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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

51.

If unsharp masking can be implemented directly in frequency domain by using a composite filter: Hhp(u, v) = 1 – Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. Then, the composite filter for High-boost filtering is __________(a) Hhb(u, v) = 1 – Hhp(u, v)(b) Hhb(u, v) = 1 + Hhp(u, v)(c) Hhb(u, v) = (A-1) – Hhp(u, v), A is a constant(d) Hhb(u, v) = (A-1) + Hhp(u, v), A is a constantThis question was addressed to me in exam.The above asked question is from Unsharp Masking, High-boost filtering and Emphasis Filtering in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT option is (d) Hhb(u, v) = (A-1) + Hhp(u, v), A is a constant

Easiest EXPLANATION: For given COMPOSITE filter of unsharp MASKING Hhp(u, v) = 1 – Hlp(u, v), the composite filter for High-boost filtering is Hhb(u, v) = (A-1) + Hhp(u, v).
52.

To accentuate the contribution to enhancement made by high-frequency components, which of the following method(s) should be more appropriate to apply?(a) Multiply the highpass filter by a constant(b) Add an offset to the highpass filter to prevent eliminating zero frequency term by filter(c) All of the mentioned combined and applied(d) None of the mentionedI have been asked this question in my homework.This interesting question is from Unsharp Masking, High-boost filtering and Emphasis Filtering in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right CHOICE is (c) All of the mentioned combined and applied

The BEST explanation: To accentuate the CONTRIBUTION to enhancement made by high-frequency components, we have to multiply the HIGHPASS FILTER by a constant and add an offset to the highpass filter to prevent eliminating zero frequency term by filter.

53.

The frequency domain Laplacian is closer to which of the following mask?(a) Mask that excludes the diagonal neighbors(b) Mask that excludes neighbors in 4-adjacancy(c) Mask that excludes neighbors in 8-adjacancy(d) None of the mentionedI have been asked this question in homework.Origin of the question is Unsharp Masking, High-boost filtering and Emphasis Filtering in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right OPTION is (a) MASK that excludes the diagonal NEIGHBORS

Best explanation: The frequency DOMAIN LAPLACIAN is closer to mask that excludes the diagonal neighbors.

54.

Unsharp masking can be implemented directly in frequency domain by using a filter: Hhp(u, v) = 1 – Hlp(u, v), where Hlp(u, v) the transfer function of a lowpass filter. What kind of filter is Hhp(u, v)?(a) Composite filter(b) M-derived filter(c) Constant k filter(d) None of the mentionedThe question was asked in homework.This is a very interesting question from Unsharp Masking, High-boost filtering and Emphasis Filtering topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct choice is (a) Composite filter

To explain I would SAY: UNSHARP masking can be IMPLEMENTED directly in frequency DOMAIN by using a composite filter: Hhp(u, v) = 1 – Hlp(u, v).

55.

If, Fhp(u, v)=F(u, v) – Flp(u, v) and Flp(u, v) = Hlp(u, v)F(u, v), where F(u, v) is the image in frequency domain with Fhp(u, v) its highpass filtered version, Flp(u, v) its lowpass filtered component andHlp(u, v) the transfer function of a lowpass filter. Then, unsharp masking can be implemented directly in frequency domain by using a filter. Which of the following is the required filter?(a) Hhp(u, v) = Hlp(u, v)(b) Hhp(u, v) = 1 + Hlp(u, v)(c) Hhp(u, v) = – Hlp(u, v)(d) Hhp(u, v) = 1 – Hlp(u, v)I had been asked this question during an interview.My query is from Unsharp Masking, High-boost filtering and Emphasis Filtering in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct choice is (d) Hhp(u, v) = 1 – Hlp(u, v)

For explanation: Unsharp masking can be implemented DIRECTLY in frequency DOMAIN by USING a composite FILTER: Hhp(u, v) = 1 – Hlp(u, v).

56.

High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant and flp(x, y) is the lowpass filtered version of f(x, y). Which of the following fact validates if A=1?(a) High-boost filtering reduces to regular Highpass filtering(b) High-boost filtering reduces to regular Lowpass filtering(c) All of the mentioned(d) None of the mentionedI got this question during an interview.This intriguing question originated from Unsharp Masking, High-boost filtering and Emphasis Filtering topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right CHOICE is (a) HIGH-boost filtering reduces to regular Highpass filtering

The EXPLANATION: High boost filtered IMAGE is MODIFIED as: fhb = (A-1) f(x, y) +f(x, y) – flp(x, y)

i.e.fhb = (A-1) f(x, y) + fhp(x, y). So, when A=1, High-boost filtering reduces to regular Highpass filtering.

57.

Which of the following is/ are a generalized form of unsharp masking?(a) Lowpass filtering(b) High-boost filtering(c) Emphasis filtering(d) All of the mentionedThe question was asked in an international level competition.Question is from Unsharp Masking, High-boost filtering and Emphasis Filtering topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right answer is (b) High-boost filtering

To ELABORATE: UNSHARP masking is defined as “obtaining a highpass filtered image by SUBTRACTING from the given image a lowpass filtered version of itself” while high-boost filtering GENERALIZES it by multiplying the input image by a constant, say A≥1.

58.

High boost filtered image is expressed as: fhb = A f(x, y) – flp(x, y), where f(x, y) the input image, A is a constant and flp(x, y) is the lowpass filtered version of f(x, y). Which of the following fact(s) validates if A increases past 1?(a) The contribution of the image itself becomes more dominant(b) The contribution of the highpass filtered version of image becomes less dominant(c) All of the mentioned(d) None of the mentionedThis question was addressed to me during an interview.I need to ask this question from Unsharp Masking, High-boost filtering and Emphasis Filtering in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct option is (c) All of the mentioned

The EXPLANATION: High BOOST filtered image is modified as: fhb = (A-1) F(x, y) +f(x, y) – FLP(x, y)

i.e.fhb = (A-1) f(x, y) + fhp(x, y). So, when A>1, the contribution of the image itself becomes more dominant over the highpass filtered version of image.

59.

Using the feature of reciprocal relationship of filter in spatial domain and corresponding filter in frequency domain along with convolution, which of the following fact is true?(a) The narrower the frequency domain filter more severe is the ringing(b) The wider the frequency domain filter more severe is the ringing(c) The narrower the frequency domain filter less severe is the ringing(d) None of the mentionedI have been asked this question in an online interview.My question comes from Smoothing Frequency-Domain Filters topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct choice is (a) The narrower the frequency DOMAIN filter more severe is the ringing

To ELABORATE: The characteristics feature of reciprocal relationship says that the narrower the frequency domain filter becomes it attenuates more low frequency component and so INCREASES blurring and more severe becomes the ringing.

60.

In frequency domain terminology, which of the following is defined as “obtaining a highpass filtered image by subtracting from the given image a lowpass filtered version of itself”?(a) Emphasis filtering(b) Unsharp masking(c) Butterworth filtering(d) None of the mentionedThe question was asked in an online quiz.Question is taken from Unsharp Masking, High-boost filtering and Emphasis Filtering in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» RIGHT CHOICE is (b) UNSHARP masking

The explanation: In frequency domain TERMINOLOGY unsharp masking is defined as “obtaining a HIGHPASS filtered image by subtracting from the given image a lowpass filtered version of itself”.
61.

What is the relation for the components of ideal lowpass filter and the image enhancement?(a) The concentric component is primarily responsible for blurring(b) The center component is primarily for the ringing characteristic of ideal filter(c) All of the mentioned(d) None of the mentionedI got this question in final exam.My question is based upon Smoothing Frequency-Domain Filters in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right choice is (d) None of the mentioned

The EXPLANATION is: The center COMPONENT of ideal LOWPASS filter is primarily RESPONSIBLE for blurring while, concentric component is primarily for the ringing CHARACTERISTIC of ideal filter.

62.

The characteristics of the lowpass filter h(x, y) is/are_________(a) Has a dominant component at origin(b) Has a concentric, circular components about the center component(c) All of the mentioned(d) None of the mentionedThe question was asked by my college director while I was bunking the class.My question is based upon Smoothing Frequency-Domain Filters topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The CORRECT option is (c) All of the mentioned

Easy explanation: the lowpass FILTER has two different characteristics: one is a dominant COMPONENT at origin and other one is a CONCENTRIC, circular components about the center component.

63.

Butterworth lowpass filter has a parameter, filter order, determining its functionality as very sharp or very smooth filter function or an intermediate filter function. If the parameter value is of lower order, the filter approaches to which of the following filter(s)?(a) Ideal lowpass filter(b) Gaussian lowpass filter(c) All of the mentioned(d) None of the mentionedI have been asked this question during an internship interview.My doubt stems from Smoothing Frequency-Domain Filters topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The CORRECT choice is (b) Gaussian lowpass filter

Explanation: For high VALUE of filter ORDER Butterworth lowpass filter behaves as Ideal lowpass filter, while for lower order value it has a smoother FORM behaving LIKE Gaussian lowpass filter.

64.

In an ideal lowpass filter case, what is the relation between the filter radius and the blurring effect caused because of the filter?(a) Filter size is directly proportional to blurring caused because of filter(b) Filter size is inversely proportional to blurring caused because of filter(c) There is no relation between filter size and blurring caused because of it(d) None of the mentionedThe question was asked in an interview for job.This is a very interesting question from Smoothing Frequency-Domain Filters in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right answer is (b) FILTER size is inversely proportional to BLURRING caused because of filter

Easiest explanation: Increase in filter size, removes LESS power from the image and so less SEVERE blurring occurs.

65.

In a filter, all the frequencies inside a circle of radius D0 are not attenuated while all frequencies outside circle are completely attenuated. The D0 is the specified nonnegative distance from origin of the Fourier transform. Which of the following filter(s) characterizes the same?(a) Ideal filter(b) Butterworth filter(c) Gaussian filter(d) All of the mentionedThis question was addressed to me in unit test.Question is taken from Smoothing Frequency-Domain Filters topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct ANSWER is (a) Ideal filter

For explanation I WOULD say: In ideal filter all the frequencies inside a CIRCLE of radius D0 are not attenuated while all frequencies OUTSIDE the circle are completely attenuated.

66.

Butterworth lowpass filter has a parameter, filter order, determining its functionality as very sharp or very smooth filter function or an intermediate filter function. If the parameter value is very high, the filter approaches to which of the following filter(s)?(a) Ideal lowpass filter(b) Gaussian lowpass filter(c) All of the mentioned(d) None of the mentionedThis question was posed to me during an online interview.The question is from Smoothing Frequency-Domain Filters topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct option is (a) Ideal lowpass FILTER

The BEST explanation: For high value of filter ORDER Butterworth lowpass filter behaves as Ideal lowpass filter, while for LOWER order value it has a smoother form behaving like GAUSSIAN lowpass filter.

67.

Which of the following lowpass filters is/are covers the range of very smooth filter function?(a) Ideal lowpass filters(b) Butterworth lowpass filter(c) Gaussian lowpass filter(d) All of the mentionedI had been asked this question in examination.My question comes from Smoothing Frequency-Domain Filters topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT OPTION is (a) Ideal lowpass filters

To ELABORATE: Gaussian lowpass FILTER covers the RANGE of very smooth filter functioning of lowpass filters.
68.

Which of the following lowpass filters is/are covers the range of very sharp filter function?(a) Ideal lowpass filters(b) Butterworth lowpass filter(c) Gaussian lowpass filter(d) All of the mentionedI got this question during a job interview.Enquiry is from Smoothing Frequency-Domain Filters in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right choice is (a) IDEAL lowpass filters

To explain I WOULD say: Ideal lowpass FILTER COVERS the range of very SHARP filter functioning of lowpass filters.

69.

Which of the following is/are considered as type(s) of lowpass filters?(a) Ideal(b) Butterworth(c) Gaussian(d) All of the mentionedThis question was posed to me during an interview.This intriguing question originated from Smoothing Frequency-Domain Filters topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right option is (d) All of the mentioned

Explanation: Lowpass FILTERS are considered of THREE TYPES: IDEAL, Butterworth, and GAUSSIAN.

70.

Smoothing in frequency domain is achieved by attenuating which of the following component in the transform of a given image?(a) Attenuating a range of high-frequency components(b) Attenuating a range of low-frequency components(c) All of the mentioned(d) None of the mentionedI had been asked this question by my college professor while I was bunking the class.Question is from Smoothing Frequency-Domain Filters topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» RIGHT answer is (a) Attenuating a RANGE of high-frequency components

The best I can explain: SINCE, EDGES and sharp transitions contribute significantly to high-frequency contents in the gray level of an image. So, smoothing is DONE by attenuating a range of high-frequency components.
71.

Using the feature of reciprocal relationship of filter in spatial domain and corresponding filter in frequency domain, which of the following fact is true?(a) The narrower the frequency domain filter results in increased blurring(b) The wider the frequency domain filter results in increased blurring(c) The narrower the frequency domain filter results in decreased blurring(d) None of the mentionedI had been asked this question in class test.This intriguing question originated from Filtering in Frequency Domain topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct answer is (a) The NARROWER the FREQUENCY DOMAIN filter results in increased blurring

Explanation: The characteristics feature of reciprocal relationship says that the narrower the frequency domain filter becomes it ATTENUATES more low frequency component and so INCREASES blurring.

72.

A frequency domain filter of the corresponding filter in spatial domain can be obtained by applying which of the following operation(s) on filter in spatial domain?(a) Fourier transform(b) Inverse Fourier transform(c) None of the mentioned(d) All of the mentionedThe question was posed to me in quiz.This intriguing question originated from Filtering in Frequency Domain in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct OPTION is (a) Fourier TRANSFORM

Easiest EXPLANATION: Filters in spatial domain and frequency domain has a Fourier transform PAIR relation.A frequency domain filter of the corresponding filter in spatial domain can be OBTAINED by applying inverse Fourier transform on spatial domain filter.

73.

Which of the following filtering is done in frequency domain in correspondence to lowpass filtering in spatial domain?(a) Gaussian filtering(b) Unsharp mask filtering(c) High-boost filtering(d) None of the mentionedI had been asked this question during an internship interview.I would like to ask this question from Filtering in Frequency Domain in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT answer is (a) Gaussian filtering

The explanation is: A plot of Gaussian filter in frequency domain can be RECOGNIZED SIMILAR to lowpass filter in spatial domain.
74.

A spatial domain filter of the corresponding filter in frequency domain can be obtained by applying which of the following operation(s) on filter in frequency domain?(a) Fourier transform(b) Inverse Fourier transform(c) None of the mentioned(d) All of the mentionedThis question was posed to me in unit test.My question is based upon Filtering in Frequency Domain in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right option is (B) Inverse Fourier transform

The best I can explain: FILTERS in spatial domain and FREQUENCY domain has a Fourier transform pair relation.A spatial domain filter of the CORRESPONDING filter in frequency domain can be OBTAINED by applying inverse Fourier transform on frequency domain filter.

75.

The feature(s) of a highpass filtered image is/are___________(a) Have less gray-level variation in smooth areas(b) Emphasized transitional gray-level details(c) An overall sharper image(d) All of the mentionedThis question was addressed to me during an interview.My question is based upon Filtering in Frequency Domain topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right choice is (d) All of the mentioned

Explanation: A HIGHPASS filter attenuates low frequency so have less gray-level variation in smooth areas, and ALLOWS high frequencies so have EMPHASIZED TRANSITIONAL gray-level details, resulting in a SHARPER image.

76.

Which of the following filter have a less sharp detail than the original image because of attenuation of high frequencies?(a) Highpass filter(b) Lowpass filter(c) Zero-phase-shift filter(d) None of the mentionedThe question was posed to me in a job interview.My doubt stems from Filtering in Frequency Domain in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct answer is (b) LOWPASS filter

The best explanation: A lowpass filter attenuates high so the image has less SHARP DETAILS.

77.

Which of the following filter(s) attenuates low frequency while passing high frequencies of an image?(a) Unsharp mask filter(b) Highpass filter(c) Zero-phase-shift filter(d) All of the mentionedI had been asked this question in a job interview.The origin of the question is Filtering in Frequency Domain topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»
78.

To set the average value of an image zero, which of the following term would be set 0 in the frequency domain and the inverse transformation is done, where F(u, v) is Fourier transformed function of f(x, y)?(a) F(0, 0)(b) F(0, 1)(c) F(1, 0)(d) None of the mentionedI had been asked this question in semester exam.This key question is from Filtering in Frequency Domain in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right option is (a) F(0, 0)

BEST explanation: For an image f(x, y), the FOURIER transform at origin of an image, F(0, 0), is equal to the average VALUE of the image.

79.

What is the name of the filter that is used to turn the average value of a processed image zero?(a) Unsharp mask filter(b) Notch filter(c) Zero-phase-shift-filter(d) None of the mentionedI got this question in an interview for job.My doubt is from Filtering in Frequency Domain in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct answer is (b) NOTCH FILTER

Best EXPLANATION: Notch filter sets F (0, 0), to zero, hence setting up the average value of image zero. The filter is named so, because it is a constant function with a notch at origin and so is able to SET F (0, 0) to zero leaving out other values.

80.

Which of the following filter(s) attenuates high frequency while passing low frequencies of an image?(a) Unsharp mask filter(b) Lowpass filter(c) Zero-phase-shift filter(d) All of the mentionedI had been asked this question during an interview.The question is from Filtering in Frequency Domain in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»
81.

In neighborhood operation for spatial filtering if a square mask of size n*n is used it is restricted that the center of mask must be at a distance ≥ (n – 1)/2 pixels from border of image, what happens to the resultant image?(a) The resultant image will be of same size as original image(b) The resultant image will be a little larger size than original image(c) The resultant image will be a little smaller size than original image(d) None of the mentionedThe question was posed to me in an internship interview.The origin of the question is Spatial Filtering topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct answer is (C) The resultant image will be a little smaller SIZE than ORIGINAL image

Explanation: If the center of mask MUST be at a DISTANCE ≥ (n – 1)/2 pixels from border of image, the border pixels won’t get processed under mask and so the resultant image would be of smaller size.

82.

What is the name of the filter that multiplies two functions F(u, v) and H(u, v), where F has complex components too since is Fourier transformed function of f(x, y), in an order that each component of H multiplies both real and complex part of corresponding component in F?(a) Unsharp mask filter(b) High-boost filter(c) Zero-phase-shift-filter(d) None of the mentionedThe question was posed to me during an interview.I would like to ask this question from Filtering in Frequency Domain topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct choice is (c) Zero-phase-shift-filter

The explanation is: Zero-phase-shift-filter multiplies two functions F(u, v) and H(u, v), where F has complex components too SINCE is FOURIER TRANSFORMED function of f(x, y), in an order that each component of H multiplies both REAL and complex part of corresponding component in F.

83.

Which of the following is/are used as basic function in nonlinear filter for noise reduction?(a) Computation of variance(b) Computation of median(c) All of the mentioned(d) None of the mentionedThe question was asked in my homework.This is a very interesting question from Spatial Filtering topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct CHOICE is (B) Computation of median

To explain I would say: Computation of median gray-level value in the neighborhood is the basic function of NONLINEAR FILTER for noise REDUCTION.

84.

Which of the following fact(s) is/are true for the relationship between high frequency component of Fourier transform and the rate of change of gray levels?(a) Moving away from the origin of transform the high frequency corresponds to smooth gray level variation(b) Moving away from the origin of transform the higher frequencies corresponds to abrupt change in gray level(c) All of the mentioned(d) None of the mentionedI had been asked this question in an interview for internship.My query is from Filtering in Frequency Domain topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct choice is (b) Moving away from the origin of TRANSFORM the higher FREQUENCIES corresponds to abrupt CHANGE in gray level

Explanation: Moving away from the origin of transform the LOW FREQUENCY corresponds to the slowly varying components in an image. Moving further away from origin the higher frequencies corresponds to faster gray level changes.

85.

Which of the following fact(s) is/are true for the relationship between low frequency component of Fourier transform and the rate of change of gray levels?(a) Moving away from the origin of transform the low frequency corresponds to smooth gray level variation(b) Moving away from the origin of transform the low frequencies corresponds to abrupt change in gray level(c) All of the mentioned(d) None of the mentionedThis question was posed to me during an interview.This interesting question is from Filtering in Frequency Domain in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right choice is (C) All of the mentioned

To explain: Moving AWAY from the origin of transform the low frequency corresponds to the slowly varying components in an image. Moving further away from origin the higher frequencies corresponds to faster GRAY level changes.

86.

Which of the following is/are a nonlinear operation?(a) Computation of variance(b) Computation of median(c) All of the mentioned(d) None of the mentionedThe question was asked in examination.The origin of the question is Spatial Filtering in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The CORRECT option is (c) All of the mentioned

Explanation: COMPUTATION of VARIANCE as well as median comes under nonlinear OPERATION.

87.

In linear spatial filtering, what is the pixel of the image under mask corresponding to the mask coefficient w (1, -1), assuming a 3*3 mask?(a) f (x, -y)(b) f (x + 1, y)(c) f (x, y – 1)(d) f (x + 1, y – 1)The question was asked in final exam.This interesting question is from Spatial Filtering in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT CHOICE is (d) f (X + 1, y – 1)

The best explanation: The pixel corresponding to mask coefficient (a 3*3 mask) w (0, 0) is f (x, y), and so for w (1, -1) is f (x + 1, y – 1).
88.

The response for linear spatial filtering is given by the relationship __________(a) Sum of filter coefficient’s product and corresponding image pixel under filter mask(b) Difference of filter coefficient’s product and corresponding image pixel under filter mask(c) Product of filter coefficient’s product and corresponding image pixel under filter mask(d) None of the mentionedThe question was asked in homework.Origin of the question is Spatial Filtering topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right choice is (a) Sum of filter coefficient’s product and corresponding image pixel under filter mask

Easiest explanation: In SPATIAL filtering the mask is moved from POINT to point and at each point the response is CALCULATED using a PREDEFINED relationship. The relationship in linear spatial filtering is GIVEN by: the Sum of filter coefficient’s product and corresponding image pixel in area under filter mask.

89.

In neighborhood operations working is being done with the value of image pixel in the neighborhood and the corresponding value of a subimage that has same dimension as neighborhood. The subimage is referred as _________(a) Filter(b) Mask(c) Template(d) All of the mentionedThis question was addressed to me in a national level competition.My enquiry is from Spatial Filtering topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct answer is (d) All of the mentioned

Explanation: Working in neighborhood operations is DONE with the VALUE of a subimage having same dimension as neighborhood corresponding to the value in the image PIXEL. The subimage is called as filter, MASK, TEMPLATE, kernel or window.

90.

The median filter also represents which of the following ranked set of numbers?(a) 100th percentile(b) 0th percentile(c) 50th percentile(d) None of the mentionedThis question was addressed to me at a job interview.This interesting question is from Smoothing Nonlinear Spatial Filter in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The CORRECT choice is (c) 50th percentile

The explanation: Since the median filter forces median intensity to the PIXEL which is ALMOST the LARGEST value in the middle of the list of values as PER the ranking, so represents a 50th percentile ranked set of numbers.

91.

Which of the following are forced to the median intensity of the neighbors by n*n median filter?(a) Isolated cluster of pixels that are light or dark in comparison to their neighbors(b) Isolated cluster of pixels whose area is less than one-half the filter area(c) All of the mentioned(d) None of the mentionedThis question was posed to me during a job interview.The above asked question is from Smoothing Nonlinear Spatial Filter in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right choice is (C) All of the mentioned

The EXPLANATION: The isolated cluster pixel value doesn’t come as a median value and since are EITHER are light or dark as compared to neighbors, so are forced with median intensity of neighbors that aren’t EVEN close to their original value and so are sometimes termed “eliminated”.

If the area of such isolated PIXELS are < n2/2, that is again the pixel value won’t be a median value and so are eliminated.

Larger cluster pixels value are more pronounced to be a median value, so are considerably less forced to median intensity.

92.

Which of the following filter represents a 0th percentile set of numbers?(a) Max filter(b) Mean filter(c) Median filter(d) None of the mentionedThis question was posed to me in an interview for job.The origin of the question is Smoothing Nonlinear Spatial Filter in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT choice is (d) None of the mentioned

To elaborate: A min filter SINCE PROVIDES the minimum value in the image, so represents a 0th percentile SET of numbers.
93.

Which filter(s) used to find the brightest point in the image?(a) Median filter(b) Max filter(c) Mean filter(d) All of the mentionedThe question was posed to me in unit test.My question is based upon Smoothing Nonlinear Spatial Filter in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right answer is (b) Max filter

The EXPLANATION is: A max filter gives the BRIGHTEST point in an image and so is USED.

94.

While performing the median filtering, suppose a 3*3 neighborhood has value (10, 20, 20, 20, 15, 20, 20, 25, 100), then what is the median value to be given to the pixel under filter?(a) 15(b) 20(c) 100(d) 25The question was posed to me during an online interview.My question is taken from Smoothing Nonlinear Spatial Filter in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct option is (b) 20

For explanation I would say: The values are FIRST sorted and so turns out to (10, 15, 20, 20, 20, 20, 20, 25, and 100). For a 3*3 NEIGHBORHOOD the 5th LARGEST value is the MEDIAN, and so is 20.

95.

An image contains noise having appearance as black and white dots superimposed on the image. Which of the following noise(s) has the same appearance?(a) Salt-and-pepper noise(b) Gaussian noise(c) All of the mentioned(d) None of the mentionedI have been asked this question in semester exam.This intriguing question comes from Smoothing Nonlinear Spatial Filter in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right option is (C) All of the mentioned

The explanation: An impulse noise has an appearance as black and white dots superimposed on the IMAGE. This is also KNOWN as Salt-and-pepper noise.

96.

Which of the following filter(s) has the response in which the central pixel value is replaced by value defined by ranking the pixel in the image encompassed by filter?(a) Order-Statistic filters(b) Non-linear spatial filters(c) Median filter(d) All of the mentionedThe question was posed to me in an interview for job.The query is from Smoothing Nonlinear Spatial Filter in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

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Right option is (d) All of the mentioned

Explanation: An Order-Statistic FILTERS also CALLED non-linear spatial filters, RESPONSE is based on ranking the pixel in the image encompassed by filter that replaces the CENTRAL pixel value. A Median filter is an example of such filters.

97.

Two filters of similar size are used for smoothing image having impulse noise. One is median filter while the other is a linear spatial filter. Which would the blurring effect of both?(a) Median filter effects in considerably less blurring than the linear spatial filters(b) Median filter effects in considerably more blurring than the linear spatial filters(c) Both have the same blurring effect(d) All of the mentionedI got this question in an interview for job.This key question is from Smoothing Nonlinear Spatial Filter in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

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Correct choice is (a) Median filter EFFECTS in considerably less blurring than the LINEAR spatial filters

For explanation: For IMPULSE NOISE, median filter is much effective for noise reduction and causes considerably less blurring than the linear spatial filters.

98.

Is it true or false that “the original pixel value is included while computing the median using gray-levels in the neighborhood of the original pixel in median filter case”?(a) True(b) FalseThis question was posed to me during an online interview.This question is from Smoothing Nonlinear Spatial Filter in division Intensity Transformations and Spatial Filtering of Digital Image Processing

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The CORRECT answer is (a) True

The best EXPLANATION: A MEDIAN FILTER the pixel value is replaced by median of the gray-level in the neighborhood of that pixel and also the original pixel value is included while computing the median.

99.

What is the relation between blurring effect with change in filter size?(a) Blurring increases with decrease of the size of filter size(b) Blurring decrease with decrease of the size of filter size(c) Blurring decrease with increase of the size of filter size(d) Blurring increases with increase of the size of filter sizeThe question was posed to me in an interview for internship.This is a very interesting question from Smoothing Linear Spatial Filters topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

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Correct answer is (d) Blurring increases with increase of the size of FILTER size

Explanation: USING a size 3 filter 3*3 and 5*5 size squares and other OBJECTS shows a significant blurring with respect to object of larger size.

The blurring gets more pronounced while using filter size 5, 9 and so on.

100.

What does using a mask having central coefficient maximum and then the coefficients reducing as a function of increasing distance from origin results?(a) It results in increasing blurring in smoothing process(b) It results to reduce blurring in smoothing process(c) Nothing with blurring occurs as mask coefficient relation has no effect on smoothing process(d) None of the mentionedThe question was asked in an interview.I'm obligated to ask this question of Smoothing Linear Spatial Filters in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

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Right option is (a) It results in increasing blurring in SMOOTHING process

Easy EXPLANATION: Use of a mask having central coefficient maximum and then the coefficients reducing as a function of increasing distance from ORIGIN is a STRATEGY to REDUCE blurring in smoothing process.