213 + Interview Questions in Intensity Transformations And Spatial Filtering in Digital Image Processing Page 3 InterviewSolution

101.	A spatial averaging filter having all the coefficients equal is termed _________(a) A box filter(b) A weighted average filter(c) A standard average filter(d) A median filterI have been asked this question in final exam.This interesting question is from Smoothing Linear Spatial Filters topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct answer is (a) A BOX FILTER Easiest explanation: An AVERAGING filter is TERMED as box filter if all the COEFFICIENTS of spatial averaging filter are equal.

Discussion

102.	At which of the following scenarios averaging filters is/are used?(a) In the reduction of irrelevant details in an image(b) For smoothing of false contours(c) For noise reductions(d) All of the mentionedI have been asked this question in an online quiz.Origin of the question is Smoothing Linear Spatial Filters in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» RIGHT choice is (d) All of the mentioned For explanation I would say: Averaging filter or smoothing LINEAR spatial filter is used: for noise REDUCTION by REDUCING the sharp transitions in gray LEVEL, for smoothing false contours that arises because of use of insufficient number of gray values and for reduction of irrelevant data i.e. the pixels regions that are small in comparison of filter mask.

Discussion

103.	What is/are the resultant image of a smoothing filter?(a) Image with high sharp transitions in gray levels(b) Image with reduced sharp transitions in gray levels(c) All of the mentioned(d) None of the mentionedThe question was posed to me in an international level competition.My enquiry is from Smoothing Linear Spatial Filters topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right answer is (B) Image with reduced sharp TRANSITIONS in gray LEVELS For explanation I would SAY: RANDOM noise has sharp transitions in gray levels and smoothing filters does noise reduction.

Discussion

104.	Which of the following filter(s) results in a value as average of pixels in the neighborhood of filter mask.(a) Smoothing linear spatial filter(b) Averaging filter(c) Lowpass filter(d) All of the mentionedI had been asked this question in an internship interview.My doubt is from Smoothing Linear Spatial Filters in section Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» RIGHT choice is (d) All of the mentioned Explanation: The output as an average of pixels in the NEIGHBORHOOD of filter mask is SIMPLY the output of the smoothing linear spatial filter also KNOWN as averaging filter and lowpass filter.

Discussion

105.	The response of the smoothing linear spatial filter is/are __________(a) Sum of image pixel in the neighborhood filter mask(b) Difference of image in the neighborhood filter mask(c) Product of pixel in the neighborhood filter mask(d) Average of pixels in the neighborhood of filter maskThe question was posed to me in quiz.Query is from Smoothing Linear Spatial Filters in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer»

Discussion

106.	Smoothing filter is used for which of the following work(s)?(a) Blurring(b) Noise reduction(c) All of the mentioned(d) None of the mentionedThis question was posed to me during a job interview.This intriguing question comes from Smoothing Linear Spatial Filters in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct CHOICE is (C) All of the mentioned Easiest explanation: Smoothing FILTER is USED for blurring and noise REDUCTION.

Discussion

107.	Which of the following is best suited for salt-and-pepper noise elimination?(a) Average filter(b) Box filter(c) Max filter(d) Median filterThe question was asked in an internship interview.The query is from Smoothing Spacial Filters in section Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right ANSWER is (d) Median FILTER Easy EXPLANATION: Median filter is better suited than average filter for salt-and-pepper noise ELIMINATION.

Discussion

108.	What does “eliminated” refer to in median filter?(a) Force to average intensity of neighbours(b) Force to median intensity of neighbours(c) Eliminate median value of pixels(d) None of the MentionedThis question was posed to me in a national level competition.My query is from Smoothing Spacial Filters in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct ANSWER is (B) Force to median intensity of neighbours To elaborate: It REFERS to FORCING to median intensity of neighbours.

Discussion

109.	Best example for a Order-statistic filter is ____________________(a) Impulse filter(b) Averaging filter(c) Median filter(d) None of the MentionedI got this question in an online interview.My doubt stems from Smoothing Spacial Filters in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» CORRECT choice is (c) MEDIAN FILTER To explain: Median filter is the BEST KNOWN Order-statistic filter.

Discussion

110.	Impulse noise in Order-statistic filter is also called as _______________(a) Median noise(b) Bilinear noise(c) Salt and pepper noise(d) None of the MentionedThis question was posed to me in unit test.This key question is from Smoothing Spacial Filters in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct option is (c) SALT and PEPPER NOISE Explanation: It is called salt-and-pepper noise because of its appearance as WHITE and black dots superimposed on an IMAGE.

Discussion

111.	Which term is used to indicate that pixels are multiplied by different coefficients?(a) Weighted average(b) Squared average(c) Spatial average(d) None of the MentionedThe question was posed to me during an online interview.The doubt is from Smoothing Spacial Filters in section Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct OPTION is (a) Weighted average To EXPLAIN I would say: It is called weighted average since more IMPORTANCE(WEIGHT) is given to some pixels.

Discussion

112.	The non linear spacial filters whose response is based on ordering of the pixels contained is called _____________.(a) Box filter(b) Square filter(c) Gaussian filter(d) Order-statistic filterThe question was asked by my college director while I was bunking the class.This question is from Smoothing Spacial Filters in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» RIGHT CHOICE is (d) Order-statistic FILTER Explanation: It is CALLED Order-statistic filter.

Discussion

113.	A spatial averaging filter in which all coefficients are equal is called _______________.(a) Square filter(b) Neighbourhood(c) Box filter(d) Zero filterThis question was addressed to me in quiz.Origin of the question is Smoothing Spacial Filters in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct answer is (c) BOX FILTER The best I can EXPLAIN: It is called a Box filter.

Discussion

114.	What is the undesirable side effects of Averaging filters?(a) No side effects(b) Blurred image(c) Blurred edges(d) Loss of sharp transitionsThe question was posed to me by my school teacher while I was bunking the class.Asked question is from Smoothing Spacial Filters in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct ANSWER is (c) Blurred EDGES Easy explanation: Blue edges is the UNDESIRABLE side effect of Averaging filters.

Discussion

115.	Averaging filters is also known as ____________ filter.(a) Low pass(b) High pass(c) Band pass(d) None of the MentionedThis question was addressed to me in my homework.This intriguing question originated from Smoothing Spacial Filters in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» RIGHT ANSWER is (a) Low pass The best I can explain: Averaging FILTERS is ALSO known asLow pass filters.

Discussion

116.	The output of a smoothing, linear spatial filtering is a ____________ of the pixels contained in the neighbourhood of the filter mask.(a) Sum(b) Product(c) Average(d) Dot ProductI got this question in an interview.My question is based upon Smoothing Spacial Filters in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct option is (C) AVERAGE Explanation: Smoothing is simply the average of the PIXELS contained in the NEIGHBOURHOOD.

Discussion

117.	In uniform PDF, the expansion of PDF is ________________(a) Portable Document Format(b) Post Derivation Function(c) Previously Derived Function(d) Probability Density FunctionI have been asked this question in an online interview.My query is from Histogram Processing in section Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» RIGHT CHOICE is (d) Probability Density Function For EXPLANATION: PDF STANDS for Probability Density Function.

Discussion

118.	Which type of Histogram Processing is suited for minute detailed enhancements?(a) Intensive(b) Local(c) Global(d) RandomThis question was addressed to me in homework.This is a very interesting question from Histogram Processing in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» CORRECT option is (B) Local Explanation: Local HISTOGRAM Processing is used.

Discussion

119.	The type of Histogram Processing in which pixels are modified based on the intensity distribution of the image is called _______________.(a) Intensive(b) Local(c) Global(d) RandomI had been asked this question during an interview.The question is from Histogram Processing in division Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» RIGHT choice is (C) GLOBAL The best I can EXPLAIN: It is CALLED Global Histogram Processing.

Discussion

120.	To reduce computation if one utilises non-overlapping regions, it usually produces ______ effect.(a) Dimming(b) Blurred(c) Blocky(d) None of the MentionedThe question was posed to me in semester exam.I would like to ask this question from Histogram Processing topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» CORRECT CHOICE is (c) BLOCKY To ELABORATE: Utilising non-overlapping regions usually produces “Blocky” effect.

Discussion

121.	What does SEM stands for?(a) Scanning Electronic Machine(b) Self Electronic Machine(c) Scanning Electron Microscope(d) Scanning Electric MachineThe question was asked during an online exam.This interesting question is from Histogram Processing topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct choice is (c) Scanning ELECTRON Microscope The BEST EXPLANATION: SEM STANDS for Scanning Electron Microscope.

Discussion

122.	Histogram Equalisation is mainly used for ________________(a) Image enhancement(b) Blurring(c) Contrast adjustment(d) None of the MentionedThis question was addressed to me in final exam.I'm obligated to ask this question of Histogram Processing topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The CORRECT choice is (a) Image enhancement Easiest EXPLANATION: It is mainly used for Enhancement of USUALLY DARK IMAGES.

Discussion

123.	What is Histogram Matching also called as?(a) Histogram Equalisation(b) Histogram Specification(c) Histogram linearisation(d) None of the MentionedThis question was addressed to me in my homework.This interesting question is from Histogram Processing in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct CHOICE is (b) Histogram Specification Best EXPLANATION: Histogram Specification is ALSO known as Histogram Matching.

Discussion

124.	What is Histogram Equalisation also called as?(a) Histogram Matching(b) Image Enhancement(c) Histogram linearisation(d) None of the MentionedI got this question in an interview for job.This interesting question is from Histogram Processing in division Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» RIGHT CHOICE is (c) Histogram linearisation To explain: Histogram Linearisation is also KNOWN as Histogram Equalisation.

Discussion

125.	In _______ image we notice that the components of histogram are concentrated on the low side on intensity scale.(a) bright(b) dark(c) colourful(d) All of the MentionedThis question was posed to me in exam.My enquiry is from Histogram Processing in section Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» CORRECT choice is (b) dark Best explanation: Only in dark images, we notice that the COMPONENTS of histogram are concentrated on the LOW side on intensity scale.

Discussion

126.	What is the basis for numerous spatial domain processing techniques?(a) Transformations(b) Scaling(c) Histogram(d) None of the MentionedThis question was posed to me during a job interview.I'd like to ask this question from Histogram Processing topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right OPTION is (C) Histogram To EXPLAIN I would say: Histogram is the basis for numerous spatial domain processing TECHNIQUES.

Discussion

127.	In a dark image, the components of histogram are concentrated on which side of the grey scale?(a) High(b) Medium(c) Low(d) Evenly distributedThis question was posed to me in examination.My question is from Histogram Processing in division Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct ANSWER is (c) Low To explain I would say: We know that in the dark image, the components of HISTOGRAM are concentrated MOSTLY on the low i.e., dark side of the grey SCALE. Similarly, the components of histogram of the BRIGHT image are biased towards the high side of the grey scale.

Discussion

128.	Histograms are the basis for numerous spatial domain processing techniques.(a) True(b) FalseThis question was addressed to me during an interview.The above asked question is from Histogram Processing in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct choice is (a) True To explain I would SAY: Histograms are the basis for numerous SPATIAL domain PROCESSING techniques. Histogram manipulation can be used EFFECTIVELY for IMAGE enhancement.

Discussion

129.	What is the method that is used to generate a processed image that have a specified histogram?(a) Histogram linearization(b) Histogram equalization(c) Histogram matching(d) Histogram processingI had been asked this question in my homework.Origin of the question is Histogram Processing in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct ANSWER is (c) HISTOGRAM matching Easiest EXPLANATION: In particular, it is useful sometimes to be able to specify the SHAPE of the histogram that we wish the processed image to have. The method USED to generate a processed image that has a specified histogram is called histogram matching or histogram specification.

Discussion

130.	Histogram equalization or Histogram linearization is represented by of the following equation:(a) sk =∑^k j =1 nj/nk=0,1,2,……,L-1(b) sk =∑^k j =0 nj/nk=0,1,2,……,L-1(c) sk =∑^k j =0 n/njk=0,1,2,……,L-1(d) sk =∑^k j =n nj/nk=0,1,2,……,L-1I have been asked this question in a national level competition.The origin of the question is Histogram Processing topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» RIGHT choice is (b) sk =∑^k j =0 nj/nk=0,1,2,……,L-1 The best EXPLANATION: A plot of pk_ (rk) versus r_k is called a HISTOGRAM .The transformation (mapping) given in sk =∑^k j =0)k nj/n k=0,1,2,……,L-1 is called histogram equalization or histogram LINEARIZATION.

Discussion

131.	The probability density function p_s (s) of the transformed variable s can be obtained by using which of the following formula?(a) p_s (s)=p_r (r)\|dr/ds\|(b) p_s (s)=p_r (r)\|ds/dr\|(c) p_r (r)=p_s (s)\|dr/ds\|(d) p_s (s)=p_r (r)\|dr/dr\|The question was asked by my college professor while I was bunking the class.This is a very interesting question from Histogram Processing in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct choice is (a) p_s (s)=p_r (r)\|dr/ds\| The explanation: The probability DENSITY function p_s (s) of the transformed variable s can be obtained using a BASIC FORMULA: p_s (s)=p_r (r)\|dr/ds\| Thus, the probability density function of the transformed variable, s, is determined by the gray-level PDF of the input image and by the chosen TRANSFORMATION function.

Discussion

132.	A transformation function of particular importance in image processing is represented in which of the following form?(a) s=T(r)=∫0 ^(2r)pr (ω)dω(b) s=T(r)=∫0 ^(r-1)pr (ω)dω(c) s=T(r)=∫0 ^(r/2)pr (ω)dω(d) s=T(r)=∫0 pr (ω)dωThis question was posed to me during an internship interview.This question is from Histogram Processing in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct option is (d) s=T(r)=∫0 PR (ω)dω Easiest explanation: A transformation function of particular importance in image processing has the form: s=T(r)=∫0 ^r pr(ω)dw, where ω is a DUMMY variable of integration. The right side of is RECOGNIZED as the cumulative distribution function (CDF) of random variable r.

Discussion

133.	The inverse transformation from s back to r is denoted as:(a) s=T^-1(r) for 0≤s≤1(b) r=T^-1(s) for 0≤r≤1(c) r=T^-1(s) for 0≤s≤1(d) r=T^-1(s) for 0≥s≥1The question was asked in an online interview.My question is taken from Histogram Processing in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right answer is (C) R=T^-1(s) for 0≤s≤1 The BEST explanation: The INVERSE transformation from s back to r is denoted by: r=T-1(s) for 0≤s≤1.

Discussion

134.	How is the expression represented for the normalized histogram?(a) p(r_k )=n_k(b) p(r_k )=n_k/n(c) p(r_k)=nn_k(d) p(r_k )=n/n_kThe question was posed to me by my school teacher while I was bunking the class.Question is taken from Histogram Processing in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct option is (b) p(r_k )=n_k/n To elaborate: It is COMMON practice to NORMALIZE a histogram by dividing each of its values by the TOTAL number of pixels in the image, denoted by n. Thus, a normalized histogram is given by p(rk )=nk/n, for k=0,1,2…..L-1. Loosely SPEAKING, p(rk ) gives an estimate of the probability of occurrence of gray-level rk. Note that the sum of all components of a normalized histogram is EQUAL to 1.

Discussion

135.	The histogram of a digital image with gray levels in the range [0, L-1] is represented by a discrete function:(a) h(r_k)=n_k(b) h(r_k )=n/n_k(c) p(r_k )=n_k(d) h(r_k )=n_k/nI had been asked this question by my school principal while I was bunking the class.I would like to ask this question from Histogram Processing in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right choice is (a) H(r_k)=n_k Easiest explanation: The histogram of a digital image with gray LEVELS in the RANGE [0, L-1] is a discrete FUNCTION h(RK )=nk, where rk is the kth gray level and nkis the number of pixels in the image having gray level rk.

Discussion

136.	The function that contains a single 1 with the rest being 0s is called ______________(a) Identity function(b) Inverse function(c) Discrete unit impulse(d) None of the MentionedThis question was posed to me during an online exam.This key question is from Fundamentals of Spatial Filtering topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» CORRECT answer is (C) Discrete UNIT impulse The best explanation: It is called Discrete unit impulse.

Discussion

137.	Which of the following involves Correlation?(a) Matching(b) Key-points(c) Blobs(d) None of the Mentioned.I have been asked this question by my school principal while I was bunking the class.My doubt is from Fundamentals of Spatial Filtering in division Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right OPTION is (a) Matching Best EXPLANATION: CORRELATION is applied in FINDING MATCHES.

Discussion

138.	An example of a continuous function of two variables is __________(a) Intensity function(b) Contrast stretching(c) Gaussian functionI got this question in an online interview.The query is from Fundamentals of Spatial Filtering in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer»

Discussion

139.	Convolution and Correlation are functions of _____________(a) Distance(b) Time(c) Intensity(d) DisplacementI have been asked this question in a job interview.This key question is from Fundamentals of Spatial Filtering in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct OPTION is (d) Displacement To explain: Convolution and CORRELATION are FUNCTIONS of displacement.

Discussion

140.	What is the difference between Convolution and Correlation?(a) Image is pre-rotated by 180 degree for Correlation(b) Image is pre-rotated by 180 degree for Convolution(c) Image is pre-rotated by 90 degree for Correlation(d) Image is pre-rotated by 90 degree for ConvolutionThe question was asked during an interview.The above asked question is from Fundamentals of Spatial Filtering in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The CORRECT choice is (b) IMAGE is pre-ROTATED by 180 degree for CONVOLUTION To explain: Convolution is the same as Correlation except that the image must be rotated by 180 degrees INITIALLY.

Discussion

141.	What is the process of moving a filter mask over the image and computing the sum of products at each location called as?(a) Convolution(b) Correlation(c) Linear spatial filtering(d) Non linear spatial filteringI have been asked this question during an internship interview.This intriguing question originated from Fundamentals of Spatial Filtering topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The CORRECT CHOICE is (b) CORRELATION Explanation: The process is CALLED as Correlation.

Discussion

142.	What is required to generate an M X N linear spatial filter?(a) MN mask coefficients(b) M+N coordinates(c) MN spatial coefficients(d) None of the MentionedThis question was addressed to me by my college professor while I was bunking the class.My question comes from Fundamentals of Spatial Filtering in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct CHOICE is (a) MN mask COEFFICIENTS Explanation: To GENERATE an M X N LINEAR spatial filter MN mask coefficients MUST be specified.

Discussion

143.	The standard deviation controls ___________ of the bell (2-D Gaussian function of bell shape).(a) Size(b) Curve(c) Tightness(d) None of the MentionedThis question was posed to me during an interview.Question is taken from Fundamentals of Spatial Filtering topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» CORRECT option is (C) Tightness Explanation: The standard deviation CONTROLS “tightness” of the BELL.

Discussion

144.	A filter that passes low frequencies is _____________(a) Band pass filter(b) High pass filter(c) Low pass filter(d) None of the MentionedI have been asked this question during an interview.My question comes from Fundamentals of Spatial Filtering in portion Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct choice is (c) LOW pass filter For EXPLANATION I WOULD SAY: Low pass filter passes low frequencies.

Discussion

145.	What is accepting or rejecting certain frequency components called as?(a) Filtering(b) Eliminating(c) Slicing(d) None of the MentionedThis question was addressed to me in semester exam.My enquiry is from Fundamentals of Spatial Filtering in division Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» The correct choice is (a) Filtering The EXPLANATION: Filtering is the PROCESS of ACCEPTING or REJECTING certain FREQUENCY components.

Discussion

146.	How do you bring out more of the skeletal detail from a Nuclear Whole Body Bone Scan?(a) Sharpening(b) Enhancing(c) Transformation(d) None of the mentionedThis question was addressed to me by my school teacher while I was bunking the class.My question is taken from Combining Spatial Enhancements Methods topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right option is (a) SHARPENING Best EXPLANATION: Sharpening is used to BRING out more of the skeletal DETAIL.

Discussion

147.	Final step of enhancement lies in _____________ of the sharpened image.(a) Increase range of contrast(b) Increase range of brightness(c) Increase dynamic range(d) None of the mentionedThe question was asked in homework.Question is from Combining Spatial Enhancements Methods topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» RIGHT answer is (C) INCREASE dynamic RANGE Easiest explanation: Increasing the dynamic range of the sharpened image is the final step in enhancement.

Discussion

148.	An alternate approach to median filtering is ______________(a) Use a mask(b) Gaussian filter(c) Sharpening(d) Laplacian filterI got this question in an interview for job.The above asked question is from Combining Spatial Enhancements Methods in section Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right OPTION is (a) USE a mask For explanation I WOULD SAY: Using a mask, formed from the smoothed version of the gradient image, can be used for median FILTERING.

Discussion

149.	_____________ is used to detect diseases such as bone infection and tumors.(a) MRI Scan(b) PET Scan(c) Nuclear Whole Body Scan(d) X-RayI got this question in an online quiz.This interesting question is from Combining Spatial Enhancements Methods topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Right option is (C) NUCLEAR WHOLE Body Scan For EXPLANATION I would say: Nuclear Whole Body Scan is used to detect diseases such as BONE infection and tumors

Discussion

150.	Which of the following fails to work on dark intensity distributions?(a) Laplacian Transform(b) Gaussian Transform(c) Histogram Equalization(d) Power-law TransformationI had been asked this question during an online exam.The origin of the question is Combining Spatial Enhancements Methods topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing
Answer» Correct option is (C) HISTOGRAM Equalization Best explanation: Histogram Equalization FAILS to WORK on dark intensity DISTRIBUTIONS.

Discussion

Explore topic-wise InterviewSolutions in .

Histograms are the basis for numerous spatial domain processing techniques.(a) True(b) FalseThis question was addressed to me during an interview.The above asked question is from Histogram Processing in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing