

InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
801. |
Give any two similarities of hydrogen with group-I elements? |
Answer» (a) Hydrogen atom has one valence electron similar to alkali metal atoms of group-I (b) Hydrogen can lose valence electron to form unipositive ion, which is similar to alkali metals which also loses their valence electron forming alkali metal ion. |
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802. |
What is water-gas shift reaction? |
Answer» A reaction in which production of dihydrogen can be increased can be increased by reacting CO of syn gas mixture with steam in the presence of iron chromate catalyst is called water gas shift reaction. Equation: CO + H2O→CO2 + H2 |
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803. |
Give the laboratory method of preparing dihydrogen? |
Answer» Hydrogen is prepared in laboratory by action of zinc with dil. HCl Equation: Zn + 2HCl → ZnCl2 + H2 |
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804. |
Which of the following is laboratory preparation of dihydrogen?A. `3Fe + 4H_(2)O(steam) rarr Fe_(3) O_(4) + 4H_(2)`B. `2Na + 2H_(2)O rarr Ca(OH)_(2) + 2H_(2)`C. `CaH_(2) + 2H_(2)O rarr Ca (OH)_(2) + 2H_(2)`D. `Zn + H_(2)SO_(4)(dil.) rarr ZnSO_(4) + H_(2)` |
Answer» Correct Answer - D In laboratory, hydrogen gas is prepared by action of dilute `H_(2)SO_(4)` on granulated zinc. `Zn+H_(2)SO_(4)(dil.)to ZnSO_(4)+H_(2)` |
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805. |
Which of the following is not true ?A. Ordinary water is electrolysed more rapidly than `D_(2)O`B. Reaction between `H_(2)` and `Cl_(2)` is much faster than `D_(2)` and `Cl_(2)`C. `D_(2)O` freezes at lower temperature than `H_(2)O`D. Bond dissocition energy for `D_(2)` is greater than `H_(2)`. |
Answer» Correct Answer - C `D_(2)O` actually has higher freezing point `(3.8^(@)C)` than water `H_(2)O(0^(@)C)`. |
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806. |
Elements hydrogen reacts with other substances only slowly at room temperature. Why? |
Answer» In the elementary state, hydrogen exists in diatomic form i.e. as `H_(2)(g)` and the two hydrogen atoms are linked to each other by single covalent bond (H-H). Since the bond dissociation energy is very high `(435.9kJ mol^(-1))`, therefore, bond cleavage is extremely difficult. As a result, elemtal hydrogen is little reactive at room temperature. | |
807. |
Which one of the following will produce permanent hardness in water ?a) Sodium sulphateb) Calcium carbonatec) Calcium sulphated) Magnesium carbonate |
Answer» c) Calcium sulphate |
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808. |
What are the ways in which water molecules are bonded to an anhydrous salt to form a hydrate? |
Answer» Co-ordinate bond and H-bond |
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809. |
Polyphosphates are used for softening agents because theyA. Form solube complexes with anionic speciesB. Precipitate anionic speciesC. Form soluble complexes with cationic speciesD. Precipitate cationic species |
Answer» Correct Answer - C Form soluble complexes with cationic species. |
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810. |
Speed of decomposition of `H_(2)O_(2)` is reduced by :A. `Na_(2)CO_(3)`B. `NaOH`C. AlcoholD. Pt. |
Answer» Correct Answer - C Alcohol. |
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811. |
How is heavy water produced from ordinary water? |
Answer» It is obtained by repeated electrolysis of ordinary water. |
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812. |
Metal(s) generally obtained by the reduction of their oxides with `H_(2)` areA. Al, ZnB. Mo, WC. Na, KD. Ca, Mg. |
Answer» Correct Answer - B Molybdenum (Mo) and trugesten (W) are obtained by the reduction of their oxides with hydrogen. |
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813. |
The strenght of an poxo acid (E - 0 - H), where E is the central atom , depends upon theA. electronegativity of EB. atomic size of EC. ability of E to share electron pair with OD. atomic size and electronegativity of E |
Answer» Correct Answer - A Higher electronegativity reduces the strength of acid. |
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814. |
Water obtained by purification with organic ion exchange resins isA. Pure waterB. Free from only `Ca^(@+, Mg^(2+)` ionsC. Free from `HCO_(3)^(-), SO_(4)^(2-) ` and `Cl^(-)` ions onlyD. None of these |
Answer» Correct Answer - d Water obtained from organic ion `-` exchange resins is free from all ionic impurites. |
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815. |
A sample of water containing some dissolved table sugar and common salt is passed through organic ion exchange resins. The resulting water will beA. testelessB. sweetC. saltyD. None of these. |
Answer» Correct Answer - B Organic ion exchange resins can remove only ionic impurities. |
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816. |
The shape of water molecule is same as that ofA. `C_(2)H_(2)`B. `CO_(2)`C. `NH_(3)`D. `Cl_(2)O` |
Answer» Correct Answer - d |
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817. |
Which statement about zeolite is false ?A. They are used as cation exchangersB. They have open structure which enables them to take up small moleculesC. Zeolites are aluminosilicates having three dimensional networkD. None of the `SiO_(4)^(4-)` units are replaced by `AlO_(4)^(5-)` and `AlO_(6)^(9-)` ions in zeolites. |
Answer» Correct Answer - D Zeolites have `SiO_(4)^(4-)` and `AlO_(4)^(5-)` tetrahedron, linked together in a three dimensional open structure in which four or six membered rings predominate. Due to open chain structure, they have cavities and can take up water and small molecules. |
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818. |
Distinguish clearly between temporary hardness and permanent hardness. |
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819. |
Whivh statement about zeolite is false ?A. They are used as cation exchangerB. They have open structure which enables them to take up small moleculesC. Zeolites are alumino silicates having three dimensional networksD. Some of the `SiO_(4)^(4-)` units are replaced by `AlO_(4)^(5-)` and `AlO_(6)^(9-)` ions in zeolites |
Answer» Correct Answer - d As `(a)`, (b)` and `(c)` are characteristic of zeolites. |
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820. |
Dicuss the position of hydrogen in periodic table? |
Answer» (i) Hydrogen can be placed in gr. 1 as well as gr. (ii) Hydrogen shares many similarities with alkali metals, i.e. elements in group I-A. This is one of the factors that dictates the position of hydrogen in the table.(some properties like electronic configuration, forms halides, reducing agent). (iii) Hydrogen shares many similar properties with halogens like electronegativity, diatomic molecules, covalent bonds. |
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821. |
30 Volume of H2O2 meansa) 30% H2O2 b)30 cm3 of the solution contains 1 gm of H2O2c)1 cm3 of solution liberates 30 cm3 of O2 at STPd) 30 cm3 of solution contains 1 mol of H2O2 |
Answer» c)1 cm3 of solution liberates 30 cm3 of O2 at STP |
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822. |
Which is true statement about `D_(2)O` and `H_(2)O` ?A. `D_(2)O` has lower dielectric constant than `H_(2)O`B. `NaCl` is more soluble in `D_(2)O` than in `H_(2)O`C. Both are correctD. None of these |
Answer» Correct Answer - A `H_(2)` has higher dielectric constant than `D_(2)O` . `H_(2)O` Dielectric constant `=(81)` `D_(2)o` Dielectric constant `=(60)` Dielectric constant `prop` good solvent. |
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823. |
Hydrogen acts as an oxidising agent in the reaction with `:`A. `Br_(2)`B. `Ca`C. `N_(2)`D. `S` |
Answer» Correct Answer - b `Ca` is more electropositive than. `H` `i.e.` Hydrogen accepts `e^(-)` `i.e.` oxidising agent show reduction. |
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824. |
Out of the following metals which will give `H_(2)` on reaction with `NaOH:` `I: Zn,` ,`II:Mg`, `III: Al,`,`IV:Be`A. `I,II,III,IV`B. `I,III,IV`C. `II,IV`D. `I,III` |
Answer» Correct Answer - B In `II A `group only `Be` gives `H_(2)` gas with alkaline solution other alkaline eath metals don’t react. `Be+2NaOH+2H_(2)O rarr Na_(2)BaO_(2).2H_(2)O+H_(2)` |
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825. |
Which of the following can adsorb largest volume of hydrogen gas ?A. Finely divided platinumB. Finely divided nikelC. Colloidal palladiumD. Colloidal platinum. |
Answer» Correct Answer - C Order of adsorption of `H_(2)` (occulsion) is Colloidal Palladium `gt "Palladium" gt "Platinum" gt ........"Gold" gt "Nickel"`. |
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826. |
Which of the following statements is correct ?A. Elements of group 15 from electron deficient hydrides.B. All elements of group 14 from electron deficient hydridesC. Electron precise hydrides have tetrahedral geometriesD. Electron rich hydrides can act as Lewis acids. |
Answer» Correct Answer - C::D Electrons precise compouds have the required number of electrons to write their convention Lewis structures. All elements of group 14 from electron-precise compounds (e.g..,`CH_(4)`) which are teterahedral in gemoetry . |
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827. |
Match List I with List II and select the correct answer using the codes given below the list : `{:(,"List I","List II",),(1.,"Heavy water",(a)"Bicarbonates of Mg and Ca in water",),(2.,"Temporary hard water",(b)"No foreign ions in water",),(3.,"Soft water",(c)D_(2)O,),(4.,"Permanent hard water",(d)"Sulphates and chlorides of Mg and Ca in water.",):}`A. 1-c,2-d.3.b,4-aB. 1-b,2-a,3-c,4-dC. 1-b2-d,3-c,4-aD. 1-c,2-a,3-b.4-d |
Answer» Correct Answer - D | |
828. |
Hydrogen from `HCl` can be prepared byA. `Mg`B. `Cu`C. `P`D. `Pt` |
Answer» Correct Answer - a `Mg+2HCl rarr MgCl_(2) + H_(2) uarr`. |
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829. |
Heavy water isA. `H_(2).^(18)O`B. Water obtained by repeted distillationC. `D_(2)O`D. Water at `4^(@)C` |
Answer» Correct Answer - C | |
830. |
Hydrogen from `HCl` can be prepared byA. MgB. CuC. PD. Pt. |
Answer» Correct Answer - A P, Pt and Cu do not give hydrogen with HCl. |
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831. |
Permutit is technical name given toA. Aluminates of Ca and NaB. Hydrated silicates of Al and NaC. Silicates of Ca and NaD. Silicates of Ca and Mg |
Answer» Correct Answer - B | |
832. |
Excess of Kl and dill. `H_(2)SO_(4)` were mixed in 50 mL `H_(2)O_(2)`. Thus, `l_(2)` liberated requires 20 mL of 0.1 N `Na_(2)S_(2)O_(3)`. What will be the strenght of `H_(2)O_(2)` in g `L^(-1)` ?A. 0.034B. 0.68C. 6.8D. 5.8 |
Answer» Correct Answer - B For 20 m L of `H_(2)O_(2)` `Meq. Kof kI = Meq. of H_(2)O_(2) in 50 mL = Meq. Of Na_(2) S_(2) O_(3)` `(Wxx 100)/(34//2)= 20 xx 0.1` `therefore W_(H_(2)O_(2))" in" 50 mL` = `(20 xx 0.1 xx 34)/(2000)= 0.034` `therefore W_(H_(2)O_(2))" in " 1000 mL` = `(0.034 xx 1000)/(50)= 0.68g//L` |
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833. |
Hydrogen from `HCl` can be prepared byA. CuB. PC. MgD. Hg |
Answer» Correct Answer - C | |
834. |
20mL of sample of `H_(2)O_(2)` gives 400mL of oxygen measured at NTP. The sample should be labelled as:A. 5 vol. `H_(2)O_(2)`B. dil. `H_(2)O_(2)`.C. anhydrous `H_(2)O_(2)`D. 20 vol. `H_(2)O_(2)` |
Answer» Correct Answer - d |
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835. |
The species that does not contain peroxide bond is //are :A. `PbO_(2)`B. `H_(2)O_(2)`C. `SrO_(2)`D. `BaO_(2)` |
Answer» Correct Answer - a `PbO_(2)` does not contain `-O-O` bond. It is lead dioxide. |
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836. |
False statement for H atom -A. It resembles halogens in some propertiesB. It resembles alkali metals in some propertyC. It can not be placed `I^(st)` group in tableD. It can be placed in `17^(th)` group of periodic table |
Answer» Correct Answer - C | |
837. |
Which of the following cannot be oxidised by `H_(2)O_(2)` ?A. PbSB. `O_(3)(g)`C. `Na_(2)SO_(3)(aq)`D. `KI(aq)`. |
Answer» Correct Answer - B `H_(2)O_(2)` cannot oxidise `O_(3).O_(3)` is a stronger oxidising agent than `H_(2)O_(2)` as such `H_(2)O_(2)` cannot oxidise `O_(3)`. In the reaction, `O_(3)+H_(2)O_(2)to2O_(2)+H_(2)O` `H_(2)O_(2)` is oxidised and `O_(3)` is reduced. |
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838. |
1 ml of `H_(2)O_(2)` solution given 10 ml of `O_(2)` at NTP. It is :A. 10 vol. `H_(2)O_(2)`B. 20 vol. `H_(2)O_(2)`C. 30 vol. `H_(2)O_(2)`D. 40 vol. `H_(2)O_(2)` |
Answer» Correct Answer - A 10 volumes of `H_(2)O_(2)` mean 10 ml. Of `O_(2)` is obtained from 1 ml. of `H_(2)O_(2)` |
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839. |
Which one of the following is used for reviving the exhusated permutit ?A. HCl soltuionB. `10% CaCl_(2)` solutionC. `10% Mgl_(2)` SolutionD. `10% `NaCl solution |
Answer» Correct Answer - D | |
840. |
Which substance does not speed up to decomposition of `H_(2)O_(2)` ?A. GlycerolB. PtC. GoldD. `MnO_(2)`. |
Answer» Correct Answer - A Glycerol, phosphoric acid or acetanilide is added to `H_(2)O_(2)` to check its decomposition. |
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841. |
Which of the following cannot be oxidised by `H_(2)O_(2)` ?A. `O_(3)`B. Kl/HClC. PbSD. `Na_(2)SO_(3)`. |
Answer» Correct Answer - A `H_(2)O_(2)` reduces `O_(3)` to `O_(2)` `O_(3)+H_(2)O_(2)toH_(2)O+20_(2)` |
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842. |
The decomposition of `H_(2)O_(2)` can be checked by addition ofA. alkali metal oxidesB. benzeneC. acetanilideD. `MnO_(2)` |
Answer» Correct Answer - C C |
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843. |
Which substance does not speed up to decomposition of `H_(2)O_(2)` ?A. GlycerolB. `Pt`C. GoldD. `MnO_(2)` |
Answer» Correct Answer - a Glycerol, phosphoric acid or acetanilide is added to `H_(2)O_(2)` to check its decomposition. |
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844. |
Which subtance cannot be reduced by `H_(2)O_(2)`A. `KMnO_(4)//H_(2)SO_(4)`B. `K_(2)Cr_(2)O_(7)//H_(2)SO_(4)`C. `Ag_(2)O`D. `Fe^(3+)`. |
Answer» Correct Answer - D `Fe^(3+)` can not be reduced by `H_(2)O_(2)` while all other get reduced. |
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845. |
Which subtance cannot be reduced by `H_(2)O_(2)`A. `Ag_(2)O`B. `Fe_(^(3+)`C. Acidified `KMnO_(4)`D. Acidified `K_(2)Cr_(2)O_(7)`. |
Answer» Correct Answer - B `H_(2)O_(2)` cannot reduce and `F^(3+)`. All other compounds are reduced by `H_(2)O_(2)`. |
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846. |
In the laboratory, `H_(2)O_(2)` is prepared by the action ofA. `MnO_(2)` is added to dilute cold `H_(3)PO_(4)`B. `BaO_(2)` is added to `CO_(2)` bubbling through cold waterC. `PbO_(2)` is added to an acidicied solution of `KMnO_(4)`D. `Na_(2)O_(2)` is added to boiling water |
Answer» Correct Answer - B By `BaO_(2)`. |
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847. |
In the laboratory `H_(2)`O_(2)` is prepared by the action of:A. cold dilute `H_(2)SO_(4)` on hydrated `BaO_(2)`B. dil. HCl on `MnO_(2)`C. cold `H_(2)SO_(4)` on `MnO_(2)`D. aqueous alkali on `Na_(2)O_(3)` |
Answer» Correct Answer - A `BaO_(2)+dilH_(2)SO_(4)rarrH_(2)O_(3)+BaSO_(4)downarrow` |
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848. |
Which subtance cannot be reduced by `H_(2)O_(2)`A. `KMnO_(4) // H_(2)SO_(4)`B. `K_(2)Cr_(2)o_(7) // H_(2)SO_(4)`C. `Ag_(2)O`D. `Re^(3+)` |
Answer» Correct Answer - d `Fe^(+3)` cannot be reduced by `H_(2)O_(2)` while all other get reduced. |
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849. |
Which is the lightest gas ?A. NitrogenB. HeliumC. OxygenD. Hydrogen |
Answer» Correct Answer - D | |
850. |
In the laboratory, `H_(2)O_(2)` is prepared by the action ofA. Cold `H_(2)SO_(4)` on `BaO_(2)`B. Aqueous alkali on `Na_(2)O_(2)`C. `MnO_(2)` and cold `H_(2)SO_(4)`D. Dilute HCl and `MnO_(2)` |
Answer» Correct Answer - A | |