InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 601. |
Represent the following statements with suitable integer :(i) Sneha deposited ₹ 2000 in her savings account.(ii) A submarine is in the depth of 350 feet in the sea level.(iii) The height of Mount Everest is 8848 m J 3 above the sea level.(iv) Temperature of 14 degrees below 0° C. |
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Answer» (i) + 2000 Rupees. (ii) – 350 feet. (iii) + 8848 m. (iv) – 14°C. |
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| 602. |
Replace the blank with an integer to make it a true statement :________ ÷ (- 9) = 16 |
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Answer» x ÷ (- 9) = 16 x = 16 × (- 9) We know, a × (- b) = – (a × b) x = – (16 × 9) ∴ x = – 144 |
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| 603. |
Add without using number line. (i) 10 + (-3) (ii) 10 + (+16) (iii) (-8) + (+8) |
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Answer» i) 10 + (-3) 10 + (-3) = 7 + 3 + (-3) = 7 + (3 + (-3)) = 7 + 3 – 3 = 7 + 0 ∴ 10 + (-3) = +7 ii) -10 + (+16) -10 + (+16) = -10 + 10 + 6 = (-10 + 10) + 6 = 0 + 6 ∴ -10 + (+16) = + 6 iii) (-8) + (+ 8) -8 + (+8) = -8 + 8 = 0 ∴ -8 + (+8) = 0 |
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| 604. |
Calculate : (- 96) ÷ 16 |
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Answer» (- a) ÷ b = – a/b = -96/16 = -6 |
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| 605. |
Which is greater?9 × (-11) or 6 × (-16) |
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Answer» 9 × (-11) or 6 × (-16) -(9 × 11) or – (6 × 16) (-99) or (- 96) (- 99) less than (- 96) (- 99) < (- 96) (or) (- 96) greater than (- 99) ∴ (-96) > (-99) |
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| 606. |
Fill in the blanks to make the statement true. (– 25) × 30 = – 30 × _______. |
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Answer» 25 (– 25) × 30 = – 30 × 25. |
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| 607. |
–16 ÷ [8 ÷ (–2)] is equal to (a) –1 (b) 1 (c) 4 (d) –4 |
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Answer» The correct option is (c) 4. –16 ÷ [8 ÷ (–2)] = (-16) ÷ (-4) = 4 |
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| 608. |
[(– 10) × (+ 9)] + ( – 10) is equal to(a) 100 (b) –100 (c) – 80 (d) 80 |
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Answer» The correct option is (b) –100. [(– 10) × (+ 9)] + ( – 10) = (-10 x 9) - 10 = - 90 - 10 = -100 |
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| 609. |
Because of Covid-19 a company lockdown for 6 months and got loss of ₹1,32,000 in the year 2020. Find the average loss of each month. |
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Answer» Since, company got loss of ₹1,32,000 in the year 2020. Total no. of months in year 2020 is 12. ∵ Average loss of each month = \(₹\left(\frac{132000}{12}\right) = ₹11000\) Given loss of 6 months = ₹ 1,32,000 Average loss of each month = 1,32,000 ÷ 6 Average loss of each month = ₹ 22,000 |
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| 610. |
Bhargavi lost 5700 calories in the month of June using yoga. If the calory loss is uniform, calculate the loss of calories per day ? |
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Answer» Given number of calories Bhargavi lost in the month of June = 5700 calories June month has 30 days. So, number of calories lost in 30 days = 5700 Number of calories lost in 1 day = 5700 ÷ 30 Number of calories lost per day = 190 Calories. |
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| 611. |
State whether the statements are True or False.(– 19) × (– 11) = 19 × 11 |
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Answer» (– 19) × (– 11) = 19 × 11 True |
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| 612. |
Fill in the blanks to make the statements true. (–157) × (–19) + 157 = ___________ |
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Answer» (–157) × (–19) + 157 = 3140 |
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| 613. |
Observe the following patterns and fill in the blanks to make the statements true:(a) – 5 × 4 = – 20– 5 × 3 = – 15 = –20 – ( – 5)– 5 × 2 = _______ = – 15 – ( –5)– 5 × 1 = _______ = _______– 5 × 0 = 0 = _______– 5 × – 1 = 5 = _______– 5 × – 2 = _______ = _______(b) 7 × 4 = 287 × 3 = _______ = 28 – 77 × 2 = __ __ = _______– 77 × 1 = 7 = _______ – 77 × 0 = _______ = _______ –________7 × – 1 = –7 = _______ – _______7 × – 2 = _______ = _______ – _______7 × – 3 _______ = _______ – ________ |
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Answer» Observe the following patterns and fill in the blanks to make the statements true: (a) – 5 × 4 = – 20 – 5 × 3 = – 15 = –20 – ( – 5) – 5 × 2 = -10 = – 15 – ( –5) – 5 × 1 = -5 = -10-(-5) – 5 × 0 = 0 = -5-(-5) – 5 × – 1 = 5 = 0-(-5) – 5 × – 2 = 10 = 5-(-5) (b) 7 × 4 = 28 7 × 3 = 21= 28 – 7 7 × 2 = 14 = 21 – 7 7 × 1 = 7 = 14 – 7 7 × 0 = 0 =7 –7 7 × – 1 = –7 = 0– 7 7 × – 2 =-14= -7 – 7 7 × – 3 = -21 = -14 - 7 |
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| 614. |
Fill in the blanks to make the statements true.___________× ( – 1) = – 35 |
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Answer» 35× ( – 1) = – 35 |
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| 615. |
Fill in the blanks to make the statements true.___________ × ( – 1) = 47 |
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Answer» -47× ( – 1) = 47 |
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| 616. |
Write all the integers between the given pairs (write them in the increasing order.) (a) `0 and -7 ` (b) `-4 and 4` (c) `-8 and -15` (d) `-30 and -23` 2)WRITE 4 integers greater than -20 and 4 integers less than -10 |
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Answer» (a) `-6,-5,-4,-3,-2,-1` (b) `-3,-2,-1,0,1,2,3` (c) `-14,-13,-12,-11,-10,-9` (d) `-29,-28,-27,-26,-25,-24` answer |
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| 617. |
The successor of the predecessor of –50 is (A) –48 (B) –49 (C) –50 (D) –51 |
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Answer» The correct option is (C) -50. |
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| 618. |
The successor of the predecessor of –50 is(A) –48 (B) –49 (C) –50 (D) –51 |
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Answer» (c) – 50 The successor of a whole number is the number obtained by adding 1 to it. To find the predecessor of a number, subtract one from the given number. So, predecessor of – 50 = – 50 – 1 = – 51 Then, successor of – 51 = – 51 + 1 = 50 |
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