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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 151. |
Domain of `f(x)=sin^(-1)[2-4x^2],`where [.] denotes the greatest integer function, is:`(a)[-(sqrt(3))/2,(sqrt(3))/2]-{0} `(b) `[-(sqrt(3))/2,(sqrt(3))/2]``(c)[-(sqrt(3))/2,(sqrt(3))/2)-{0}`(d) `(-(sqrt(3))/2,(sqrt(3))/2)-0` |
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Answer» Correct Answer - (a) |
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| 152. |
Value of `int_(0)^(2pi)[sin2x(1+cos3x)]dx` (where [.] denotes greatest integer fucntion)A. `-2pi`B. `pi`C. `2pi`D. `-pi` |
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Answer» Correct Answer - D |
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| 153. |
In contect with the transition elements, which of the following statements is incorrect ?A. In addition to the normal oxidation states, the zero oxidation state is also shown by these elements in complexesB. In the highest oxidation states, the transition metal show basic character and form cationic complexes.C. In the highest oxidation states of the first five transition elements (Sc to Mn), all the 4s and 3d electrons are used for bonding.D. Once the `d^(5)` configuration is exceeded, the tendency to involveall the 3d electrons in bonding decreases. |
| Answer» Correct Answer - B | |
| 154. |
The pair of compounds having metals in their highest oxidation state isA. `MnO_(2) "and "CrO_(2)Cl_(2)`B. `[Fe(CN)_(6)]^(3-) "and" [Cu(CN)_(4)]^(-2)`C. `[NiCl_(4)]^(2-) "and" [CoCl_(4)]^(2-)`D. `[FeCl_(4)]^(-)"and"Co_(2)O_(3)` |
| Answer» Correct Answer - A | |
| 155. |
The IUPAC name of the following compound is A. 2-Ethyl-1, 1-dimethylcyclohexaneB. 1, 1-Dimethyl 1-2-ethylcyclohexaneC. 2, 2-Dimethyl-1-1-ethylcyclohexaneD. 1-Ethyl-2,2-dimethylcyclohexane |
| Answer» Correct Answer - A | |
| 156. |
`Fe^(2+)+Ag^(+)toFe^(3+)+Ag` if `E^(@)` of `Ag^(+)//Ag=x` `E^(@)` of `Fe^(@+)//Fe=y` `E^(@)` of `Fe^(3+)//Fe=z` Determine std. EMF of given cell reaction.A. `x+2y-3z`B. `x-y`C. `x-z`D. `2x+y-3z` |
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Answer» Correct Answer - A |
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| 157. |
`S(s)+O_(2)hArrSO_(@)(g)" "K_(1)=10^(52)` `2S(s)+3O_(2)hArr2SO_(3)(g)" "K_(2)=10^(129)` Calculate `K_("equilibrium")` forA. `10^(25)`B. `10^(77)`C. `10^(70)`D. `10^(40)` |
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Answer» Correct Answer - A |
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| 158. |
Which of the following is incorrect about interstitial compounds.A. very reactiveB. high metallic conductivityC. very hardD. high melting point. |
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Answer» Correct Answer - A |
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| 159. |
IUPAC symbol of atomic number 119.A. UuhB. UunC. UueD. Uub |
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Answer» Correct Answer - C |
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| 160. |
5 mole of ideal gas at `100K(C_(v.m)=28J//mol//K)`. It is heated upto 200 K. calculate `triangleU` and `triangle(PV)` for the process `(R=8J//mol-K)`A. `triangleU=28KJ,triangle(PV)=8KJ`B. `triangleU=14KJ,triangle(PV)=4KJ`C. `triangleU=14KJ:triangle(PV)=8KJ`D. `triangleU=28KJ,triangle(PV)=4KJ` |
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Answer» Correct Answer - B |
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| 161. |
Which of the following correct about `[Icl_(4)]^(-)` and `iCl_(4)` compoundA. both isostructuralB. `[ICl_(4)]^(-)` is square planar and `ICl_(5)` is square pyramidal.C. `[ICl_(4)]^(-)` is square pymidal and `ICl_(5)` is square planar.D. `[ICl_(4)]^(-)` is tetrahedral and `ICl_(5)` is pentagonal bipyramidal. |
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Answer» Correct Answer - B |
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| 162. |
Which of the following on heating with aqueous `KOH` produces acetaldehyde?A. `CH_(3)COCl`B. `CH_(3)CH_(2)Cl`C. `CH_(2)Cl CH_(2)Cl`D. `CH_(3)CHCl_(2)` |
| Answer» Correct Answer - D | |
| 163. |
Which of the following compounds will behave as a reducing sugar in an aqueous KOH solution ?A. B. C. D. |
| Answer» Correct Answer - D | |
| 164. |
In the following reaction, ZnO is respectively acting as a/an (i) `ZnO+Na_(2)O rarr Na_(2)ZnO_(2)` (ii) `ZnO+CO_(2)rarr ZnCO_(3)`A. base and baseB. acid and acidC. acid and baseD. base and acid |
| Answer» Correct Answer - C | |
| 165. |
Ionisation energy of `He^+` is `19.6 xx 10^-18 J "atom"^(-1)`. The energy of the first stationary state `(n = 1)` of `Li^( 2 +)` is.A. `4.41xx10^(-16)"J atom"^(-1)`B. `-4.41xx10^(-17)"J atom"^(-1)`C. `-2.2 xx10^(-15)"J atom"^(-1)`D. `8.82xx10^(-17)"J atom"^(-1)` |
| Answer» Correct Answer - B | |
| 166. |
The major product of the following reaction is : A. B. C. D. |
| Answer» Correct Answer - A | |
| 167. |
The number of 4 digit numbers that can be formed using digits `0,1,2,3,4,5` (repetition allowed) which are greater than `4321` isA. 306B. 310C. 288D. 280 |
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Answer» Correct Answer - B |
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| 168. |
A fruit shop has 5 dozen oranges, 3 dozen mangoes, 6 dozen bananas their selling prices are Rs 60, Rs40, Rs30 each respectively Using matrix algebra the value of the fruits in the shop is |
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Answer» writing the data in the form of matrix matrix A fruit = `12 [ 5, 3 ,6]` `= [60, 36, 72]` matrix B selling price=` [(60),(40),(30)] ` `total amount = A * B` `= [60, 36, 72][(60),(40),(30)]` `= 60*60 + 36*40 + 72*30 ` `= 3600 + 1440 + 2160` `= 7200`Rs answer |
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| 169. |
In order to eliminate the first degree terms from the equation `2x^2+4xy+5y^2-4x-22y+7=0`, the point to which origin is to be shifted is- (1) `(1,-3)` (2) `(2,3)` (3) `(-2,3)` (4) `(1,3)` |
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Answer» `a=2,b=5,h=2,g=-2,f=-11` `((2*-11-5*-2)/(10-4),(-2*2-2*-11)/(10-4))` `((-22+10)/6,(-4+22)/6)` `(-2,3)`. |
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| 170. |
A given object taken n time more time to slide down `45^(@)` rough inclined plane as it taken to slide down a perfectly smooth `45^(@)` incline The coefficient of kintic friction between the object and the incline is .A. `1- 1/(n^(2))`B. `sqrt((1)/(1-n^(2)))`C. `sqrt(1 - 1/(n^(2)))`D. `(1)/(2-n^(2))` |
| Answer» Correct Answer - A | |
| 171. |
A Carnot engine, whose efficiency is `40%`, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency `60%`. Then, the intake temperature for the same exhaust (sink) temperature must be:A. efficiency of Carnot engine cannot be made larger than 50%B. 1200 KC. 750 KD. 600 K |
| Answer» Correct Answer - C | |
| 172. |
A body of mass `m=10^(-2) kg` is moving in a medium and experiences a frictional force `F=-Kupsilon^(2).` Its initial speed is `upsilon_(0)=10ms^(-2)`. If , after `10s`, its energy is `(1)/(8)m upsilon_(0)^(2)`, the value of `k` will beA. `10^(-1)kgm^(-1)s^(-1)`B. `10^(-3)kgm^(-1)`C. `10^(-3)kgs^(-1)`D. `10^(-4)kgm^(-1)` |
| Answer» Correct Answer - D | |
| 173. |
Let `y^(2)=4x` is a parabola. Then minimum area of a circle touching parabola at `(1,2)` as well as `x-`axis isA. `4pi(3-2sqrt(2))`B. `8pi(3-2sqrt(2))`C. `8pi(4-2sqrt(2))`D. `8pi(3-5sqrt(2))` |
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Answer» Correct Answer - B |
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| 174. |
Find the equation of the circle touching the negative `y-`axis at a distance `5` from the origin and intercepting a length `8` on the `x`-axis. |
| Answer» equation of circle`(x-h)^2+(y+5)^2=h^2`line is intecepting on X-axisso, y=0`(x-h)^2+25=h^2``(x-h)^2=h^2-25``x=h+-(h^2-25)` -(1)to find the height`2h^2-50=8``h^2-25=4``h=+-sqrt29` | |
| 175. |
A block of mass `500g` and specific heat `400J//KgK` is attached with a spring of spring constant `800 N//m`. Now block is dipped in water of mass `1kg` and specific heat `4184J//KgK`. Now the spring is elongated by `2cm` and released. Find rise in temperature of water and block system when block finally comes to rest.A. `7.64xx10^(-4)K`B. `3.64xx10^(-3)K`C. `3.64xx10^(-5)K`D. `3.64xx10^(-6)K` |
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Answer» Correct Answer - C |
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| 176. |
A 1 kg block attached to a spring vibrates with a frequency of 1 Hz on a frictionless horizontal table. Two springs identical to the original spring are attached in parallel to an 8 kg block placed on the same table. So, the frequency of vibration of the 8 kg block isA. 2 HzB. `(1)/(4)` HzC. `(1)/(2sqrt(2)) Hz`D. `(1)/(2)` Hz |
| Answer» Correct Answer - D | |
| 177. |
A 1 kg block attached to a spring vibrates with a frequency of 1 Hz on a frictionless horizontal table. Two springs identical to the original spring are attached in parallel to an 8 kg block placed on the same table. So, the frequency of vibration of the 8 kg block isA. 2 HzB. `(1)/(4) Hz`C. `(1)/(2sqrt(2))Hz`D. `(1)/(2)` Hz |
| Answer» Correct Answer - D | |
| 178. |
Proton , deuton and alpha particle of same kinetic energy are moving in circular trajectories in a constant magnetic field. The radii of proton , deuteron and alpha particle are respectively `r_(p), r_(d) and r_(alpha)`. Which one of the following relation is correct?A. `r_(e ) lt r_(alpha) lt r_(p)`B. `r_(e ) gt r_(p)=r_(alpha)`C. `r_(e )lt r_(p) lt=r_(alpha)`D. `r_(e ) lt r_(p) lt r_(alpha)` |
| Answer» Correct Answer - C | |
| 179. |
On interchanging the resistances, the balance point of a meter bridge shifts to the left by 10 cm. The resistance of their series combination is `1 kOmega`. How much was the resistance on the left slot before interchanging the resistances?A. `910 Omega`B. `990 Omega`C. `505 Omega`D. `550 Omega` |
| Answer» Correct Answer - D | |
| 180. |
If the series limit frequency of the Lyman series is `v_(L)`, then the series limit frequency of the Pfund seriesis :A. `v_(L)//25`B. `25 v_(L)`C. `16 v_(L)`D. `v_(L)//16` |
| Answer» Correct Answer - A | |
| 181. |
In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across `0.52 m` of the potentiometer wire. If the cell is shunted by a resistance of `5Omega` balance is obtained when the cell connected across` 0.4m` of the wire. Find the internal resistance of the cell.A. `2.5 Omega`B. `1 Omega`C. `1.5 Omega`D. `2 Omega` |
| Answer» Correct Answer - C | |
| 182. |
The dimension of magnetic field in M, L, T and C (Coulomb) is given as :A. `MLT^(-1)C^(-1)`B. `MT^(-2)C^(-2)`C. `MT^(-1)C^(-1)`D. `MT^(-2)C^(-1)` |
| Answer» Correct Answer - C | |
| 183. |
If `X` is capacitance and `Y` is the magnetic field which are related by `X=2aY^(2)`. Dimension of a will be:-A. `[M^(-1)L^(-2)T^(3)Q^(-3)]`B. `[M^(-3)L^(-2)T^(4)Q^(4)]`C. `[M^(-2)L^(-1)T^(3)Q^(-3)]`D. `[M^(-2)L^(-2)T^(3)Q^(-2)]` |
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Answer» Correct Answer - B |
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| 184. |
A man grows into a giant such that his linear dimension increase by a factor of 9. Assuming that his density remains same, the stress in the leg will change by a factor ofA. `(1)/(81)`B. `9`C. `(1)/(9)`D. 81 |
| Answer» Correct Answer - B | |
| 185. |
Starting from the centre of the earth having radius R, the variation of `g` (acceleration due to gravity) is shown byA. B. C. D. |
| Answer» Correct Answer - A | |
| 186. |
When a current of 5mA is passed through a galvanometer having a coil of resistance `15Omega`, it shows full sacle deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range `0-10V` is:A. `4.005xx10^(3)Omega`B. `1.985xx10^(3)Omega`C. `2.045xx10^(3)Omega`D. `2.535xx10^(3)Omega` |
| Answer» Correct Answer - B | |
| 187. |
In the figure, given that `V_(BB)` supply can vary from 0 to `5.0V,V_(CC)=5V,beta_(dc)=200,R_(B)=100Komega,R_(C)=1Komega` and `V_(BE)=1.0V`, The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively:A. `25muA and 3.5V`B. `20muA and 3.5V`C. `25muA and 2.8V`D. `20muA and 2.8V` |
| Answer» Correct Answer - A | |
| 188. |
In the figure, given that `V_(BB)` supply can vary from 0 to `5.0V,V_(CC)=5V,beta_(dc)=200,R_(B)=100Komega,R_(C)=1Komega` and `V_(BE)=1.0V`, The minimum base current and the input voltage at which the transistor will go to saturation, will be, respectively:A. `25muA and 3.5V`B. `20muA and 3.5V`C. `25muA and 2.8V`D. `20muA and 2.8V` |
| Answer» Correct Answer - A | |
| 189. |
If `alpha` and `beta` be two real roots of the equation `x^3+px^2 + qx r = 0`,`(r!=0)` satisfying the real `alpha beta+1=0`then prove that `r^2 + pr + q + 1 =0`. |
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Answer» `x^3+px^2+qx+r=0` has 3 roots `alpha,beta and gamma` now product of roots=>`alphabetagamma=-r` given `alphabeta=-1` thus`gamma=r` so -r is a root of the equation so it should satisfy it , so replace x with -r we get, `r(r^2+pr+q+1)=0` but r cannot be 0 so=>`(r^2+pr+q+1)=0`. Hence Proved. |
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| 190. |
If `alpha,beta` are the roots of `x^(2)+x+1=0` then `|{:(y+1,beta,alpha),(beta,y+alpha,1),(alpha,1,y+beta):}|`A. `y^(2)-1`B. `y(y^(2)-1)`C. `u^(2)-y`D. `y^(3)` |
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Answer» Correct Answer - D |
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| 191. |
If `c>0` and `4a+c |
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Answer» `f(x) = ax^2 - bx +c` `f(0) = 0-0 +c` `f(0) = c> 0` `f(-2)=4a-2b+c` `4a +c < 2b` `4a +c - 2b < 0` `f(2) < 0` `f(0) > 0 & f(2) < 0` `f(x) ` changes it sign between 0 & 2 answer is `(0,2)` option a is correct |
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| 192. |
If `alpha` and `beta` are roots of the equation `x^(2)+sintheta.x-2sintheta=0` then `(a^(12)+beta^(12))/((a^(-12)+beta^(-12))(alpha-beta)^(24))` is equal toA. `(2^(24))/((8+sintheta)^(12))`B. `(2^(12))/((8+sintheta)^(12))`C. `(2^(12))/((8-sintheta)^(12))`D. `(1)/(2^(24))` |
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Answer» Correct Answer - B |
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| 193. |
Let `alpha & beta` are the roots of `(m^(2)+1)x^(2)-3x+(m+1)^(2)=0`. If sum of roots is maximum then `|alpha^(2)-beta^(3)|=`A. `8sqrt(5)`B. `8sqrt(3)`C. `10sqrt(5)`D. `4sqrt(3)` |
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Answer» Correct Answer - A |
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| 194. |
If `alpha` and `beta` are the roots of `ax^2+bx+c=0`, then the equation `ax^2-bx(x-1)+c(x-1)^2=0` has roots |
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Answer» As `alpha` and `beta` are the roots of `ax^2+bx+c = 0`. `:. alpha+beta = -b/a and alphabeta = c/a` Now, second equation is, `ax^2-bx(x-1)+c(x-1)^2 = 0` `=>(a-b+c)x^2-x(b-2c)+c = 0` Let `m` and `n` are the roots of this equation. Then, `mn = c/(a-b+c) = (c/a)/(1-b/a+c/a)` `=(alpha beta)/(1+(alpha+beta)+alpha beta)` `=(alpha beta)/((1+alpha)+beta(1+alpha))` `:. mn=(alpha beta)/((1+alpha)(1+beta))->(1)` Now, `m+n = (2c-b)/(a-b+c) = ((2c)/a - b/a)/(1-b/a+c/a)` `= (2alpha beta + alpha+ beta)/(1+(alpha+beta)+alpha beta)` `= (alpha beta + alpha beta+ alpha+ beta)/(1+(alpha+beta)+alpha beta)` `= (alpha(beta+1)+beta(alpha+1))/((1+alpha)(1+beta))` `m+n= alpha/(alpha+1)+ beta/(beta+1)->(2)` From (1) and (2), `m = alpha/(alpha+1), n = beta/(beta+1)` |
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| 195. |
Time (T), velocity (3) and angular momentum (h) are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would beA. `[M]=[T^(-1)C^(-2)h]`B. `[M]=[TC^(-2)h]`C. `[M]=[T^(-1)C^(-2)h^(-2)]`D. `[M]=[T^(-1)C^(2)h]` |
| Answer» Correct Answer - A | |
| 196. |
` tan alpha + 2 tan 2alpha + 4 tan4alpha + 8 cot8alpha` is equal to : |
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Answer» `8cot8alpha` `8(cot^24alpha-1)/(2cot4alpha)` `4cot4alpha-4tan4alpha` `4(cot^2 2alpha-1)/(2cot2alpha)-4tan4alpha` `2cot2alpha-2tan2alpha-4tan4alpha` `cotalpha-tanalpha-2tan2alpha-4tan4alpha` `=cotalpha` option c is correct. |
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| 197. |
A solenoid has fixed N number of turns and fixed radius `a` its length is given by `l` which can be varied its self-inductance is proportional toA. `l`B. `(1)/(l)`C. `l^(2)`D. `(1)/(l^(2))` |
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Answer» Correct Answer - B |
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| 198. |
Some energy levels of a molecule are shown in the figure. The ratio of the wavelength `r=lamda_(1)lamda_(2)`,is given by:A. `r=(1)/(3)`B. `r=(4)/(3)`C. `r=(2)/(3)`D. `r=(3)/(4)` |
| Answer» Correct Answer - A | |
| 199. |
Two identical non-re,aticivistic particles move at right angle to each other. Possesing de Broglie wavelength `lambda_(1)` and `lambda_(2)` Find the Broglie wavelength of each particle in the frame of their centre of inertia.A. `lambda_(CM) = ((lambda_(1) +lambda_(2))/(2))`B. `lambda_(CM) = (2lambda_(1) lambda_(2))/(sqrt(lambda_(1)^(2) +lambda_(2)^(2)))`C. `lambda_(CM) = lambda_(1) = lambda_(2)`D. `1/(lambda_(CM))= (1)/(lambda_(1)) +(1)/(lambda_(2))` |
| Answer» Correct Answer - B | |
| 200. |
Four charges are arranged on y axis as shown in figure. Then the electric field at point P is proportional to:A. `(1)/(d)`B. `(1)/(d^(2))`C. `(1)/(d^(4))`D. `0` |
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Answer» Correct Answer - B |
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