Explore topic-wise InterviewSolutions in .

This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.

1.

State the statement true or false: “BLPF has sharp discontinuity and ILPF doesn’t, and so ILPF establishes a clear cutoff b/w passed and filtered frequencies”.(a) True(b) FalseI have been asked this question by my college professor while I was bunking the class.I'd like to ask this question from Smoothing Frequency-Domain Filters topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right ANSWER is (B) False

For explanation I would say: ILPF has sharp discontinuity and BLPF doesn’t, so BLPF ESTABLISHES a clear cutoff b/w passed and filtered FREQUENCIES.

2.

A Butterworth filter of what order has no ringing?(a) 1(b) 2(c) 3(d) 4The question was posed to me in quiz.This question is from Smoothing Frequency-Domain Filters topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT answer is (a) 1

Explanation: A BUTTERWORTH filter of ORDER 1 has no ringing and ringing exist for order 2 although is imperceptible. A Butterworth filter of higher order shows significant factor of ringing.
3.

Which of the following method is/are used for padding the image?(a) Adding rows and column of 0 or other constant gray level(b) Simply replicating the rows or columns(c) All of the mentioned(d) None of the mentionedThis question was addressed to me during an internship interview.My enquiry is from Spatial Filtering topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct option is (c) All of the mentioned

The best explanation: In neighborhood operation for spatial filtering USING SQUARE MASK, padding of original image is done to obtain filtered image of same size as of original image done, by adding ROWS and column of 0 or other constant gray level or by replicating the rows or columns of the original image.

4.

In neighborhood operation for spatial filtering using square mask of n*n, which of the following approach is/are used to obtain a perfectly filtered result irrespective of the size?(a) By padding the image(b) By filtering all the pixels only with the mask section that is fully contained in the image(c) By ensuring that center of mask must be at a distance ≥ (n – 1)/2 pixels from border of image(d) None of the mentionedI had been asked this question in exam.I'm obligated to ask this question of Spatial Filtering in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» RIGHT choice is (c) By ensuring that center of MASK must be at a distance ≥ (n – 1)/2 pixels from border of image

Easiest explanation: By ensuring that center of mask must be at a distance ≥ (n – 1)/2 pixels from border of image, the resultant image would be of smaller size but all the pixels would be the result of the filter processing and so is a fully filtered result.

In the other APPROACH like PADDING affect the values near the edges that GETS more prevalent with mask size increase, while the another approach results in the band of pixels near border that gets processed with partial filter mask. So, not a fully filtered case.
5.

Which of the following helps to obtain the number of bits to be used to quantize each pixel.(a) Gray-level slicing(b) Contrast stretching(c) Contouring(d) Bit-plane slicingThis question was posed to me during a job interview.My question is from Piecewise-Linear Transformation Functions in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct option is (d) Bit-plane slicing

Easiest EXPLANATION: Bits-plane slicing helps in obtaining the IMPORTANCE played by each bit in the IMAGE by separating the image into bit-planes.

6.

In bit-plane slicing if an image is represented by 8 bits and is composed of eight 1-bit plane, with plane 0 showing least significant bit and plane 7 showing most significant bit. Then, which plane(s) contain the majority of visually significant data.(a) Plane 4, 5, 6, 7(b) Plane 0, 1, 2, 3(c) Plane 0(d) Plane 2, 3, 4, 5I got this question in my homework.I'd like to ask this question from Piecewise-Linear Transformation Functions topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT OPTION is (a) Plane 4, 5, 6, 7

To explain: In bit-plane SLICING, for the given data, the higher-ordered bits (mostly top four) CONTAINS most of the data visually signified.
7.

Which of the following transform produces a binary image after processing?(a) Contrast stretching(b) Gray-level slicing(c) All of the mentioned(d) None of the mentionedThis question was addressed to me during a job interview.My doubt stems from Piecewise-Linear Transformation Functions in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right OPTION is (C) All of the mentioned

Easy explanation: The approach of gray-level SLICING “to give all gray level of a specific range high value and a low value to all other gray levels” PRODUCES a binary image.

One of the transformation in Contrast stretching darkens the value of R (input image gray-level) below m (some predefined gray-value) and brightens the value of r above m, giving a binary image as result.

8.

What is/are the approach(s) of the gray-level slicing?(a) To give all gray level of a specific range high value and a low value to all other gray levels(b) To brighten the pixels gray-value of interest and preserve the background(c) All of the mentioned(d) None of the mentionedI had been asked this question in a national level competition.This interesting question is from Piecewise-Linear Transformation Functions in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct choice is (C) All of the mentioned

Easy explanation: There are basically two approach of gray-level slicing:

One approach is to give all gray level of a SPECIFIC RANGE high value and a low value to all other gray levels.

Second approach is to brighten the pixels gray-value of interest and PRESERVE the BACKGROUND.

9.

Specific bit contribution in the image highlighting is the basic idea of __________(a) Contrast stretching(b) Bit –plane slicing(c) Thresholding(d) Gray-level slicingI had been asked this question during a job interview.I need to ask this question from Piecewise-Linear Transformation Functions topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct answer is (b) Bit –plane slicing

For EXPLANATION I would SAY: Bit-plane slicing highlights the contribution of specific BITS made to TOTAL image, instead of highlighting a specific gray-level range.

10.

A specific range of gray-levels highlighting is the basic idea of __________(a) Contrast stretching(b) Bit –plane slicing(c) Thresholding(d) Gray-level slicingThe question was posed to me during an interview for a job.My query is from Piecewise-Linear Transformation Functions topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right choice is (d) Gray-level slicing

To ELABORATE: gray-level slicing is being done by TWO approach: One approach is to give all gray level of a SPECIFIC RANGE high value and a low value to all other gray levels.

Second approach is to BRIGHTEN the pixels gray-value of interest and preserve the background.

I.e. in both highlighting of a specific range of gray-level is been done.

11.

What condition prevents the intensity artifacts to be created while processing with contrast stretching, if r and s are gray-values of image before and after processing respectively?(a) r1 = s1 and r2 = s2(b) r1 = r2, s1 = 0 and s2 = L – 1, L is the max gray value allowed(c) r1 = 1 and r2 = 0(d) r1 ≤ r2 and s1 ≤ s2I have been asked this question by my college professor while I was bunking the class.My doubt stems from Piecewise-Linear Transformation Functions in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct choice is (d) R1 ≤ r2 and s1 ≤ s2

To elaborate: While PROCESSING through contrast STRETCHING, if r1 ≤ r2 and s1 ≤ s2 is MAINTAINED, the function remains single valued and so monotonically increasing. This helps in the prevention of CREATION of intensity artifacts.

12.

A contrast stretching result been obtained by setting (r1, s1) = (rmin, 0) and (r2, s2) = (rmax, L – 1), where, r and s are gray-values of image before and after processing respectively, L is the max gray value allowed and rmax and rmin are maximum and minimum gray-values in image respectively. What should we term the transformation function if r1 = r2 = m, some mean gray-value.(a) Linear function(b) Thresholding function(c) Intermediate function(d) None of the mentionedI got this question in a national level competition.My doubt stems from Piecewise-Linear Transformation Functions topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct ANSWER is (b) Thresholding function

Easy EXPLANATION: From (r1, s1) = (rmin, 0) and (R2, s2) = (rmax, L – 1), we have s1 = 0 and s2 = L – 1 and if r1 = r2 = m is set then the result becomes r1 = r2, s1 = 0 and s2 = L – 1, i.e. a thresholding function.

13.

When is the contrast stretching transformation a thresholding function, for r and s as gray-value of image before and after processing respectively?(a) r1 = s1 and r2 = s2(b) r1 = r2, s1 = 0 and s2 = L – 1, L is the max gray value allowed(c) r1 = 1 and r2 = 0(d) None of the mentionedI had been asked this question in an interview for internship.My question is based upon Piecewise-Linear Transformation Functions topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct ANSWER is (b) R1 = r2, s1 = 0 and s2 = L – 1, L is the max gray value allowed

Explanation: If r1 = r2, s1 = 0 and s2 = L – 1, the CONTRAST stretching transformation is a thresholding FUNCTION.

14.

When is the contrast stretching transformation a linear function, for r and s as gray-value of image before and after processing respectively?(a) r1 = s1 and r2 = s2(b) r1 = r2, s1 = 0 and s2 = L – 1, L is the max gray value allowed(c) r1 = 1 and r2 = 0(d) None of the mentionedThis question was posed to me in an interview for internship.Asked question is from Piecewise-Linear Transformation Functions topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct option is (a) r1 = s1 and r2 = s2

The best I can EXPLAIN: If r1 = s1 and r2 = s2 the CONTRAST STRETCHING TRANSFORMATION is a linear FUNCTION.

15.

Which gray-level transformation increase the dynamic range of gray-level in the image?(a) Power-law transformations(b) Negative transformations(c) Contrast stretching(d) None of the mentionedI got this question in an interview for job.The query is from Piecewise-Linear Transformation Functions in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right choice is (C) Contrast STRETCHING

The EXPLANATION: Increasing the DYNAMIC range of gray-levels in the image is the basic IDEA behind contrast stretching.

16.

Which of the following is not a principle step in fuzzy technique?(a) Fuzzify input(b) Apply implication method(c) Defuzzify final output(d) None of the mentionedI had been asked this question in an international level competition.Question is from Fuzzy Techniques in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» RIGHT option is (d) None of the MENTIONED

Explanation: All of the mentioned above are KEY STEPS in fuzzy technique.
17.

Using IF-THEN rule to create the output of fuzzy system is called _______________.(a) Inference(b) Implication(c) Both the mentioned(d) None of the mentionedThis question was addressed to me in examination.The above asked question is from Fuzzy Techniques topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right CHOICE is (c) Both the mentioned

The explanation is: It is CALLED INFERENCE or IMPLICATION.

18.

What is the independent variable of fuzzy output?(a) Maturity(b) Membership(c) Generic Element(d) None of the mentionedI got this question by my school principal while I was bunking the class.My question is taken from Fuzzy Techniques in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct ANSWER is (a) Maturity

Easy EXPLANATION: Maturity is the independent VARIABLE of fuzzy output.

19.

Which of the following is not a type of Membership function?(a) S-shape(b) Bell shape(c) Truncated Gaussian(d) None of the mentionedThe question was asked by my school principal while I was bunking the class.Question is from Fuzzy Techniques topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right OPTION is (d) NONE of the mentioned

For explanation: All of the mentioned above are types of MEMBERSHIP functions.

20.

Which of the following is a type of Membership function?(a) Triangular(b) Trapezoidal(c) Sigma(d) All of the mentionedI have been asked this question in a job interview.This key question is from Fuzzy Techniques topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right OPTION is (d) All of the mentioned

The EXPLANATION is: All of them are TYPES of MEMBERSHIP functions.

21.

If Z is a set of elements with a generic element z, i.e. Z = {z}, then this set is called _____________(a) Universe set(b) Universe of discourse(c) Derived set(d) None of the mentionedThis question was addressed to me during an interview.Question is taken from Fuzzy Techniques topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT ANSWER is (b) UNIVERSE of DISCOURSE

Easy EXPLANATION: It is called the universe of discourse.
22.

A fuzzy set ‘A’ in Z is characterized by a ____________ that associates with element of Z, a real number in the interval [0, 1].(a) Grade of membership(b) Generic element(c) Membership function(d) None of the mentionedThe question was asked in semester exam.I'm obligated to ask this question of Fuzzy Techniques topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct OPTION is (c) Membership function

Best explanation: A FUZZY set is CHARACTERIZED by a membership function.

23.

A fuzzy set is ________ if and only if membership function is identically zero in Z.(a) Empty(b) Subset(c) Complement(d) None of the mentionedThe question was asked by my school teacher while I was bunking the class.This intriguing question originated from Fuzzy Techniques topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» RIGHT CHOICE is (a) EMPTY

Easiest explanation: It is CALLED an Empty SET.
24.

Which is the set, whose membership only can be true or false, in bi-values Boolean logic?(a) Boolean set(b) Crisp set(c) Null set(d) None of the mentionedI had been asked this question during an online interview.Question is taken from Fuzzy Techniques in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct option is (b) Crisp set

The BEST I can EXPLAIN: The so CALLED Crisp set is the one in which MEMBERSHIP only can be true or false, in bi-values Boolean LOGIC.

25.

What is the set generated using infinite-value membership functions, called?(a) Crisp set(b) Boolean set(c) Fuzzy set(d) All of the mentionedI have been asked this question in exam.My question is based upon Fuzzy Techniques topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right CHOICE is (C) FUZZY set

To EXPLAIN: It is CALLED fuzzy set.

26.

Which of the following involves reversing the intensity levels of an image?(a) Log Transformations(b) Piecewise Linear Transformations(c) Image Negatives(d) None of the MentionedThis question was addressed to me in quiz.Question is from Intensity Transformation Functions topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT CHOICE is (c) IMAGE Negatives

To explain I would say: Image negatives use reversing INTENSITY levels.
27.

Piecewise Linear Transformation function involves which of the following?(a) Bit-plane slicing(b) Intensity level slicing(c) Contrast stretching(d) All of the MentionedI got this question during an internship interview.Query is from Intensity Transformation Functions topic in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right option is (d) All of the Mentioned

To explain I would say: PIECEWISE Linear TRANSFORMATION function INVOLVES all the mentioned FUNCTIONS.

28.

Highlighting the contribution made to total image by specific bits instead of highlighting intensity-level changes is called ____________________(a) Intensity Highlighting(b) Byte-Slicing(c) Bit-plane slicing(d) None of the MentionedThe question was posed to me in final exam.I'm obligated to ask this question of Intensity Transformation Functions in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct OPTION is (C) Bit-plane SLICING

Easiest explanation: It is CALLED Bit-plane slicing.

29.

Highlighting a specific range of intensities of an image is called _______________(a) Intensity Matching(b) Intensity Highlighting(c) Intensity Slicing(d) None of the MentionedI had been asked this question in final exam.The doubt is from Intensity Transformation Functions in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»
30.

Which process expands the range of intensity levels in an image so that it spans the full intensity range of the display?(a) Shading correction(b) Contrast sketching(c) Gamma correction(d) None of the MentionedI have been asked this question in semester exam.My query is from Intensity Transformation Functions in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right choice is (b) Contrast SKETCHING

To explain I would say: Contrast sketching is the process USED to expand INTENSITY LEVELS in an image.

31.

What is Gamma Correction?(a) A Power-law response phenomenon(b) Inverted Intensity curve(c) Light brightness variation(d) None of the MentionedThe question was asked during an interview.This intriguing question originated from Intensity Transformation Functions topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct OPTION is (a) A Power-law response phenomenon

Easy explanation: The exponent in Power-law is called GAMMA and the PROCESS used to correct the response of Power-law transformation is called Gamma CORRECTION.

32.

For what value of the output must the Power-law transformation account for offset?(a) No offset needed(b) All values(c) One(d) ZeroThis question was posed to me by my college professor while I was bunking the class.I'm obligated to ask this question of Intensity Transformation Functions in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» RIGHT CHOICE is (d) ZERO

For explanation I WOULD say: When the OUTPUT is Zero, an offset is necessary.
33.

Power-law transformations has the basic form of ________________ where c and ∆ are constants.(a) s = c + r^∆(b) s = c – r^∆(c) s = c * r^∆(d) s = c / r.∆I had been asked this question at a job interview.My query is from Intensity Transformation Functions topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct option is (C) s = c * r^∆

For explanation I would say: s = c * r^∆ is CALLED the Power-law TRANSFORMATION.

34.

The general form of log transformations is ____________________(a) s = c.log(1 + r)(b) s = c+log(1 + r)(c) s = c.log(1 – r)(d) s = c-log(1 – r)I had been asked this question in an interview for internship.I'd like to ask this question from Intensity Transformation Functions in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT ANSWER is (a) s = c.log(1 + R)

The explanation is: s = c.log(1 + r) is the log transformation.
35.

How is negative of an image obtained with intensity levels [0,L-1] with “r” and “s” being pixel values?(a) s = L – 1 + r(b) s = L – 1 – r(c) s = L + 1 + r(d) s = L + 1 + rI had been asked this question by my school teacher while I was bunking the class.This is a very interesting question from Intensity Transformation Functions topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» RIGHT OPTION is (b) s = L – 1 – r

Easiest explanation: The negative is obtained using s = L – 1 + r.
36.

If the contribution made by illumination component of image is decreased and the contribution of reflectance component is amplified, what will be the net result?(a) Dynamic range compression(b) Contrast enhancement(c) All of the mentioned(d) None of the mentionedI have been asked this question during an online exam.The above asked question is from Homomorphic filtering in portion Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct answer is (C) All of the mentioned

For EXPLANATION I would say: The illumination component of an image is characterized by a slow SPATIAL variation and the reflectance component of an image VARIES abruptly particularly at the junction of dissimilar OBJECTS, so, if the contribution made by illumination component of image is decreased and the contribution of reflectance component is amplified then there is simultaneous dynamic range compression and contrast stretching.

37.

The illumination component of an image is characterized by a slow spatial variation. The characteristic lead to associate illumination with __________(a) The low frequency of Fourier transform of logarithm of the image(b) The high frequency of Fourier transform of logarithm of the image(c) All of the mentioned(d) None of the mentionedThis question was addressed to me during an online exam.This interesting question is from Homomorphic filtering in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT option is (a) The LOW frequency of Fourier transform of logarithm of the IMAGE

Explanation: The illumination component of an image is characterized by a slow spatial VARIATION, so, is ASSOCIATED with the low frequency of Fourier transform of logarithm of the image.
38.

The reflectance component of an image varies abruptly particularly at the junction of dissimilar objects. The characteristic lead to associate illumination with __________(a) The low frequency of Fourier transform of logarithm of the image(b) The high frequency of Fourier transform of logarithm of the image(c) All of the mentioned(d) None of the mentionedThis question was posed to me during an online interview.Origin of the question is Homomorphic filtering in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The CORRECT option is (b) The high FREQUENCY of Fourier transform of LOGARITHM of the image

To elaborate: The reflectance component of an image VARIES abruptly, so, is associated with the high frequency of Fourier transform of logarithm of the image.

39.

Which of the following image component is characterized by a slow spatial variation?(a) Illumination component(b) Reflectance component(c) All of the mentioned(d) None of the mentionedThe question was posed to me by my school principal while I was bunking the class.My doubt is from Homomorphic filtering in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» RIGHT answer is (a) Illumination COMPONENT

To explain I WOULD SAY: The illumination component of an image is characterized by a slow SPATIAL variation.
40.

Which of the following image component varies abruptly particularly at the junction of dissimilar objects?(a) Illumination component(b) Reflectance component(c) All of the mentioned(d) None of the mentionedThe question was posed to me in an international level competition.My question comes from Homomorphic filtering in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct answer is (b) Reflectance component

To explain I would say: The reflectance component of an image VARIES ABRUPTLY particularly at the JUNCTION of DISSIMILAR OBJECTS.

41.

In Homomorphic filtering which of the following operations is used to convert input image to discrete Fourier transformed function?(a) Logarithmic operation(b) Exponential operation(c) Negative transformation(d) None of the mentionedI got this question in exam.My doubt is from Homomorphic filtering topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The CORRECT answer is (a) LOGARITHMIC operation

The explanation is: For an image is expressed as the multiplication of ILLUMINATION and reflectance component i.e. f(x, y) = i(x, y) * r(x, y), the EQUATION can’t be used DIRECTLY to operate separately on the frequency component of illumination and reflectance because the Fourier transform of the product of two function is not separable. So, the logarithmic operation is used.I{z(x,y)}=I{ln⁡(f(x,y)) }=I{ln⁡(i(x,y)) }+I{ln⁡(r(x,y))}.

42.

If an image is expressed as the multiplication of illumination and reflectance component i.e. f(x, y)= i(x, y) * r(x, y), then Validate the statement “We can directly use the equation f(x, y)= i(x, y) * r(x, y) to operate separately on the frequency component of illumination and reflectance” .(a) True(b) FalseI have been asked this question in a national level competition.I'd like to ask this question from Homomorphic filtering topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct option is (b) False

For explanation I WOULD say: For an image is expressed as the multiplication of illumination and reflectance component i.e. f(x, y)= i(x, y) * r(x, y), the equation can’t be used directly to operate separately on the frequency component of illumination and reflectance because the Fourier TRANSFORM of the product of TWO FUNCTION is not separable.

43.

A class of system that achieves the separation of illumination and reflectance component of an image is termed as __________(a) Base class system(b) Homomorphic system(c) Base separation system(d) All of the mentionedI have been asked this question during an online exam.This interesting question is from Homomorphic filtering in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT option is (B) Homomorphic system

The best explanation: Homomorphic system is a class of system that achieves the separation of illumination and REFLECTANCE COMPONENT of an image.
44.

Validate the statement “Because of High frequency emphasis the gray-level tonality due to low frequency components is not lost”.(a) True(b) FalseThis question was addressed to me in an online quiz.I'd like to ask this question from Unsharp Masking, High-boost filtering and Emphasis Filtering topic in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The correct CHOICE is (a) True

To EXPLAIN I would SAY: Because of High frequency emphasis the gray-level tonality DUE to low frequency components is not lost.

45.

Which of the following fact is true for a image?(a) An image is the addition of illumination and reflectance component(b) An image is the subtraction of illumination component from reflectance component(c) An image is the subtraction of reflectance component from illumination component(d) An image is the multiplication of illumination and reflectance componentThis question was posed to me in quiz.Origin of the question is Homomorphic filtering topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Correct CHOICE is (d) An image is the MULTIPLICATION of illumination and reflectance component

To elaborate: An image is EXPRESSED as the multiplication of illumination and reflectance component.

46.

The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a≥0 and b>a. When b increases past 1 the filtering process is specifically termed as__________(a) Unsharp masking(b) High-boost filtering(c) Emphasized filtering(d) None of the mentionedThe question was asked in quiz.My doubt stems from Unsharp Masking, High-boost filtering and Emphasis Filtering topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» RIGHT option is (c) Emphasized filtering

Explanation: The TRANSFER FUNCTION of HIGH frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a≥0 and b>a. When b increases past 1, the high frequency are emphasized and so the filtering PROCESS is better known as Emphasized filtering.
47.

Which of the following a transfer function of High frequency emphasis {Hhfe(u, v)} for Hhp(u, v) being the highpass filtered version of image?(a) Hhfe(u, v) = 1 – Hhp(u, v)(b) Hhfe(u, v) = a – Hhp(u, v), a≥0(c) Hhfe(u, v) = 1 – b Hhp(u, v), a≥0 and b>a(d) Hhfe(u, v) = a + b Hhp(u, v), a≥0 and b>aI have been asked this question during an interview.This question is from Unsharp Masking, High-boost filtering and Emphasis Filtering topic in section Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

Right answer is (d) Hhfe(u, v) = a + B Hhp(u, v), a≥0 and b>a

The best I can explain: The TRANSFER function of High FREQUENCY emphasis is given as:Hhfe(u, v) = a + b Hhp(u, v), a≥0 and b>a.

48.

The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a≥0 and b>a. What happens when b increases past 1?(a) The high frequency are emphasized(b) The low frequency are emphasized(c) All frequency are emphasized(d) None of the mentionedThis question was posed to me in an internship interview.I need to ask this question from Unsharp Masking, High-boost filtering and Emphasis Filtering in chapter Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer» CORRECT ANSWER is (a) The HIGH frequency are emphasized

Easiest explanation: The transfer function of High frequency emphasis is GIVEN as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a≥0 and b>a. When b increases past 1, the high frequency are emphasized.
49.

The transfer function of High frequency emphasis is given as: Hhfe(u, v) = a + b Hhp(u, v), for Hhp(u, v) being the highpass filtered version of image,a≥0 and b>a. for certain values of a and b it reduces to High-boost filtering. Which of the following is the required value?(a) a = (A-1) and b = 0,A is some constant(b) a = 0 and b = (A-1),A is some constant(c) a = 1 and b = 1(d) a = (A-1) and b =1,A is some constantThis question was posed to me in a national level competition.I want to ask this question from Unsharp Masking, High-boost filtering and Emphasis Filtering in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The CORRECT OPTION is (d) a = (A-1) and b =1,A is some constant

Easiest explanation: The transfer function of High frequency EMPHASIS is GIVEN as: Hhfe(u, v) = a + b HHP(u, v) and the transfer function for High-boost filtering is Hhb(u, v) = (A-1) + Hhp(u, v), A being some constant. So, for a = (A-1) and b =1, Hhfe(u, v) = Hhb(u, v).

50.

A process that accentuate the contribution to enhancement made by high-frequency components, by multiplying the highpass filter by a constant and adding an offset to the highpass filter to prevent eliminating zero frequency term by filter is known as _______(a) Unsharp masking(b) High-boost filtering(c) High frequency emphasis(d) None of the mentionedI got this question in an interview.Question is taken from Unsharp Masking, High-boost filtering and Emphasis Filtering topic in division Intensity Transformations and Spatial Filtering of Digital Image Processing

Answer»

The CORRECT choice is (C) HIGH frequency emphasis

Explanation: High frequency emphasis is the method that accentuate the contribution to enhancement made by high-frequency component. In this we multiply the HIGHPASS FILTER by a constant and add an offset to the highpass filter to prevent eliminating zero frequency term by filter.