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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 901. |
The number of completely filled shells for the element 16S32 is(A) 1 (B) 2 (C) 3 (D) 4 |
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Answer» Correct Option :- (B) 2 Explanation :- Electronic configuration of sulphur is 1S2 , 2S2 , 2P6 , 3S2 , 3P4 |
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| 902. |
Particle sused in the Rutherford’s scattering experiment to deduce the structure of atoms (A) had atomic number 2 and were fully ionised. (B) had atomic number 2 and were neutral. (C) had atomic number 4 and were fully ionised. (D) had atomic number 4 and were neutral. |
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Answer» Correct Option :- (A) had atomic number 2 and were fully ionised. Explanation :- α-particle bombard during experiment α-particles ionized helium |
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| 903. |
For the reaction `A rarr B , DeltaH^(@) = 7.5 mol^(-1)` and `DeltaS^(@) = 2.5 J mol^(-1)`. The value of `DeltaG^(@)` and the temperature at which the reaction reaches equilibrium are, respectively.A. `0 kJ mol^(-1)` and `400 K`B. `-2.5 kJ mol^(-10)` and `400 K`C. `2.5 kJ mol^(-1)` and `200 K`D. `0 kJ mol^(-1)` and `300 K` |
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Answer» Correct Answer - D At equation `DeltaG^(@) = 0` `:. T = (DeltaH)/(DeltaS) = (7.5 xx 1000)/(25) = 300 K` |
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| 904. |
The solubility product of `Mg(OH)_(2)` is `1.0 xx 10^(-12)`. Concentrated aqueous `NaOH` solution is added to a `0.01 M` aqueous solution of `MgCl_(2)`. The pH at which precipitation occur is -A. 7.2B. 7.8C. `8.0`D. `9.0` |
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Answer» Correct Answer - D `{:(MgCl_(2)rarr,Mg^(+2),2Cl^(-)),(,?),(,0.01M):}` `K_(sp) = Q = [Mg^(+2)][OH^(-)]^(2)` `10^(-12)=[0.01][OH^(-)]^(2)` `[OH^(-)]^(2) = 10^(-10)` `[OH^(-)] = 10^(-5)` `pOH = 5 :. pH = 9` |
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| 905. |
Identify the cyclic silicate ion given in the figure below A. `[Si_(4)O_(25)]^(24-)`B. `[Si_(6)O_(18)]^(18-)`C. `[Si_(4)O_(12)]^(12)`D. `[Si_(6)O_(24)]^(12-)` |
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Answer» Correct Answer - B Cyclic or ring silicates have general formula `underset(Si_(3)O_(9^(6-)))underset(darr)((Si-O_(3^(2-)))_(n))` or `underset(Si_(6)O_(18^(12-)))underset(darr)((Si-O_(3))_(n^(2n-)))` |
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| 906. |
A metal with an atomic radius of `141.4` pm crystallizes in the face centered cubic structure. The volume of the unit cell in pm is -A. `2.74 xx 10^(7)`B. `2.19 xx 10^(7)`C. `6.40 xx 10^(7)`D. `9.20 xx 10^(7)` |
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Answer» Correct Answer - C `r = (a)/(2sqrt(2)) = 141.4` pm `a = 2 xx sqrt(2) xx 141.4` `:. V = a^(3) = (2 xx sqrt(2) xx 141.4)^(3)` |
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| 907. |
the percentage of nirtogen by mass in ammonium sulphate is closect is closect to (atomic Masses `H=1, N=-14, O=16, S=32` )A. 0.21B. 0.24C. 0.36D. 0.16 |
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Answer» Correct Answer - A 5 Nitrogen `=(" Wt of N") /( Wt "of" (NH_(4))_(2) SO_(4))` ` % N =(28)/(132 ) xx100` `=21.21%` |
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| 908. |
The stability of carbocationsfollows the order (A) III < IV < II < I (B) III < IV < I < II (C) IV < III < II < I (D) IV < III < I < II |
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Answer» Correct Option :- (B) III < IV < I < II Explanation :- (II) is most stable due to resonance then 3° > 2° > 1° carbocation |
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| 909. |
The acidity of compounds I-IV in water I. Ethanol II. Acetic AcidIII. Phenol IV. Acetonitrile follows the order (A) IV < I < III < II (B) I < II < III < IV (C) IV < I < II < III (D) IV < III < I < II |
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Answer» Correct Option :- (A) IV < I < III < II Explanation :- Acetic acid is most acidic due to equivalent resonating structure. |
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| 910. |
Friedel-Crafts acylation is- (A) α-acylation of a carbonyl compound (B) acylation of phenols to generate esters (C) acylation of aliphatic olefins (D) acylation of aromatic nucleus |
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Answer» Correct Option :- (D) acylation of aromatic nucleus Explanation :- Friedel craft reaction used for introducing an alkyl or acyl group in benzene nucleus by an alkylating or acylating agent in presence of a suitable catalyst. |
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| 911. |
Friedel-Crafts acylation is-A. `alpha`-acylation of a carbonyl compoundB. acylation of phenols to generate estersC. acylation of aliphatic olefinsD. acylation of aromatic nucleus |
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Answer» Correct Answer - D Friedel craft used for introducing an alkyl or acyl group in benzene nucleus by an alkylating or acylating agent in presence of a suitable catalyst. |
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| 912. |
Let A = {θ ∈ R | cos2 (sin θ) + sin2 (cosθ) = 1} and B = {θ ∈ R | cos(sinθ) sin(cosθ) = 0}. Then A ∩ B (A) is the empty set (B) has exactly one element (C) has more than one but finitely many elements (D) has infinitely many elements |
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Answer» Correct Option :- (A) is the empty set Explanation :- for A ∩ B cos (sin θ) = 1 or –1 & sin(cos θ) = 0 which is not possible or cos (sin θ) = 0 & sin (cos θ) = 1 or –1 also not possible so A ∩ B is an empty set |
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| 913. |
Let A and B any two `n xx n` matrices such that the following conditions hold : `AB= BA` and there exist positive integers `k` and `l` such that `A^(k)=I` (the identity matrix) and `B^(l)=0` (the zero matrix). Then-A. `A + B = I`B. det (AB) =0C. det `(A + B) ne 0`D. `(A + B)^(m)= 0` for some integer m |
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Answer» Correct Answer - B `A^(k)=I, B^(l)=0 ("det (B) = 0")` `rArr" det "(AB)=0` |
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| 914. |
Let A and B be any two n × n matrices such that the following conditions hold : AB = BA and there exist positive integers k and l such that Ak = I (the identity matrix) and Bl = 0 (the zero matrix). Then- (A) A + B = I (B) det (AB) = 0 (C) det (A + B) ≠ 0 (D) (A + B)m = 0 for some integer m |
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Answer» Correct Option :- (B) det (AB) = 0 Explanation :- Ak = I, Bl = 0 (det (B) = 0) ⇒ det (AB) = 0 |
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| 915. |
A thin metallic disc is rotating with constant angular velocity about a vertical axis that is perpendicular to its plane and passes through its centre. The rotation causes the free electrons in the disc to redistribute. Assume that there is no external electric or magnetic field. Then (A) a point o the rim of the disc is at a higher potential than the centre (B) a point on the rim of the disc is at a lower potential than the centre (C) a point on the rim of the disc is at the same potential as the centre (D) the potential in the material has an extremum between center and the rim. |
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Answer» Correct option (B) a point on the rim of the disc is at a lower potential than the centre Explanation: Due to contrifugal force electrons have a tendency to go towards the circumference. |
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| 916. |
Consider the following parametric equation of a curve : `x(theta)=|cos 4 theta| cos theta` `y(theta)|cos 4 theta|sin theta` for `0 le theta le 2 pi ` Which of the following graphs represents the curve ?A. B. C. D. |
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Answer» Correct Answer - A Make graph and observe yourself |
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| 917. |
A diploid plant has 14 chromosomes, but its egg cell has 6 chromosomes. Which one of the following is the most likely explanation of this?A. Non-disjunction in meiosis I and IIB. Non-disjunction in meiosis IIC. Non-disjunction is mitosisD. Normal meiosis |
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Answer» Correct Answer - B Egg cell is formed by meiosis. Less number of chromosome indicates non-disjunction in meiosis I. |
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| 918. |
Let `nge3` be an integer. For a permutaion `sigma=(a_(1),a_(2),.....,a_(n)` of (1,2,.....,n) we let `f_(sigma)(x)=a_(n)X^(n-1)+a_(n-1)X^(x-2)+....+a_(2)x+a_(1)`. Let `S_(sigma)` be the sum of the roots of `f_(sigma)(x)=0` and let S denote the sum over all permutations `sigma` of (1,2,.....,n) of the numbers `S_(sigma)`. Then-A. `Slt0n!`B. `-n!ltSlt0`C. `0lt Slt n!`D. `n!leS` |
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Answer» Correct Answer - B `S=-[(lambda-a_(n))/(a_(jn))+(lambda-a_(n-1))/(a_(n-1))+.....+(lambda-a_(1))/(a_(1))]` `AAlambda=a_(1)+a_(2)+....+a_(n)` `S=-[(a_(1)+a_(2)+....+a_(n))((1)/(a_(1))+(1)/(a_(2))+.....+(1)/(a_(n)))-n]` `S=n-(a_(1)+a_(2)+....+a_(n))((1)/(a_(1))+(1)/(a_(2))+.....+(1)/(a_(n)))` Fom `A.M.geH.M` `(a_(1)+a_(2)+....+a_(n))((1)/(a_(1))+(1)/(a_(2))+.....+(1)/(a_(n)))gen^(2)` `Sle-n(n-1)` |
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| 919. |
Let `A=(a_(1),a_(2)) " and " B=(b_(1),b_(2))` be two points in the plane with integer coordinates. Which one of the following is not a possible value of the distance between A an B ?A. `sqrt(65)`B. `sqrt(74)`C. `sqrt(83)`D. `sqrt(97)` |
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Answer» Correct Answer - C `AB=sqrt((a_(1)-b_(2))^(2)+(a_(2)-b_(2))^(2))` Squrare + Square = `sqrt(65)` possible when `=64+1` `sqrt(74)=49+25` `sqrt(97)= 81+16` But `sqrt(83)` not possible. |
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| 920. |
Let `f(x) = " max " {3,x^(2),(1)/(x^(2))}` for `(1)/(2) le x le 2`. Then the value of integral `int_(1//2)^(2)f(x) dx` isA. `(11)/(3)`B. `(13)/(3)`C. `(14)/(3)`D. `(16)/(3)` |
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Answer» Correct Answer - C Given Integral can be distributed ito `int_(1//2)^(1//sqrt(3))(1)/(x^(2)).dx+ int_(1//sqrt(3))^(sqrt(3))3dx+ int_(sqrt(3))^(2)x^(2).dx=(14)/(3)` |
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| 921. |
Let `a_(i) = i+ (1)/(i)` for i= 1 , 2 …………. , 20. Put `p = (1)/(20) ( a_(1) + a_(2) +……… + a_(20))` and `q = (1)/(20) ((1)/(a_(1)) + (1)/(a_(2)) + ……… + (1)/(a_(20)))`. ThenA. ` q in ( 0 , (22 - p)/(21))`B. `q in ((22- p)/(21) , (2(22-p))/(21))`C. `q in ((2 (22 - p))/(21), (22-p)/(7))`D. `q in ((22 - p)/(7), (4 (22 -p))/(21))` |
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Answer» Correct Answer - A `q gt 0` try to the contra prove that `q lt (22 - p)/(21)` ` q + (p)/(21) lt (22)/(21)` `q + (p)/(21) = (1)/(20)[sum_(i = 1)^(20) (1)/(a_(i)) + (1)/(21) sum_(i = 1)^(20) a_(i)]` `= (1)/(20)[sum_(i=1)^(20) ((i)/(i^(2) + 1)) + (1)/(21) sum_(i=1)^(20) ( i + (1)/(i))]` `= (1)/(2) + (1)/(20) [sum_(i = 1)^(20) (i)/(i^(2) + 1) + sum_(i=1)^(20)((1)/(21i))]` `(1)/(2) + (1)/(20)[(1)/(2) + sum_(i=2)^(20) (i)/(i^(2) + 1) + sum_(i=1)^(20) (1)/(21i)]` `lt (1)/(2) + (1)/(20) [ (1)/(2) + (2)/(5) sum_(i=2)^(20) 1 + (1)/(21)sum_(i = 1)^(20)1]` `lt (1)/(2) + (1)/(20) [ (1)/(2) + (2)/(5) xx 19 + (1)/(21) xx 20]` `lt (1)/(2) + (1)/(20) (1 + 8 + 1)` `lt (1)/(2) + (1)/(2)` `lt (22)/(21)` |
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| 922. |
Let x,y,z be positive integers such that HCF(x,y,z)=1 and `x^(2)+y^(2)=2z^(2)`. Which of the following statements are true ? I. 4 divides x or 4 divides y. II. 3 divides x+y or 3 divides x-y III. 5 divides `z(x^(2-y^(2)))`A. I and II onlyB. II and III onlyC. II onlyD. III only |
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Answer» Correct Answer - B Take combination such as x=1,y=7,z=5 Now, check option (ii) & (iii) statement are correct. |
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| 923. |
1 Kg of ice at `-20^(@)C` is mixed with 2 Kg of water at `90^(@)C`. Assuming that there is no loss of energy to the environment, what will be the final temperature of the mixture ? (Assume latent heat of ice = `334.4` KJ/Kg, specific heat of water and ice are `4.18 kJ//(kg.K)` and `2.09 kJ//(kg.K)`, respectively.)A. `30^(@)C`B. `0^(@)C`C. `80^(@)C`D. `45^(@)C` |
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Answer» Correct Answer - A |
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| 924. |
Among the following species, the H-X-H angle (X=B,N or P ) follows the orderA. `PH_(3) lt NH_(3) lt NH_(4)^(+) lt BF_(3)`B. `NH_(3) lt PH_(3) lt NH_(4)^(+) lt BF_(3)`C. `BF_(3) lt PH_(3) lt NH_(4)^(+) lt NH_(3)`D. `BF_(3) lt NH_(4)^(+) lt NH_(3) lt PH_(3)` |
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Answer» Correct Answer - A `underset(120^(@))(BF_(3)) lt underset(109^(@)28)(NH_(4)^(+)) lt underset(107^(@))(NH_(3)) lt underset(92^(@))(PH_(3))` |
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| 925. |
the Amonut of Ag (atomic mass =108) deposited at the cathode when a current of 0. amp is passed through a solution of` Ag Co_(3) ` for 1 hour is closest toA. 2gB. 5gC. 108gD. 11g |
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Answer» Correct Answer - A `W=(Eit)/(96500)` `=(108xx0.5xx3600)/(96500)` `=2gm` |
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| 926. |
The black shapes in the figure below are closed surfaces. The electric field lines are in red. For which case the net flux through the surfaces is non-zero ? A. In all cases net flux is non-zeroB. Only (c) and (d)C. Only (a) and (b)D. Only (b), (c) and (d) |
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Answer» Correct Answer - C |
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| 927. |
A star of mass M and radius R is made up of gases. The average gravitational pressure compressing the star due to gravitational pull of the gases making up the star depends on R asA. `(1)/(R^(4))`B. `(1)/(R)`C. `(1)/(R^(2))`D. `(1)/(R^(6))` |
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Answer» Correct Answer - A |
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| 928. |
Which ONE of the following coenzymes is required for the conversion of L-alanine to a racemic mixture of D-and L-alanine ?A. Pyridoxal-6-phosphateB. Thiamine pyrophosphateC. Coenzyme AD. Flavin adenine dinucleotide |
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Answer» Correct Answer - A Information base question |
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| 929. |
Myeloid tissue is a type of – (A) haematopoietic tissue (B) cartilage tissue (C) muscular tissue (D) areolar tissue |
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Answer» Correct option (A) haematopoietic tissue Explanation: Myeloid tissue is a biologic tissue with the ability to perform hemotopiesis. It is mainly found as the red bone moved in bone and is after. synonymous with this. |
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| 930. |
Which one of the following animals is a connecting link between reptiles and mammals? (A) Platypus (B) Bat(C) Armadillo (D) Frog |
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Answer» Correct Option :- (A) Platypus Explanation :- Connecting link between Reptile and Mammals is/are (1) Platypus (2) Echidina |
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| 931. |
The source of mammalian hormone "Relaxin" is (A) ovary (B) stomach (C) intestine (D) pancreas |
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Answer» Correct Option :- (A) ovary Explanation :- Relaxin hormone secreted from ovary at the time of Parturition. |
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| 932. |
The source of mammalian hormone " Relaxin" isA. ovaryB. stomarchC. intestineD. pancreas |
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Answer» Correct Answer - a Relaxin hormone secreted from ovary at the time of parturition. |
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| 933. |
Bombyx mori ( silk worm) belongs to the orderA. LepidopteraB. DipteraC. HymenoteraD. Coleoptera |
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Answer» Correct Answer - a order of Silkworm `to` Lepidoptera (Bombax mori) |
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| 934. |
According to Watson-Crick model, hydrogen bonding in a double-stranded DNA occures between (A) Adenine and guanine (B) Adenine and thymine (C) Cytosine and adenine (D) guanine and thymine |
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Answer» Correct Option :- (B) Adenine and thymine Explanation :- A pairs with T & G pairs with C in DNA. |
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| 935. |
According to Watson-Crick model, hydrogen bonding in a double-stranded DNA occures betweenA. Adenine and guanineB. Adenine and thymineC. Cytosine and adenineD. guanine and thymine |
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Answer» Correct Answer - B A pairs with T & G pairs with C in DNA. |
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| 936. |
The following DNA sequence (5' → 3') specifies part of a protein coding sequence, starting from position I. Which of the following mutations will give rise to a protein that is shorter than the full-length protein ? 123456789101112131415ATGCAAGATATAGCT(A) Deletion of nucleotide 13 (B) Deletion of nucleotide 8 (C) Insertion of a single nucleotide between 3 and 4 (D) Insertion of a single nucleotide between 10 and 11 |
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Answer» Correct Option :- (B) Deletion of nucleotide 8 |
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| 937. |
The amino acid sequences of a bacterial protein and a human protein carrying out similar function are found to be 60% identical. However the DNA sequences of the genes coding for these proteins are only 45% identical. This is possible because- (A) Protein sequence does not depend on DNA sequence (B) DNA codons having different nucleotides in the third position can code for the same amino acids (C) DNA codons having different nucleotides in the second position can code for the same amino acids (D) Same DNA codons can code for multiple amino acids |
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Answer» Correct Option :- (B) DNA codons having different nucleotides in the third position can code for the same amino acids |
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| 938. |
A rectangle is divided into 16 sub-rectangles as in the figure, the number in each sub rectangle represents the are of that sub-rectangle. What is the area of the rectangle KLMS ? (A) 20 (B) 30 (C) 40 (D) 50 |
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Answer» Correct Option :- (D) 50 Explanation :- Area = 10 × 5 = 50 (from figure) (assuming all sides to be integers) |
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| 939. |
A rectangle is divided into 16 sub-rectangles as in the figure, the number in each sub rectangle represents the are of that sub-rectangle. What is the area of the rectangle KLMS ? A. 20B. 30C. 40D. 50 |
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Answer» Correct Answer - D Area `=10xx5=50` (from figure) (assuming all sides to be integers) |
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| 940. |
The set of principal (n), .azimuthal (l) and magnetic `(m_(1))` quantum number that is not allowed for the electron in H-atom isA. n = 3, l = 1, `m_(1) = -1`B. n = 3, l = 0, `m_(1) = 0`C. n = 2, l = 1, `m_(1)= 0`D. n = 2, l = 2, `m_(1) = -1` |
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Answer» Correct Answer - D n is always greater than l and m = - l……….0 ………..+l If n = 2, then l = 0, 1 and `m_(l) = 0, { -1, 0, + 1}` |
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| 941. |
Individuals of one kind occupying a particular geographic area at given time are calledA. communityB. populationC. speciesD. biome |
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Answer» Correct Answer - B Population is a group of individual belonging to same sps. (one kind) occupying a particular geographic area in a given time. |
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| 942. |
Excess salt inhibits bacterial growth in pickles by-A. EndosmosisB. exosmosisC. oxidationD. denaturation |
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Answer» Correct Answer - B Excessive salt in pickle inhibits the bacterical growth by exososis because external external medium become hypertonic . |
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| 943. |
The first ionization enthalpies for three elements are 1214, 1680 and `2080kjmol^(-1)`,respectively, The correct sequence of the element is :A. O, F and NeB. F, O and NeC. Ne, F and OD. F, Ne and O |
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Answer» Correct Answer - A First ionisation enthalpies for three elements are 1314, 1680, 2080. These are in increasing order so elements should be O, F, Ne |
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| 944. |
The schematic below describes the status of lac operon in the absence of lactose. Which ONE of the following happens lactose is present in the cell ? A. Lactose binds to `p^(1)` and stops the transcription of i.B. Lactose is converted to allolactose, which binds to `P^(lac)` and results in the displacements of the repressor from O.C. Lactose is converted to allolactose, which bind to the repressor protein and prevents its interaction with O.D. Lactose has no effect on the status of the lac operon. |
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Answer» Correct Answer - C Lac operon is inducible operon here. |
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| 945. |
The minimum number of plant to be screened to obtain a plant of the genotype AabbCcDd from a cross between plants of genotypes AaBbCcDd and AABnCCDd isA. 8B. 16C. 32D. 64 |
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Answer» Correct Answer - C `{:("AaBbCcDd"xx"AaBbCCDd"),(" "darr),(" AabbCcDd"):}` `(1)/(2)xx(1)/(4)xx(1)/(2)xx(1)/(2)=(1)/(32)` |
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| 946. |
The atmospheric pressure is 760 mm Hg at the sea level. Which of the following ranges in nearest to the partial pressure of `CO_(2)` in mm Hg ?A. 0.30.0.31B. 0.60 - 0.61C. 3.0 -3.1D. 6.0 -6.1 |
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Answer» Correct Answer - a `P_(CO_(3))=0.30-0.31` mm Hg in Air |
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| 947. |
The atmospheric pressure is 760 mm Hg at the sea level. Which of the following ranges is nearest to the partial pressure of CO2 in mm Hg? (A) 0.30–0.31 (B) 0.60–0.61 (C) 3.0–3.1 (D) 6.0–6.1 |
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Answer» Correct Option :- (A) 0.30–0.31 Explanation :- PCO2 = 0.30 - 0.31 mm Hg in Air |
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| 948. |
Let `A_(1),A_(2)….. A_(m)` be non -empty subsets of {1,2,3 …….. 100}, satisfying the following conditions. (1) the numbers `|A_(1)|,|A_(2)|....,|A_(m)|` are disjoint. (2) `A_(1),A_(2) ,….. A_(m)` are pairwise disjoint. (Here|A| denotes the number fo elements in the set A.) Then the maximum possible value of m isA. 13B. 14C. 15D. 16 |
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Answer» Correct Answer - a The possibility is `|A_(1)|=1,|A_(2)|, |A_(3)|=3,........,|A_(m)|=m`lt brgt1+2+3+.....+m`ge100` {because all are disjoint} `Rightarrow(m(m+1))/2 le100` `Rightarrow mlt14` `14^("th") set will have the same size as that of one of the previous sets So, m=13 |
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| 949. |
Let a, b, c, d be real numbers between – 5 and 5 such that `|a|=sqrt(4-sqrt(5-a)),|b|=sqrt(4+sqrt(5-b))`, `|c|=sqrt(4-sqrt(5+c)),|d|=sqrt(4+sqrt(5+d)),`. Then the product abcd isA. 11B. -11C. 121D. -121 |
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Answer» Correct Answer - A `"Given "|a| =sqrt(4-sqrt(5-a))` `"squaring"` `a^(2)=4-sqrt(5-a)` `rArra^(4)+16-8a^(2)=5-a` `rArra^(4)-8a^(2)+a+11=0` Similarly squaring other given equations `&` solving we can say that a,b,-c,-d are roots `" of "x^(4)-8x^(2)+x+11=0` `therefore "product of roots "` ab(-c)(-d)=11 abcd=11 |
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| 950. |
Hence or otherwise show that every positive rational number can be expressed in the form a /10b (10c −1) for some natural numbers a, b, c. |
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Answer» Sol. If p/q is any rational number (p > 0, q > 0), then we may write q = 2r 5s t, where t is coprime to 10. Choose a number m having only 1's as its digits and is divisible by t. Consider 9m, Which has only 9 as its digits and is still divisible by t. Let k = 9 m/t. We see that; qk = 9m 2r 5s = (10º –1) 2r 5s , where c is the number of digits in m. Hence we can find d such that qd = 10b (10c – 1) (multiply by a suitable power of 2 if s > r and by a suitable power of 5 if r > s). Then p/q =pd/qd = a/10b(10c - 1) where a = pd. |
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