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Refer to Q7 and Q8 and calculate the mass-transfer coefficient by using the mass and heat transfer analogy.(a) 1.661×10^-05 mole/m^2 .s.Pa(b) 1.663×10^-05 mole/m^2 .s.Pa(c) 1.665×10^-05 mole/m^2 .s.Pa(d) 1.669×10^-05 mole/m^2 .s.PaI have been asked this question by my college professor while I was bunking the class.I'm obligated to ask this question of Liquid- Solid Mass Transfer Correlations topic in portion Heterogenous Reactions of Bioprocess Engineering

Answer»

The correct answer is (C) 1.665×10^-05 mole/m^2 .s.Pa

To EXPLAIN: ANALOGY to heat transfer

Sh = 0.453 Re^0.568 Sc^0.36 = 207.68

So, kG RTD/DAB = 207.68

Therefore, kG = (207.68*DAB) / RTd = 1.665×10^-05 mole/m^2 .s.Pa.



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