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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 5851. |
2+3+3-44/77 |
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| 5852. |
Area of csa of cylinder |
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Answer» 2Πrh 2πrh |
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| 5853. |
one common fact between three angles of a triangle and a liear pair axioms |
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| 5854. |
What are important concepts in real numbers |
| Answer» For important concepts in real numbers U can go through pg.27 of ncert book math class9th i.e. Summary portion...& for better preparation, practise questions like:-•how to represent rational as well as irrational numbers on number line•how to find rational as well as irrational b/w two real numbers •how to express irrational numbers in the form of p/q•rationalization of denominator• laws of exponents for real numbers.. | |
| 5855. |
Lcm of 2no\'s is 1200.what will be HCF |
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| 5856. |
how to remember the theorems of ln 8 quadrilaterals easily |
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Answer» For remembering the theorems, practise the theorems based questions and for quick review see pg.151 summary of chapter Quadrilaterals Chapter8 QuadrilateralsFollowing are the basic concepts:-• Introduction - about what is quadrilaterals• Angle Sum Property of a □ - 360°•Types of □ - ▪square, rectangle, rhombus are llgm ▪kite is not a llgm•Properties of a llgm(prooving questions come)Th.8.1a diagonal divides it into two congruent ?s▪Th.8 2-in llgm , opposites side are equal▪Th.8.3- converse of Th.8.2▪Th.8.4- in llgm, opposite angles are equal ▪Th.8.5- converse of Th.8.4▪Th.8.6- diagonals bisect each other ▪Th.8.7- converse of Th.8.6▪Th.8.8- in llgm, pair of opposite sides are equal and parallel •Mid-point theorem- two theorems only▪Th.8.9- line segment joining the midpoints of two sides of a ? is ll to the 3rd side▪Th.8.10- converse of Th.8.9YOU CAN GO THROUGH THIS WAY AND ALSO PRACTICE THE THEOREMS WITH EXERCISE QUESTIONS... & for overview U can follow pg.151 summary..So that it can help U, Hope so... |
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| 5857. |
2x + 5x = 9x |
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| 5858. |
Square of 14 |
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Answer» 196 169 196 Answer is 169 196 |
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| 5859. |
Find the median of all prime numbers between 20 and 40. |
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Answer» How to solve that question (Find the median....40)? 30 |
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| 5860. |
What is the full form of (s) in heron\'s formula?? |
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Answer» Semi perimeter Semi perimeter Semi perimeter Semi perimeter Semicircle This means half perimeter or semi perimeter Semi perimeter |
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| 5861. |
what is pie? |
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Answer» π is represented by 22/7 or 3.14 The value of π is 22/7 Pie is form of this π type and its value is 22/7 |
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| 5862. |
62728_88282992 |
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| 5863. |
45+98 |
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Answer» 143 143 143 143 |
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| 5864. |
Use of 3d snow flakes |
| Answer» 18√3 | |
| 5865. |
Find the zero of polynomial 2x+5. |
| Answer» 2x + 5 = 02x = -5x = -5/2 | |
| 5866. |
Find the median of first ten prime numbers. |
| Answer» First 10 prime numbers are 2,3,5,7,11,13,17,19,23,27.\xa0Median = value of (n/2)th observation + value of(n/2 + 1) observation/2 = value of 5th observation + value of 6th observation/2 = 11+13/2 = 24/2 = 12\xa0 | |
| 5867. |
In which app they take question |
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| 5868. |
If x=3+√2 then find 1/x^2+x^2 |
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| 5869. |
Prove that bisectors of angles of a parallelogram forms a rectangle. |
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Answer» Given: ABCD is a parallelogram. AE bisects ∠BAD. BF bisects ∠ABC. CG bisects ∠BCD and DH bisects ∠ADCTo prove: LKJI is a rectangle∠BAD + ∠ABC = 180° because adjacent angles of a parallelogram are supplementary\xa0ΔABJ is a right triangle since its acute interior angles are complementarySimilar in ΔCDL we get ∠DLC = 90° and in ΔADI we get ∠AID = 90°Then ∠JIL = 90° as ∠AID and ∠JIL are vertical opposite anglesSince three angles of quadrilateral LKJI are right angles, hence 4th angle is also a right angle.Thus LKJI is a rectangle.\xa0 \xa0 \xa0
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| 5870. |
What is time |
| Answer» Time is the indefinite continued progress of existence and events that occur in an apparently irreversible succession from the past, through the present, to the future.Time is a component quantity of various measurements used to sequence events, to compare the duration of events or the intervals between them, and to quantify rates of change of quantities in material reality or in the conscious experience.Time is often referred to as a fourth dimension, along with three spatial dimensions. | |
| 5871. |
Ch -10 theorem 10.10 |
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| 5872. |
state and prove factor theorem |
| Answer» If a line segment joining two points subtends equal angles at two other points lying on the same side of the line containing the line segment the four points lie on a circle | |
| 5873. |
if a and b are two rational no and 2 + √3 /2-√3=a+b√3 find the value of a and b |
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| 5874. |
Practice question paper 2 Class 9th mathematics |
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| 5875. |
PProve that all the sum of probabilities is 1 |
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| 5876. |
Ch 10 page no 180 solution |
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| 5877. |
If a-b =7 and (a)2 + (b) =85 ,find (a)3 - (b)3. |
| Answer» a-b=7 ⇒a=7+b .....(i)a²+b²=85 ....(ii)Substitution of equation 1 to equation 2.(7+b)²+b² =8549+14b +b²+b² =852b²+14b-36 =0 b² +7b -18 =0\xa0(b+9)(b-2) =0b=-9 v b=2Find value of aa-b=7⇒if b=-9a-(-9)=7a =7-9 =-2⇒if b=2a-2=7a = 7+2 =9So value of a³ - b³ there are 2 options⇒if (a,b) = (-2,-9)a³-b³ = -2³ - (-9)³ = -8 +729 = 721⇒if (a,b) = (2,9)a³-b³ = 2³ - 9³ = 8-729 = -721\xa0 | |
| 5878. |
If a- b= 7 and (a)2 +(b)2 = 85 ,find (a)3 - (b)3. |
| Answer» a-b=7 ⇒a=7+b .....(i)a²+b²=85 ....(ii)Substitution of equation 1 to equation 2.(7+b)²+b² =8549+14b +b²+b² =852b²+14b-36 =0 b² +7b -18 =0\xa0(b+9)(b-2) =0b=-9 v b=2Find value of aa-b=7⇒if b=-9a-(-9)=7a =7-9 =-2⇒if b=2a-2=7a = 7+2 =9So value of a³ - b³ there are 2 options⇒if (a,b) = (-2,-9)a³-b³ = -2³ - (-9)³ = -8 +729 = 721⇒if (a,b) = (2,9)a³-b³ = 2³ - 9³ = 8-729 = -721 | |
| 5879. |
,chapter 6ex6.3 question 6 |
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| 5880. |
Determine |
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| 5881. |
Theorm 8.9 |
| Answer» The line segment joining the mid points of two sides of a triangle is parallel to third side. | |
| 5882. |
What is the value of Phai |
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Answer» 22/7 or 3.14 22/7 3.14 22 upon 7 22/7 |
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| 5883. |
Devide (√3+√7) by(√3-√7) |
| Answer» (√3+√7)/(√3-√7) × (√3+√7)/(√3+√7)(3+2√21+7) / 3-7 = ( 10+2√21) / -4= -10/4-1/2(√21)=-5/2- √21/2= (-5-√21)/2 or=( 5+√21)/(-2) | |
| 5884. |
Theorem of Pythagoras. |
| Answer» (p)sq.=(b)sq.× (h)sq. | |
| 5885. |
Angle is semicircle is a right angle |
| Answer» 90॰ | |
| 5886. |
M²-7m-30 factorise |
| Answer» m²-7m-30= m2 - 10m + 3m - 30= m(m - 10) + 3 (m - 10)= (m -10) (m + 3) | |
| 5887. |
Sides of atriangle a, b, c. If s-a=4cm, s-b=8, s-c=12 then find the value of a, b, c. |
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Answer» Value of a = 20 , b = 16 and c =12. If a, b, c are sides of triangle thens=(a+b+c)/2Given:s-a=4 cms-b=8 cms-c=12 cmAdding these we gets+s+s-a-b-c = 243s-(a+b+c) =243s-2s = 24s = 24Now,s-a=424 - a =4a = 24 - 4 = 20 cms-b=824 - b = 8b = 24 - 8 = 16 cms - c = 1224 - c = 12c = 24 -12 = 12 cm |
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| 5888. |
If the sum of a pair of opposite angels of a quadrilateral is 180; the quadrilateral is cyclic |
| Answer» Given the sum of pair of opposite angles of a quadrilateral is 180° we have to prove that the quadrilateral is cyclic.Let us assume that the quadrilateral ABCD is not cyclic i.e Let the point D does not lie on the circle which makes the quadrilateral non-cyclic. Now, let us do a construction such that join CD\' where D\' is the point of intersection of side AD with the circle.Now, ABCD\' is cyclic⇒ ∠3 + ∠4 = 180°Now, it is given that the sum of pair opposite angles of a quadrilateral ABCD is 180°Therefore, ∠2 + ∠4 = 180°From above two equations we get∠3 + ∠4 = ∠2 + ∠4⇒ ∠3 = ∠2Now, in triangle CDD\', by external angle property∠3 = ∠1 + ∠2⇒ ∠1 = 0 , hence the side CD\' and CD coincides⇒ Point D lies on circleHence, our supposition is wrong quadrilateral ABCD is cyclic. | |
| 5889. |
R 21, h 25Volume of cylinder =? If π=22/7 |
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Answer» 34650 cm^3 34560 v=πr^2 hv=22/7*21*21*25=34650 cm^3 2πRsq. H 2×22/7×21×21×2522×3×21×2534650 cm cube |
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| 5890. |
AAS congruence explanation |
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Answer» If two angle and one side is congruent Angle side angle If two angles and one side of a triangle is equal to the corresponding two angles and one side then the both triangles are said to be congruent by AAS conference criteria.AAS - Two angles and any other side except the angle lying between both angle. |
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| 5891. |
Simple explanation of SAS rule and cpct |
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Answer» SAS→side angle sideCPCT→corresponding part of congruent triangle The full form of CPCT is Corresponding parts of Congruent triangles. Congruency can be predicted without actually measuring the sides and angles of a triangle.If any two sides and angle included between the sides of one triangle are equivalent to the corresponding two sides and the angle between the sides of the second triangle, then the two triangles are said to be congruent by SAS rule.SAS-Congruence Of TrianglesIn above given figure, sides AB= PQ, AC=PR and angle between AC and AB equal to angle between PR and PQ i.e. Ð A = Ð P, hence D ABC ≅ D PQR. |
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| 5892. |
The radii of sphere is 2r.find its volume |
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Answer» Volume of sphere = 4/3 π R*(3)Here R = 2rVolume of sphere = 4/3 π (2r)*3Volume =( 4/3 )8π r*(3)Volume of sphere = 32/3 π r*3 Sometimes we afraid of these questions because of these types of data so it is very simple student radii -2r 4/3×22/7×8r^388/21×8r^3 |
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| 5893. |
Three sides of a isosceles triangle are a,b,b. Finad the area of Triangle |
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Answer» A+b+b=1802b+a=180A+b=90Let a n b be x X+x=902x=90X=45A=45B=90B=45 [24/12, 16:01] Hemant Kumar Sharma: Gd evening sir[24/12, 16:01] Hemant Kumar Sharma: Main hemant[24/12, 20:08] Hemant Kumar Sharma: This is my new phone no.[24/12, 20:08] Hemant Kumar Sharma: Sir purana no.hta dena[24/12, 20:08] Hemant Kumar Sharma: 6397380234 wala[24/12, 20:09] Hemant Kumar Sharma: Gd might sir[24/12, 20:09] Hemant Kumar Sharma: Gd night |
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| 5894. |
Prove that sum of all of interiors angle of triangle is 180° |
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Answer» In ∆ ABC, const. a line PQ through point A and parllel to BC. Then angle PAB + angle A + angle QAC=180° BUT angle PAB=angle B and Angle QAC=angle C [ alternative int. angle] SO, angle B + angle A + angle C = 180° ∆ABCangle A +angle B +angle C =180° (angle sum property of a triangle) |
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| 5895. |
ABC is an isosceles triangle such that BC=BD is the median to base AC then find the measure of ABD |
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| 5896. |
Find the value of f (x)=3x^3-4x^2+7x+5 when x=3 and x=-3 |
| Answer» p(x) = 3x3 - 4x2 + 7x - 5Remainder when x = 3 divides p(x) is\xa0p(3) = 3 33 - 4 32 + 7 3 - 5= 3 27 - 4 9 + 21 - 5 = 61Remainder when x = - 3 divides p(x) is p(-3) = 3 (-3)3 - 4(-3)2 + 7 (-3) - 5= 3 (-27) - 4 9 - 21 - 5= -143Therefore, the required remainders are 61 and -143. | |
| 5897. |
Summative assessment -2(2014-15) |
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| 5898. |
Summative assessment -2 ( 2014 -15) |
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| 5899. |
Find the mean of the first six multiplies of 3 |
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Answer» No idea 3,6,9,12,15,18 are first three multiples of 3. we know that ,{tex}mean =\\frac{sum \\: of \\: the \\: observations }{number \\: of \\: observations }{/tex}{tex}mean =\\frac{3+6+9+12+15+18}{6}\\\\=\\frac{63}{6}\\\\=\\frac{21}{2}\\\\=10.5{/tex}Therefore,mean = 10.5\xa0 |
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| 5900. |
Sides AB and AC of triangle ABC are produced |
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