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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 801. |
In a diploid organism, there are three different alleles for a particular gene. Of these three alleles one is recessive and the other two alleles exhibit co-dominance. How many phenotypes are possible with this set of alleles ? (A) 3 (B) 6 (C) 4 (D) 2 |
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Answer» Correct Option :- (C) 4 |
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| 802. |
A bust cell has intracellular bacteria symbionts. If the growth rate of the bacterial symbiont is always 10% higher than that of the host cell, after 10 generations of the host cell the density of bacteria in host cells will increase - (A) by 10 % (B) two-fold (C) ten-fold (D) hundred-fold |
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Answer» Correct Option :- (B) two-fold |
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| 803. |
Rice has a diploid genome with 2n = 24. If crossing-over is stopped in a rice plant and then selfed seeds are collected, will all the offsprings be genetically identical to the parent plant ? (A) yes, because crossing-over is the only source of genetic variation (B) no, because stopping of crossing-over automatically increases rate of point mutation (C) yes, only if the parent plant was a completely inbred line (D) yes, only if the parent plant was a hybrid between two pure-bred lines |
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Answer» Correct Option :- (C) yes, only if the parent plant was a completely inbred line |
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| 804. |
A bust cell has intracellular bacteria symbionts. If the growth rate of bacterial symbiont is always `10%` higher than that of the host cell, after 10 generations of the host cell the density of bacteria in host cells will increase -A. by `10%`B. two-foldC. ten-foldD. hundred-fold |
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Answer» Correct Answer - BLet us consider, Mass of host cell = m, Mass of bacterial symbiont= n Now, for 1st generation, the host cell divides into two so total mass of host cell=2m Total mass of bacterial symbiont in two 1st generation cells = 2n+(2/10)*n Mass of bacterial symbiont in one of the two cells of 1st generation = n+(1/10)*n In general, mass of bacterial symbiont in one of the (2^k)th cells of kth generation = n+(k/10)*n Thus, for 10th generation, mass of bacterial symbiont in one of the (2^10)th cells = n+(10/10)*n=n+n=2n. Hence, density of bacterial symbiont in 10th generation increased by 2 folds (n to 2n).Option B correct. |
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| 805. |
Estimate the order of the speed of propagation of an potential or nerve impulse -A. nm/sB. micron/sC. cm/sD. m/s |
| Answer» Correct Answer - D | |
| 806. |
Rodents can distinguish between many different types of odours. The basis for odour discrimination is that- (A) they have a small number of odorant receptors that bind to many different odorant molecules (B) the mechanoreceptors in the nasal cavity are activated by different odorant molecules found in the air passing through the nostrils (C) the part of the brain that processes the sense of smell has many different receptors for odorant molecules (D) a large number of different chemoreceptors are present in the nasal cavity that binds a variety of odorant molecules |
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Answer» Correct Option :- (D) a large number of different chemoreceptors are present in the nasal cavity that binds a variety of odorant molecules |
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| 807. |
The distance between two consecutive DNA base pairs is `0.34 nm`. If the length of a chromosome is 1mm, the number of base pairs in the chromosome is approximately-A. `3` millionB. `30` millionC. `1.5` millionD. `6` million |
| Answer» Correct Answer - A | |
| 808. |
Rodents can distinguish between many different types of odours. The basis for odour discrimination is that-A. they have a small number of odorant receptors that bind to many different odorant moleculesB. the mechanoreceptors in the nasal cavity are activated by different by odorant molecules found in the air passing through the nostrilsC. the part of the brain that processes the sense of smell has many different receptors for odorant moleculesD. a large number of different chemoreceptors are present in the nasal cavity that binds a variety of odorant molecules |
| Answer» Correct Answer - D | |
| 809. |
The distance between two consecutive DNA base pairs is 0.34 nm. If the length of a chromosome is 1 mm, the number of base pairs in the chromosome is approximately- (A) 3 million (B) 30 million (C) 1.5 million (D) 6 million |
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Answer» Correct Option :- (A) 3 million |
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| 810. |
Although blood flows through large arteries at high pressure, when the blood reaches small capillaries the pressure decreases because-A. the valves in the arteries regulate the rate of blood flow into the capillariesB. the volume of blood in the capillaries is much lesser than that in the arteriesC. the total cross-sectional area of capillaries arising from an artery is much greater than that of the arteryD. elastin fibers in the capillaries help to reduce the arterial pressure |
| Answer» Correct Answer - C | |
| 811. |
The fluid part of blood flows in and out of capillaries in tissue to exchange nutrients and waste materials. Under which of the following conditions will fluid flow out from the capillaries into the surrounding tissue ? (A) When arterial blood pressure exceeds blood osmotic pressure (B) When arterial blood pressure is less than blood osmotic pressure (C) When arterial blood pressure is equal to blood osmotic pressure (D) Arterial blood pressure and blood osmotic pressure have nothing to do with the outflow of fluid from capilleries |
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Answer» Correct Option :- (A) When arterial blood pressure exceeds blood osmotic pressure |
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| 812. |
Restriction endonucleases are enzymes that cleave DNA molecules into smaller fragments. Which type of bond do they act on ? (A) N-glycosidic Bond (B) Hydrogen bond (C) Phosphodiester bond (D) Disulfide bond |
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Answer» Correct Option :- (C) Phosphodiester bond |
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| 813. |
Restriction endonucleases are enzymes that cleave DNA molecules into smaller fragments. Which type of bond do they act on ?A. N-glycosidic BondB. Hydrogen bondC. Phosphodiester bondD. Disulfide bond |
| Answer» Correct Answer - C | |
| 814. |
Some of the wavelength observed in the emission spectrum of neutral hydrogen gas are 912, 1026, 1216, 3646, 6563 `Å`. If broad band light is passing through neutral hydrogen gas at room temperature, the wavelength that will not be absorbed strongly isA. 1026 `Å`B. 1216 `Å`C. 912 `Å`D. 3646 `Å` |
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Answer» Correct Answer - D |
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| 815. |
The graph that does not repersent the behaviour of an ideal gas is-A. B. C. D. |
| Answer» Correct Answer - A::B::C::D | |
| 816. |
Consider two masses with `m_(1) gt m_(2)` connected by a light inextensible string that passes over a pulley of radius R and moment of inertia I about its axis of rotation. The string does not slip on the pulley and the pulley turns without friction. The two masses are released from rest separated by a vertical distance 2h. When the two masses pass each other, the speed of the masses is proportional toA. `sqrt((m_(1)-m_(2))/(m_(1)+m_(2)+(1)/(R^(2))))`B. `sqrt(((m_(1)-m_(2))(m_(1)-m_(2)))/(m_(1)+m_(2)+(1)/(R^(2))))`C. `sqrt((m_(1)+m_(2)+(1)/(R^(2)))/(m_(1)-m_(2)))`D. `sqrt(((1)/(R^(2)))/(m_(1)+m_(2)))` |
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Answer» Correct Answer - C |
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| 817. |
The standard Gibbs free energy change (∆Gº in kJ mol–1), in a Daniel cell ( V Eºcell =1.1 V ), when 2 moles of Zn(s) is oxidized at 298 K, is closest to (A) – 212.3 (B) – 106.2 (C) – 424.6 (D) – 53.1 |
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Answer» Correct Option :- (C) – 424.6 Explanation :- Zn + Cu+2 → Zn+2 + Cu 2Zn + 2Cu+2 → 2Zn+2 + 2Cu For 2 moles of Zn, n = 4 ∆Gº = –nFEºCell = – 4 × 96500 × 1.1 = – 424.6 kJ |
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| 818. |
To obtain a diffraction peak, for a crystalline solid with interplane distance equal to the wavelength of incident X-ray radiation, the angle of incidence should be (A) 90º (B) 0º (C) 30º (D) 60º |
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Answer» Correct Option :- (C) 30º Explanation :- From Bragg's equation nλ = 2d sinθ d = λ, n = 1 1 × λ = 2 × λ sinθ sinθ = 2/1 θ = 30º |
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| 819. |
The value of the limiting molar conductivity (Λº) for NaCl, HCl and NaOAc are 126.4, 425.9 and 91.0 S cm2 mol–1, respectively. For HOAc, Λº in S cm2 mol–1 is(A) 390.5 (B) 299.5 (C) 208.5 (D) 217.4 |
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Answer» Correct Option :- (A) 390.5 Explanation :- Λ (HOAc) = Λº(NaOAc) + Λº(HCl) – Λº(NaCl) = 91 + 425.9 – 126.4 = 390.5 |
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| 820. |
Which of the following statements is true about the flow of electrons in an electric circuit ? (A) Electrons always flow from lower to higher potential (B) Electrons always flow from higher to lower potential (C) Electrons flow from lower to higher potential except through power sources (D) Electrons flow from higher to lower potential, except through power sources |
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Answer» (C) Electrons flow from lower to higher potential except through power sources |
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| 821. |
In the Arcitc region hemispherical houses called Igloos are made of ice. It is possible to maintain a temperature inside an Igloo as high as 20º C because– (A) Ice has high thermal conductivity (B) Ice has low thermal conductivity (C) Ice has high specific heat (D) Ice has higher density than water |
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Answer» Correct option (B) Ice has low thermal conductivity Explanation: Ice has low thermal conductivity So no exchange of heat outside surrounding. |
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| 822. |
A boat crossing a river moves with a velocity v relative to still water. The river is flowing with a velocity v/2 with respect to the bank. The angle with respect to the flow direction with which the boat should move to minimize the drift is–A. `30^(@)`B. `60^(@)`C. `150^(@)`D. `120^(@)` |
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Answer» Correct Answer - D |
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| 823. |
Two parallel discs are connected by a rigid rod of length L =`0.5` m centrally. Each disc has a slit oppositely placed as shown in the figure. A beam of neutral atoms are incident on one of the discs axially at different velocities v, while the system is rotated at angular speed of 600 rev/second so that atoms only with a specific velocity emerge at the other end. Calculate the two largest speeds (in meter/second) of the atoms that will emerge at the other end. A. 75, 25B. 100,50C. `300,100`D. `600,200` |
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Answer» Correct Answer - D |
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| 824. |
Four identical pendulums are made by made by attaching a small ball of mass 100 g on a 20 cm long thread and suspended from the same point. Now each ball is given charge Q so that balls move away from each other with each thread making an angle of `45^(@)` from the vertical. The value of Q is close to `((1)/(4piin_(0)) = 9 xx10^(9) " in SI units")`A. `1muC`B. `1.5muC`C. `2muC`D. `2.5muC` |
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Answer» Correct Answer - B |
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| 825. |
The roots of (x – 41)49 + (x – 49)41 + (x – 2009)2009 = 0 are - (A) all necessarily real (B) non-real except one positive real root (C) non-real except three positive real roots (D) non-real except for three real roots of which exactly one is positive |
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Answer» Correct Option :- (B) non-real except one positive real root Explanation :- (x – 41)49 + (x – 49)41 + (x – 2009)2009 = 0 f(x) = (x – 41)49 + (x – 49)41 + (x – 2009)2009 f ′ (x) = 49(x – 41)48 + 41(x – 49)40 + 2009 (x – 2009)48 > 0 hence f(x) will cut x-axis only once. 1 real root . |
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| 826. |
The inter-planar spacing between the (2 2 1) planes of a cubic lattice of length 450 pm is -A. 50 pmB. 150 pmC. 300 pmD. 450 pm |
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Answer» Correct Answer - B `d_("hkl")=(a)/(sqrt(h^(2)+k^(2)+l^(2)))` `=(450)/(sqrt(4+4+1))=(450)/(sqrt(9))=150` |
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| 827. |
The coefficient of `x^(2012)` in `(1_x)/((1+x^(2))(1-x))` is -A. 2010B. 2011C. 2012D. 2013 |
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Answer» Correct Answer - B Coeff. Of `x^(2012)` `((1+x))/((1+x^(2))(1-x^(2)))` `=(1+x^(2))(1-x^(4))^(-1)` `=(1+2x+x^(2))(1-x^(4))^(-1)` Coeff. Of `x^(2012)+2"Coeff of x"^(2011)+"Coeff of x"^(2010)` in the expansion of `(1-x^(4))^(-1)` `x^(2011) and x^(2010)` not possible in `(1-x^(4))^(-1)` = only coeff. of `x^(2012)` in the expassion of `(1-x^(4))^(-1)` `.^(1+503-1)C_(503)=1` |
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| 828. |
The sum of all `x in [0,pi]` which satisfy the equation sin `x+(1)/(2)cos x =sin^(2)(x+(pi)/(4))` is -(A) ` pi/6 ` (B) ` (5pi)/6 ` (C) ` pi ` (D) `2pi `A. `(pi)/(4)`B. `(5pi)/(6)`C. `pi`D. `2pi` |
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Answer» Correct Answer - C `sin x +(1)/(2)cos x=sin^(2)(x+(pi)/(4))` `sin x+(1)/(2)cos x =(1)/(2)(1-cos((pi)/(2)+2x))` `sin x+(1)/(2)co x =(1)/(2)(1+sin 2x)` `2 sin x +cos x = 1+sin x cos x` `2 sin x cos x -2 sin x (1-cos x)=0` `(1-cos x)-2 sin x(1-cos x)=0` `(1-cos x)(1-2 sin x) = 0` `1-cos x =0" "1-2sin x= 0` `cos x =1" "sin x =(1)/(2)` `x=0," "x=(pi)/(6),(5pi)/(6)` sum `=0+(pi)/(6)+(5pi)/(6)=pi` |
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| 829. |
Let (x,y) be a variable point on the curve `4x^(2)+9y^(2)-8x-36y+15=0`. Then min`(x^(2)-2x+y^(2)-4y+5)+"max"(x^(2)-2x+y^(2)-4y+5)` is-(A) `325/36 ` (B) ` 36/325 ` (C) ` 13/25 ` (D) `25/13 `A. `(325)/(36)`B. `(36)/(325)`C. `(13)/(25)`D. `(25)/(13)` |
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Answer» Correct Answer - A `4x^(2)+9y^(2)-8y-36y+15=0` `4(x^(2)-2y)+9(y^(2)-4y)=-15` `4(x^(2)-2x+1)+9(y^(2)-4y+4=-15+4+36` `4(x-1)^(2)+9(y-2)^(2)=25` `((x-a)^(2))/(((5)/(2))^(2))+((y-2)^(2))/(((5)/(3))^(2))=1`……….(1) `x^(2)-2x+y^(2)-4y+5` `(x-1)^(2)+(y-2)^(2)` min of `((x-1)^(2)+(y-2)^(2))=(25)/(9)` max of `((x-1)^(2)+(y-2)^(2))=(25)/(4)` `=(25)/(9)+(25)/(4)=(325)/(36)` |
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| 830. |
Which one of the following is true about enzyme catalysis ? (A) The enzyme changes at the end of the reaction (B) The activation barrier of the process is lower in the presence of an enzyme (C) The rate of the reaction is retarded in the presence of an enzyme (D) The rate of the reaction is independent of substrate concentration |
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Answer» Correct Option :- (B) The activation barrier of the process is lower in the presence of an enzyme |
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| 831. |
Which one of the following is true about enzyme catalysis ?A. The enzyme changes at the end of reactionB. The activation barrier of the process is lower in the presence of enzymeC. The rate of the reaction is retarded in the presence of an enzymeD. The rate of the reaction is independent of substrate concentration |
| Answer» Correct Answer - B | |
| 832. |
Vibrio cholera causes cholera in humans. Ganga water was once used successfully to combat the infection. The possible reason could be-A. High salt content of Ganga waterB. Low salt content of Ganga waterC. Presence of bacterophases in Ganga waterD. Presence of antibiotics in Ganga Water |
| Answer» Correct Answer - D | |
| 833. |
A hollow tilted cylindrical vessel of negligible mass rest on a horizontal plane as shown. The diameter of the base is a and the side of the cylinder makes an angle `theta` with the horizontal. Water is then slowly poured into the cylinder. The cylinder topples over when the water reaches a certain height h, given by A. `h=2a tan theta`B. `h=a tan^(2)theta`C. `h=a tan theta`D. `h=(a)/(2)tan theta` |
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Answer» Correct Answer - C |
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| 834. |
Persons A and B are standing on the opposite sides of a `3.5` m wide water stream which they wish to cross. Each one of them has a rigid wooden plank whose mass can be neglected. However, each plank is only slightly longer than 3 m. So they decide to arrange them together as shown in the figure schematically. With B (mass 17 kg) standing, the maximum mass of A, who can walk over the plank is close to A. 17 kgB. 65 kgC. 80 kgD. 105 kg |
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Answer» Correct Answer - C |
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| 835. |
Mendel showed that unit factors, now called alleles, exhibit a dominant/ recessive relationship. In a monohybrid cross, the .................. trait disappears in the first filial generation (A) dominant (B) co-dominant (C) recessive (D) semi-dominan |
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Answer» Correct option (C) recessive Explanation: Recessive allele does not express itself in presence of dominant allele. |
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| 836. |
If man with an X-linked dominant disease has six sons with a woman having a normal complement of genes, then the sons willA. not show any symptoms of the diseaseB. show strong symptoms of the diseaseC. three will show a disease symptom, while three will notD. five will show a disease symptom, while one will not |
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Answer» Correct Answer - A Son get their X chromosome from mother. |
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| 837. |
If a man with an X-linked dominant disease has six sons with a woman having a normal complement of genes, then the sons will (A) not show any symptoms of the disease (B) show strong symptoms of the disease (C) three will show a disease symptom, while three will not (D) five will show a disease symptom, while one will not |
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Answer» Correct option (A) not show any symptoms of the disease Explanation: Son get their X chromosome from mother. |
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| 838. |
In evolutionary terms, an Indian school boys is more closely related to (A) an Indian frog (B) an American snake (C) a Chinese horse (D) an African shark |
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Answer» Correct option (C) a Chinese horse Human & horse both belongs to mammalia . |
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| 839. |
A gas obeying the equation of state PV = RT undergoes a hypothetical reversible process described by the equation, `PV^(5//3)"exp"(-(PV)/(E_(0)))= c_(1 )` where `c_(1)` and `E_(0)` are dimensioned constants. Then, for this process, the thermal compressibility at high temperatureA. approaches a constant value.B. is proportional to T.C. is proportional to `T^(1//2)`D. is proportional to `T^(2)`. |
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Answer» Correct Answer - A |
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| 840. |
Which one of the following colours is the LEAST useful for plant life? (A) red (B) blue (C) green (D) violet |
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Answer» Green is the LEAST useful for plant life. |
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| 841. |
Let S = {1, 2, 3, …..,n} and A = {(a, b) |1≤ a, b ≤ n} = S x S. A subset B of A is said to be a good subset if (x, x) ∈ B for every x ∈ S. Then the number of good subsets of A is – (A) 1 (B) 2n (C) 2n(n–1) (D) 2n2 |
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Answer» Correct :- (C) 2n(n–1) Explanation :- Good subset is total number of symmetric subset |
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| 842. |
Which ONE of the following gases is produced during fermentation by yeast ? (A) CO2 (B) O2 (C) H2 (D) N2 |
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Answer» Correct option (A) CO2 Explanation: In fermentation yeast convert pyruvic acid into ethanol and CO2 gas. |
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| 843. |
Which ONE of the following gases is produced during fermentation by yeast ?A. `CO_(2)`B. `O_(2)`C. `H_(2)`D. `N_(2)` |
| Answer» Correct Answer - A | |
| 844. |
Which ONE of the following properties of normal cell is lost during its transition to cancerous cell ? (A) Glutamine utilization (B) Contact inhibition (C) Glucose utilization (D) Membrane fluidity |
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Answer» Correct option (B) Contact inhibition Explanation: In normal mitotic cells they have contact inhibition because of that they do not get contact & not make a cluster of cells. But in cancerous cells they last the property and get attached with each other. |
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| 845. |
ONE of the following properties of normal cell is lost during its transition to cancerous cell ?A. Gluratamine utilizationB. Contact inhibitionC. Glucose utilizationD. Membrane fluidity |
| Answer» Correct Answer - B | |
| 846. |
The graph below represents the absorption spectrum of major pigment contributing to photosynthesis ? A. B. C. D. |
| Answer» Correct Answer - A | |
| 847. |
In biological nitrogen fixation, the enzyme nitrogenase converts (A) nitrate to nitrite (B) atmospheric nitrogen to nitrite(C) nitrite to ammonia (D) atmospheric nitrogen to ammonia |
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Answer» Correct option (D) atmospheric nitrogen to ammonia Explanation: Nitrogenase enzyme under biological N-fixation reduce atmospheric N2 (N ≡ N) into NH3. |
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| 848. |
The graph below represents the absorption spectrum of a major pigment contributing to photosynthesis. Which ONE of the following best represents the photosynthetic efficiency of |
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Answer» Correct option (A) Explanation: The above given absorbance graph relate the absorption spectrum of chlorophyll ‘a’. Action spectrum of photosynthesis resemble the absorption spectrum of Chl ‘a’ but not completely overlape.
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| 849. |
A proton of mass `m` and charge e is projected from a very large distance towards an `alpha` particle with velocity `v`. Intially, particle is at rest, but it is free to move. If gravity is neglected, then the minimum separation along the straight line of their motion will beA. `e^(2)//4 piepsilon_(0) mv^(2)`B. `5e^(2)//4pi epsilon_(0) mv^(2)`C. `2e^(2)//4 pi epsilon_(0) mv^(2)`D. `4e(2)//4pi epsilon mv^(2)` |
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Answer» Correct Answer - B |
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| 850. |
Suppose is a positive real number such that `a^(5)-a^(3)+a=2`. ThenA. `a^(6)lt2`B. `2lt a^(6)lt3`C. `3lt a^(6)lt4`D. `4lea^(6)` |
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Answer» Correct Answer - c `a^(5)-a^(3)a=2,aepsilonR^(+)` `Let f(a)=a^(5)-a^(3)+a-2, {"Note f"(a) gt0AAa in R}` `"for"a^(6)=3Rightarrowa=3^(1//6)=1.2 {"use calculator"}` `"we get" f(1.2)lt 0 and at a=4^(1//6)RightarrowF(4^(1//6))gt0` so one root in a `in (3,4)` |
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