If a sum of a no. And it\'s resiprocal is 26 /5 . Find number.

1.	If a sum of a no. And it\'s resiprocal is 26 /5 . Find number.
Answer» Let the no be xSo its reciprocal is 1/xAccording to questionx+1/x=26/55(Xsq+1)=26x5Xsq-5-26x=05Xsq-26x+5=05Xsq-26x+x+5=05x(x-5)-1(x-5)=0x=1/5 & x=5 x + 1/x = 26/5 represents the given statement. Solve for x. since x cannot be zero (which has no reciprocal), you can multiply all terms by x to getx2 +1 = (26/5) x. You have to solve for x. It\'s a quadratic equation: multiply by 5 to get: 5x2 -26x +5 = 0.

Discussion