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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 851. |
Find the volume strength of 1.6N NH2O2 solution. |
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Answer» Strength = Normality × Eq. wt. Eq. wt. of H2O2 = 17 ∴ Strength of 1.6 NH2O2 solution = 1.6 × 17gL-1 Now 68g of H2O2 gives 22400 mL O2 at NTP/STP ∴ 1.6 × 17g of H2O2 will give = \(\frac{22400}{68}\) × l.6 × 17 = 8960 mL of O2 at STP But 1.6 × 17g of H2O2 are present in 1000 mL of H2O2 solution. Hence 1000 mL of H2O2 solution gives 8960 mL of O2 at STP 1 mL of H2O2 will give = 8.96 mL of O2 at STP Hence the volume strength of 1.6 N H2O2 solution is = 8.96 volume. |
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| 852. |
The amount of `H_(2)O_(20` present in `1L` of `1.5 NH_(2)O_(2)` solution isA. `2.5 g`B. `25.5g`C. `3.0g`D. `8.0g` |
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Answer» Correct Answer - a `Cu` and dil. `HCl` will not preoduce `H_(2)`. |
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| 853. |
Which of the following pairs will not produce dihydrogen gas ?A. `Cu+HCl`B. `Fe+H_(2)SO_(4)`C. `Mg+"Steam"`D. `Na+"alcohol"` |
| Answer» Correct Answer - A | |
| 854. |
The amount of `H_(2)O_(2)` present in `1L` of `1.5 NH_(2)O_(2)` solution isA. `2.5g`B. `25.5 g`C. `3.0 g`D. `8.0 g` |
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Answer» Correct Answer - b Strength `=` Normality `xx` Eq. mass ` =1.5 xx 17(` eq. mass of `H_(2)O_(2))` `=25.5 g L^(-1)` |
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| 855. |
Which of the following pairs will not produce dihydrogen gas ?A. `Cu+HCl(dil)`B. `Fe+H_(2)SO_(4)`C. `Mg+` steamD. `Na+` alcohol |
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Answer» Correct Answer - A `Cu` and dil. `HCl` will not preoduce `H_(2)`. |
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| 856. |
Point out the incorrect statementA. Hardness of water depends upon its soap consuming powerB. Temporary hardness is due to bicarbonates of calsium and magnesiumC. Permanent hardness is due to soluble sulphates, chlorides and nitrates of `Ca` and `Mg`D. Permanent hardness can be removed by boiling water |
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Answer» Correct Answer - d Permanent hardness can be treated only by chemicals. |
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| 857. |
Hydrogen gas will not reduce:A. heated cupric oxideB. heated ferric oxideC. heated stannic oxideD. heated aluminium oxidi. |
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Answer» Correct Answer - D `H_(2)` will not reduce heated `Al_(2)O_(3)`. |
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| 858. |
The correct order of stability of hydrides of alkali metals isA. `LiHgtNaHgtKHgtRbH`B. `RbHgtKHgtNaHgtLiH`C. `BaH_(2)gtSrH_(2)gtCaH_(2)`D. None of these |
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Answer» Correct Answer - a Stability order of ionic hydride is `LiH gtNaHgtKHgtRbH` ionic Hydrides are colourless and crystal Reason `:` Size of cation `uarr` `& LE` decreases stability `darr` `[L.E. prop (1)/(r)]` |
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| 859. |
Which of the following will give hydrogen peroxide on hydrolysisA. `H_(2)S_(2)O_(8)`B. `H_(2)SO_(5)`C. `H_(3)PO_(5)`D. `HClO_(4)` |
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Answer» Correct Answer - A,B,C H_(2) S_(2)O_(8)+ 2H_(2)O to 2H_(2)SO_(4) +H_(2)O_(2)` `H_(2)SO_(5)+H_(2)O to H_(2)SO_(4)+H_(2)O_(2)` `H_(3)PO_(5) + 2H_(2)O to H_(2)PO_(4) + H_(2) O_(2)` `HCLO_(4)` on hydroliysis does not produced `H_(2)O_(2)` |
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| 860. |
Radio-activity can be detected in hydrogn due to the presence ofA. `._(1)^(1)H`B. `._(1)^(2)H`C. `._(1)^(3)H`D. `He` |
| Answer» Correct Answer - C | |
| 861. |
Which one of the following chlorides will not fume in air ?A. `BiCl_(3)`B. `C Cl_(4)`C. `PCl_(5)`D. None of the air. |
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Answer» Correct Answer - B `C Cl_(4)` will not fume in moist air. |
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| 862. |
The `H-O-H` angle in water molecule is aboutA. `90^(@)`B. `180^(@)`C. `102^(@)`D. `105^(@)` |
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Answer» Correct Answer - D H-O-H angle in water molecule is `(104*5)^(@)`. |
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| 863. |
The soaps contain salts of higher fatty acids likeA. Stearic acidB. oxalic acidC. Palmitic acidD. Oleic acid |
| Answer» Correct Answer - A::C::D | |
| 864. |
Statement-I: Acetanilide acts as a negative catalyst for decomposition of `H_(2)O_(2)`. ltbr. Statement-II: In the presence of acetanilide, the stability of `H_(2)O_(2)` increases.A. If both Statement-1 `&` Statement-II are True `&` the Statement-II is not a correct explanation of the Statement I.B. If both Statement-I `&` Statement-II are True but Statement-II is not a correct explanantion of the Statement-I.C. If Statement-I is True but the Statement-II is False.D. If Statement-I is False but the Statement-II is True. |
| Answer» Correct Answer - A | |
| 865. |
Statement-I: Polarity of `H_(2)O_(2)` is more than `H_(2)O` but it is a fewer solvent than `H_(2)O`. Statement-II: In chemical reactions, `H_(2)O` is decomposed but `H_(2)O` does not.A. If both Statement-1 `&` Statement-II are True `&` the Statement-II is not a correct explanation of the Statement I.B. If both Statement-I `&` Statement-II are True but Statement-II is not a correct explanantion of the Statement-I.C. If Statement-I is True but the Statement-II is False.D. If Statement-I is False but the Statement-II is True. |
| Answer» Correct Answer - A | |
| 866. |
Match List I with List II and select the correct answer using the codes given below the list : `{:(,"List I","List II",),(1.,"Heavy water",(a)"Bicarbonates of Mg and Ca in water",),(2.,"Temporary hard water",(b)"No foreign ions in water",),(3.,"Soft water",(c)D_(2)O,),(4.,"Permanent hard water",(d)"Sulphates and chlorides of Mg and Ca in water.",):}`A. 1-c, 2-d, 3-b, 4-aB. 1-b, 2-a, 3-c, 4-dC. 1-b, 2-d, 3-c, 4-aD. 1-c, 2-a, 3-b, 4-d. |
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Answer» Correct Answer - D Heavy water is `D_(2)O` (1-c). Temporaary hard water contains bicarbonates of `Ca^(2+)` and `Mg^(2+)` (2-a) Soft water may no foreign ions (3-b) Permanent hard water contains sulphates and chlorides of `Ca^(2+)` and `Mg^(2+)` (4-d). |
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| 867. |
Mass precentage of deuterium in heavy water isA. same as that of protium in waterB. 11.1C. 20D. Cannot be predicated |
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Answer» Correct Answer - C Formula of heavy water is `D_(2)O`, i.e. molecular mass = 20 `% "of deuterium"=(4 xx 100)/(20)` `= 20%` |
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| 868. |
Which of the following can effectively remove all types of hardness of water?A. SoapB. Washing sodaC. Slaked limeD. None of these |
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Answer» Correct Answer - a Soap can remove all types of hardness of water as it converts the hardness producing cations into insoluble ppt. |
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| 869. |
Which of the following can effectively remove all types of hardness of water ?A. Washing sodaB. SoapC. Slaked limeD. Boiling. |
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Answer» Correct Answer - B Washing sode can effectively remove hardness due to `Ca^(2+)` ions, but cannot remove the hardness due to `Mg^(2+)` ions as `MgCO_(3)` is quite soluble in water. Slaked lime can remove temporary hardness, but permanent hardness due to `Mg^(2+)` when removed with `Ca(OH)_(2)` introduces `Ca^(2+)` ions in solution, thus making it hard once again. Boiling can remove only temporary hardness. Soap can effectively remove all types of hardness. |
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| 870. |
Chemical additive which can be used to remove water hardness isA. `Na_(2)[Na_(4)(PO_(3))_(6)]`B. `Ca(OH)_(2)`C. `Na_(2)CO_(3)*10H_(2)O`D. `CaCO_(3)` |
| Answer» Correct Answer - A::B::C | |
| 871. |
Assertion (A) Acidulated water is an example of hard water. Reason (R ) In the presence of an acid, soap is converted into insoluble free fatty acids.A. Both A and R are true and R is the correct explanation of AB. Both A and R are true but R is not a correct explanation of AC. A is true but R is falesD. A is fales but R is true. |
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Answer» Correct Answer - A Both assertion (A) and reason (R ) are true and R is the correct explanation A. |
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| 872. |
Which of the following incorrect :A. Ionic product `D_(2)OgtH_(2)O`B. Solubility of inorganic substances `H_(2)OgtD_(2)O`C. Mass `D_(2)OgtH_(2)O`D. Heat of fusion `D_(2)OgtH_(2)O` |
| Answer» Correct Answer - A | |
| 873. |
Match List I with List II and select the correct answer using the codes given below the list : `{:(,"List I","List II",),(1.,"Heavy water",(a)"Bicarbonates of Mg and Ca in water",),(2.,"Temporary hard water",(b)"No foreign ions in water",),(3.,"Soft water",(c)D_(2)O,),(4.,"Permanent hard water",(d)"Sulphates and chlorides of Mg and Ca in water.",):}`A. 1-C, 2-D, 3-B, 4-AB. 1-B, 2-A, 3-C, 4-DC. 1-B, 2-D, 3-C, 4-AD. 1-C, 2-A, 3-B, 4-D |
| Answer» Correct Answer - D | |
| 874. |
Permanent hardness in water due to pressance of :A. `Ca^(+),Mg^(+)`B. `CaCl_(2),MgCl_(2)`C. `CaCO_(3),MgCO_(3)`D. All |
| Answer» Correct Answer - B | |
| 875. |
Which of the following oxides is a peroxide ?A. `Na_(2)O_(2)`B. `MnO_(2)`C. `BaO`D. `So_(2)` |
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Answer» Correct Answer - A `Na_(2)O_(2)` is a peroxide, all others are double oxides `(MnO_(2), SO_(2))` and simple oxide `(BaO)`. |
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| 876. |
Temperature of maximum density in `H_(2)O and D_(2)O` respectivelt areA. `9^(@)C`B. `11.5^(@)C`C. `15.9^(@)C`D. `20^(@)C` |
| Answer» Correct Answer - B | |
| 877. |
Calculate the volume of 10 volume `H_(2)O` solution that will react with 200 mL of 2N `KMnO_(4) ` in acidic medium. |
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Answer» Normality of 10 volume `H_(2)O_(2)=("Volume strength")/(5.6)=(10)/(5.6) N` Applying normality equation, `N_(1)V_(1)(H_(2)O_(2))=N_(2)V_(2)(KMnO_(4)` `(10)/(5.6)xxV_(1)=2xx200` or `V_(1)=(2xx200xx5.6)/(10)=224` mL. |
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| 878. |
Why does `H^(+)` ion always get associated with atoms or molecules ?A. Ionisation enthalpy of hydrogen resembles that of alkali metals.B. Its reactivity is similar to halogensC. It resembles both alkali metals and holgensD. Loss of an electron form hydrogen atom results in a nucleus of very small sizes as compared to other atoms or ions. Due to small size it cannot exist free. |
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Answer» Correct Answer - D `H^(+)` ion always get associated with other atoms or molecules. The reason is that loss of an electron from hydrogen atom results in a nucles of very small size as compared to other atoms or ions. Due to small size it cannot exist free. |
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| 879. |
Why does `H^(+)` ion always get associated with atoms or molecules ?A. lonisation enthalpy of hydrogen resembles to that of alkaliB. Its reactivity is similar to halogensC. It resembles both alkali metals and halogensD. Loss of an electron from hydrogen atom results in a nucleus of very samall size as compared to other atoms or ions. Due to small size , it cannot exist free |
| Answer» Correct Answer - D | |
| 880. |
Which of the following is not true ?A. Ordinary water is electrolysed more rapidly than `D_(2)O`B. `D_(2)O` freezes at lower temperature than `H_(2)O`C. Reaction between `H_(2)` and `Cl_(2)` is much faster than `D_(2)` and `Cl_(2)`D. Both dissociation energy for `D_(2)` is greater than `H_(2)` |
| Answer» Correct Answer - B | |
| 881. |
Temperature of maximum density in `H_(2)O and D_(2)O` respectivelt areA. `277*15K, 284*75K`B. `273*15K, 277*15K`C. `277*15K, 285*75K`D. `284*75K, 277*15K`. |
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Answer» Correct Answer - A Temperature of maximum density of `H_(2)O is 277*15K` Temperature of maximum density of `D_(2)O is 284*75K` |
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| 882. |
Which of the following can effectively remove all types of hardness of water?A. SoapB. Washing sodaC. Slaked limeD. None of these. |
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Answer» Correct Answer - A Soap can remove all type of hardness of water as it converts the hardness producing cations into insoluble ppt. |
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| 883. |
Why does `H^(+)` ion always get associated with atoms or molecules ?A. Ionisation enthalpy of hydrogen resembles that of alkali metals.B. Its reactivity is similar to halogens.C. It resembles both alkali metals and halogens.D. Loss of an electron from hydrogen atom results in a nucleus of very small size as compared to other atoms or ions. Due to small size it cannot exist free. |
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Answer» Correct Answer - D Loss of an electron from H atom results in `H^(+)` ion having extremely small size `(~ 1.5 xx 10^(-3)"pm")` as compared to normal atomic and ionic sizes of 50-200 pm. As a consequence, `H^(+)` does not exist freely and is always associated with other atoms or molecules. |
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| 884. |
`HCl` is added to following oxides. Which one would give `H_(2)O_(2)` ?A. `MnO_(2)`B. `PbO_(2)`C. BaOD. None of the above. |
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Answer» Correct Answer - D `MnO_(2), PbO_(2)` and BaO will not give `H_(2)O_(2)` with HCl. `MnO_(2)` and `BaO_(2)` will give `Cl_(2)` and BaO will react with HCl to give `BaCl_(2)` and water. |
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| 885. |
`HCl` is added to following oxides. Which one would give `H_(2)O_(2)` ?A. `MnO_(2)`B. `PbO_(2)`C. `BaO`D. None of these |
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Answer» Correct Answer - D `MnO_(2),PbO_(2)` and `BaO` will not give `H_(2)O_(2)` with`HCl. MnO_(2)` and `PbO_(2)` will give `Cl_(2)` and `BaO` will react with `HCl` to give `BaCl_(2)` and water. |
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| 886. |
The degree of hardness of a given sample of hard water is 40 ppm. If the entire hardness in due to `MgSO_(4)` , how much of `MgSO_(4)` is present per kg of water ? |
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Answer» Degree of hardness of `H_(2)O` is 40 ppm, i.e., `10^(6)` g of water contain `CaCO_(3)`=40 g Since 1 mole of `CaCO_(3)-=1 `mole of `MgSO_(4)` `therefore 100 ` g of `CaCO_(3)-=120` g of `MgSO_(4)` `therefore 10^(6)` g of water contain `MgSO_(4)=(40xx120)/(100)=48 g` or `10^(3)` g of water contain `MgSO_(4)=(48xx10^(3))/(10^(6))xx10^(3) ` mg or 1 kg of water will contain `MgSO_(4)=48` mg |
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| 887. |
A mixture of hydazine `(N_(2)H_(4))` and `58-60%` solution of `H_(2)O_(2)` is used asA. antisepticB. fertilliserC. rocket fuelD. None of the above |
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Answer» Correct Answer - C A mixture of `H_(2)O_(2)` and hydrazine `(N_(2)H_(4))` is used as a rocket fuel . |
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| 888. |
HCl is added to the following oxides, which one would give `H_(2)O_(2)`?A. `BaO_(2)`B. `MnO_(2)`C. `PbO_(2)`D. `NO_(2)` |
| Answer» Correct Answer - A | |
| 889. |
Permutit is:A. hydrated sodium aluminium silicateB. sodium hexametaphosphateC. sodium silicateD. sodium meta-aluminate |
| Answer» Correct Answer - A | |
| 890. |
Which of the following statements is not true?A. the temporary hardness is due to presence of Ca and Mg bicarbonatesB. permanent hardness is removed by adding limeC. permanent hardness is due to the presence soluble Ca and Mg sulphates and chloridesD. Temporary hardness is removed by boiling |
| Answer» Correct Answer - B | |
| 891. |
Which of following true structure of `F_(2)O_(2)`:A. B. `F-O-O-F`C. NoneD. Both |
| Answer» Correct Answer - A | |
| 892. |
A mixture of hydazine `(N_(2)H_(4))` and `58-60%` solution of `H_(2)O_(2)` is used asA. antisepticB. rocket fuelC. finely divided metalsD. insecticide |
| Answer» Correct Answer - B | |
| 893. |
Volume strength of resulting solution = 1.339 × 5.6 = 7.5 the degree of hardness of a given sample of hard water is 60 ppm. If the entire hardness is due to MgSO4, how much of MgSO4 is present per kilogram of hard water? |
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Answer» Degree of hardness of water = 60ppm Since degree of hardness is the number of parts of calcium carbonate or equivalent to calcium and magnesium salts present in a million parts of water by mass. 106 g of water contain 60 g of CaCO3 Now 1 mol of CaCCO3 = 1 mol of MgSO4 100g of CaCOa = 120g of MgSO4 106 g of water contain MgSO4 = \(\frac{60\times 200}{100}\) = 72 g 103 g of water will contain MgSO4 = \(\frac{72}{10^6}\) x 103 = 0.072 g 1 kg of water contain MgSO4 = 72 mg |
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| 894. |
Cation exchange resins are generated by treating with_____. |
| Answer» Correct Answer - Dilute acid. | |
| 895. |
Permutit is :A. Hydrated sodium aluminium silicateB. Sodium hexaphosphateC. Sodium bicarbonateD. Calcium hydroxide |
| Answer» Correct Answer - A | |
| 896. |
`H_(2)O_(2)` generally conllected in:A. In colour Bottle & surface of bottle is roughB. In white bottle & smooth surface of bottleC. May be contain in white bottle after adding inhibitorD. None of these |
| Answer» Correct Answer - C | |
| 897. |
Which of the following is a true structure of `H_(2)O_(2)`?A. B. C. D. |
| Answer» Correct Answer - B | |
| 898. |
`O-O-H` bond angle in `H_2O_2` is approximately______.A. `107.28^(@)`B. `109.28^(@)`C. `104.5^(@)`D. `97^(@)` |
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Answer» Correct Answer - d d |
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| 899. |
Heavy water reacts respectively with `CO_(2),SO_(3), P_(2)O_(5) and N_(2)O_(5)` to give the compounds :A. `D_(2)CO_(3),D_(2)SO_(4),D_(3)PO_(2),DNO_(2)`B. `D_(2)CO_(3),D_(2)SO_(4),D_(3)PO_(4),DNO_(2)`C. `D_(2)CO_(3),D_(2)SO_(3),D_(3)PO_(4),DNO_(2)`D. `D_(2)CO_(3),D_(2)SO_(4),D_(3)PO_(4),DNO_(3)` |
| Answer» Correct Answer - D | |
| 900. |
In cation exchange process for removing hardness of water, the resulting water turnsA. AcidicB. BasicC. NeutralD. Both 1 and 2 |
| Answer» Correct Answer - A | |