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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 39451. |
If the distance between the points ( x,2) and (3,-6) is 10 units , then find the positive value of x |
| Answer» Distance between the points P(x, 2) and Q(3, - 6) is 10.Using distance formula PQ = 10{tex}\\Rightarrow{/tex}\xa0{tex}\\sqrt { ( x - 3 ) ^ { 2 } + \\{ 2 - ( - 6 ) \\} ^ { 2 } }{/tex}\xa0= 10{tex}\\Rightarrow{/tex}\xa0{tex}\\sqrt { x ^ { 2 } + 3 ^ { 2 } - 2 \\times 3 \\times x + ( 2 + 6 ) ^ { 2 } }{/tex}\xa0= 10{tex}\\Rightarrow{/tex}\xa0{tex}\\sqrt { x ^ { 2 } + 9 - 6 x + 8 ^ { 2 } }{/tex}\xa0= 10{tex}\\Rightarrow{/tex}\xa0{tex}\\sqrt { x ^ { 2 } + 9 - 6 x + 64 }{/tex}\xa0= 10{tex}\\Rightarrow{/tex}\xa0{tex}\\sqrt { x ^ { 2 } - 6 x + 73 }{/tex}\xa0= 10Squaring both sides, we getx2 - 6x + 73 = 100{tex}\\Rightarrow{/tex}\xa0x2 - 6x + 73 - 100 = 0{tex}\\Rightarrow{/tex}\xa0x2- 6x -27 = 0{tex}\\Rightarrow{/tex}\xa0x2- 9x + 3x-2 7 = 0{tex}\\Rightarrow{/tex}\xa0x(x - 9) + 3(x - 9) = 0{tex}\\Rightarrow{/tex} (x - 9) (x + 3) = 0{tex}\\Rightarrow{/tex}\xa0either\xa0x-9 = 0 or x + 3 = 0{tex}\\Rightarrow{/tex}\xa0x = 9 or x = - 3Ignoring x = - 3 as it is given that x is a positive integer.Thus, only solution\xa0is x = 9. | |
| 39452. |
What is the refrence book of all subjects |
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Answer» For science : S. Chand is the best bookFor maths: R.D. sharma Their ncert exampler and Exam idea. |
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| 39453. |
AD is the bisector of angle BAC of triangle ABC .prove that AB^2+AC^2=AD^2+BD•DC |
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Answer» Anyone who do this question are genius Please do it quickly |
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| 39454. |
Explain root 2 .3 |
| Answer» | |
| 39455. |
How student improve his persentage |
| Answer» By studies | |
| 39456. |
If alpha and bita are zeroes of polynomial ax2 |
| Answer» Yes | |
| 39457. |
Draw a graph of the equation x + y = 6 and 2x-y + 2 = 0. shade the region of the |
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Answer» Plzz graph showing mee Answer kaisa aya |
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| 39458. |
Has pattern of maths changed for grade 10 students |
| Answer» Hope so no..*##! | |
| 39459. |
Why is tossing a coin consodered to be |
| Answer» We know that a coin has only two choices-head or tail and both are equally likely events i.e. the probability of occurrence of both is same. Hence, a coin is a fair option to decide which team will choose ends in the game. | |
| 39460. |
How can prove irrational number easily ? |
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Answer» The number which is not in the p/q from and q is not equal to 0 Any no. Which cannot be in the form of p/q , are said to be irrational number. |
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| 39461. |
Find the value of x.3x+2y=5 ( y=2) |
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Answer» X=1/3 1/3 3x+2×2=53x+4=53x=5-43x=1x=1/3 |
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| 39462. |
Full form of rhs and lhs |
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Answer» RHS= RIGHT HAND SIDELHS= LEFT HAND SIDE Right hand side and left hand side respectively. Right hand side and left hand side R.H.S.= Right hand side L.H.S.= Left hand side |
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| 39463. |
Prove that 2+2=5 |
| Answer» Let 2=x then ,x+x=5 now u can solve this ????? | |
| 39464. |
Which term of the AP: 3,8,13,18,.......,is 78 ? |
| Answer» As we know thatFormula in question Tn= a+(n_1)dTn=78, a=3, n=?, d=8_3=578=3+(n_1)578=3+5n_578+2=5n80=5nn=16 | |
| 39465. |
Proofs of all theorems of triangles |
| Answer» | |
| 39466. |
What is the difference between Euclid\'s division lemma and Euclid\'s division algorithm? |
| Answer» lemma : it is a proven statement which is used for proving another statement.Algorithm: an algorithm is a series of well defined steps which gives a procedure for solving a type of problem. | |
| 39467. |
Mode = 2 median - ??? |
| Answer» | |
| 39468. |
x4+x |
| Answer» | |
| 39469. |
Exercise 8.2-1st Ques part 3rd |
| Answer» | |
| 39470. |
Find the roots of equation5x^2_6x_2=0 |
| Answer» 【3+√19】/5 , (3-√19)/5 | |
| 39471. |
HCF and LCM of 1152 , 1664 |
| Answer» LCM of 1152 =2×2 ×2 ×2 ×2 ×2 ×2 ×3 ×3LCM of 1664 =2×2 ×2 ×2 ×2 ×2 ×2 ×13 LCM of 1152, 1664 =2 ×2 ×2 ×2 ×2 ×2 ×2 ×3 ×3 ×13 LCM =14976 | |
| 39472. |
If sinA=CosAFind value of A |
| Answer» 45 | |
| 39473. |
Find the two irrational numbers between 2 and 3. Write any two of them. |
| Answer» 2.1 ,2.2, 2.2 ,.......2.9 | |
| 39474. |
Show that (1,-1),(5,2),(9,5) are collinear |
| Answer» These all lie in the same line | |
| 39475. |
If cosA +sinA=√2cos AProve that cos A-sinA=√2sinA |
| Answer» ??? no ans | |
| 39476. |
In acute angled triangle ABC ,if AD is prependicular to BC then prove that AD2 = BD× DC |
| Answer» | |
| 39477. |
example 13 of 3rd linear equation in two variable? ??? |
| Answer» See in ncert solutions in my cbse guide | |
| 39478. |
Find if an² + bn is the sum of nth term |
| Answer» | |
| 39479. |
6 x square minus 7 x square + 2 is equal to zero factorise |
| Answer» | |
| 39480. |
For what value of n, are the nth term of two AP:63,65,67......and 3,10,17....equal? |
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Answer» Sorry 61+2n is Tn = a+(n-l)da=63, d=65-63=2Tn=63+(n-1)2Tn=63+2n-2Tn=61-2n_____( i)Case-(ii)Tn=a+(n-1)da=3,d=10_3=7Tn=3+(n-1)7Tn=3+7n-7Tn=7n-4________(i)Solve u |
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| 39481. |
The word problem of quadratic equation and letv are same solution are different why |
| Answer» | |
| 39482. |
Practicle me kon sa experiment lekhna hai sir? |
| Answer» | |
| 39483. |
Why contradict method are used for proofs |
| Answer» The proof by contradiction is grounded in the fact that any proposition must be either true or false, but not both true and false at the same time. | |
| 39484. |
Alpha-bita |
| Answer» Alpha-bitta-gama | |
| 39485. |
Find the sum of the following APs: |
| Answer» | |
| 39486. |
If the polynomial az3+az2+3z-4and z3-4z+a leave the same remainder when divided by z-3 find a |
| Answer» Let p(z) = az3 + 4z2 + 3z - 4And q(z) = z3 - 4z + aAs these two polynomials leave the same remainder, when divided by z - 3, then p(3) = q(3).{tex}\\therefore{/tex} p(3) = a(3)3 + 4(3)2 + 3(3) - 4= 27a + 36 + 9 - 4Or p(3) = 27a + 41And q(3) = (3)3 - 4(3) + a= 27 - 12 + a = 15 + aNow, p(3) = q(3){tex}\\Rightarrow{/tex} 27a + 41 = 15 + a{tex}\\Rightarrow{/tex} 26a = -26; a = -1Hence, the required value of a = -1. | |
| 39487. |
2543*52585 |
| Answer» 133723655 | |
| 39488. |
In a triangle ABC, DE is parallel to base BC with D on AB and E on AC. If AD/DB=2/3.Find Bc/BD |
| Answer» | |
| 39489. |
Find the next number...0,7,26,63..... |
| Answer» 124....but how.... | |
| 39490. |
Which sample papers should i follow for the CBSE board |
| Answer» You can check the sample papers here :\xa0https://mycbseguide.com/cbse-sample-papers.html | |
| 39491. |
If x=3 then x+3 value |
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Answer» 6 Common 6 is the right answer 6 x=-3 |
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| 39492. |
X2 - 3√5x + 10 |
| Answer» | |
| 39493. |
what is ogive ? |
| Answer» Ogive is simply a graphical method of finding median | |
| 39494. |
Solve the following pairs of linear equations in two variables by graph 2x+3y=5,x+y=2 |
| Answer» Soln: Algebraical soln : -The given eqn: are 2x+3y=5 -( i ) X+y=2. -( ii ) Now Graphical soln : - Now from ( i ) , we get : - 2x=5 - 3y ( iii )Now from ( ii ) ,we get : - X=2 - y ( iv )Now put y = 0 in eqn ( iii ) ,we get 2x=5 -3 × 0 Or , 2x = 5 - 0 Or , 2x = 5 Or , x = 5/2 | |
| 39495. |
Cos 45°/ sec 30° + cosec 30° evaluate the following |
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Answer» But ansr is dfrnt You can put the values of these digits and solve it |
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| 39496. |
What is a quadratic equation and alpha beta gamma |
| Answer» equation whose degree of x is only 2 and inthe form of axsquare + bx +c | |
| 39497. |
Which is best exam idea or oswaal question bank |
| Answer» Oswal because it has also topper question printed so that you can take an idea how to write in exam | |
| 39498. |
Solve by quadratic formula :-X^2 - 3 root 5 x + 10 = 0 |
| Answer» | |
| 39499. |
Express trignometric ratios sin A,secA and tanA in tems of cotA |
| Answer» For sin A,By using identity {tex}cosec ^ { 2 } A - \\cot ^ { 2 } A = 1 \\Rightarrow \\cos e c ^ { 2 } A = 1 + \\cot ^ { 2 } A{/tex}{tex}\\Rightarrow \\frac { 1 } { \\sin ^ { 2 } A } = 1 + \\cot ^ { 2 } A{/tex}{tex}\\Rightarrow \\sin A = \\frac { 1 } { \\sqrt { 1 + \\cot ^ { 2 } A } }{/tex}For secA,\xa0By using identity {tex}\\sec ^ { 2 } A - \\tan ^ { 2 } A = 1 \\Rightarrow \\sec ^ { 2 } A = 1 + \\tan ^ { 2 } A{/tex}{tex}\\Rightarrow \\sec ^ { 2 } A = 1 + \\frac { 1 } { \\cot ^ { 2 } A } = \\frac { \\cot ^ { 2 } A + 1 } { \\cot ^ { 2 } A } \\Rightarrow \\sec ^ { 2 } A = \\frac { 1 + \\cot ^ { 2 } A } { \\cot ^ { 2 } A }{/tex}{tex}\\Rightarrow \\sec A = \\frac { \\sqrt { 1 + \\cot ^ { 2 } A } } { \\cot A }{/tex}For tanA,{tex}\\tan A = \\frac { 1 } { \\cot A }{/tex} | |
| 39500. |
4444=20 use addition,subtract, multipleand division |
| Answer» 4444-444=40004000÷200=20 | |