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101.

The shortest distance from the origin to a variable point on the sphere `(x-2)^(2)+(y-3)^(2)+(z-6)^(2)=1` is-A. 5B. 6C. 7D. 8

Answer» Correct Answer - B
Sphere `x^(2)+y^(2)+z^(2)-4x-6x-12z+48=0`
Centre (2,3,6)
radius `=sqrt(4+9+36-48)=1`
distance between centre and origin `=sqrt(4+9+36)=7`
shortest distance =7-1-6 (Origin lies outside the sphere)
102.

A train leaves Pune at 7 :30 am and reaches Mumbai at 11 : 30 am. Another train leaves Mumbai at 9 : 30 am and reaches Pune at 1 : 00 pm. Assuming that the two trains at constant speeds, at what time do the two trains cross each other-A. `10 : 20am`B. `11:30am`C. `10:26am`D. Data not sufficinet

Answer» Correct Answer - B
First train from Pune to Mumbai takes 4hrs.
Second train from Mumbai to Pune takes 3.5hrs.
Speed of train from Pune to Mumbai is `V_(1)=(d)/(4)`
Speed of train from Mumbai to Pune is `V_(2)=(d)/(3.5)`
Distance traveled by first train till 9:30 is `x=(d)/(4)xx2=(d)/(2)`
Say now both trains meet after time from 9:30
`(x)/(d//4)=((d)/(2)-xx)/((d)/(3.5))implies(4x)/(d)=(3.5)/(2)-(3.5x)/(d)implies(7.5x)/(d)=(3.5)/(2)implies15xx=3.5dimplies30xx=7d`
time taken by first train 9:30 is `(4x)/(d)=4((7)/(30))`
`=(14)/(15)`
56min
Then both train meet at 9:30+56min =10:26am
103.

The major product in the following reaction is - A. B. C. D.

Answer» Correct Answer - A
`CH_(3)CHBroverset(NaNH_(2))underset(-HBr)rarrCH-=CH`
104.

`O^(2-)` is isoelectronic withA. `Zn^(2+)`B. `Mg^(2+)`C. `K^(+)`D. `Ni^(2+)`

Answer» Correct Answer - B
`O^(2-) "is isoelectronic with" Mg^(+2)`
`O^(2-)to8+2=10e^(-)`
`Mg^(+2)to12-2=10e^(-)`
105.

The isoelectronic pair of ions is -A. `Sc^(2+)` and `V^(3+)`B. `Mn^(2+)` and `Fe^(3+)`C. `Mn^(3+)` and `Fe^(2+)`D. `Ni^(3+)` and `Fe^(2+)`

Answer» Correct Answer - B
`Mn^(+2)=23e^(-)`
`Fe^(+3)=23e^(-)`
106.

The equilibrium constant for the following reactions are K1 and K2, respectively. 2P(g) + 3Cl2(g) ⇋ 2PCl3(g) PCl3(g) + Cl2(g) ⇋ PCl5(g) Then the equilibrium constant for the reaction 2P(g) + 5Cl2(g) ⇋ 2PCl5(g) is –(A) K1K2 (B) K1K22  (C) K12 K22  (D) K12 K2

Answer»

Correct :- (B) K1K22

Explanation :-

2P(g) + 3Cl2(g) 2PCl3(g) K1 

 2PCl3(g) + 2Cl2(g) 2PCl5(g) K2

 Net reaction : 2P(g) + 5Cl2(g) 2PCl5(g) K = K1K22

107.

When the size of a spherical nanoparticle decreases from 30 nm to 10 nm, the ratio surface area/volume becomesA. 1//3 of the originalB. 3 times the originalC. 1/9 of the originalD. 9 times the original

Answer» Correct Answer - B
`("Surface area")/("Volume")=(pid^(2))/((pid^(3))/6)=6/d`
`d_(1)=30 nm" "d_(2)=10 nm`
`((("Surface area")/("Volume"))_(2))/((("Surface area")/("Volume"))_(1))=(6/d_(2))/(6/d_(!))=d_(1)/d_(2)=30/10=3`
108.

For a process to occurs spontaneouslyA. Only the entropy of the system must increaseB. only the entropy of the siroundings must increaseC. either the entropy of the system or that of the surroundings must increaseD. the total entropy of the system and the surroundings must increase

Answer» Correct Answer - D
`(DeltaS)_("system")+(DeltaS)_("surrounding")gt 0` (irreversible process)
109.

On complete hydrogenation, natural rubber produces  (A) polyethylene (B) ethylene-propylene copolymer  (C) polyvinyl chloride (D) polypropylene

Answer»

Correct option (B) ethylene-propylene copolymer

Explanation:

Natural rubber forms due to polymerisation of isoprene and on hydrogenation provides polymer of ethylene, propylene. 

110.

At 298 K, the ratio of osmotic pressure of two solutions of a substance with concentrations of 0.01 M and 0.001 M, respectively, isA. 1B. 100C. 10D. 1000

Answer» Correct Answer - C
`pi=CRT rArr pi prop C` at const. T
`pi_(1)/pi_(2)=C_(1)/C_(2)=0.01/0.001=10`
111.

Assuming ideal begaviour, the enthalpy and volume of mixing of two liquids, respectively, areA. zero and zeroB. `+ve` and zeroC. `-ve` and zeroD. `-ve` and `-ve`

Answer» Correct Answer - A
For Ideal solution
`DeltaH` Mix `=0" "DeltaV` Mix `=0`
112.

The angle of a prism is `60^(@)`. When light is incident at an angle of `60^(@)`on the prism, the angle of emergence is `40^(@)`. The angle of incidence i for which the light ray will deviate the least is such thatA. `I lt 40^(@)`B. `40^(@) lt I lt 50^(@)`C. `50^(@) lt I lt 60^(@)`D. `I gt 60^(@)`

Answer» Correct Answer - B
113.

A solution containing 8.0 g of nicotine in 92 g of water freezes 0.925 degrees below the normal freezing point of water. If the molal freezing point depression constant Kf = – 1.85ºC mol–1 then the molar mass of nicotine is- (A) 16 (B) 80 (C) 320 (D) 160 

Answer»

Correct Option :- (D) 160

114.

The heating of `(NH_(4))2Cr_(2)O_(7)` produces another chromium compound along with `N_(2)` gas. The change of oxidation state of Cr in the reaction isA. `+6 "to" +2`B. `+7 " to " +4`C. `+8 " to " +4`D. `+6 " to " +3`

Answer» Correct Answer - D
`(NH_(4))underset(+6)underset(darr)(underline(Cr_(2)))O_(4) to N_(2)+underset(+3)underset(darr)(underline(Cr_(2)))O_(3)+4H_(2)O`
`+6 " to " +3`
115.

For a tetrahedral complex `[MCl_(4)]^(2-)`, the spin-only magnetic moment is 3.83 B.M. The element M is -A. CoB. CuC. MnD. Fe

Answer» Correct Answer - A
`[MCl_(4)]^(2-)` Tetrahedral `=sp^(3)` hybridisation
`M^(+2)`
`because mu=sqrt(n(n+2))B.M.=3.83`
n = 3
Means configuration of `M^(+2)=3d^(7)`
so, `M=3d^(7)4s^(2)=._(27)Co`
116.

The Crystal Field Stabilization Energy (CPSE) and the spin-only magnetic moment in Bohr Magneton (BM) for the complex `K_(3)[Fe(CN)_(6)]` are, respectively-A. `0.0 Delta_(s)` and `sqrt(35) BM`B. `+2.0 Delta_(s)` and `sqrt(3) BM`C. `-0.4 Delta_(s)` and `sqrt(24) BM`D. `-2.4 Delta_(s)` and `0 BM`

Answer» Correct Answer - B
Informative
117.

 The Crystal Field Stabilization Energy (CPSE) and the spin-only magnetic moment in Bohr Magneton (BM) for the complex K3[Fe(CN)6] are, respectively- (A) 0.0 ∆s and √35 BM  (B) –2.0 ∆s and √3 BM (C) –0.4 ∆s and √24 BM (D) –2.4 ∆s and 0 BM 

Answer»

Correct Option :- (B) –2.0 ∆s and 3 BM

118.

The complex having the highest spin-only magnetic moment isA. `[Fe(CN)_(6)]^(3-)`B. `[Fe(H_(2)O)_(6)]^(2+)`C. `[MnF_(6)]^(4-)`D. `[NiCl_(4)]^(2-)`

Answer» Correct Answer - C
`{:((A)[Fe(CN)_(6)]^(3-),d^(5),"Low spin",n=1,mu=sqrt(2)),((B)[Fe(H_(2)O)_(6)]^(2+),d^(6),"High spin",n=4,mu=sqrt(4)),((C)[MnF_(6)]^(4-),d^(5),"High spin",n=5,mu=sqrt(35)),((D)[NiCl_(4)]_("Tetrahedral")^(2-),d^(8),"High spin",n=2,mu=sqrt(6)):}`
119.

Among `Ce(4f^(1)5d^(1)6s^(2)), Nd(4f^(4)6s^(2)),Eu(4f^(7)6s^(2))" and " Dy(4f^(10)6s^(2))`, the element having highest and lowest 3rd ionization energies, respectively areA. Nd and CeB. Eu and CeC. Cu and DyD. Dy and Nd

Answer» Correct Answer - B
Highest `3^(rd) I.E. =E4(4f^(7)6s^(2))`
3rd I.E. `Eu^(2+) to Eu^(3+)+e^(Θ)` removal of `E^(Theta)` from half filled `E^(Theta)` configuration
Lowest `3^(rd) I.E= Ce (4f^(1)5d^(1)6s^(2))`
3rd `E^(Theta)` removal from 5d
120.

Among Ce(4f1 5d1 6s2 ), Nd(4f4 6s2 ), Eu(4f7 6s2 ) and Dy(4f10 6s2 ), the elements having highest and lowest 3rd ionization energies, respectively, are  (A) Nd and Ce (B) Eu and Ce (C) Eu and Dy(D) Dy and Nd

Answer»

Correct option (B) Eu and Ce

Explanation: 

After removig 2 electrons in E, it acquires stable half –filled orbital whereas in ce 3rd electron can easily removed from 5d sub-shell.  

121.

Bacteriochlorophylls are photosynthetic pigments found in phototrophic bacteria. Their function is distinct from the plant chlorophylls in that they- (A) do not produce oxygen (B) do not conduct photosynthesis (C) absorb only blue light (D) function without a light source 

Answer»

Correct Option :- (A) do not produce oxygen

122.

In photosynthetic carbon fixation, which ONE of the following reacts with CO2?  (A) Phosphoglycolate (B) 3-Phosphoglycerate (C) Ribulose-1, 5-bisphosphate (D) Ribose-5-phosphate 

Answer»

Correct option (C) Ribulose-1, 5-bisphosphate

Explanation:

Ribulose –1,5 – bis – phosphate is the 1st CO2 acceptor in C3 cycle during photo synthesis and produce 3– PGA. 

123.

Match the diseases in Column I with the routes of infection in Column II. Choose the CORRECT combinationColumn IColumn IIP. Tuberculosis i. Contaminated food and water Q. Dysentryii. Inhalation of aerosolR. Filariasis iii. Contact via skinS. Syphilis iv. Sexual intercourse v. Mosquito bite(A) P-ii, Q-i, R-v, S-iv (B) P-ii, Q-i, R-iii, S-v (C) P-i, Q-iii, R-v, S-iv (D) P-ii, Q-iii, R-iv, S-v 

Answer»

The Correct option is (A) P-ii, Q-i, R-v, S-iv 

124.

Match the disease given in Column I with the principal causal organism in Column II and choose the correct combination.     Colum IColumn II(P) AIDS(i) HBV(Q) Syphilis(ii) Neisseria sp.(R) Viral hepatitis(iii) Treponema sp.(S) Gonorrhoea (iv) HIV (A) P-iv, Q-iii, R-i, S-ii (B) P-iv, Q-ii, R-i, S-iii (C) P-i, Q-ii, R-iv, S-iii (D) P-i, Q-iv, R-ii, S-ii 

Answer»

Correct Option :- (A) P-iv, Q-iii, R-i, S-ii

125.

Which ONE of the following options lists the primary energy source (s) for all forms of life on earth ?(A) Light, Inorganic substances (B) Inorganic substances, Organic substances (C) Light, Organic substances (D) N2 , CO2

Answer»

Correct Option :- (A) Light, Inorganic substances

Explanation :-

Autotrophs uses light for photosynthesis and some bacteria inorganic compound for chemosynthesis these organisms are produces in ecosystem. 

126.

A particle of mass m moves around the origin in a potential `(1)/(2)momega^(2)r^(2)`, where r is the distance from the origin. Applying the Bohr model in this case, the radius of the particle in its `n^(th)` orbit in terms of `a=sqrt(h//2pimomega)` isA. `asqrtn`B. anC. `an^(2)`D. `ansqrtn`

Answer» Correct Answer - A
127.

Name the terminal acceptor of electrons in the mitochondrial electron transport chainA. NitrateB. FumarateC. SuccinateD. Oxygen

Answer» Correct Answer - D
Oxygen is the acceptor of el ectrons in mitochondrial ETS.
128.

At rest the volume of air that moves in and out per breath is called (A) resting volume (B) vital capacity (C) lung capacity (D) tidal volume  

Answer»

At rest the volume of air that moves in and out per breath is called  tidal volume.  

129.

The presence of nutrients in the food can be tested. Benedict's test is used to detect (A) sucrose (B) glucose (C) fatty acid (D) vitamin 

Answer»

Correct option (B) glucose

Explanation:

Only reducing sugar give the test with benedict solution.  

130.

At rest the volume of air that moves in and out per breath is calledA. resting volumeB. vital capacityC. lung capacityD. tidal volume

Answer» Correct Answer - D
131.

The cell that transfers information about pain to the brain is called a (A) neuron (B) blastocyst (C) histoblast (D) haemocyte 

Answer»

The cell that transfers information about pain to the brain is called a neuron. 

132.

In the 16th century, sailors who travelled long distances had diseases related to malnutrition, because they were not able to eat fresh vegetables and fruits for months at a time. Scurvy is a result of deficiency ofA. carbohydratesB. proteinsC. Vitamin CD. Vitamin D

Answer» Correct Answer - C
133.

The cell that transfers information about pain to the brain is called aA. neuronB. blastocystC. histoblastD. haemocyte

Answer» Correct Answer - A
134.

Several minerals such as iron, iodine, calcium and phosphorous are important nutrients. Iodine is found in (A) thyroxine (B) adrenaline (C) insulin (D) testosterone 

Answer»

Several minerals such as iron, iodine, calcium and phosphorous are important nutrients. Iodine is found in thyroxine .

135.

You remove four fresh tobacco leaves of similar size and age. Leave "leaf 1" as it is, smear "leaf 2" with vaseline on the upper surface, "leaf 3" on the lower surface and "leaf 4" on both the surfaces. Hang the leaves for a few hours and you observe that leaf 1 wilts the most, 2 has wilted, leaf 3 wilted less than leaf 2 and leaf 4 remains fresh. Which of the following conclusion is most logical?A. tobacco leaf has more stomata on the upper surfaceB. tobacco leaf has more stomata on the lower surfaceC. stomata are equally distributed in upper and lower surfacesD. no conclusion on stomatal distribution can be drawn from this experiment

Answer» Correct Answer - B
136.

Several minerals such as iron, iodine, calcium and phosphorous are important nutrients. Iodine is found inA. thyroxineB. adrenalineC. insulinD. testosterone

Answer» Correct Answer - A
137.

The principle upon which a lactometer works is  (A) viscosity (B) density (C) surface tension (D) presence of protein 

Answer»

The principle upon which a lactometer works is density. 

138.

Mammalian liver cells will swell when kept in  (A) hypertonic solution (B) hypotonic solution (C) isotonic solution (D) isothermal solution  

Answer»

Correct option (B) hypotonic solution 

Explanation:

Endo-osmosis occur in cell, when cell is placed in Hypotonic solution 

139.

The principle upon which a lactometer works isA. viscosityB. densityC. surface tensionD. presence of protein

Answer» Correct Answer - B
140.

Mammalian liver cells will swell when kept inA. hypertonic solutionB. hypotonic solutionC. isotonic solutionD. isothermal solution

Answer» Correct Answer - B
Endo-osmosis occur in cell, when cell is placed in Hypotonic solution
141.

Two mutually perpendicular long straight conductors carrying uniformly distributed charges of linear charges densities `lambda_(1)` and `lambda_(2)` are position at a distance a from each other. How does the interaction between the rods depends on a ? A. `1//r`B. `1//r^(2)`C. `r`D. `r^(0)`

Answer» Correct Answer - D
142.

A nucleus has a half-life of 30 minutes. At 3 PM its decay rate was measured as 120,000 counts/sec. What will be the decay rate at 5 PM ?A. 120,000counts/secB. 60,000counts/secC. 30,000counts/secD. 7500counts/sec

Answer» Correct Answer - D
143.

A book is resting on shelf that is undergoing vertical simple harmonic oscillations with an amplitude of 2.5 cm. What is the minimum frequency of oscillation of the shell for which the book will lose contact with the shelf ? (Assume that `g = 10 m//s^(2)`)A. 20 HzB. 3.18 HzC. 125.6 HzD. 10 Hz

Answer» Correct Answer - B
144.

 An ideal gas is made to undergo a cycle depicted by the PV diagram alongside. The curved line from A to B is an adiabat,Then- (A) The efficiency of this cycle is given by unity as no heat is released during the cycle (B) Heat is absorbed in the upper part of the straight line path and released in the lower part (C) If T1 and T2 are the maximum and minimum temperatures reached during the cycle, then the efficiency is given by 1 – T1 / T2 (D) The cycle can only be carried out in the reverse of the direction shown in figure 

Answer»

Correct Option :- (B) Heat is absorbed in the upper part of the straight line path and released in the lower part

Explanation :-

From the analysis of P-V diagram we can easily say that B is the correct option. 

145.

In human brain two cerebral hamisphcres are com by a bundle of fibers which is known asA. Medulla oblongataB. cerebrumC. cerebellumD. corpus cellosum

Answer» Correct Answer - D
Corpus callosm id nercous attaches both carebral hemispheres of mammals.
146.

The major final product in the following reaction is - `CH_(3)CH_(2)CNoverset("1)CH"_(3)MgBr)underset("2)"H_(3)O^(+))rarr`A. B. C. D.

Answer» Correct Answer - C
`{:(" "N-MgBr" O"),(" | ||"),(H_(3)C-CH_(2)-C-CH_(3)overset(H_(2)O^(+))rarrH_(3)C-CH_(2)-C-CH_(3)):}`
147.

LiOH reacts with `CO_(2)` to form `Li_(2)CO_(3)` (atomic mass of Li=7) the amount of `CO_(2)` (in g) consumed by 1g of LiOH is closet toA. 0.916B. 1.832C. 0.544D. 1.088

Answer» Correct Answer - a
`2Lion+CO_(2)toLi_(2)CO_(3)+H_(2)O`
`1/24 1/(24xx2)`
`"no of moles of" CO_(2)=1/48`
`"mass of "CO_(2)=1/48xx 44= 0.916g`
148.

The potential energy of a point particle is given by the expression V (x) = –αx + β sin (x/γ). A dimensionless combination of the constant α, β and γ is– (A) α/βγ (B) α2 /βγ (C) γ/αβ (D) αγ/β 

Answer»

Correct :- (D) αγ/β

Explanation :-

[ α ] = MLT-2

[ β ] = ML2T−2  

γ ] = L

149.

A neutron star with magnetic moment of magnitude m is spinning with angular velocity `omega` about its magnetic axis. The electromagnetic power P radiated by it is given by `mu_(0)^(x)m^(y)omega^(z)c^(u)` where `mu_(0)` and c are the permeability and speed of light in free space, respectively. ThenA. x = 1, y = 2, z = 4 and u =` –3`B. x = 1, y = 2, z = 4 and u = 3C. x = `–1`, y = 2, z = 4 and u = `–3`D. x = `–1`, y = 2, z = 4 and u = 3

Answer» Correct Answer - A
150.

A solid sphere spinning about a horizontal axis with an angular velocity `omega` is placed on a horizontal surface. Subsequently it rolls without slipping with an angular velocity of :A. `2omega//5`B. `7omega//5`C. `2omega//7`D. `omega`

Answer» Correct Answer - C