Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

51.

The ratio of momentum diffusivity (kinematic viscosity) and mass diffusivity is referred as:(a) Nusselt number(b) Schimdt number(c) Sherwood number(d) Reynolds numberThis question was addressed to me in a national level competition.Enquiry is from External Mass Transfer topic in portion Heterogenous Reactions of Bioprocess Engineering

Answer»

Correct choice is (b) Schimdt number

Best explanation: SCHMIDT number (Sc) is a dimensionless number DEFINED as the ratio of momentum diffusivity (kinematic viscosity) and MASS diffusivity, and is used to CHARACTERIZE fluid FLOWS in which there are simultaneous momentum and mass diffusion convection processes.

52.

What is the unit of mass transfer coefficient?(a) ms(b) m/s(c) ms^2(d) ms^-2This question was posed to me during an interview.My enquiry is from External Mass Transfer in portion Heterogenous Reactions of Bioprocess Engineering

Answer» RIGHT OPTION is (b) m/s

Explanation: Molar flux form a BULK fluid at concentration CAb to the surface of a spherical particle of diameter dp at concentration CAs:

WA = kC (CAb-CAs)

Where, WA (Molar flux) = moles/m^2s

kC (Mass transfer coefficient) = m/s.
53.

The immobilized cells have different temperature gradient.(a) True(b) FalseThe question was asked in a national level competition.This question is from Internal Mass Transfer and Reaction topic in portion Heterogenous Reactions of Bioprocess Engineering

Answer»

Correct answer is (b) False

Explanation: Kinetic PARAMETERS for enzyme and cell reactions are strong FUNCTIONS of temperature. If temperature in the particle varies, different VALUES of the kinetic parameters must be applied. However, as temperature GRADIENTS generated by immobilised cells and enzymes are generally negligible, ASSUMING constant temperature throughout the particle is reasonable.

54.

The heat diffusion is which type of process?(a) Conduction(b) Convection(c) Radiation(d) OsmosisThis question was addressed to me in class test.This interesting question is from Internal Mass Transfer and Reaction topic in section Heterogenous Reactions of Bioprocess Engineering

Answer»

Correct choice is (B) Convection

For explanation: Convection is usually the dominant form of HEAT transfer in liquids and gases. Although often discussed as a distinct method of heat transfer, convective heat transfer involves the combined PROCESSES of unknown conduction (heat DIFFUSION) and ADVECTION (heat transfer by bulk fluid flow).

55.

The minimum amount of energy needed to start a reaction is called the ______(a) Activation energy(b) Energy of reaction(c) Entropy of reaction(d) Reaction mechanism energyThis question was posed to me in final exam.The above asked question is from Concentration Gradients and Reaction Rates in Solid Catalysts in division Heterogenous Reactions of Bioprocess Engineering

Answer»

Correct option is (a) ACTIVATION energy

Easiest explanation: Activation energy is the MINIMUM energy required for a reaction to occur. Catalysis is the increase in the rate of a CHEMICAL reaction by LOWERING its activation energy. TRANSITION state is an intermediate state during a chemical reaction that has a higher energy than the reactants or the products.

56.

Which of the following is not an example of bulk catalyst?(a) Silica-alumina catalyst(b) Molybdenum oxide supported on alumina(c) Iron-molybdate(d) Iron doped with alumina and potassium oxideThis question was addressed to me in class test.My enquiry is from Concentration Gradients and Reaction Rates in Solid Catalysts topic in section Heterogenous Reactions of Bioprocess Engineering

Answer»

Correct OPTION is (B) Molybdenum oxide supported on ALUMINA

To explain: The supported catalysts are the catalytically active materials which are dispersed over the high surface area support material. For example, hydrodesulphurization is CARRIED out over molybdenum oxide supported on alumina.

57.

Refer to Q7 and Q8 and calculate the mass-transfer coefficient by using the mass and heat transfer analogy.(a) 1.661×10^-05 mole/m^2 .s.Pa(b) 1.663×10^-05 mole/m^2 .s.Pa(c) 1.665×10^-05 mole/m^2 .s.Pa(d) 1.669×10^-05 mole/m^2 .s.PaI have been asked this question by my college professor while I was bunking the class.I'm obligated to ask this question of Liquid- Solid Mass Transfer Correlations topic in portion Heterogenous Reactions of Bioprocess Engineering

Answer»

The correct answer is (C) 1.665×10^-05 mole/m^2 .s.Pa

To EXPLAIN: ANALOGY to heat transfer

Sh = 0.453 Re^0.568 Sc^0.36 = 207.68

So, kG RTD/DAB = 207.68

Therefore, kG = (207.68*DAB) / RTd = 1.665×10^-05 mole/m^2 .s.Pa.

58.

Refer to Q4 and Estimate the amount of enzyme present.(a) 4.81×10^-8 kg(b) 4.83×10^-8 kg(c) 4.85×10^-8 kg(d) 4.87×10^-8 kgThe question was asked in an interview for job.My question is based upon Internal Mass Transfer and Reaction in division Heterogenous Reactions of Bioprocess Engineering

Answer»

Right answer is (b) 4.83×10^-8 KG

For EXPLANATION I WOULD say: 10 BEADS have volume 2.68×10^-6 m^3. The AMOUNT of enzyme present is:

2.68 ×10^-6 m^3 (0.018 kgm^-3) = 4.83 × 10^-8 kg.