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Refer to Q4 and Estimate the amount of enzyme present.(a) 4.81×10^-8 kg(b) 4.83×10^-8 kg(c) 4.85×10^-8 kg(d) 4.87×10^-8 kgThe question was asked in an interview for job.My question is based upon Internal Mass Transfer and Reaction in division Heterogenous Reactions of Bioprocess Engineering

Answer»

Right answer is (b) 4.83×10^-8 KG

For EXPLANATION I WOULD say: 10 BEADS have volume 2.68×10^-6 m^3. The AMOUNT of enzyme present is:

2.68 ×10^-6 m^3 (0.018 kgm^-3) = 4.83 × 10^-8 kg.



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