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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
301. |
for class 11th CBSE maths examination I should solve miscellaneous exercise ... |
Answer» Yes , because examiners mostly choose the question from this exercise for the exam question paper.<br>Yes u should try as it will make you strong in chapters<br>Ys of some chapters only but<br>You should only do mai exercise if you are attempting examination<br>Yes | |
302. |
Find the derivative of (x^2+1)(x-2) |
Answer» (x-2)(x^2-1)Solution by u.v method (x-2)(x square+1)u\'v+uv\'(x-2)\'(x^2+1)+(x-2)(x^2+1)\'(1+0)(x^2+1)+(x-2)(2x+0)x^2+2(x-2)x+13x^2-4x+1<br>First derivative | |
303. |
Find the derivative of 2x^3-3x-5 at x=-5. |
Answer» Derivative of 2x³ - 3x - 5 is 6x² -3 so at \'x=-5\' its derivatives l will be 6(-5)² - 3 = 150-3 = 147 | |
304. |
Find the derivative of tan x by first principle |
Answer» By first principalF(x)h=0=tan(x+h)-tan(x)upon h{tanA+B=1+tanAtanB upon tanA-tanB} =1+tanxtanh-tanx upontanx-tanh. h=<br>Sec²x | |
305. |
Write the radiant measure of 5 degrees 37\'30\'\' |
Answer» Answer:\xa05 degree 37\xa0minute\xa030\xa0second=0.098 Radians. | |
306. |
If INDIA is coded as KMFHC then what will be AMERICA coded as? |
Answer» CLGQKBC<br>CLGQKBC" The pattern followed is - I - skip one letter then the next one is used(K) N - the previous letter is used(M) D -skip one letter then the next one is used(F) I -the previous letter is used(H) A -skip one letter then the next one is used(C)Hope it helps you...<br>HelloI think the answer would be -"CLGQKBC"The pattern followed is -I - skip one letter then the next one is used(K)N - the previous letter is used(M)D -skip one letter then the next one is used(F)I -the previous letter is used(H)A -skip one letter then the next one is used(C) | |
307. |
Write the degree measure of 5degree 37\' 30\'\' |
Answer» | |
308. |
Show that (2,-3,5),(1,2,3) and (7,0,-1) are collinear |
Answer» | |
309. |
Insert 6 numbers between 3 and 23 such that the resulting sequence is an AP |
Answer» Add 20/7 to 3 to get first number then add it again to obtain next numberCommon difference = (last term - first term)/no. of numbers to be inserted +1 = (23-3)/6+1 = 20/7 | |
310. |
prove that sin 10*sin 30*sin 50 *sin 70= 1/16 |
Answer» We know thati) sin 2A = 2sinAcosAii) sin(90-A)= cosAiii) sin30=1/2LHS = sin 10 sin30 sin50sin 70=sin 10 × 1/2 × sin (90-40)× sin(90-20)=1/2[sin 10 ×cos 40×cos 20]We multiply with[2 cos 10/2cos 10]=(1/2×1/2cos10)[2sin10cos10×cos20×cos40]=(1/4cos10)[sin20cos20×cos40]=(1/8cos10)[2sin20cos20×cos40]=(1/8cos10)[sin40cos40]=(1/16cos10)[2sin40co40]=(1/16cos10)×sin80=(1/16cos10)×sin(90-10)=(1/16cos10)×cos10=1/16= RHS | |
311. |
Limit X tends to zero sin a x + b x by x + sin BX |
Answer» | |
312. |
Exercise 3.3 question 10 |
Answer» U may search on YouTube u will get better explanation<br>Of NCERT or any other reference book... | |
313. |
Xdy/dx-2y=e^x.x^3 |
Answer» | |
314. |
(3-x)=|x-3| solve for x. |
Answer» (3-x)=|x-3|Remove modulus-±(3-x)=x-33-x=x-3 or -(3-x)=x-3x=9/2 or -3+x=x-3 x=9/2 or 0=0So,x=9/2<br>X=9/2<br>X= 3<br>The value of x will be 3<br>The value o x is 3 | |
315. |
d/dx (3√x) |
Answer» 7568zc fyi<br>d/dx(3√x)=3/2√x<br>d/dx(3x^1/2) It will be. 3/2 x^-1/2It can further written as3/2√x | |
316. |
Find the eccentricity of the ellipse 5 x square + 9 y square is equal to 1 |
Answer» Eccentricity of the question is 2/3 | |
317. |
Find the equation of the circle concentrated with x^2 +y^2 -8x +6y -5 =0 and passing through (-2,-7) |
Answer» x²+y²-8x+6y-35=0 | |
318. |
Write the intervals in set builder form. (-3,6] |
Answer» {-2,-1,0,1,2,3,4,5,6} | |
319. |
Find the x intersept and y intersept of theline 5x+2y+7=0 |
Answer» | |
320. |
If ?? ? = ? and ?? ? = ?? , then find the value of (? + ?). |
Answer» What | |
321. |
If A is a finite set containing ‘n’ elements then find the number of subsets of A. |
Answer» Subset =2power n | |
322. |
Compute the derivative of cos4 x |
Answer» -4sin4x.<br>Sin4x | |
323. |
How many hairs are on your head ?? |
Answer» Exactly the same you have.<br>Sakshi you are not capable to answer sensefull questions so this is why I ask you nonsence questions so please shut your bullshit mouth<br>Very nonsence question<br>Let X be the no. Of hairs on your head...Therefore, your head have X no. Of hairs. | |
324. |
Lim x |
Answer» | |
325. |
Limx=2 x²-4/√3x-2-√x+2 |
Answer» | |
326. |
What is eccentricity |
Answer» e²=(a²-b²)/b²<br>e=c/a | |
327. |
How do we find the roots of a quadratic equation. |
Answer» X = (-b+√D)/2a and X= (-b-√D)/2a | |
328. |
Trigonometry some important formula |
Answer» ᴅᴇᴅɪᴄᴀᴛɪᴏɴ ᴏꜰ ᴀʟʟ ꜰᴏʀᴍᴜʟᴀ ᴀʀᴇ ɪᴍᴩᴏʀᴛᴀɴᴛ<br>Gili Gili bili bili<br>All formula NCERT Book me h<br>All formula trigonometry in ncert book<br>All formula are important | |
329. |
i^100+i^50+i^2+i^68+i^2 |
Answer» Answer is 1 | |
330. |
((x + 1)(x - 2))/(sqrt(x))Find the derivatives |
Answer» | |
331. |
Tan4x |
Answer» Tan4x = tan(2.2x)<br>tan(2x+2x)then use tan(a+b)= tan a+tanb/i-tana.tanbok | |
332. |
1/8x³-1/27y³ |
Answer» | |
333. |
Cos47degree. Cos13degree-sin47degree. Sin13degree |
Answer» use formulacosa.cosb-sina.sinb=cos(a+b)answer is :- 1/2 | |
334. |
Tangent 45 |
Answer» 1<br>1<br>1 | |
335. |
Value of sin765° |
Answer» Sin 765°=Sin (720+45)° = Sin 45°Since, Sin (360+x)°=Sin x°Therefore, Sin 45°=1/under root 2 | |
336. |
Area of triangle in co-ordinate geometry |
Answer» Area= (1/2)(x1(y2-y3) + x2(y3-y1) + x3(y1-y2))<br>A = (1/2) [x1 (y2 – y3 ) + x2 (y3 – y1 ) + x3(y1 – y2)] | |
337. |
2x^2+7x+3 |
Answer» 2x^2+7x+3Multiply 2 with 3=6Split the middle term 7x in 6x+1xYou will get2x^2+6x+1x+3Take 2x common from 2x^2+6x you will get 2x (x+3)Take 1 common from 1x+3 you will get 1 (x+3)Now,2x (x+3)+1 (x+3)=(x+3)(2x+1)=x=(-3)........................(1)=x=(-1/2).....................(2)there are two values of x | |
338. |
Factorize 2x2+7x+3 |
Answer» 2x²+7x+32x²+6x+x+32x(x+3)+1(x+3)(X+3)(2x+1)X=-3 or -1/2 | |
339. |
F ( x)=x^100/100+x^99/99+.....x^2/2+x+1 |
Answer» X⁹⁹+x⁹⁸+x⁹⁷+......+x²+x+1 | |
340. |
Find mean variance and S. D for groupes data xi 8,11,17,20,25,30,35 fi 2,3,4,1,5,7,3 answer |
Answer» | |
341. |
1/h×8^1/3-1/2h |
Answer» | |
342. |
Find domain and range of the following questions:(i)f=1÷x-3 (ii)f=1÷√x-3 |
Answer» | |
343. |
Find the domain and range of f(x)=1/2x-1 |
Answer» Since we can put every value of x except 0 (as it yeilds 0 in denominator, which is not function) and then range you can solve | |
344. |
Find domain and range for the following questions:(i)f=1÷x-3 (ii)f=1÷√x-3 |
Answer» | |
345. |
linear inequalities in two variable s daily life example |
Answer» Like this daily life examples let\'s suppose shayam ke pass total money 120 hai , use one register buy krna hai toh one register 80 ka hai aur use pen bhi lena , ek pen 20 rupee ka , bato inequality | |
346. |
Find the mean and variance for the data 6,7,10,12,13,4,8,12 |
Answer» Thanks<br>Mean =72/8=9 | |
347. |
Find the domain and range √(? − 3) (3 − ?). |
Answer» | |
348. |
g(x)= x²-4/x-2 |
Answer» | |
349. |
Thales theorem.. explains it. |
Answer» | |
350. |
If 9th term of an a.p. is zero then proof that 29th term is double the 19th term |
Answer» Too.long process.. you have done<br>Let a and b respectively be the first term and common difference of the AP Given A9=0So ,a+(9-1)d=0a+8d=0a=-8dNow ,29 th term= a+28d=-8d+28d=20d=2*10d=2(-8d+18d)=2(a+18d)=2*19th term Thus ,the 29 th term of the AP is double the 19th term | |