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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 41451. |
Which term of the AP 3, 15, 27, 39,.....will be 132 more than its 54th term? |
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Answer» After now it will be 132+639=771 A = 3n = 54d = 12we know thata + ( n - 1 ) d= 3 + ( 54 - 1 ) 12= 3 + 53 × 12= 3 + 636= 639Now32 + 639 = 771771 = 3 + (n - 1) 12768/12 + 1 = n64 + 1 = nn = 65Therfore 65th term term 132 more than 54th term. |
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| 41452. |
A4+b4 identity |
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Answer» (a2+b2)^2-2a^2b^2 Not in syllabus of class 10th.... |
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| 41453. |
Cot sq A-1÷sin sq A |
| Answer» 1/sin sq is cosec sq......hence cot sq - cosec sq= -1......according to the identity | |
| 41454. |
SinA(1+tanA)+cosA(1+cotA) |
| Answer» Sin (1+sin/cos) + cos (1+cos/sin)......sin(sin+cos/cos)+ cos (sin+cos/sin).... Sin+cos (sin/cos+cos/sin)...sin+cos(sin2+cos2/sincos).....= Sin+cos/ sincos= sec+cosec | |
| 41455. |
root of 25 ? |
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Answer» 5 \xa0√25 = √ 5× 5 = 5 |
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| 41456. |
[ 1-tanA]^2/[1-cotA]^2=tan^A |
| Answer» {tex}\\begin{array}{l}\\frac{(1-\\mathrm{tanA})^2}{(1-\\mathrm{cotA})^2}=\\frac{(1-{\\displaystyle\\frac{\\mathrm{sinA}}{\\mathrm{cosA}}})^2}{(1-\\frac{\\mathrm{cosA}}{\\mathrm{sinA}})^2}\\\\=\\frac{{\\displaystyle(}\\cos{\\displaystyle\\mathrm A}{\\displaystyle-}{\\displaystyle\\mathrm{sinA}}{\\displaystyle{\\displaystyle)}^2}}{{\\displaystyle\\cos^2}{\\displaystyle\\mathrm A}}\\times\\frac{{\\displaystyle\\sin^2}{\\displaystyle\\mathrm A}}{(\\mathrm{sinA}-\\mathrm{cosA})^2}=\\frac{\\sin^2\\mathrm A}{{\\displaystyle\\cos}^2\\mathrm A}=\\tan^2\\mathrm A\\\\\\end{array}{/tex} | |
| 41457. |
Find the perpendicular distance of the point p(4,2) from x-axis |
| Answer» According to conditionThe perpendicular point on y axis will be (0,2)Distance between (4,2) and (0,2) = √ (x2 - x1)2 + (y2 - y1)2= √ (4 -0)2 + (2 - 2)2= √ 42 + 0= 4 units | |
| 41458. |
Which chapters are most important in mathematics |
| Answer» Trigonometry , coordinate geometry and Statics | |
| 41459. |
Two dice is thrown simentaneously. Find the probability of getting a sum 8? |
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Answer» explain how 5/36 Mera toh 1/36 aaraha h 5/36 |
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| 41460. |
If An+ a =6 and d=3 then find the value of a |
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| 41461. |
Find (a+b)2 |
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Answer» 2a +2b What a question it is |
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| 41462. |
Find x when mean is 31:4Class:0-10 10-20 20-30 30-40 40-50 50-60 Frequency :5 x 10 12 7 8 |
| Answer» If mean is 31.4 then x =8 | |
| 41463. |
When two dice are thrown simultaneously find the probality of getting sum of 8 |
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Answer» 5/36 5/36 5/36 |
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| 41464. |
2 divide 6 |
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Answer» 1/3 1/3 3 |
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| 41465. |
All formulas |
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Answer» Consult your book which u don\'t see in whole year and that\'s why asking for all formulas Which chapter |
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| 41466. |
9 x square - 12 x + 4 is equal to zero |
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Answer» 2/3 2/3 sorry wo ans glti se type ho gya tha 2/3 is ryt 6 |
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| 41467. |
4 x square + 3 X + 5 |
| Answer» Is it 4x^2 + 3x + 5 ? | |
| 41468. |
Find the zeros of the polynomial 4xsquare - 4x+1 |
| Answer» 4xsquare -2x -2x +1=0 2x(2x-1) -1(2x-1)=0(2x-1)(2x-1)=02x-1=0,2x-1=0X=1/2, X=1/2 | |
| 41469. |
SecA=2 X + 1 by 4 x prove that secant theta + tangent theta is equal to 2 x 2 x |
| Answer» By the given condition of question\xa0{tex}\\sec \\theta = x + \\frac { 1 } { 4 x }{/tex}{tex}\\therefore \\quad \\tan ^ { 2 } \\theta = \\sec ^ { 2 } \\theta - 1{/tex}{tex}\\Rightarrow \\quad \\tan ^ { 2 } \\theta = \\left( x + \\frac { 1 } { 4 x } \\right) ^ { 2 } - 1 = x ^ { 2 } + \\frac { 1 } { 16 x ^ { 2 } } + \\frac { 1 } { 2 } - 1 = x ^ { 2 } + \\frac { 1 } { 16 x ^ { 2 } } - \\frac { 1 } { 2 } = \\left( x - \\frac { 1 } { 4 x } \\right) ^ { 2 }{/tex}{tex}\\Rightarrow \\quad \\tan \\theta = \\pm \\left( x - \\frac { 1 } { 4 x } \\right){/tex}{tex}\\Rightarrow \\quad \\tan \\theta = \\left( x - \\frac { 1 } { 4 x } \\right) \\text { or, } \\tan \\theta = - \\left( x - \\frac { 1 } { 4 x } \\right){/tex}CASE 1: When\xa0{tex}\\tan \\theta = - \\left( x - \\frac { 1 } { 4 x } \\right) :{/tex}\xa0In this case,{tex}\\sec \\theta + \\tan \\theta = x + \\frac { 1 } { 4 x } + x - \\frac { 1 } { 4 x } = 2 x{/tex}CASE 2: When\xa0{tex}\\theta = - \\left( x - \\frac { 1 } { 4 x } \\right) :{/tex}\xa0In this case,{tex}\\sec \\theta + \\tan \\theta = \\left( x + \\frac { 1 } { 4 x } \\right) - \\left( x - \\frac { 1 } { 4 x } \\right) = \\frac { 2 } { 4 x } = \\frac { 1 } { 2 x }{/tex}Hence,\xa0{tex}\\sec \\theta + \\tan \\theta = 2 x \\text { or } , \\frac { 1 } { 2 x }{/tex} | |
| 41470. |
P is the midpoint of an arc QPR of a circle. Show that the tangent at P is parallel to the chord QR. |
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| 41471. |
Prove pythagorus theorm |
| Answer» One angle 90 and hypotenuse is longest side and one side | |
| 41472. |
Chapter Weightage of maths |
| Answer» Ch 1........6marksCh 2,3,4,5......20 marksCh 6,10,11.......15 marksCh 7......6 marksCh 8,9........12 marksCh 12,13......10 marksCh 14,15........11marks | |
| 41473. |
What is the value of root 2 |
| Answer» 1.414 | |
| 41474. |
2+25663365522 |
| Answer» 25663365524 | |
| 41475. |
Pythagorus theorem |
| Answer» Given in ncert... | |
| 41476. |
Prove that root 3 is rational number |
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Answer» This is of root 2 Assume $\\sqrt{2}$ is rational, i.e. it can be expressed as a rational fraction of the form $\\frac{b}{a}$, where $a$ and $b$ are two relatively prime integers. Now, since $\\sqrt{2}=\\frac{b}{a}$, we have $2=\\frac{b^2}{a^2}$, or $b^2=2a^2$. Since $2a^2$ is even, $b^2$ must be even, and since $b^2$ is even, so is $b$. Let $b=2c$. We have $4c^2=2a^2$ and thus $a^2=2c^2$. Since $2c^2$ is even, $a^2$ is even, and since $a^2$ is even, so is a. However, two even numbers cannot be relatively prime, so $\\sqrt{2}$ cannot be expressed as a rational fraction; hence $\\sqrt{2}$ is irrational. $\\blacksquare$ Given in ncert examples |
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| 41477. |
What are the possible outcomes if we tossed three differe nt coins simultunously |
| Answer» 8 | |
| 41478. |
Solve for x and y:2x+3y=7 (a+b+1)x+(a+2b+2)y=4 (a+b)+1 |
| Answer» If infinite number of solutions,{tex}\\frac{{{a_1}}}{{{a_2}}} = \\frac{{{b_1}}}{{{b_2}}} = \\frac{{{c_1}}}{{{c_2}}}{/tex}or {tex}\\frac{2}{{a + b + 1}} = \\frac{3}{{a + 2b + 2}} = \\frac{7}{{4a + 4b + 1}}{/tex}If\xa0{tex}\\frac{2}{{a + b + 1}} = \\frac{3}{{a + 2b + 2}}{/tex}{tex}\\Rightarrow{/tex} a - b = 1and if {tex}\\frac{3}{{a + 2b + 2}} = \\frac{7}{{4a + 4b + 1}}{/tex}{tex}\\Rightarrow{/tex} 5a - 2b = 11On solving we get,a = 3 and b = 2 | |
| 41479. |
If a sum of a no. And it\'s resiprocal is 26 /5 . Find number. |
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Answer» Let the no be xSo its reciprocal is 1/xAccording to questionx+1/x=26/55(Xsq+1)=26x5Xsq-5-26x=05Xsq-26x+5=05Xsq-26x+x+5=05x(x-5)-1(x-5)=0x=1/5 & x=5 x + 1/x = 26/5 represents the given statement. Solve for x. since x cannot be zero (which has no reciprocal), you can multiply all terms by x to getx2 +1 = (26/5) x. You have to solve for x. It\'s a quadratic equation: multiply by 5 to get: 5x2 -26x +5 = 0. |
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| 41480. |
Find the value of k for which one root of the quadratic equation kx_14x+8=o is 2 |
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Answer» Shayad k=10 Put 2 in the place of x because 2 is a root. Use Euclid \'s division Algorithm to find tha HCF of : 135 and 225 Equation mein sq. shayad reh gya hain but k =5 |
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| 41481. |
2017 question paper cbse maths |
| Answer» Just go to the shop in this app nd take the last year papers? | |
| 41482. |
if sin theta =9/6 then cos theta Solutions |
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Answer» SinQ=perpendicular/hypotenuse From pythagoras therom find baseThen cosQ=base/hypotenuse 3√5/6 |
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| 41483. |
Cosec=5/3 then what is the value of cos theta +tan theta |
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Answer» AC\'2=BC\'2+AB\'2AB\'2=AC\'2-AB\'2 =5×5-3×3 =25-9 =16 AB =4cosQ=b/h=4/5 TanQ= p /b= 3/ 4C+t=4/5+3/4 =16+15/20 =31/20 tan theta = 3/4 Cos theta = 4/5 31/20 |
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| 41484. |
Draw 3cm circle |
| Answer» Take a scale and by compass measure 3cm then take 3cm as radius and draw a circle | |
| 41485. |
Find the roots for the equation 5√5x2+30x+8√5 |
| Answer» X= -2/ root5, and - 4 root 5/5........ | |
| 41486. |
dividing line segment in to k:1 formula |
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Answer» Jab ratio given na ho to ye formula use hota hai YouTube · 7activestudio4:00RespirationMay 14, 2013 |
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| 41487. |
In two dice doublet mean? |
| Answer» Doublet in two dice refer to getting same number on both the Dice.... Doublet in two dice are -(1,1),(2,2),(3,3),(4,4),(5,5)&(6,6) | |
| 41488. |
Who was baudhayan? |
| Answer» | |
| 41489. |
Find the value of x for which(x+2),2x,(2x+3)are three consecutive terms of an AP. |
| Answer» (2x+3)-(2x)=(2x)-(x+2) as common difference is same3= x-2x=5 | |
| 41490. |
value tan30 |
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Answer» 1/root 3 1/√3 1/√3 |
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| 41491. |
5+8+9 |
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Answer» 22 23 22... |
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| 41492. |
Did any one know the easiest way to mugup value table of tignometry |
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Answer» For sin- whole root 0/4 (0 degree),whole root of 1/4 ( 30 degree),whole root of 2/4 (45 degree),whole root of3/4(60 degree), whole root of 4/4 (90 degree),........... then make other values with the help of sin Learn the value of sin and write its revese in the value of cos......divide the value of sin and cos to get the value of tan ..n as we know cosec is reciprocal of sin , sec is reciprocal of cos and cot of tan .....then u have to only learn the value of sin...hope it helps u ???? The easiest way is to memorize the important values of trignometry such as of tan 30 or tan60 or by making the whole table on the answer sheet??? |
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| 41493. |
If hcf (a,b)=12 and a×b=1800,then find lcm (a,b) |
| Answer» We Have Formula.H.C.F multiply L.C.M = Product of two Numbers.HCF × LCM = Product of two numbersTherefore,12 × L.C.M = 1800Hence, L.C.M = 1800/12 = 15 | |
| 41494. |
What mean of √ |
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Answer» 4 square root is 2 Square root |
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| 41495. |
Complete this series,9=4, 21=9, 22=9 ,24=10, 8=5,7=5 ,99=10,100=7,16=?,17=? |
| Answer» 16=7, and 17= 9 | |
| 41496. |
In a year ,some month have 30 days,while some have 31days ,Guess which month has 28 days? |
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Answer» Honey, ji ka answer shi hai......? All months have 28 days All |
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| 41497. |
R.D sharma me se kitna paper aa sakta h |
| Answer» Around 20% | |
| 41498. |
If you devide 30 by half and add ten,what do you get. |
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Answer» Its, 70 Oh ya sorry it is 70 25 70 |
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| 41499. |
Sin20+sin70-tan45 |
| Answer» Sin(90 - 20) + sin(90 - 70) - tan(90 - 45)_____ cos70 + cos20 - cot45 | |
| 41500. |
What is quadratic polynomial |
| Answer» It is in the form of ax2 +bx +c = 0 it\'s highest degree is 2 for example : 2x square + 4x + 3 = 0 it\'s a quadratic polynomial... | |