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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
401. |
An ideal gas undergoes a cyclic process as shown in figure `delta U_(BC)` = `-5 KJ mol^(-1)`, `q_(AB) = 2 KJ mol^(-1)`, `W_(AB) = -5 KJ mol^(-1)`, `W_(CA) = 3 KJ mol^(-1)` Heat absorbed by the system during process CA is:. A. `-5 k mol^(-1)`B. `+5 kJ mol^(-1)`C. `-18 kJ mol^(-1)`D. `-18 kJ mol^(-1)` |
Answer» Correct Answer - B | |
402. |
Which of the following exists as covalent crystals in the solid state?A. SiliconB. SulphurC. PhosphorousD. Iodine |
Answer» Correct Answer - A | |
403. |
P is a point on the circle `x^2+y^2=9` Q is a point on the line `7x+y+3=0`. The perpendicular bisector of PQ is `x-y+1=0`. Then the coordinates of P are: |
Answer» `|(m-1)/(1+m)|=|(1+7)/(1-7)|` `|(m-1)/(1+m)|=4/3` `(m-1)/(1+m)=4/3,-4/3` `3m-3=4+4m,3m-3=-4=4m` `m=-7,-1/7` `(y-1/2)=-1/7(x+1/2)` `7y+x-3=0` `x^2+y^2=9` `48y^2-42y+9+y^2=9` `50y^2-42y=0` `y=0,21/25` `x=3,-72/25` `(3,0),(-72/25,21/25)`. |
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404. |
The major product formed in the following reation is `CH_(3)-underset(H)underset(|)overset(CH_(3))overset(|)C-CH_(2)-Br underset(CH_(3)OH)overset(CH_(3)ONa)rarr` .A. `CH_(3)CH=CH-CH=CHCH_(3)`B. `CH_(2)=CHCH=CHCH_(2)CH_(3)`C. `CH_(3)CH=C=CHCH_(2)CH_(3)`D. `CH_(2)=CHCH_(2)CH=CHCH_(3)` |
Answer» Correct Answer - A | |
405. |
In which one of the following reactions, hydrogen is acts as an oxidising agent ?A. `HOCl+ H_(2)O_(2) to H_(3)O^(+) + Cl^(-) + O_(2)`B. `I_(2) + H_(2)O_(2) + 2OH^(-) to 2H_(2)O + O_(2)`C. `PbS + 4H_(2)O_(2) to PbSO_(4) + 4H_(2)O`D. `2MnO_(4)^(-) + 3H_(2)O_(2) to 2MnO_(2) + 3O_(2) + 2H_(2)O + 2OH^(-)` |
Answer» Correct Answer - C | |
406. |
Hysteresis loops for two magnetic materials `A and B` are given below : These materials are used to make magnets for electric generators , transformer core and electromagnet core. Then it is proper to use :A. A for electromagnets and B for electric generatorsB. A for transformers and B for electric generatorsC. B for electromagnets and transformersD. A for electric generators and transformers |
Answer» Correct Answer - C | |
407. |
The treatment of `CH_(3)MgX` with `CH_(3)-C-=C-H` producesA. `CH_(3) - CH = CH_(2)`B. `CH_(3)C -= C - CH_(3)`C. `CH_(3) -overset(H) overset(|)(C) = overset(H)overset(|)(C) - CH_(3)`D. `CH_(4)` |
Answer» Correct Answer - D | |
408. |
In a compound ,atoms of element Y from ccp lattice and those of element X occupy 2/3rd tetrahedral voids.The formula of the compound will be:A. `X_(4)Y_(3)`B. `X_(2)Y_(3)`C. `X_(2)Y`D. `X_(3)Y_(4)` |
Answer» Correct Answer - A | |
409. |
Lights of wavelength 550 nm falls normally on a slit of width k`22.0 xx 10^(-5) cm`. The angular position of the central maximum will be (in radian) :A. `pi/6`B. `(pi)/(4)`C. `(pi)/(8)`D. `(pi)/(12)` |
Answer» Correct Answer - C | |
410. |
A body of mass m is moving in a circular orbit of radius R about a planet of mass M. At some instant, it splits into two equal masses. The first mass moves in a circular orbit of radius `R/2`. And the other mass, in a circular orbit of radius `(3R)/(2)`. The difference between the final and initial total energies is :A. `- (GMm)/(2R)`B. `(GMm)/(2R)`C. `-(GMm)/(6R)`D. `+(GMm)/(6R)` |
Answer» Correct Answer - C | |
411. |
A tuning fork vibrats with frequnecy `256 Hz` and gives one beat per seond with the third normal mode of vibration of an open pipe. What is the length of the pipe (Speed of sound in air is `340 ms^(-1)`)A. 190 cmB. 200 cmC. 220 cmD. 180 cm |
Answer» Correct Answer - B | |
412. |
The equivalent capacitance between A and B in the circuit given below , is : A. `3.6muF`B. `4.9 muF`C. `5.4muF`D. `2.4 muF` |
Answer» Correct Answer - D | |
413. |
`0.1M HCl` is added to an unknown strength of `NaOH` solution. Identify the correct diagramA. B. C. D. |
Answer» Correct Answer - B |
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414. |
Which of the following statement is incorrect about the given energy profile diagram. A. C is thermodynamically most stableB. D is kinetically most stableC. Activation energy for making `A+B` from `C` is the maximumD. Enthalpy to form `C` is `5kJ` less than to that to form `D`. |
Answer» Correct Answer - D |
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415. |
In a given polymers which is a condensation polymers.A. TeflonB. NeopreneC. Buna-SD. Nylon-6,6 |
Answer» Correct Answer - D |
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416. |
What is the value of spin only magnetic moment of anionic and cationic part of complex `[Fe(H_(2)O)_(6)]_(2)` `[Fe(CN)_(6)]`A. `4.9 B.M` & zeroB. zero and 4.9 B.MC. 2.9 B.M. and 0D. 0 and 2.9 B.M. |
Answer» Correct Answer - B |
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417. |
A particle of mass `20 g` is released with an initial velocity `5m//s` along the curve from the point A, as shown in the figure. The point A is at height h from point B. The particle slides along the frictionless surface. When the particle reaches point B, its angular momentum about O will be : (Take `g=10m//s^2`). A. `2kg-m^2//s`B. `8kg-m^2//s`C. `6kg-m^2//s`D. `3kg-m^2//s` |
Answer» Correct Answer - A | |
418. |
If wavelength of particle moment `P` is equal to `lamda`, then what will be its wavelength for momentum 1.5PA. `(2)/(3)lamda`B. `(4)/(3)lamda`C. `(3)/(2)lamda`D. `lamda` |
Answer» Correct Answer - A |
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419. |
Biuret test is not given by:A. carbohydratesB. polypeptidesC. ureaD. proteins |
Answer» Correct Answer - A | |
420. |
Which one of the following will most readily be dehydrated in acidic condition?A. 3-Hydroxypentan-2-oneB. 4-Hydroxypentan-2-oneC. 1-pentanolD. 2-Hydroxycyclopentanone |
Answer» Correct Answer - B | |
421. |
The major product of the following reaction is A. B. C. D. |
Answer» Correct Answer - BCORRECT OPTION B COCL WILL REACT 1ST. |
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422. |
Number of zeroes at the end of `99^(1001)+1`? |
Answer» `(100-1)^(1001)+1` `(-1101*1000)/2*(100)^2+1001*100-1+1` `-1001*500*(100)^2+100100-1+1` `100100` Number of zero at the end=2. |
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423. |
Match List - I (Fundamental Experiment) with List - II (its conclusion) and select the correct option from the choice given below the list : A. (A) - (ii) (B) - (iv) (C) - (iii)B. (A) - (ii) (B) - (i) (C) - (iii)C. (A) - (iv) (B) - (iii) (C) - (ii)D. (A) - (i) (B) - (iv) (C) - (iii) |
Answer» Correct Answer - B | |
424. |
From a solid sphere of M and radius R a cube of maximum possible volume is cut. Moment of inertia of cube about an axis passing through its centre and perpendiular to one of its faces is:A. `(MR^(2))/(16 sqrt(2pi))`B. `(4MR^(2))/(9sqrt(3pi))`C. `(4MR^(2))/(3sqrt(3pi))`D. `(MR^(2))/(32sqrt(2pi))` |
Answer» Correct Answer - B | |
425. |
A particle is released at point A. Find Kinetic energy at point P Given m = 1 kg and all surfaces are frictionless |
Answer» Correct Answer - 10 | |
426. |
if `cos^(-1)x-cos^(-1)(y//2)=alpha,x in [-1,1],y in [-2,2]` then the value of `4x^(2)-4xycosalpha+y^(2)` isA. `4sin^(2)alpha`B. `2sin^(2)alpha`C. `4cos^(2)alpha`D. `2cos^(2)cos^(2)alpha` |
Answer» Correct Answer - A |
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427. |
The maximum value of `f(x)=(2x^2+2x+4)/(x^2+x+1) AA x in [0,1] is ` |
Answer» `f(x) = (2x^2+2x+4)/(x^2+x+1)` `=>f(x) = (2(x^2+x+2))/(x^2+x+1)` `=>f(x) = (2(x^2+x+1+1))/(x^2+x+1)` `=>f(x) = 2(1+1/(x^2+x+1))` Now, `f(x)` will be maximum when `x^2+x+1` is minimum. Now, we will try to draw the graph for `x^2+x+1.` Please refer to video to see the grah. From the graph, we can see that minimum value of `x^2+x+1` is `1` as `x in [0,1]`. `:. f(x)_max = 2(1+1/1) = 4` |
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428. |
Prove that`(tan 25^@-tan 35^@ +tan 85^@)/(tan 25^@ tan 35^@ tan 85^@)`= 3 |
Answer» Here, we will use, `tanxtan(60^@-x)tan(60^@+x) = tan3x` `tanx+tan(60^@+x)+tan(120^@+x) = 3tan3x` Now, `L.H.S. = (tan25^@ - tan35^@+tan85^@)/(tan25^@ tan35^@tan85^@)` `= (tan25^@ + tan(180-35)^@+tan85^@)/(tan25^@ tan(60-25)^@tan(60+25)^@)` `= (tan25^@ +tan85^@+tan 145^@)/(tan25^@ tan(60-25)^@tan(60+25)^@)` `= (tan25^@ +tan(60+25)^@+tan(120+25)^@)/(tan25^@ tan(60-25)^@tan(60+25)^@)` Now, using the above identities, `=(3tan75^@)/tan75^@` `=3 = R.H.S.` |
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429. |
A non-isotropic solid metal cube has coefficients of linear expansion as` 5 xx 10^(–5) //'^(@)C` along the x-axis and` 5 xx 10^(–6)//""^(@)C `along the y and the z-axis. If coefficient of volume expansion of the solid is `C xx 10^(–6) //""^(@)C` then the value of C is |
Answer» Correct Answer - 60 | |
430. |
number of real solutions of the equation `|cotx|= cotx + 1/ sin x` `(0 |
Answer» `|cotx| = cotx +1/sinx` `cotx` will be positive when `x in (0,pi/2)`. `:. x in (0,pi/2)`, `cotx = cotx +1/sinx` `=>1/sinx = 0` `=>sinx = oo` We know, maximum value of `sin x` is `1.` So, no solution possible when `x in (0,pi/2)`. `cotx` will be negative when `x in (pi/2,pi)`. `:. x in (pi/2,pi)`, `-cotx = cotx +1/sinx` `=>-2cotx = 1/sinx` `=>-2cosx/sinx = 1/sinx` `=>cosx = -1/2` `=>x = (2pi)/3` So, `x = (2pi)/3` is the only solution available for the given equation. `:.` Number of solutions for this equation is `1`. |
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431. |
An inverted cone with semi vertical angle `0=tan^(-1)((1)/(2))` is being filled with water at the rate of `5cm^(3)` min. Then the rate of change of height of water when height of water is `10cm` isA. `(2)/(3pi)cm//min`B. `(3)/(2pi)cm//min`C. `(1)/(5pi)cm//min`D. `(2)/(5pi)cm//min` |
Answer» Correct Answer - C |
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432. |
The coefficient of `x^20` in the expansion of `(1+x^2)^40.(x^2+2+1/x^2)^-5` is: |
Answer» `(1+x^2)^40(x^2+2+1/x^2)^(-5)` `=(1+x^2)^40[(x+1/x)^2]^-5` `=(1+x^2)^40[((x^2+1)/x)^2]^-5` `=(1+x^2)^30[1/x^2]^-5` `=(1+x^2)^30x^10` `=x^10(C(30,0)*1+C(30,1)x^2+C(30,2)x^4+C(30,3)x^6+C(30,4)x^8+C(30,5)x^10+...C(30,30)x^60)` So, term with involving `x^20` will be `C(30,5)x^20`. So, coefficient of `x^20` will be `C(30,5).` Also, `C(30,5) = C(30,25)` So, option `(b)` is the correct option. |
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433. |
Number of real solution of the equation `x^(2)+|2^(n)-1|=2^(x)(2^(x)-2)` is |
Answer» Correct Answer - B |
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434. |
If the sum of first `3` terms of an `A.P.` is `33` and their product is `1155`. Then the `11^(th)` term of the `A.P`. IsA. `25`B. `25`C. `36`D. `-36` |
Answer» Correct Answer - A |
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435. |
If the coefficient of x in binomial expansion of expression `(x^(2)+(1)/(x^(3)))^(n)` is `.^(n)C_(23)`. Then the minimum value of `n` isA. 28B. 48C. 58D. 38 |
Answer» Correct Answer - D |
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436. |
Sum of the series `1+2.3+3.5+4.7+........` up to `11` terms isA. 942B. 892C. 946D. 960 |
Answer» Correct Answer - C |
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437. |
If the ratio of coefficients of the three consecutives terms in binomial expansion of `(1+x)^(n)` is `2: 5: 70.` Then the average of these coeficients isA. 227B. 232C. 964D. 804 |
Answer» Correct Answer - B |
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438. |
If `PrArr(q v r)` is false then truth value of `p,q,r` is respectivelyA. TTTB. FFFC. FTTD. TFF |
Answer» Correct Answer - D |
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439. |
The element that does NOT show catenation is :A. GeB. SiC. SnD. Pb |
Answer» Correct Answer - A | |
440. |
Among the following, the false statement is :A. It is possible to cause artificial rain by throwing electrified sand carrying charge opposite to the one on clouds from an aeroplane.B. Tyndall effect can be used to distinguish between a colloidal solution and a true solution.C. Lyophilic sol can be coagulated by adding an electrolyte.D. Latex is a colloidal solution of rubber particles which are positively charged. |
Answer» Correct Answer - A | |
441. |
The correct structure of histidine in a strongly acidic solution `(Ph=2)` is :A. B. C. D. |
Answer» Correct Answer - A | |
442. |
The major proudct of the following reaction is : A. B. C. D. |
Answer» Correct Answer - A | |
443. |
`CH_(3)-underset(CH_(3))underset(|)(CH)-underset(H)underset(|)overset(Cl)overset(|)(C)-CH_(3)overset(CH_(3)OH)to` major product isA. `CH_(3)-underset(CH_(3))underset(|)(CH)-overset(OCH_(3))overset(|)(CH)-CH_(3)`B. `CH_(3)-underset(CH_(3))underset(|)overset(OCH_(3))overset(|)(C)-CH_(2)-CH_(3)`C. `CH_(3)-underset(CH_(3))underset(|)(C)=CH-CH_(3)`D. `CH_(3)-underset(CH_(3))underset(|)(CH)-CH=CH_(2)` |
Answer» Correct Answer - B |
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444. |
in `Sc^(3+),Ti^(2+),Ti^(3+),V^(2+)` increasing order of spin only magnetic moment is:A. `Sc^(3+)ltTi^(2+)ltTi^(3+)ltV^(2+)`B. `Sc^(3+)ltTi^(3+)ltTi^(2+)ltV^(2+)`C. `Ti^(2+)ltSc^(3+)ltTi^(3+)ltV^(2+)`D. `Sc^(3+)ltTi^(2+)ltV^(2+)ltTi^(3+)` |
Answer» Correct Answer - B |
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445. |
Which species is diamagnetic and have shortest bond length?A. `C_(2^(-2))`B. `N_(2^(-2))`C. `O_(2^(-2))`D. `O_(2)` |
Answer» Correct Answer - B |
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446. |
Calculate depression in freezing point of `0.03 m` solution of `K_(2)SO_(4)` (assumed ionised) in a solvent with `K_(f)=4K kg "mol"^(-1)`A. `0.36K`B. `0.12K`C. `0.48K`D. `0.24K` |
Answer» Correct Answer - A |
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447. |
`20% (W)/(W)Kl` will have molality _ (given `GMM=166gm`)A. `1.35`B. `1.51`C. `1.48`D. `1.30` |
Answer» Correct Answer - B |
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448. |
The locus of the point of intersection of tangents of `x^2/a^2 + y^2/b^2 =1` at two points whose eccentric angles differ by `pi/2` is an ellipse whose semi-axes are: (A) `sqrt2 a,sqrt 2 b`(B) `a/sqrt2,b/sqrt2` (C) `a/2,b/2` (D) `2a,2b` |
Answer» Let the points on ellipse be`p(acos(theta),bsin(theta))` and `Q(acos(pi/2+theta),bsin(pi/2+theta))=(-asintheta,bcostheta)` Equation of tangent at point p: `x/acostheta+y/bsintheta=1` Equation of tangent at point Q: `-x/asintheta+y/bcostheta=1` On solving these equations we get,`x/a=(costheta-sintheta)` `y/b=(costheta+sintheta)` On squaring and adding these equations, `2=(x/a)^2+ (y/b)^2`Therefore, `(x/(asqrt2))^2+(y/(bsqrt2))^2=1` |
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449. |
Light in incident on a metal plate whose work function is 2 eV. Electric field associated with light is given by `E=E_(0)sin(omegat-(2pi)/(5xx10^(7))x)`{ S.I unit} if energy of photom is given by `(12375)/(lamda("in"A))` eV then stopping potential isA. `2.48eV`B. `0.48eV`C. `0.78eV`D. `1.24eV` |
Answer» Correct Answer - B |
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450. |
Wavelength of the first line of balmer seris is 600 nm. The wavelength of second line of the balmer series will beA. 444 nmB. 800 nmC. 388 nmD. 632 nm |
Answer» Correct Answer - A |
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