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301.

A epidemic broke out in a village in which 5% of the population died. Of the remaining, 20% fled out of panic. If the present population is 4655, then the population of the village originally was1. 62252. 67853. 61254. 6025

Answer» Correct Answer - Option 3 : 6125
Net% effect = [– x – y + xy]%
100
 
=  [– 5 –20 + 5 × 20] =  – 25 + 1 = – 24%
100

∴    Current population = 100 – 24 = 76%

With ratio & proportion rule,

76% : 4655 :: 100% : ?
 
∴   ? = 4655 × 100 = 245 × 25 = 6125.
76
 
Discussion
302.

The wheat sold by a grocer contained 10% low quality wheat. What quantity of good quality wheat should be added to 150 kgs of wheat so that the percentage of low quality wheat becomes 5%? (a) Rs.150kg (b) Rs.135kg (c) Rs.50kg (d) Rs.85kg (e) None of these

Answer» (a) Weight of low quality of wheat in 150 kgs of wheat = 150 x 10/100 = 15 kg.
Suppose that x kgs of good quality wheat is mixed.
According to the question,
(x + 150) x 5/100 = 15
or, x = 150 kg.
Discussion
303.

What is 26% of 55% of 10/13th of 6100? (a) 617 (b) 681 (c) 706 (d) 734 (e) None of these

Answer» (e) Required value  = 6100 x 10/13 x 55/100 x 26/100= 671
Discussion
304.

What is the percentage error in the calculation if Trisha multiplies a number N by 32*1/3 instead of 32*1/2?1. 66.66%2. 45.55%3. 33.33%4. 55.55%

Answer» Correct Answer - Option 3 : 33.33%

Calculations :

When N is multiplied by 32*1/3 or 32/3 we get 

N × 32/3 = (32/3)N 

When N is multiplied by 32*(1/2) or 16 we get,

N × 16 = 16(N) 

Percent of error = [16(N) - 32/3(N)/16(N)] × 100 

⇒ [(16/3)N/16N] × 100 

⇒ 100/3 = 33.33% 

∴ The percentage error will be 33.33%
Discussion
305.

If A's salary is 30% more than B's salary, then by what percentage is B's salary less than that of A ? (correct to one decimal place)1. 17.5%2. 19.7%3. 23.1%4. 25%

Answer» Correct Answer - Option 3 : 23.1%

Given:

Salary of A is 30% more than salary of B.

Calculations:

Let the salary of B be 100x.

Salary of A  = 100x + 100x × 30%

⇒ 130x

Percentage Difference = {(130x - 100x)/130x} × 100

⇒ (30x/130x) × 100

⇒ 23.07% ≈ 23.1%

∴ B's salary is 23.1% less than that of A
Discussion
306.

Mathew scored 42 marks in Biology, 51 marks in Chemistry. 58 marks Mathematics, 35 marks in Physics and 48 marks in English. The maximum marks a student can score in each subject are 60. How much overall percentage did Mathev. get in this exam? (a) 76 (b) 82 (c) 68 (d) 78 (e) None of these

Answer»

(d) Marks scored by Mathew = 42 + 51 + 58 + 35 +48 = 234
Max.Marks = 60 × 5 = 300

Percentage scored = 234 /300 x 100 = 78%
Discussion
307.

If 24% of a number exceeds its 18% by 60, then the number is:1. 1002. 5003. 10004. 600

Answer» Correct Answer - Option 3 : 1000

Given

24% of a number exceeds its18% by 60.

Formula Used

a% of b = b × (a/100)

Calculation

Let the number be x.

24% of x - 18% of x = 60

⇒ 6% of x = 60

⇒ x × (6/100) = 60

⇒ x = 60 × (100/6)

⇒ x = 1000
Discussion
308.

52% of 666 + ? = 500 (a) 138.53 (b) 168.46 (c) 144.54 (d) 153.68 (e) None of these

Answer» (d) 666 x 52/100 + ?= 500
? = 500 – 346.32 = 153.68
Discussion
309.

A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:1. 672 apples2. 700 apples3. 588 apples4. 600 apples

Answer» Correct Answer - Option 2 : 700 apples

Given:

Percentage of apples the fruit seller sells = 40% 

No of apples he left with = 420 

Calculation:

Initially, the fruit seller had 100% apples.

⇒ He sold 40% of them, now he has (100 - 40) = 60%

⇒ 60% of the apples = 420 

∴ 100% of the apples = 420 × 100/60 = 700 

Originally, he had 700 apples.
Discussion
310.

Ratan smashes 86 runs against his opposite team in 16 balls. If he only scored in boundaries (fouRs. and sixes), then find the maximum percent of runs he scored by hitting fours.1. 26.25%2. 23.25%3. 30%4. 28%

Answer» Correct Answer - Option 2 : 23.25%

Given:

Ratan scored his runs only in boundaries.

Total balls played = 16

Total runs = 86

Calculations:

Ratan scored his runs only in boundaries.

Let the number of fouRs. be x and the number of sixes be y.

Total balls played = 16

⇒ x + y = 16

⇒ x = 16 – y     ----(1)

Total runs = 86

⇒ 4x + 6y = 86     ----(2)

Put value of x from equ. (1) to eq. (2)

⇒ 4(16 – y) + 6y = 86

⇒ 64 – 4y + 6y = 86

⇒ 2y = 22

⇒ y = 11

From eq. (1)

x = 16 – 11 = 5

x = 5 and y = 11

Runs scored in the boundaries i.e fouRs. = 4 × 5 = 20

Percentage of runs scored in fouRs. = (20/86) × 100 = 23.25%

∴ The maximum percent of runs he scored by hitting fouRs. is 23.25%.
Discussion
311.

Ram’s monthly income is 20% more than that of Shyam. Shyam’s monthly income is 15% less than that of Sohan. If the difference between the monthly income of ram and Sohan is Rs. 350. What is the monthly income of Shyam?1. 155852. 148753. 143754. 152755. 14500

Answer» Correct Answer - Option 2 : 14875

Given :

Ram’s monthly income = Shyam’s monthly income × 120%

Shyam’s monthly income = Monthly income of Sohan ×  85%

Difference between the monthly income of ram and Sohan = 350 Rs.

Calculation:

120% = 6 / 5

85% = 17 / 20

Ram  :   Shyam  : Sohan

 6      :     5                          (× 17)

                17      :       20      (× 5)

⇒ 102    :    85    :      100

Difference between the monthly income of ram and Sohan = 350 Rs.

102 Ratio – 100 Ratio = 350Rs

2 Ratio = 350Rs.

Shyam’s monthly income (85 Ratio) = \(\frac{{350}}{2} \times {\rm{\;}}85\)

∴ The monthly income of Shyam is Rs. 14875.
Discussion