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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 51. |
Find the sum of the pairs of integers: (a) – 6, – 4 (b) +3, – 4 (c) +4, –2 |
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Answer» (a) – 6 and – 4 both have negative signs. So, – 6 + (– 4) = – (6 + 4) = –10 (b) + 3 and – 4 have opposite signs. As 4 – 3 = 1, therefore + 3 + (– 4) = –1 (c) + 4 and –2 have opposite signs. So, 4 + (–2) = 4 – 2 = 2 |
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| 52. |
What will be the sign of the product, if we multiply 90 negative integers and 9 positives integers? |
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Answer» If we multiply the 90 -ve integers the answer we are getting is positive integer. Because, 90 is an even number and the product of even number of negative integer is positive. The product of number of positive integer is not affect the sign of product. So the product obtained from this is positive. |
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| 53. |
Fill in the blanks to make the statement true.(– 95) ÷ _____ = 95 |
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Answer» -1: (– 95) ÷ (-1) = 95 |
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| 54. |
Fill in the blanks to make the statement true.51 ÷ _____ = – 51 |
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Answer» -1: 51 ÷ (-1) = – 51 |
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| 55. |
Fill in the blanks to make the statement true._____ ÷ ( – 1) = 75 |
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Answer» -75: (-75) ÷ ( – 1) = 75 |
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| 56. |
Fill in the blanks to make the statement true. ___ × ( – 1) = – 35 |
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Answer» 35: 35 × ( – 1) = – 35 |
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| 57. |
Represent the following using integers with proper sign: (a) 3 km above sea level (b) A loss of Rs 500 |
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Answer» (a) +3 (b) –500 |
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| 58. |
Fill in the blanks to make the statement true.( – 69) ÷ ( 69) = _____ |
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Answer» -1 ( – 69) ÷ ( 69) = (-69)/ 69 = -1 |
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| 59. |
Fill in the blank using or = to make the statement correct.3 + (–2) ____ 3 + (–3) |
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Answer» 3 + (–2) > 3 + (–3) |
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| 60. |
Fill in the blanks to make the statement true.____ × ( – 1) = 47 |
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Answer» -47: -47 × ( – 1) = 47 (product of even number of negative integers is a positive integer) |
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| 61. |
Fill in the blank using <, > or = to make the statement correct 3 + (–2) ____ 3 + (–3) |
| Answer» 3 + (–2) > 3 + (–3) | |
| 62. |
State whether the statements are True or False. Product of a negative integer and a positive integer is a positive integer. |
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Answer» Product of a negative integer and a positive integer is a positive integer. False |
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| 63. |
Write (T) for true and (F) for false:Zero is larger than every negative integer. |
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Answer» Zero is larger than every negative integer. True (T), Because in the number line all the negative numbers are come left side of the zero. |
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| 64. |
State whether each of the following statements is true or false: (a) Every positive integer is greater than 0. (b) Every integer is either positive or negative. |
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Answer» (a) True (b) False |
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| 65. |
Write the correct answer from the given four options: Sania and Trapi visited Leh and Tawang respectively during winter. Sania reported that she had experienced –4°C on Sunday, while Trapi reported that she had experienced –2°C on that day. On that Sunday (A) Leh was cooler than Tawang. (B) Leh was hotter than Tawang. (C) Leh was as cool as Tawang. (D) Tawang was cooler than Leh. |
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Answer» The correct answer is (A) Leh was cooler than Tawang. |
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| 66. |
Which of the following shows the maximum rise in temperature? (A) 0°C to 10°C (B) –4°C to 8°C (C) –15°C to –8°C (D) –7°C to 0°C |
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Answer» (B) –4°C to 8°C |
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| 67. |
Write the correct answer from the given four options: Sania and Trapi visited Leh and Tawang respectively during winter. Sania reported that she had experienced –4°C on Sunday, while Trapi reported that she had experienced –2°C on that day. On that Sunday (A) Leh was cooler than Tawang. (B) Leh was hotter than Tawang. (C) Leh was as cool as Tawang. (D) Tawang was cooler than Leh. |
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Answer» The correct answer is (A) Leh was cooler than Tawang. |
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| 68. |
The average age of 18 persons was decreased by 4 months. when two of them of age was 32 years and 48 years were replaced by two new person whose difference in the age of 4 years. Find the age of each new person. |
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Answer» Initial average age=A years. Final average years=(A-1/3)years. A=(Sum of ages of 16 personc+32+48)/18 Sum of ages of 16 persons=18A-80 age of first person=x age of second person=x+4 Final average age=A-1/3=18A-80+2x+4 18A-6=18A-80+2x+4 x=35 Ages are=35,39 years. |
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| 69. |
Check weather the following statements are same(-8) + (-4) and (-4) + (-8)(-2) + 5 and 5 + (-2)12 + 0 and 0 + 12does integers also follow commutative property of addition ? Find some other additions also. |
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Answer»
From table it is clear that integers also follow the commutative property of addition. |
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| 70. |
An uplift moves down words in a mine- well out the rate of 6 metre/minute. If lift starts going down wards from the height 10 m above the ground, then how much time will it take to reach – 350 m? |
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Answer» Difference between two heights = 10 m – (- 350 m) = 10 m + 350 m = 360 m Rate of going downwards = 6 m/minute ∴ Time of reach at lowest point = 360/6 = 60 minute = 1 hour. |
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| 71. |
Check for the integers(-3) x 1 =-3 1 x 5=5(-4) x 1 = 1 x 8 =1 x (-5) = 3 x 1 =1 x (-6) = 7 x 1 = |
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Answer» (-4) x 1 =-4 1 x 8 = 8 Outcome : Multiplicative identity for integers is 1. |
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| 72. |
Write two such integers, whose :(i) sum is (-7)(ii) difference is 4(iii) sum is 0(iv) difference is – 2 |
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Answer» (i) Such integers are (-1) and (-6) because (-1) + (-6) = -7 (ii) Such integers are (6) and (+ 2) because 6 + (-2) = 6- 2 = 4 (iii) Such integers may be -1 and + 1 because (1) + (-1) = 0 (iv) Such integers may be (-3) and (-1) because -3 – (-1) = -3 + 1 = -2 |
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| 73. |
If going up a 60 feet multi storied by a lift is represented by positive integers then:(i) How will we represented the height of flat at 60 feet above?(ii) Represent the parking 15 feet below integer.(iii) If lift goes upwards at the rate of 5 feet/ sec, represented as + 5 and if travels In a opposite direction, then what is the integer representing downward direction? |
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Answer» (i) Height of flat at 60 feet is an integer = + 60 (ii) Position of parking 15 feet down as integer = – 15 (iii) Lift coming downwards at the rate of 5 feet/ sec as an integer = – 5 |
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| 74. |
Write the integers for the following situations. i) A kite is flying at a height of 225 m in the sky. ( ) ii) A whale is at a depth of 1250 m in the ocean. ( ) iii) The temperature in Sahara desert is 12°C below freezing temperature. ( ) iv) Ravi withdrawn Rs. 3800 from ATM using his debit card. ( ) |
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Answer» i) 225 m ii) – 1250 m iii) – 12°C iv) -3800 |
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| 75. |
Fill in the blanks to make the statements true.113 ÷ _____ = – 1 |
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Answer» 113 ÷ -113 = – 1 |
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| 76. |
Simplify 26 × (- 48) + (- 48) × (- 36) using suitable laws. |
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Answer» 26 × (- 48) + (- 48) × (- 36) = (- 48) × 26 + (- 48) × (- 36) (Commutative law) = (- 48) × [26 + (- 36)] (Distributive law) = (- 48) × (- 10) = 480 |
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| 77. |
Divide:(i) 102 by 17(ii) -85 by 5(iii) -161 by -23(iv) 76 by -19(v) 17654 by -17654(vi) (-729) by (-27)(vii) 21590 by -10(viii) 0 by -135 |
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Answer» (i) Given 102 by 17 We can write given question as 102 ÷ 17 102 ÷ 17 = |102/17| = |102|/|17| [by applying the mod] = 102/17 = 6 (ii) Given -85 by 5 We can write given question as -85 ÷ 5 -85 ÷ 5 = |-85/5| = |-85|/|5| [by applying the mod] = -85/5 = -17 (iii) Given -161 by -23 We can write given question as -161 ÷ -23 -161 ÷ -23 = |-161/-23| = |-161|/|-23| [by applying the mod] = 161/23 = 7 (iv) Given 76 by -19 We can write given question as 76 ÷ -19 76 ÷ -19 = |76/-19| = |76|/|-19| [by applying the mod] = 76/-19 = -4 (v) Given 17654 by 17654 We can write given question as 17654 ÷ -17654 17654 ÷ -17654 = |17654/-17654| = |17654|/|-17654| [by applying the mod] = 17654/-17654 = -1 (vi) Given (-729) by (-27) We can write given question as (-729) ÷ (-27) (-729) ÷ (-27) = |-729/-27| = |-729|/|-27| [by applying the mod] = 729/27 = 27 (vii) Given 21590 by -10 We can write given question as 21590 ÷ -10 21590 ÷ -10 = |21590/-10| = |21590|/|-10| [by applying the mod] = 21590/-10 = -2159 (viii) Given 0 by -135 We can write given question as 0 ÷ -135 0 ÷ -135 = 0 [because anything is divided by 0 we get the result as 0] |
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| 78. |
Find each of the following products:(i) 3 × (-8) × 5(ii) 9 × (-3) × (-6)(iii) (-2) × 36 × (-5)(iv) (-2) × (-4) × (-6) × (-8) |
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Answer» (i) Given 3 × (-8) ×5 Here we have to find the product of given number. 3 × (-8) × 5 = 3 × (-8 × 5) =3 × -40 = -120 Since the product of two integers of opposite signs is equal to the additive inverse of the product of their absolute values. (ii) Given 9 × (-3) × (-6) Here we have to find the product of given number. 9 × (-3) × (-6) = 9 × (-3 × -6) [∵ the product of two integers of like signs is equal to the product of their absolute values.] =9 × +18 = +162 (iii) Given (-2) × 36 × (-5) Here we have to find the product of given number. (-2) × 36 × (-5) = (-2 × 36) × -5 [∵ the product of two integers of like signs is equal to the product of their absolute values.] =-72 × -5 = +360 (iv) Given (-2) × (-4) × (-6) × (-8) Here we have to find the product of given number. (-2) × (-4) × (-6) × (-8) = (-2 × -4) × (-6 × -8) [∵ the product of two integers of like signs is equal to the product of their absolute values.] =-8 × -48 = +384 |
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| 79. |
Find the values of – 2 × (- 5) = _________ |
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Answer» – 2 × (- 5) = 10 |
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| 80. |
Find the values of (- 2) × (- 4) = _________ |
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Answer» (- 2) × (- 4) = 8 |
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| 81. |
Find the values of (- 10) × 6 |
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Answer» (- 10) × 6 = – (10 × 6) = – 60 |
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| 82. |
Find the values of(i) (-6) × 5(ii) (- 15) × 2(iii) (- 12) × 8(iv) (- 10) × 6 |
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Answer» (i) (-6) × 5 = -(6 × 5) = – 30 (ii) (- 15) × 2 = – (15 × 2) = – 30 (iii) (- 12) × 8 = – (12 × 8) = – 96 (iv) (- 10) × 6 = – (10 × 6) = – 60 |
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| 83. |
Find the values of(i) 4×(-8)(ii) 5 × (-20)(iii) 7 × (-8)(iv) 10 × (-9) |
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Answer» (i) 4×(-8) = -(4×8) = – 32 (ii) 5 × (-20) = – (5 × 20) = – 100 (iii) 7 × (-8) = – (7 × 8) = – 56 (iv) 10 × (-9) = -(10 × 9) = – 90 |
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| 84. |
Find the values of 5 × (-20) |
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Answer» 5 × (-20) = – (5 × 20) = – 100 |
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| 85. |
Find the values of 10 × (-9) |
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Answer» 10 × (- 9) = -(10 × 9) = – 90 |
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| 86. |
Find the values of 7 × (-8) |
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Answer» 7 × (-8) = – (7 × 8) = – 56 |
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| 87. |
– 35 × 107 is not same as(a) – 35 × (100 + 7) (b) (– 35) × 7 + ( – 35) × 100(c) – 35 × 7 + 100 (d) (– 30 – 5) × 107 |
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Answer» (c) – 35 × 7 + 100 – 35 × 107 = (– 30 – 5) × 107 = – 35 × (100 + 7) = (– 35) × 7 + ( – 35) × 100 But, – 35 × 107 ≠ – 35 × 7 + 100 |
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| 88. |
The integer ‘5 units to the right of 0 on the number line’ is (A) +5 (B) –5 (C) +4 (D) – 4 |
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Answer» The correct option is (A) +5. |
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| 89. |
Every integer less than 0 has the sign (A) + (B) – (C) × (D) ÷ |
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Answer» The option is (B) – . |
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| 90. |
State whether the given statements are true (T) or false (F).Zero is less than every positive integer. |
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Answer» Zero is less than every positive integer. True |
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| 91. |
State whether the given statement are true (T) or false (F) :Since 5 > 3, therefore –5 > –3 |
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Answer» False. In case of negative integer, big number is smaller. So, – 5 < -3 |
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| 92. |
Every integer less than 0 has the sign(A) +(B) –(C) ×(D) + |
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Answer» (B) - Every integer which is less than 0 has negative sign. |
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| 93. |
State whether the given statement are true (T) or false (F) :Zero is less than every positive integer. |
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Answer» True Since, zero lies on the left side of every positive integer on the number line. Therefore, zero is less than every positive integer. |
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| 94. |
Find each of the following products: (a) `3 xx (-1)` (b) `(-1) xx 225` (c) `(-21) xx (-30)` (d) `(-316) xx (-1)` (e) `(-15 xx 0 xx (-18)` (f) `(-12) xx (-11) xx (10)` (g) `9 xx (-3) xx (-6)` (h) `(-18) xx (-5) xx (-4)` (i) `(-1) xx (-2) xx (-3) xx 4` (j) `(-3) xx (-6) xx (-2) xx (-1)` |
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Answer» Here, we will use the below rules, `(+)xx(-) = (-)` `(-)xx(+) = (-)` `(-)xx(-) = (+)` `(+)xx(+) = (+)` (a)`3xx(-1) = -3` (b)`(-1)xx225 = -225` (c)`(-21)xx(-30) = 630` (d)`(-316)xx(-1) = 316` (e)`(-15)xx0xx(-18) = 0` (f)`(-12)xx(-11)xx(10) = 1320` (g)`9xx(-3)xx(-6) = 162` (h)`(-18)xx(-5)xx(-4) = -360` (i)`(-1)xx(-2)xx(-3)xx4 = -24` (j)`(-3)xx(-6)xx(-2)xx(-1) = 36` |
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| 95. |
A cement company earns a profit of Rs 8 per bag of white cement sold and a loss of Rs 5 per bag of grey cement sold.(a) The company sells 3,000 bags of white cement and 5,000 bags of grey cement in a month. What is its profit or loss?(b) What is the number of white cement bags it must sell to have neither profit nor loss, if the number of grey bags sold is 6,400 bags |
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Answer» a) 3000*8+5000*(-5)=24000-25000Rs=-1000Rs He is in loss. b) 6400*(-5)+x+8=0 8x=5*6400 x=4000 white cement. |
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| 96. |
In a class test containing 10 questions, 5 marks are awarded for every correct answer and (-2) marks are awarded for every incorrect answer and 0 for question not attempted. Reshma gets five correct answers and five incorrect answers, what is her score? |
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Answer» Reshma marks for 5 correct answers = 5 × 5 |
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| 97. |
In a class test containing 10 questions, 5 marks are awarded for every correct answer and (-2) marks are awarded for every incorrect answer and 0 for question not attempted. Heena gets two correct and five incorrect answers out of seven questions she attempts. What is her score ? |
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Answer» Heena marks for 2 correct answers = 2 × 5 |
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| 98. |
A cement company earns a profit of 8 per bag of white cement sold and a loss of 5 per bag of grey cement sold. The company sells 3,000 bags of white cement and 5,000 bags of grey cement in a month. What is its profit or loss ? |
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Answer» Profit on white cement = Rs +8 Loss on grey cement = Rs -5 ∴ Profit on 1 bag of white cement = Rs 8 Profit on 3,000 bags of white cement = Rs 8 × 3000 = Rs 24,000 Loss on 1 bag cement = Rs -5 Loss on 5000 bags grey cement = Rs -5 × 5000 = Rs -25000 Total profit / loss = Total profit + Total loss = 24000 + (-2500) = 24000 – 25000 ∴ Total loss = -1000 |
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| 99. |
A cement company earns a profit of 8 per bag of white cement sold and a loss of 5 per bag of grey cement sold. What is the number of white cement bags it must sell to have neither profit nor loss, if the number of grey bags sold is 6,400 bags. |
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Answer» Loss on 1 bag grey cement bag = Rs -5 Loss on 6400 bag grey cement =Rs -5 × 6400 = Rs -32000 Let number of bags of white cement = n profit on 1 bag white cement = Rs 8 Profit on n bags white cement = Rs 8n ∴ Total profit / loss = 0 Total profit + Total loss = 0 8n + (-32000) = 0 8n – 32000 = 0 ⇒ 8n = 32000 n = \(\frac{8000}{8}\) n = 4000 |
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| 100. |
Sirisha has ₹25, she purchased certain items for ₹2, ₹8, ₹17 then the remaining money with her? A) – ₹ 2 B) ₹ 2 C) – ₹ 3D) None |
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Answer» Correct option is A) – ₹ 2 Remaining money with Sirisha = Rs 25 - Rs.(2 + 8 + 17) = Rs. (25 - 27) = -Rs. 2 Correct option is A) – ₹ 2 |
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