoral immunity of readymade antibodies. It can occur naturally, when maternal antibodies are transferred to foetus through placenta and it can be induced artificially when high level of antibodies specific to a pathogen or toxin are transferred to non-immune persons through blood products that contain antibodies, such as antivenom injections are given.

Correct option (D) Artificially acquired passive immunity

Explanation:

Antivenom injection have performed antibodies against snake poison. 

So, using antivenom injection is develops artificial aquired passive immunity. 

Answer is : (b) uric acid

Gout is caused by the deposition of uric acid in joints. Composition of kidney stone is calcium oxalate, calcium phosphate, uric acid, xanthine and indigo calculi. Researches have shown that kidney stones are a complication of gout because extra uric acid can collect in the urinary tract and crystallise into stones.

Answer is : (c) Electrons flow from lower to higher potential, except through power sources

The free electrons experiences electrostatic force in the direction opposite to the direction of electric fired being is of negative charge. The electric field always directed from higher potential to lower potential. Therefore electrostatic force and negative charge or electrons always flows from lower to higher potential until the potantials become equal.

Correct option  (B)

Explanation:

Electric field lines should be perpendicular to surface of metal.

Answer is : (a) K < |U| always

For a satellite or planet, if total energy is E, then

kinetic energy, K = - E

and potential energy, U = 2E

where, E is negative.

So, K < |U|

Answer is : (b) ascorbic acid

Scurvy is caused by the deficiency of vitamin-C (Ascorbic acid) in the body. It can lead to anaemia, debility, exhaustion, spontaneous bleeding, pain in the limbs and especially the legs, swelling in some parts of the body and sometimes ulceration of the gums and loss of teeth.

Correct option  (A)

Option 'A' is correct option. According charge conservation & Gauss's law.

Answer is : (c) recessive

Gregor Mendel studied inheritance of traits in pea plants. In a monohybrid cross, the recessive trait disappears in the first filial generation. The traits that were visible in the F₁-generation are referred to as dominant traits. This happens because recessive allele does not express itself in the presence of dominant allele.

Answer is : (c) a Chinese horse

In evolutionary terms, an Indian school boy is more closely related to Chinese horse. Human and horse irrespective of their country are more generally similar in their chromosomal management, than to rest of the species mentioned here. This is because human and horse both belong to class Mammalia. Other options like frog, snake and shark belong to class– Amphibia, Reptilia and Chondrichthyes.

Correct option is (a) N < O < S < Cl

Electron affinities of II period element are less negative as compared to corresponding III period element. This is because of small size of II period elements. Also, nitrogen has the least electron affinity due to stable half-filled configuration. Thus, the correct order of electron affinity is N < O < S < Cl.

The correct option is (a) 9.

N is least positive integer and when a digit c is written after last digit of N, the resulting number is divisible by c.

⇒  So, (N)c / c​

Least positive integer (N) which is divisible by digit c i.e. (1−9)

So possible number is

⇒ (9 × 8 × 7 × 5)c​ / c

Number, 9 × 8 × 7 × 5 is divisible by all the digits from 1 to 9

⇒  So, Number is 72 × 35 = 2520 = N

⇒  Sum of the digits of number N = 2 + 5 + 2 + 0 = 9

The correct option is (C).

Let x₁​,x₂​,x₃​,x₄​,...........x₁₁​ are distinct positive integers

Suppose the increasing order of the numbers are

⇒  x₁​,x₂​,x₃​,x₄​,x₅​,x₆​,x₇​,x₈​,x₉​,x₁₀​,x₁₁​

x₁₁​ is largest number and the median is x₆​.

Now, the median of first 10 numbers = (x₅​ + x₆)/2​​

⇒  Let a =  (x₅​ + x₆)/2

Now, we have to replace largest number x₁₁​ by the median of first 10 numbers i.e. a.

So, new increasing order will be

⇒  x₁​, x₂​, x₃​, x₄​, x₅​, a , x₆​, x₇​, x₈​, x₉​, x₁₀​

And new median will be a i.e. (x₅​ + x₆)/2

Which is lesser than the median of first eleven number x_6​

⇒  So, median decreases.

Answer is : (a) 9

As N be the least positive integer and when a non-zero digit C is written after the last digit of N, the resulting number is divisible by C.

So, 10N + C is divisible by C.

∴10 N must be divisible by C.

Now, the least integer (N) which is divisible by digit ‘C’ i.e. (1 to 9) must be L.C.M of {1, 3, 4, 6, 7, 9}.

= L.C.M of {4, 7, 9} = 252 = N

and sum of digits of number ‘N’ is 2+5+2 = 9

Answer is : (d) 90

Since in the group of first 10 two digit number 10-19, has atleast 1 prime number similarly in other groups of 10 two digits numbers

20-29, 30-39, 40-49, 50-59, 60-69, 70-79, 80-89 and 90-99 have almost 1 prime numbers.

So, the number of almost prime two-digit number is 90.

Correct option(c)

Explanation:

a³ + b³ + c³-3abc = [a + b + c] [(a + b + c)² - 3(ab + bc + ca)] 

= [7] [(7)² - 3(9)] = 7(49 - 27) = 7 × 22 = 154

(d) Only statements II, III and IV are correct

A plano-concave lens is a diverging lens and a plano-convex lens is a converging lens.

Image formed by a plano-concave lens is always erect and virtual.

Image formed by a plano-convex lens is real and inverted when object is placed at a distance larger than focal length of lens. Plano-convex lens is a converging lens. Hence, image formed by a plano-convex lens is inverted.

So, all statements are correct.

Answer is : (c) Anaphase-I

During anaphase-I, no crossing over leads to segregation of alleles. Anaphase-I begins when the two chromosomes of each bivalent (tetrad) separate and start moving toward opposite poles of the cell as a result of the action of the spindle, but their centromeres are still attached.

Unlike humans, dogs cannot perspire to get rid to excess metabolic heat. They lose metabolic heat by Panting.

(D) Does not clump when either antiserum A or antiserum B is added

Answer is : (c) Charles Darwin

‘On the Origin of Species, by Means of Natural Selection’ or ‘The Preservation of Favoured Races in the Struggle for Life’, published on 24 November 1859 is a work of scientific literature by Charles Darwin which is considered to be the foundation of evolutionary biology.

Haemodialysis is a treatment option for patients with malfunctions of Kidney.

Answer is : (a) kidney

Haemodialysis is a process of purifying the blood of a person whose kidneys are not working normally. It helps to filter waste, removes extra fluid and balances electrolytes (sodium, potassium, bicarbonate, chloride, calcium, magnesium and phosphate). During haemodialysis, blood is removed from the body and filtered through a man-made membrane called a dialyser, or artificial kidney and then the filtered blood is returned to the body.

Answer is : (b) the rate of bacterial multiplication increases

The rate of bacterial multiplication increases in warmer weather thereby forming curd from milk faster. This happens because Lactobacillus (i.e. bacteria that turns milk into curd) is more active in summers and develops more, which inturn accelerates the fermentation process.

Answer is : (d) does not clump when either antiserum A or antiserum B is added

An individual has ‘O’ blood group if his/her blood sample does not clump when either antiserum ‘A’ or antiserum ‘B’ is added. Antiserum is a blood serum containing antibodies against specific antigens. Clumping or Agglutination is the process that occurs if an antigen is mixed with its corresponding antibody. A person with ‘O’ blood group neither have ‘A’ nor ‘B’ antigens on his/her red blood cells, but both ‘a’ and ‘b’ antibodies in his/her plasma. Thus, they are also called as universal donor.

Answer is : (c) Thursday

There are 90 days from 1 January to 31 March (Non-leap year)

If year 13 leap year, then total number of days = 91(13 weeks)

But we have 12 Sunday

∴12 weeks

∴ Ist Jan will be Monday as there will be 90 days January 1 to 31 March.

∴ 15th February will be Thursday.

Answer is : (d) K < 25

Let two digits number ab = 10a + b, b ≠ 0 if b is erased.

Then, the resulting number is a.

∴ ab is divisible by a if ab is multiple of c.

∴ Such number are 11, 12, 13, 14, 15, 16, 17, 18, 19, 22, 24, 26, 28, 33, 36, 39, 44, 48, 55, 66, 77, 88, 99.

∴ Total number are 23.

Hence, K < 25

Answer is : (a) 0

Pure water at standard temperature and atmospheric pressure has a water potential of zero. As solute is added, its value becomes more negative. This causes water potential to decrease. Water potential is the measure of the potential energy in water. It is denoted by the Greek letter ψ (Psi) and is expressed in units of pressure (pressure is a form of energy) called Mega Pascals (MPa).

Answer is : (d) sodium ions

An action potential is generated by the rapid influx of Na⁺ ions followed by a slightly slower efflux of K⁺ ions. The action potential is the mechanism by which nerve cells communicate and conduct information and muscle cells are induced to contract.

Correct option is (b)

As the substrate concentration increases, the rate of reaction increases until a maximum, when saturation of all the enzymes active sites occurs. When this happens, the limiting factor is enzyme concentration. 

Correct option (B) NH₄Cl < NaCl < CH₃COONa

Explanation:

Order of pH 

Correct option is (c) Sphincter of Oddi

Sphincter of Oddi guards the opening of hepatopancreatic duct into the duodenum. Hepatopancreatic duct brings secretion of liver as well as pancreas to the duodenum.

Answer is : (d) Mitochondrion

Mitochondria have their own DNA and ribosomes. Ribosomes are the site of protein synthesis. Therefore, mitochondria are capable of making their own protein. Mitochondria are also capable of synthesising their own genetic material.

Correct option is (c) the coiling of the polypeptide chain

The structures adopted by polypeptides can be divided into four levels of organisation, i.e., the primary, secondary, tertiary and quaternary structures. The secondary structure pertains to the coiling of the polypeptide chains into regular structure such as α-helices and β-pleated sheets.

Correct option  (B)  5

Explanation:

There should be five membrane bilayer that line will cross

1 -Cell membrane

2 -Mitochondrial membrane

2 -Nucleus

Correct option  (A) inhibiting T cell infiltration

Explanation:

Immunosuppressive Drug inhibits T-cell infiltration  

Correct option is (a) Archaebacteria

Archaebacteria are the most primitive form of bacteria. These live in diverse habitat, e.g. extreme hot temperature, saline condition, variable pH, etc. Saline bacteria are called halophiles (e.g. Halobacterium, Halococcus).

Answer is : (a)

The most often used stationary phase gel and alumina are polar material. Consequently, the least polar compound will have the highest R_f value, as they will be least bounded to the stationary phase and moves quickly up the TLC plate.

Among the given compound, compound (a) is least polar, so its R_f value will be maximum.

Correct option (A)

Explanation:

The most often used stationary phase silica gel and alumina are polar material. Consequently the least polar compound will have the highest R_f value. 

Correct option (A) BaCO₃ > SrCO₃ > CaCO₃ > MgCO₃

Explanation:

Thermal stability of polyvalent anion salt like CO₃^2– increase down the group due to increase in ionic character

Answer is : (c) Only statements II, III and IV are correct

For a nucleus, _Z^AX

Mass number, A = N + Z

where, N = number of neutrons and Z = number of protons.

In ₃₂⁶⁵X and ₃₃⁶⁵Y, number of protons are different. So, these are not isotopes.

In ₄₂⁸⁶X and ₄₂⁸⁵Y, number of protons are equal. So, these are isotopes.

In ₈₅¹⁷⁴X and ₈₈¹⁷⁷Y, number of neutrons are 174 - 85 = 89 and 177 - 88 = 89.

So, both have same number of neutrons.

In ₉₂²³⁵ X and ₉₄²³⁵Y, both have same mass number, so these are isobars.

Correct option (D) depend on ionic and hydrophobic interactions. 

Explanation:

Antibody- antigen interaction is essentially Non-Covalent, Electrostatic interaction, Hydrogen Bonds, Vander walls forces and Hydrophobic interactions are all known to be involved depending on the interaction sites.

Answer is : (b) Lysine

Lysine is not involved in gluconeogenesis. Gluconeogenesis is the biosynthesis of new glucose from certain non-carbohydrate carbon substrates like amino acids, etc. Out of the 20 amino acids, 18 are glucogenic (i.e. can be converted to glucose upon gluconeogenesis) while the remaining two amino acids, i.e. lysine and leucine are purely ketogenic (i.e. can be degraded into acetyl-Co-A).

Correct option (C) 35%

Explanation:

Cytosine = 15%

According to chargaff principle 

A = T & G = C

A + T + G + C = 100

Thus A will be 35%

Answer is : (b) Q–i–b

Hypermetropia is far sightedness. A vision condition in which nearby objects are blurry. It is corrected by using convex lens.

Myopia is near sightedness. A condition in which close objects appear clearly but far ones do not. It is corrected using concave lens.

Correct option  (C) p > q and p – q = 1/10 

Explanation:

when n = 10

Let A_r be no. of ways of selecting r numbers.

No. of selection of A is

= n (A₀) + n(A₁) + n (A₂) + n(A₃) + n(A₄)

= 1 + 10 + (7 + 6 + 5 +…+ 1) + (4 + 3 + 2 + 1) + (3 + 2 + 1) + (2 + 1) + 1

= 11 + 7.8/2  + 10 + 6 + 3 + 1 + 1 = 60

N(p) = n(no. of ways 1 is selected) = 1 + 7 + 4 + 3 + 2 + 1 + 1 = 19

N(q) = n(no. of ways 2 is selected) = 1 + 6 + 3 + 2 + 1 = 13

So  p = 19/60    q  = 13/60

p-q = 1/10

Answer is : (c) 17

We have, S = {1, 2, 3, 4, ..., 40}

A is subset of S whose sum of two element of A is not divisible by 5.

Possible set A = {1, 2, 5, 6, 7, 11, 12, 16, 17, 21, 22, 26, 27, 31, 32, 36, 37}

∴ Maximum number of elements in A is 17.

Correct option (A) speed and wavelength are different but frequency remains same. 

Explanation:

On refraction of light, frequency remain unchanged. However speed and wavelength get change. 

Correct option  (D) Pseudomonas

Explanation:

Pseudomonas denitrificans is involved in formation of elemental N₂ from nitrogen compound (denitrification).

Correct option  (D) Vitamin K

Explanation:

Vitamin K helps in synthesis of blood clotting factor in liver.