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401.

An ideal gas undergoes a cyclic process as shown in figure `delta U_(BC)` = `-5 KJ mol^(-1)`, `q_(AB) = 2 KJ mol^(-1)`, `W_(AB) = -5 KJ mol^(-1)`, `W_(CA) = 3 KJ mol^(-1)` Heat absorbed by the system during process CA is:. A. `-5 k mol^(-1)`B. `+5 kJ mol^(-1)`C. `-18 kJ mol^(-1)`D. `-18 kJ mol^(-1)`

Answer» Correct Answer - B
402.

Which of the following exists as covalent crystals in the solid state?A. SiliconB. SulphurC. PhosphorousD. Iodine

Answer» Correct Answer - A
403.

P is a point on the circle `x^2+y^2=9` Q is a point on the line `7x+y+3=0`. The perpendicular bisector of PQ is `x-y+1=0`. Then the coordinates of P are:

Answer» `|(m-1)/(1+m)|=|(1+7)/(1-7)|`
`|(m-1)/(1+m)|=4/3`
`(m-1)/(1+m)=4/3,-4/3`
`3m-3=4+4m,3m-3=-4=4m`
`m=-7,-1/7`
`(y-1/2)=-1/7(x+1/2)`
`7y+x-3=0`
`x^2+y^2=9`
`48y^2-42y+9+y^2=9`
`50y^2-42y=0`
`y=0,21/25`
`x=3,-72/25`
`(3,0),(-72/25,21/25)`.
404.

The major product formed in the following reation is `CH_(3)-underset(H)underset(|)overset(CH_(3))overset(|)C-CH_(2)-Br underset(CH_(3)OH)overset(CH_(3)ONa)rarr` .A. `CH_(3)CH=CH-CH=CHCH_(3)`B. `CH_(2)=CHCH=CHCH_(2)CH_(3)`C. `CH_(3)CH=C=CHCH_(2)CH_(3)`D. `CH_(2)=CHCH_(2)CH=CHCH_(3)`

Answer» Correct Answer - A
405.

In which one of the following reactions, hydrogen is acts as an oxidising agent ?A. `HOCl+ H_(2)O_(2) to H_(3)O^(+) + Cl^(-) + O_(2)`B. `I_(2) + H_(2)O_(2) + 2OH^(-) to 2H_(2)O + O_(2)`C. `PbS + 4H_(2)O_(2) to PbSO_(4) + 4H_(2)O`D. `2MnO_(4)^(-) + 3H_(2)O_(2) to 2MnO_(2) + 3O_(2) + 2H_(2)O + 2OH^(-)`

Answer» Correct Answer - C
406.

Hysteresis loops for two magnetic materials `A and B` are given below : These materials are used to make magnets for electric generators , transformer core and electromagnet core. Then it is proper to use :A. A for electromagnets and B for electric generatorsB. A for transformers and B for electric generatorsC. B for electromagnets and transformersD. A for electric generators and transformers

Answer» Correct Answer - C
407.

The treatment of `CH_(3)MgX` with `CH_(3)-C-=C-H` producesA. `CH_(3) - CH = CH_(2)`B. `CH_(3)C -= C - CH_(3)`C. `CH_(3) -overset(H) overset(|)(C) = overset(H)overset(|)(C) - CH_(3)`D. `CH_(4)`

Answer» Correct Answer - D
408.

In a compound ,atoms of element Y from ccp lattice and those of element X occupy 2/3rd tetrahedral voids.The formula of the compound will be:A. `X_(4)Y_(3)`B. `X_(2)Y_(3)`C. `X_(2)Y`D. `X_(3)Y_(4)`

Answer» Correct Answer - A
409.

Lights of wavelength 550 nm falls normally on a slit of width k`22.0 xx 10^(-5) cm`. The angular position of the central maximum will be (in radian) :A. `pi/6`B. `(pi)/(4)`C. `(pi)/(8)`D. `(pi)/(12)`

Answer» Correct Answer - C
410.

A body of mass m is moving in a circular orbit of radius R about a planet of mass M. At some instant, it splits into two equal masses. The first mass moves in a circular orbit of radius `R/2`. And the other mass, in a circular orbit of radius `(3R)/(2)`. The difference between the final and initial total energies is :A. `- (GMm)/(2R)`B. `(GMm)/(2R)`C. `-(GMm)/(6R)`D. `+(GMm)/(6R)`

Answer» Correct Answer - C
411.

A tuning fork vibrats with frequnecy `256 Hz` and gives one beat per seond with the third normal mode of vibration of an open pipe. What is the length of the pipe (Speed of sound in air is `340 ms^(-1)`)A. 190 cmB. 200 cmC. 220 cmD. 180 cm

Answer» Correct Answer - B
412.

The equivalent capacitance between A and B in the circuit given below , is : A. `3.6muF`B. `4.9 muF`C. `5.4muF`D. `2.4 muF`

Answer» Correct Answer - D
413.

`0.1M HCl` is added to an unknown strength of `NaOH` solution. Identify the correct diagramA. B. C. D.

Answer» Correct Answer - B
414.

Which of the following statement is incorrect about the given energy profile diagram. A. C is thermodynamically most stableB. D is kinetically most stableC. Activation energy for making `A+B` from `C` is the maximumD. Enthalpy to form `C` is `5kJ` less than to that to form `D`.

Answer» Correct Answer - D
415.

In a given polymers which is a condensation polymers.A. TeflonB. NeopreneC. Buna-SD. Nylon-6,6

Answer» Correct Answer - D
416.

What is the value of spin only magnetic moment of anionic and cationic part of complex `[Fe(H_(2)O)_(6)]_(2)` `[Fe(CN)_(6)]`A. `4.9 B.M` & zeroB. zero and 4.9 B.MC. 2.9 B.M. and 0D. 0 and 2.9 B.M.

Answer» Correct Answer - B
417.

A particle of mass `20 g` is released with an initial velocity `5m//s` along the curve from the point A, as shown in the figure. The point A is at height h from point B. The particle slides along the frictionless surface. When the particle reaches point B, its angular momentum about O will be : (Take `g=10m//s^2`). A. `2kg-m^2//s`B. `8kg-m^2//s`C. `6kg-m^2//s`D. `3kg-m^2//s`

Answer» Correct Answer - A
418.

If wavelength of particle moment `P` is equal to `lamda`, then what will be its wavelength for momentum 1.5PA. `(2)/(3)lamda`B. `(4)/(3)lamda`C. `(3)/(2)lamda`D. `lamda`

Answer» Correct Answer - A
419.

Biuret test is not given by:A. carbohydratesB. polypeptidesC. ureaD. proteins

Answer» Correct Answer - A
420.

Which one of the following will most readily be dehydrated in acidic condition?A. 3-Hydroxypentan-2-oneB. 4-Hydroxypentan-2-oneC. 1-pentanolD. 2-Hydroxycyclopentanone

Answer» Correct Answer - B
421.

The major product of the following reaction is A. B. C. D.

Answer» Correct Answer - BCORRECT OPTION B

COCL WILL REACT 1ST.
422.

Number of zeroes at the end of `99^(1001)+1`?

Answer» `(100-1)^(1001)+1`
`(-1101*1000)/2*(100)^2+1001*100-1+1`
`-1001*500*(100)^2+100100-1+1`
`100100`
Number of zero at the end=2.
423.

Match List - I (Fundamental Experiment) with List - II (its conclusion) and select the correct option from the choice given below the list : A. (A) - (ii) (B) - (iv) (C) - (iii)B. (A) - (ii) (B) - (i) (C) - (iii)C. (A) - (iv) (B) - (iii) (C) - (ii)D. (A) - (i) (B) - (iv) (C) - (iii)

Answer» Correct Answer - B
424.

From a solid sphere of M and radius R a cube of maximum possible volume is cut. Moment of inertia of cube about an axis passing through its centre and perpendiular to one of its faces is:A. `(MR^(2))/(16 sqrt(2pi))`B. `(4MR^(2))/(9sqrt(3pi))`C. `(4MR^(2))/(3sqrt(3pi))`D. `(MR^(2))/(32sqrt(2pi))`

Answer» Correct Answer - B
425.

A particle is released at point A. Find Kinetic energy at point P Given m = 1 kg and all surfaces are frictionless

Answer» Correct Answer - 10
426.

if `cos^(-1)x-cos^(-1)(y//2)=alpha,x in [-1,1],y in [-2,2]` then the value of `4x^(2)-4xycosalpha+y^(2)` isA. `4sin^(2)alpha`B. `2sin^(2)alpha`C. `4cos^(2)alpha`D. `2cos^(2)cos^(2)alpha`

Answer» Correct Answer - A
427.

The maximum value of `f(x)=(2x^2+2x+4)/(x^2+x+1) AA x in [0,1] is `

Answer» `f(x) = (2x^2+2x+4)/(x^2+x+1)`
`=>f(x) = (2(x^2+x+2))/(x^2+x+1)`
`=>f(x) = (2(x^2+x+1+1))/(x^2+x+1)`
`=>f(x) = 2(1+1/(x^2+x+1))`
Now, `f(x)` will be maximum when `x^2+x+1` is minimum.
Now, we will try to draw the graph for `x^2+x+1.`
Please refer to video to see the grah.
From the graph, we can see that minimum value of `x^2+x+1` is `1` as `x in [0,1]`.
`:. f(x)_max = 2(1+1/1) = 4`
428.

Prove that`(tan 25^@-tan 35^@ +tan 85^@)/(tan 25^@ tan 35^@ tan 85^@)`= 3

Answer» Here, we will use,
`tanxtan(60^@-x)tan(60^@+x) = tan3x`
`tanx+tan(60^@+x)+tan(120^@+x) = 3tan3x`
Now,
`L.H.S. = (tan25^@ - tan35^@+tan85^@)/(tan25^@ tan35^@tan85^@)`
`= (tan25^@ + tan(180-35)^@+tan85^@)/(tan25^@ tan(60-25)^@tan(60+25)^@)`
`= (tan25^@ +tan85^@+tan 145^@)/(tan25^@ tan(60-25)^@tan(60+25)^@)`
`= (tan25^@ +tan(60+25)^@+tan(120+25)^@)/(tan25^@ tan(60-25)^@tan(60+25)^@)`
Now, using the above identities,
`=(3tan75^@)/tan75^@`
`=3 = R.H.S.`
429.

A non-isotropic solid metal cube has coefficients of linear expansion as` 5 xx 10^(–5) //'^(@)C` along the x-axis and` 5 xx 10^(–6)//""^(@)C `along the y and the z-axis. If coefficient of volume expansion of the solid is `C xx 10^(–6) //""^(@)C` then the value of C is

Answer» Correct Answer - 60
430.

number of real solutions of the equation `|cotx|= cotx + 1/ sin x` `(0

Answer» `|cotx| = cotx +1/sinx`
`cotx` will be positive when `x in (0,pi/2)`.
`:. x in (0,pi/2)`,
`cotx = cotx +1/sinx`
`=>1/sinx = 0`
`=>sinx = oo`
We know, maximum value of `sin x` is `1.`
So, no solution possible when `x in (0,pi/2)`.
`cotx` will be negative when `x in (pi/2,pi)`.
`:. x in (pi/2,pi)`,
`-cotx = cotx +1/sinx`
`=>-2cotx = 1/sinx`
`=>-2cosx/sinx = 1/sinx`
`=>cosx = -1/2`
`=>x = (2pi)/3`
So, `x = (2pi)/3` is the only solution available for the given equation.
`:.` Number of solutions for this equation is `1`.
431.

An inverted cone with semi vertical angle `0=tan^(-1)((1)/(2))` is being filled with water at the rate of `5cm^(3)` min. Then the rate of change of height of water when height of water is `10cm` isA. `(2)/(3pi)cm//min`B. `(3)/(2pi)cm//min`C. `(1)/(5pi)cm//min`D. `(2)/(5pi)cm//min`

Answer» Correct Answer - C
432.

The coefficient of `x^20` in the expansion of `(1+x^2)^40.(x^2+2+1/x^2)^-5` is:

Answer» `(1+x^2)^40(x^2+2+1/x^2)^(-5)`
`=(1+x^2)^40[(x+1/x)^2]^-5`
`=(1+x^2)^40[((x^2+1)/x)^2]^-5`
`=(1+x^2)^30[1/x^2]^-5`
`=(1+x^2)^30x^10`
`=x^10(C(30,0)*1+C(30,1)x^2+C(30,2)x^4+C(30,3)x^6+C(30,4)x^8+C(30,5)x^10+...C(30,30)x^60)`
So, term with involving `x^20` will be `C(30,5)x^20`.
So, coefficient of `x^20` will be `C(30,5).`
Also, `C(30,5) = C(30,25)`
So, option `(b)` is the correct option.
433.

Number of real solution of the equation `x^(2)+|2^(n)-1|=2^(x)(2^(x)-2)` is

Answer» Correct Answer - B
434.

If the sum of first `3` terms of an `A.P.` is `33` and their product is `1155`. Then the `11^(th)` term of the `A.P`. IsA. `25`B. `25`C. `36`D. `-36`

Answer» Correct Answer - A
435.

If the coefficient of x in binomial expansion of expression `(x^(2)+(1)/(x^(3)))^(n)` is `.^(n)C_(23)`. Then the minimum value of `n` isA. 28B. 48C. 58D. 38

Answer» Correct Answer - D
436.

Sum of the series `1+2.3+3.5+4.7+........` up to `11` terms isA. 942B. 892C. 946D. 960

Answer» Correct Answer - C
437.

If the ratio of coefficients of the three consecutives terms in binomial expansion of `(1+x)^(n)` is `2: 5: 70.` Then the average of these coeficients isA. 227B. 232C. 964D. 804

Answer» Correct Answer - B
438.

If `PrArr(q v r)` is false then truth value of `p,q,r` is respectivelyA. TTTB. FFFC. FTTD. TFF

Answer» Correct Answer - D
439.

The element that does NOT show catenation is :A. GeB. SiC. SnD. Pb

Answer» Correct Answer - A
440.

Among the following, the false statement is :A. It is possible to cause artificial rain by throwing electrified sand carrying charge opposite to the one on clouds from an aeroplane.B. Tyndall effect can be used to distinguish between a colloidal solution and a true solution.C. Lyophilic sol can be coagulated by adding an electrolyte.D. Latex is a colloidal solution of rubber particles which are positively charged.

Answer» Correct Answer - A
441.

The correct structure of histidine in a strongly acidic solution `(Ph=2)` is :A. B. C. D.

Answer» Correct Answer - A
442.

The major proudct of the following reaction is : A. B. C. D.

Answer» Correct Answer - A
443.

`CH_(3)-underset(CH_(3))underset(|)(CH)-underset(H)underset(|)overset(Cl)overset(|)(C)-CH_(3)overset(CH_(3)OH)to` major product isA. `CH_(3)-underset(CH_(3))underset(|)(CH)-overset(OCH_(3))overset(|)(CH)-CH_(3)`B. `CH_(3)-underset(CH_(3))underset(|)overset(OCH_(3))overset(|)(C)-CH_(2)-CH_(3)`C. `CH_(3)-underset(CH_(3))underset(|)(C)=CH-CH_(3)`D. `CH_(3)-underset(CH_(3))underset(|)(CH)-CH=CH_(2)`

Answer» Correct Answer - B
444.

in `Sc^(3+),Ti^(2+),Ti^(3+),V^(2+)` increasing order of spin only magnetic moment is:A. `Sc^(3+)ltTi^(2+)ltTi^(3+)ltV^(2+)`B. `Sc^(3+)ltTi^(3+)ltTi^(2+)ltV^(2+)`C. `Ti^(2+)ltSc^(3+)ltTi^(3+)ltV^(2+)`D. `Sc^(3+)ltTi^(2+)ltV^(2+)ltTi^(3+)`

Answer» Correct Answer - B
445.

Which species is diamagnetic and have shortest bond length?A. `C_(2^(-2))`B. `N_(2^(-2))`C. `O_(2^(-2))`D. `O_(2)`

Answer» Correct Answer - B
446.

Calculate depression in freezing point of `0.03 m` solution of `K_(2)SO_(4)` (assumed ionised) in a solvent with `K_(f)=4K kg "mol"^(-1)`A. `0.36K`B. `0.12K`C. `0.48K`D. `0.24K`

Answer» Correct Answer - A
447.

`20% (W)/(W)Kl` will have molality _ (given `GMM=166gm`)A. `1.35`B. `1.51`C. `1.48`D. `1.30`

Answer» Correct Answer - B
448.

The locus of the point of intersection of tangents of `x^2/a^2 + y^2/b^2 =1` at two points whose eccentric angles differ by `pi/2` is an ellipse whose semi-axes are: (A) `sqrt2 a,sqrt 2 b`(B) `a/sqrt2,b/sqrt2` (C) `a/2,b/2` (D) `2a,2b`

Answer» Let the points on ellipse be`p(acos(theta),bsin(theta))` and
`Q(acos(pi/2+theta),bsin(pi/2+theta))=(-asintheta,bcostheta)`
Equation of tangent at point p:
`x/acostheta+y/bsintheta=1`
Equation of tangent at point Q:
`-x/asintheta+y/bcostheta=1`
On solving these equations we get,`x/a=(costheta-sintheta)`
`y/b=(costheta+sintheta)`
On squaring and adding these equations,
`2=(x/a)^2+ (y/b)^2`Therefore,
`(x/(asqrt2))^2+(y/(bsqrt2))^2=1`
449.

Light in incident on a metal plate whose work function is 2 eV. Electric field associated with light is given by `E=E_(0)sin(omegat-(2pi)/(5xx10^(7))x)`{ S.I unit} if energy of photom is given by `(12375)/(lamda("in"A))` eV then stopping potential isA. `2.48eV`B. `0.48eV`C. `0.78eV`D. `1.24eV`

Answer» Correct Answer - B
450.

Wavelength of the first line of balmer seris is 600 nm. The wavelength of second line of the balmer series will beA. 444 nmB. 800 nmC. 388 nmD. 632 nm

Answer» Correct Answer - A