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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 101. |
Resolving power of an optical instrument is associated withA. diffractionB. polarisationC. scattering of lightD. interference |
| Answer» Correct Answer - A | |
| 102. |
The correct relation between limit of resolution and resolving power isA. limit of resolution `=(1)/("resolving power")`B. limit of resolution `prop` resolving powerC. limit of resolution `prop (1)/("resolving power")`D. limit of resolution `prop` (1-resolving power) |
| Answer» Correct Answer - A | |
| 103. |
The interference differs from diffraction in thatA. it cannot be oberved with white lightB. unlike diffraction the interference fringes are of varying intensityC. interference minima are perfectly dark and that of diffraction may not be darkD. the diffraction fringes are of equal width but the interference fringes are of unequal width |
| Answer» Correct Answer - C | |
| 104. |
A diffraction is obtained by using a beam of red light. What will happen if the red light is replaced by the blue light?A. no changeB. diffraction bands become narrower and crowed togetherC. bands become broader and farther apartD. bands disappear |
| Answer» Correct Answer - B | |
| 105. |
In a biprism experimentn is performed yellow light of wavelength `5600Å`. The yellow light was then replaced by red light of wavelengts `6400Å`. Find the value of n for which `(n+1)^(th)` yellow bright band consider with the `n^(th)` red bright band for the same setting.A. 4B. 5C. 6D. 7 |
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Answer» Correct Answer - D `x_((n+1))` for yellow `=x_(n)` for red `rArr (D)/(d) (n+1)lambda_(y)= (D)/(d) n lambda_(r)` `:. N= (lambda_(y))/(lambda_(r)- lambda_(y))` `=(5600)/(64000-5600)=7` |
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| 106. |
In a biprism experiment, interfernce bands are obtined in the focal of the eyepiece which is at a distance of `1.2` m from the slit. The distance between the two virtual images of the slits is 1 mm. If the slit is illuminated by light of wavelenght 4800Å. The change in band width when the eyepiece is moved towards other the slit by 50 cm without distrubing the other arrangement isA. `1.24 mm`B. `2.24 mm`C. `0.24 mm`D. `1.1 mm` |
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Answer» Correct Answer - C ` beta_(1)=(D_(1))/(d)lamda" "beta_(2)=(D_(2))/(d)lamda` `beta_(1)-beta_(2)=((D_(1)-D_(2))lamda)/(d)=(0.5xx4.8xx10^(-7))/(10^(-3))` =0.24mm |
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| 107. |
In a biprism expeirment to determine the wavelenght of light, the distance between slit and eyepiece is 1,. Wavelenght of light used is 5600Å. When a convex lens is kept at a distance of 30 cm from the slit, the distance of fourth the two images is 0.7 mm. The distance of fourth dark band from the central bright band isA. 6.5 mmB. `4.5 mm`C. `7.5 mm`D. `7.0 mm` |
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Answer» Correct Answer - A `(d_(1))/(d)=(v)/(u):.d=(0.7xx30)/(70)=0.3mm` `x_(4d)=3.5beta=3.5(Dlamda)/(d)=(3.5xx1xx5.6xx10^(-7))/(3xx10^(4))` =6.5mm |
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| 108. |
In a biprism experiment, the distance between the two virtual images of the slit is `1.2` mm and the wavelenght of light used is 4000Å . If the distance of third bright band from central bright band is 1 mm, and the distance is and the distance between the brprism and focal palne of the eyepiece is `0.9`, then distannce between slit and biprism will beA. `0.1m `B. `1.1 m`C. `0.5 m`D. `0.15`mm |
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Answer» Correct Answer - A `x_(3b)=3beta:.beta=(1)/(3)mm` `:.D=(d.beta)/(lamda)=(1.2xx10^(-3)xx10^(-3))/(4xx10^(-7)xx3)=1m=u+V` `:.u=1-0.9=0.1m` |
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| 109. |
In a biprism experiment, the distance between the slit and the focal plane of the eyepiece is `1.2 m ` and the wavelenght of light used is 5000Å. When a convex lenz is interposed (between the biprism and eyepiece) the images of the slits in the two positios are 5 mm and `1.8` mm part. the distance betwene the centre of the pattern and twelfth dark band isA. `1.3xx10^(-3) m`B. `2.2xx10^(-3) m`C. `3.3xx10^(-3) m`D. `2.3xx10^(-3) m` |
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Answer» Correct Answer - D `x_(12d)=11.5beta=11.5(Dlamda)/(d)=(11.5xx1.2xx5xx10^(-7))/(3xx10^(-3))` `=2.3xx10^(-3)m` |
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| 110. |
Biprism experiment is conducted with a wavelength of `5000Å`. The distance between the virtual sources is 0.2 mm and the micrometer eyepiece is at a distance of 100 cm from the slits. The distance between the consecutive bright and dark between the consecutive bright and dark band isA. `1.25 mm`B. `2.5 mm`C. `3.5 mm`D. `0.25 mm` |
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Answer» Correct Answer - A `lambda 5000A^(@), d=0.2 mm D=1 m, beta = ?` `beta =(D)/(d) lambda` `=(1xx5xx10^(-7))/(0.2xx10^(-3))` `25xx10^(-4)` `=2.5 mm` b Thus distance between consecutive bright and dark band is `(beta)/(2)=(2.5)/(2)=1.25 mm` |
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| 111. |
The distance between diminshed and magnified images of slits for two positions are `d_(1) and d_(2)` respectively of the slite isA. `d=d_(1)d_(2)`B. `d=(d_(1))/(d_(2))`C. `d=sqrt(d_(1)d_(2))`D. `d=sqrt((d_(1))/(d_(2)))` |
| Answer» Correct Answer - C | |
| 112. |
Light d of wavelength `5000Å` is incident normally on a slite. The first minimum of the distance of 5 mm from the central maximum on a screen placed at a distance of 2 m from the slit. The width of slit isA. `0.1mm`B. `0.2mm`C. `0.3 mm`D. `0.4 mm` |
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Answer» Correct Answer - B `asintheta=nlamda` `:.a=(1xx5xx10^(-7)xx2)/(5xx10^(-3))=0.2mm` |
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| 113. |
A monochromatic light of `lambda=5000Å` is inciden on two slits seperated by a distance of `5xx10^(-4)m.` if a thin glass of thickness `1.5xx10^(-6)` m and refractive index `1.5` placed between one of the slits and screen. The pahses difference introduced at the position of central maxima isA. `3pi `B. `2 pi`C. `2pi//3`D. `pi//3` |
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Answer» Correct Answer - A Path difference `(mu-1)t=(1.5-1)1.5xx10^(-6)` Phase difference `=(2pi)/(lamda)xx(mu-1)t` `=(2pixx0.5xx1.5xx10^(-6))/(5ccx10)` `=3pi` |
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| 114. |
If the path difference between the two light waves at a point is equal to intergral multiple of wavelength of then points appears asA. brightB. darkC. may be bright or darkD. none of these |
| Answer» Correct Answer - A | |
| 115. |
For constructive interference to take place between two monochromatic light waves of wavelength `lambda` , the path difference should beA. `(2n-1) (lambda)/(4)`B. `(2n-1) (lambda)/(2)`C. `n lambda`D. `(2n+1)(lambda)/(2)` |
| Answer» Correct Answer - C | |
| 116. |
For obtaining diffraction pattern, aperture of the slite should be of the order ofA. `lambda`B. `lambda//2`C. `lambda//4`D. `2lambda` |
| Answer» Correct Answer - A | |
| 117. |
For constructive interference to take place between two monochromatic light waves of wavelength `lambda` , the path difference should beA. `n lambda`B. `(2n-1) (lambda)/(4)`C. `(2n-1) (lambda)/(2)`D. `(2n-1) lambda` |
| Answer» Correct Answer - C | |
| 118. |
For constructive interference to take place between two monochromatic light waves of wavelength `lambda` , the path difference should beA. `(2n-1) pi`B. `(2n-1) pi`C. `2 pi n`D. `pi n` |
| Answer» Correct Answer - C | |
| 119. |
For destructive interference to take place between two light, waves the path difference should beA. intergral multiple of wave lengthB. odd multiple of half of wave lengthC. zeroD. none of these |
| Answer» Correct Answer - B | |
| 120. |
A small circular disce is placed in the path of monochromatic light. The centreof the geometrical shadow is alwaysA. brightB. darkC. colouredD. partly bright and partly dark |
| Answer» Correct Answer - A | |
| 121. |
In a single slit diffraction pattern intensity and width of fringes areA. unequal widthB. equal widthC. equal width and equal intensityD. unequal width and unequal intensity |
| Answer» Correct Answer - D | |
| 122. |
Consider Fraunhoffer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum the phase difference (in radians) between the wavelets from the opposite edges of the slit isA. `pi//4`B. `pi//4`C. `pi`D. `2pi` |
| Answer» Correct Answer - D | |
| 123. |
A very samml opaque is place in the path of monochormatic light. Its shadow hasA. bright point at the centre surrounded by alternate bright and dark ringsB. dark point at the centre surrounded by alternate bright and dark ringsC. uniform darknessD. uniform illumination |
| Answer» Correct Answer - A | |
| 124. |
A zone plae acts similar to aA. convex lensB. prismC. plane mirrorD. plane glass plate |
| Answer» Correct Answer - A | |
| 125. |
The phenomenon of diffractin can be treated as interferene phenomenon if the number of coherent sources areA. oneB. twC. zeroD. infinity |
| Answer» Correct Answer - B | |
| 126. |
The bandwidth of fringes is independent ofA. wavelengthB. distance between two sourceC. distance between slit and screenD. order of the fringes |
| Answer» Correct Answer - D | |
| 127. |
The distances of a point on the screen from two slits in biprism experiment is `1.8xx10^(-5)` m and `1.23xx10^(-5)` m if wavelength of light used is 6000 Å then fringe formed at that point isA. `8^(th)` darkB. `9^(th)` darkC. `10^(th)` darkD. `11^(th)` dark |
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Answer» Correct Answer - C Path diff. `=1.8xx10^(-5)-1.23xx10^(-5)` `=0.57xx10^(-5) m` Now, `n= ("Path diff.")/("Wavelength")= (0.57xx10^(-5))/(6xx10^(-7))=9.5` Thus, given, point is `10^(th)` dark point. |
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| 128. |
The ratio of intensities of consecutive maxima in the diffraction pattern due to a single slit isA. `1:2:3`B. `1:4:9`C. `1:(2)/(pi^(2))`D. `1:(4)/(9pi^(2)):(4)/(25 pi^(2))` |
| Answer» Correct Answer - D | |
| 129. |
For steady interference pattern in biprism experiment, which of the following is true ?A. Distance between slit and biprims should be less.B. The refracting edge of the biprims should be verticl and paralle to the slit.C. The slite biprism and eyepiece should be at same height.D. all of these |
| Answer» Correct Answer - D | |
| 130. |
In interference of light, `beta` is fringe width. The distance of `n^(th)` maxima from the centre of interferene pattern isA. `x_(n) n.beta`B. `x_(n)=(2n-1) (beta)/(2)`C. `x_(n)=(beta)/(n)`D. `x_(n)=n^(2). beta` |
| Answer» Correct Answer - A | |
| 131. |
In an interference experiment with a biprism, the distance of the slits from the screenn is increased by 25% annd the separation between the slits is halved. If X represents the original fringe width, the new fringe width will beA. `2.5X`B. `1.5X`C. `2X`D. `4X` |
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Answer» Correct Answer - A `D_(2)=1.25 D_(1) D_(2)=(d_(2))/(2), beta_(2)= b ? beta_(1)=x` `b=(D)/(d)` `:. (beta_(2))/(beta_(1))=(D_(2))/(D_(1))xx(d_(1))/(d_(2))` `beta_(2)=(1.25 D_(1))/(D_(1))xx (d_(2) xx 2)/( d_(1)) xx beta_(1)` `beta_(2)=2.5 beta_(1) = 2.5 X` |
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| 132. |
When separation between the central maxima of the two objects is equal to the sepration between central maximum of first object and the first minima of the first objectn, then the objects are said to beA. just resolvedB. well resolvedC. not resolvedD. none of these |
| Answer» Correct Answer - A | |
| 133. |
When separation between the central maxima of the two objects is greater than the separation between central maximumu of first object and the first minima of the first object, then the objects are said to beA. just resolvedB. well resolvedC. not resolvedD. none of these |
| Answer» Correct Answer - B | |
| 134. |
The reciprocal of the smalles angular separation between two distance object, so that they appear just separated isA. resolving power of convex lenseB. resolving power of bipirsmC. resolving power of microscopeD. resolving power of telescop |
| Answer» Correct Answer - D | |
| 135. |
The central point of the diffraction pattern due to a circular disc isA. always darkB. always brightC. blurredD. not clear |
| Answer» Correct Answer - B | |
| 136. |
In the diffraction pattern due to single slit, in the direction of `theta=0` we getA. first secondary minimumB. central maximumC. first secondary maximumD. second secondary maximum |
| Answer» Correct Answer - B | |
| 137. |
Two coherent light sources `S_1` and `S_2 (lambda=6000Å)` are `1mm` apart from each other. The screen is placed at a distance of `25cm` from the sources. The width of the fringes on the screen should beA. `0.0015 cm`B. `0.025` cmC. `0.010` cmD. `0.030cm` |
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Answer» Correct Answer - A `beta =(D)/(d) lambda=(25xx600xx10^(8))/(10^(-1)) =0.015 cm` |
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| 138. |
A windwo fitted with a wire mesh and distant 200 m is being viewed with the help of telescope. The spacing between the wires of the mesh is 2 mm. The wavelengths of light used is 5000Å . The minimum diamtere telescop must beA. `6.1 cm`B. `5.9 cm`C. `4.2 cm`D. `3.6 cm` |
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Answer» Correct Answer - A `(d)/(x)=(1.22lamda)/(D)` `:.D=(1.22xx5xx10^(-7)xx2xx10^(2))/(2xx10^(-3))=6.1xx10^(-2)m` |
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| 139. |
In an interference experiment, third bright fringe is obtained at a point on the screen with a light of 700 nm . What should be the wavelength of the light source in order to obtain 5th bright fringe at the same pointA. 630 mmB. 500 mmC. 420 mmD. 750 mm |
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Answer» Correct Answer - C `lamda_(1)=700nm,n_(1)=3n_(2)=5,lamda=?` For same path diff. `n_(1)lamda_(1)=n_(2)lamda_(2)` `lamda_(2)=(n_(1)lamda_(1))/(n_(2))=(3xx700)/(5)=420nm` |
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| 140. |
In bipism experiment, the distance of `20^(th)` bright band from the centre of the interference pattern is 8 mm. The distance of the `30^(th)` bright band isA. 4 mmB. 8 mmC. 12 mmD. 16 mm |
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Answer» Correct Answer - C `(x_(30))/(x_(20))=(30beta)/(20 beta)` `:. X_(30)=(30)/(20)x_(20)=12 mm` |
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