InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 3101. |
The domain of √sin(cosx) |
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Answer» The domain of √sin(cosx) |
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| 3102. |
The value of ∣∣∣∣∣(b+c)2baacba(c+a)2cbcacb(a+b)2∣∣∣∣∣ is: |
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Answer» The value of ∣∣ |
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| 3103. |
Let A=⎡⎢⎣100210321⎤⎥⎦. U1,U2,U3 are column matrices satisfying AU1=⎡⎢⎣100⎤⎥⎦, AU2=⎡⎢⎣230⎤⎥⎦ and AU3=⎡⎢⎣231⎤⎥⎦. If U is 3×3 matrix whose columns are U1,U2 and U3, then det(U) equals |
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Answer» Let A=⎡⎢⎣100210321⎤⎥⎦. U1,U2,U3 are column matrices satisfying AU1=⎡⎢⎣100⎤⎥⎦, AU2=⎡⎢⎣230⎤⎥⎦ and AU3=⎡⎢⎣231⎤⎥⎦. If U is 3×3 matrix whose columns are U1,U2 and U3, then det(U) equals |
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| 3104. |
If p(x) = – x2 + px – p – 8 and p(x) < 0 for all real values of x, then the value of p cannot be a)7 b)-3 c) 0 d)10 |
| Answer» If p(x) = – x2 + px – p – 8 and p(x) < 0 for all real values of x, then the value of p cannot be a)7 b)-3 c) 0 d)10 | |
| 3105. |
For the differential equation given in the question find a particular solution satisfying the given condition. dydx+2y tanx=sinx, y=0 when x=π3. |
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Answer» For the differential equation given in the question find a particular solution satisfying the given condition. |
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| 3106. |
A tangent to the parabola y2=8x makes an angle of 45∘ with the straight line y=3x+5. Then one of the points of contact has the coordinates |
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Answer» A tangent to the parabola y2=8x makes an angle of 45∘ with the straight line y=3x+5. Then one of the points of contact has the coordinates |
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| 3107. |
If tan θ=12 then evaluate cos θsin θ+sin θ1+cos θ |
| Answer» If then evaluate | |
| 3108. |
If f(x)=x+∫10(xy2+x2y) f(y)dy, and f(x)=Ax2+Bx119 then [A+B100] = (where [.] is G.I.F) ___ |
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Answer» If f(x)=x+∫10(xy2+x2y) f(y)dy, and f(x)=Ax2+Bx119 then [A+B100] = (where [.] is G.I.F) |
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| 3109. |
Solution set of the inequality log0.8(log6x2+xx+4)<0 |
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Answer» Solution set of the inequality log0.8(log6x2+xx+4)<0 |
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| 3110. |
A line passing through the point A with position vector →a=4^i+2^j+2^k is parallel to the vector →b=2^i+3^j+6^k. Find the length of the perpendicular drawn on this line from a point P with position vector →r1=^i+2^j+3^k. |
| Answer» A line passing through the point A with position vector →a=4^i+2^j+2^k is parallel to the vector →b=2^i+3^j+6^k. Find the length of the perpendicular drawn on this line from a point P with position vector →r1=^i+2^j+3^k. | |
| 3111. |
Find thederivative of the following functions (it is to be understood that a,b, c, d, p, q, r and s arefixed non-zero constants and m and n are integers): |
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Answer» Find the
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| 3112. |
7. If sin 8θ + sin 6θ + sin 4θ = 0, then θ is equal to |
| Answer» 7. If sin 8θ + sin 6θ + sin 4θ = 0, then θ is equal to | |
| 3113. |
5x−2y=6, 15x−6y=c Which of the following choices of c will result in a system of linear equation with no solution? |
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Answer» 5x−2y=6, 15x−6y=c Which of the following choices of c will result in a system of linear equation with no solution? |
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| 3114. |
If y(α)=√2(tan α+cot α1+tan2α)+1sin2α where α∈(3π4,π), then dydα at α=5π6 is |
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Answer» If y(α)=√2(tan α+cot α1+tan2α)+1sin2α where α∈(3π4,π), then dydα at α=5π6 is |
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| 3115. |
Let f:R→(0,1) be a continuous function. Then, which of the following function(s) has(have) the value zero at some point in the interval (0, 1)? |
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Answer» Let f:R→(0,1) be a continuous function. Then, which of the following function(s) has(have) the value zero at some point in the interval (0, 1)? |
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| 3116. |
a+bx, x128. Suppose f(x)=x=1and if limf (x)-f (1) what are possible values of a and b? |
| Answer» a+bx, x<14,b-ax, x>128. Suppose f(x)=x=1and if limf (x)-f (1) what are possible values of a and b? | |
| 3117. |
If X and Y are two sets such that n (X) = 17, n (Y) = 23 and n(X∪Y)=38, find n(X∩Y). |
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Answer» If X and Y are two sets such that n (X) = 17, n (Y) = 23 and n(X∪Y)=38, find n(X∩Y). |
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| 3118. |
If |x−2|≤1, then |
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Answer» If |x−2|≤1, then |
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| 3119. |
The value of ∣∣∣∣∣a2+1abacabb2+1bcacbcc2+1∣∣∣∣∣ is: |
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Answer» The value of ∣∣ |
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| 3120. |
Simplify : (9p – 5q )^2 +180pq = (9p + 5q)^2 |
| Answer» Simplify : (9p – 5q )^2 +180pq = (9p + 5q)^2 | |
| 3121. |
The value(s) of ′m′ for which the area of the region bounded by the curve y=x–x2 and the line y=mx(92) is sq.units, is |
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Answer» The value(s) of ′m′ for which the area of the region bounded by the curve y=x–x2 and the line y=mx(92) is sq.units, is |
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| 3122. |
{\operatorname{sin}(α t-α t^2)=0}{ Find }t |
| Answer» {\operatorname{sin}(α t-α t^2)=0}{ Find }t | |
| 3123. |
How much money does 4 ten-rupee notes and 3 five-rupees notes together make? What about 7 ten rupee notes and 4 five-rupees notes? Let us denote the number of ten rupee notes by t, five rupees notes by f and the total amount by m. What is the relation involving t, f, m? |
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Answer» How much money does 4 ten-rupee notes and 3 five-rupees notes together make? What about 7 ten rupee notes and 4 five-rupees notes? Let us denote the number of ten rupee notes by t, five rupees notes by f and the total amount by m. What is the relation involving t, f, m? |
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| 3124. |
Distance between two parallel planes 2x+y+2z=8 and 4x+2y+4z+5=0 is : |
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Answer» Distance between two parallel planes 2x+y+2z=8 and 4x+2y+4z+5=0 is : |
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| 3125. |
The remainder when 7103 is divided by 25 is: |
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Answer» The remainder when 7103 is divided by 25 is: |
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| 3126. |
If C1 and C2 are circles whose equations are x2+y2−20x+64=0 and x2+y2+30x+144=0, then the length of the shortest line segment PQ that is tangent to C1 at P and to C2 at Q is |
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Answer» If C1 and C2 are circles whose equations are x2+y2−20x+64=0 and x2+y2+30x+144=0, then the length of the shortest line segment PQ that is tangent to C1 at P and to C2 at Q is |
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| 3127. |
15. Simplify:cot (b-c)cot (c-a)+cot (c-a)cot (a-b)+cot (a-b)cot (b-c) |
| Answer» 15. Simplify:cot (b-c)cot (c-a)+cot (c-a)cot (a-b)+cot (a-b)cot (b-c) | |
| 3128. |
2¹⁰⁰÷7 |
| Answer» 2¹⁰⁰÷7 | |
| 3129. |
Prove that: 2sin23π4+2cos2π4+2sec2π3=10 |
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Answer» Prove that: 2sin23π4+2cos2π4+2sec2π3=10 |
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| 3130. |
The least value of a for which the equation 4sinx+11−sinx=a has atleast one solution in the interval (0,π2) is |
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Answer» The least value of a for which the equation 4sinx+11−sinx=a has atleast one solution in the interval (0,π2) is |
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| 3131. |
If the parabola x2=ay makes an intercept of length √40 units on the line y−2x=1, then a is equal to |
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Answer» If the parabola x2=ay makes an intercept of length √40 units on the line y−2x=1, then a is equal to |
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| 3132. |
A function f is such that f(h)=−1,f(−h)=1 as h→0+ has a maximum at x=0. Then the set of value(s) of f(0) can be |
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Answer» A function f is such that f(h)=−1,f(−h)=1 as h→0+ has a maximum at x=0. Then the set of value(s) of f(0) can be |
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| 3133. |
If (1,−2) is a pole of the circle x2+y2−10x−10y+25=0, then the equation of the diameter which bisects the polar is |
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Answer» If (1,−2) is a pole of the circle x2+y2−10x−10y+25=0, then the equation of the diameter which bisects the polar is |
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| 3134. |
Find the intervals in which the function f given by f ( x ) = 2 x 2 − 3 x is (a) strictly increasing (b) strictly decreasing |
| Answer» Find the intervals in which the function f given by f ( x ) = 2 x 2 − 3 x is (a) strictly increasing (b) strictly decreasing | |
| 3135. |
The solution of differential equationdydx=3x−6y+7x−2y+4 is (where c is constant of integration and log is given with base ′e′) |
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Answer»
dydx=3x−6y+7x−2y+4 is (where c is constant of integration and log is given with base ′e′) |
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| 3136. |
Let ABCD be a parallelogram whose diagonals intersect at P and let O be the origin, then −−→OA+−−→OB+−−→OC+−−→OD equals |
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Answer» Let ABCD be a parallelogram whose diagonals intersect at P and let O be the origin, then −−→OA+−−→OB+−−→OC+−−→OD equals |
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| 3137. |
If secθ+tanθ=x, then tanθ=(a) x2+1x(b) x2-1x(c) x2+12x(d) x2-12x |
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Answer» If , then (a) (b) (c) (d) |
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| 3138. |
Let S be the sum of all x in the interval of [0,2π] such that 3cotx^2+ cotx +8. = 0, then he value of S/π is a) 3b)4c)5d)6 |
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Answer» Let S be the sum of all x in the interval of [0,2π] such that 3cotx^2+ cotx +8. = 0, then he value of S/π is a) 3 b)4 c)5 d)6 |
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| 3139. |
If →a,→b and →c are three unit vectors equally inclined to each, then the maximum angle between vectors is |
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Answer» If →a,→b and →c are three unit vectors equally inclined to each, then the maximum angle between vectors is |
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| 3140. |
If f(x) = {sinxx≠nπ,n=0,±1,±2...2,otherwise and g(x) = ⎧⎪⎨⎪⎩x2+1,x≠0,24,x=05,x=2, then limx→0g{f(x)} is |
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Answer» If f(x) = {sinxx≠nπ,n=0,±1,±2...2,otherwise and g(x) = ⎧⎪⎨⎪⎩x2+1,x≠0,24,x=05,x=2, then limx→0g{f(x)} is |
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| 3141. |
Total number of solution of the equation cos4xcosx=sin4xsinx where x∈[0,π] is |
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Answer» Total number of solution of the equation cos4xcosx=sin4xsinx where x∈[0,π] is |
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| 3142. |
ị7.ganttan3r)4 |
| Answer» ị7.ganttan3r)4 | |
| 3143. |
If the circle x2+y2+2λx=0, λ∈R touches the parabola y2=4x externally, then |
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Answer» If the circle x2+y2+2λx=0, λ∈R touches the parabola y2=4x externally, then |
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| 3144. |
The set of all points, where the function f(x)=x1+|x| is differentiable, is |
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Answer» The set of all points, where the function f(x)=x1+|x| is differentiable, is |
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| 3145. |
If find in terms of y alone. |
| Answer» If find in terms of y alone. | |
| 3146. |
Question 61State whether the following statement is true or false:Ratio of area of a circle to the area of a square whose side equals radius of circle, is 1:π |
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Answer» Question 61 State whether the following statement is true or false: Ratio of area of a circle to the area of a square whose side equals radius of circle, is 1:π |
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| 3147. |
Given f(x)=|x−1|+|x+1|. Then f(x) is |
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Answer» Given f(x)=|x−1|+|x+1|. Then f(x) is |
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| 3148. |
Explain quantum number and its types. |
| Answer» Explain quantum number and its types. | |
| 3149. |
A plane which is tangent to the sphere (x−a)2+(y−a)2+(z−a)2=2a2a normal is drawn to the sphere which makes equal intercepts to the coordinate axis. Let the the equation of the line of the intersection is x−2a=y−a−2=z−0Then the equation of the tangent plane is |
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Answer» A plane which is tangent to the sphere (x−a)2+(y−a)2+(z−a)2=2a2 |
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| 3150. |
Let y=y(x) be the solution of the differential equaiton cosec2xdy+2dx=(1+ycos2x)cosec2xdx, with y(π4)=0. Then, the value of (y(0)+1)2 is equal to: |
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Answer» Let y=y(x) be the solution of the differential equaiton cosec2xdy+2dx=(1+ycos2x)cosec2xdx, with y(π4)=0. Then, the value of (y(0)+1)2 is equal to: |
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