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The integers –8, –7, –6, –5, –4 and –3 lie between –9 and –2. So, there are six integers between – 9 and –2.

1 – 2 + 3 – 4 + 5 – 6 + 7 –8 + 9 – 10 

= (1 – 2) + (3 – 4 ) + (5 – 6) + (7 – 8) + (9 – 10) 

= (–1) + ( –1) + (–1) + (–1) + (–1) 

= –5.

1 – 2 + 3 – 4 + 5 – 6 + 7 – 8 + 9 – 10 

= (1 + 3 + 5 + 7 + 9) – (2 + 4 + 6 + 8 + 10) 

= 25 – 30 

= –5.

1 – 2 + 3 – 4 + 5 – 6 + 7 – 8 + 9 – 10 

= (1 + 3 + 5 + 7 + 9) – (2 + 4 + 6 + 8 + 10) 

= 25 – 30 

= –5

As the sum is 47, the other integer is obtained by subtracting –24 from 47. So, the required integer 

= 47 – (–24) 

= 47 + 24 

= 71.

As the sum is 47, the other integer is obtained by subtracting –24 from 47. So, the required integer 

= 47 – (–24) 

= 47 + 24 

= 71

(a) 0 + 1 – 2 + 3 – 4 + 5 – 6 + 7 –8 + 9 = 5 

(b) 0 – 1 – 2 + 3 + 4 – 5 + 6 – 7 + 8 – 9 = –3

The sum of any two negative integers is always greater than both the integers.

False

False.

The successor of a whole number is the number obtained by adding 1 to it.

Successor of 1 = 1 + 1

= 2

The successor of the integer 1 is 0.

False

The sum of any two negative integers is always smaller than both the integers.

True

True.

In negative integer = -6 + (-7)

= – 6 – 7

= – 13

In negative integer the sum is less than both the integer.

The smallest natural number is zero. 

False

False.

The sum of all integers between -5 and -1 = -4 -3 -2

= -9

The sum of all the integers between –5 and –1 is –6.

False

The sum of any two positive integers is greater than both the integers. 

True

True.

Example: consider the two positive integer 11 and 21

Sum of two integers = 11 + 21

= 32

Therefore, sum of any two positive integers is greater than both the integers.

Zero is not an integer as it is neither positive nor negative.

False.

True.

Whole numbers start from 0, 1, 2, 3…. so it contains 0 and positive integers.

Hence, all whole numbers are integers.

All whole numbers are integers.

True

(A) +5

The integer which is 5 units to the right of 0 on the number line is + 5.

All integers are whole numbers.

False.

False.

Whole numbers start from 0, 1, 2, 3….

Whole numbers are not containing negative integers, but integers contain both positive and negative numbers.

Therefore, all integers are not whole numbers.

Since 5 > 3, therefore –5 > –3 

False

(B) to the right of 0 

(B) -11

In case of negative integer, small number is greater.

(D) 5

We know that, whole numbers are starts from 0.

Then, number of whole numbers between -5 and 5 are 0, 1, 2, 3, and 4.

(D) –14

In case of negative integer, big number is smaller.

(C) -2

The number which comes immediately before a particular number is called its predecessor.

To find the predecessor of a number, subtract one from the given number.

So, predecessor of -1 = -1 -1 = -2

By assuming Closure property of addition [a+b=c],

Let,

a=53, assume b=x, c=-16

=53+x=-16

= x =-16-53

( By sending 53 from left hand side to the right hand side, it changes to -53)

= x = -69

By the calculation we got another integer is -69

From the Commutative law of Subtraction

Left hand side (LHS),

= {(-9)-(-6)}

= {-9+6}

=-{9-6}

(Take out the –ve sign outside and do subtract smaller from bigger number)

=-{3}

=-3

Right hand side (RHS),

= {(-6)-(-9)}

= {-6+9}

=-{6-9}

(Take out the –ve sign outside and do subtract smaller from bigger number)

=-{-3}

=3

By comparing LHS and RHS

LHS≠RHS

From the Associative law of Addition

= {-8+ (-7)} +6= -8 + {(-7) +6}

Left hand side (LHS),

= {-8+ (-7)} +6

= {-8-7} +6

= {-15} + 6

= -9

Right hand side (RHS),

=-8 + {(-7) +6}

=-8 + {-7+6}

=- 8 + {-1}

=-8-1

=-9

By comparing LHS and RHS,

LHS = RHS

From the commutative law of Subtraction [a-b = b-a]

Let,

a=36, b=-64

Left hand side (LHS),

= {36 – (-64)}

= {36+64}

= 100

Right hand side (RHS),

= (-64-36)

=-(64+36)

(Take out the –ve sign outside and do subtract smaller from bigger number)

=-100

By comparing LHS and RHS,

LHS ≠RHS

= {-13+27} + {-25 + 40} …[∴( – x – = + ) ]

= {14} + {15}

= 29

integer and a negative integer, wemultiply them as Whole numbers and put a negative numbers sign before 

(a) The charge on an atom is 0

(b) The charge on an atom if it loses an electron isc +1

(c) the charge on an atom if it gains an electron is -1

(a) 725 years 

(b) 71 years 

(c) 1383BC

(d) Archimedes

– 350 feets.

On the number line, the number increases as we move to right and decreases as we move to the left

∴ -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.

We know that one more than the given number is its successor.

+ 2000 Rupees.

The opposite of each are

a) loss of ₹ 500

b) withdrawal of ₹ 2000

c) 50 km towards North.

No, we can’t find at least one pair of integers whose sum of product is not an integer.