InterviewSolution
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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 401. |
Find the derivative of 2^x. |
| Answer» x.2^x-1 is the derivative for 2^x.Use a^n = n.a^n-1 formula<br>Put a = 2<br>logea . ax | |
| 402. |
HAPPY NEW YEAR ALLL OF YOU ??? |
| Answer» Sowndu and smarkee ko bulao<br>No bro mai use nhi krta fb insta and etc.<br>Same 2u bro<br>Happy New Year ?<br>Same 2u | |
| 403. |
Who was the father of algebr |
| Answer» Al_khwarizmi<br>I mean algebra | |
| 404. |
What is set N? |
| Answer» Natural number<br>Set N denotes the set all natural numbers.<br>N is the set of netural numbers only , 0(zero) not included ✓✓<br>A natural number is a number that occurs commonly and obviously in nature. As such, it is a whole, non-negative number. The set of natural numbers, denoted N, can be defined in either of two ways:N = {0, 1, 2, 3, ...}N = (1, 2, 3, 4, ...} | |
| 405. |
Formulas of chapters from ch 1-ch 14 |
| Answer» Say one chap only or have only one of them brooo<br>Itna long | |
| 406. |
If y = 5cosø - 3sinøThen prove that d^2 y / dx^2 +y = 0 |
| Answer» It\'s simpledy/dx = -5sin-3cosd2y/dx^2 = -5cos+3sinAdding y both side we getD^2y/dx^2 +y=0<br>Hey | |
| 407. |
If A,B,&C are any 3 sets , then A- (BUC) =_____________. ????? |
| Answer» A-(BUC)=A<br>Good doubt | |
| 408. |
example 24 |
| Answer» Which chapter? | |
| 409. |
n(A)=1 n(B)=1 the what is the no. Of relations in the Cartesian product (AxB) |
| Answer» 1<br>Use formula \'n(A)×n(B)=n(A×B)\' so ans is 1<br>1<br>2 | |
| 410. |
A child has 6 pockets and 3 coins in how many ways he can put the coins in the pocket |
| Answer» Total no of ways =3×3×3.. =3^6<br>If repetition is not allowed then He can put 6permutation3 ways that is 6!/3!6×5×4× 3!/3!6×5×4= 120-<br>6C3 ways<br>6*6*6=216 ways | |
| 411. |
Derivate (x+a) |
| Answer» (0+1) = 1<br>if a is a constant then the derivative of (x+a) is 1 by the rule xn=n*xn-1 | |
| 412. |
Mod(x-1) greater than equal to mod (x-3) |
| Answer» Find the critical points, here they are 1 and 3.solve for x<1,-(x-1)-(-(x-3))≥0-x+1+x-3≥0-2≥0 (not possible)Thus, x should be greater than 1For 1 ≤ x ≤ 3(x-1)-(-(x-3))≥02x-4≥0x≥2So one solution set is 2≤x≤3For x>3(x-1)-(x-3)≥02≥0Therefore from above two results,x≥2 | |
| 413. |
Find the sum to n terms of the sequence 5+55+555... to n terms |
| Answer» Answer : 5+ 55+555+......n term5(1+11+111+........n term)Dividing and multliply by 9 5/9(9+99+999.....n term)5/9{(10-1)+(100-1)+1000-1)... n term}5/9{(10+10²+10³+... n term)-(1+1+1+...n term)}5/9[{10(10*n-1)/10-1)}-n]5/81{10(10*n-1)-n<br>Answer:\xa0Sum = 5 + 55 + 555 + …. n terms.= 5/9 [9 + 99 + 999 + …. n terms]= 5/9 [(10 – 1) + (100 – 1) + (1000 – 1) + … n terms]= 5/9 [10 + 100 + 1000 ….. – (1 + 1 + … 1)]= 5/9 [10(10n\xa0– 1)/(10 – 1) + (1 + 1 + … n times)]= 50/81(10n\xa0– 1) – 5n/9 | |
| 414. |
5542-111 |
| Answer» 5432<br>Calculator nhi tha kya apke pass ?<br>5431??<br>5431 How simple ??? | |
| 415. |
Find the lines through (2,-1) which cut the axes so that the intercepts are equal in magnitude |
| Answer» As the intercepts are equal therefore x+y=a. As the equation passes through points(2,-1), a=2-1=1Therefore the required equation is x+y=1 | |
| 416. |
Flower |
| Answer» Variety ???? | |
| 417. |
Which term of the A. P. 15, 20, 25, ... is 115? |
| Answer» Given,a=25d=20−25=−5Tn\u200b<0a+(n−1)d<025+(n−1)(−5)<025<5(n−1)5<(n−1)n>6⇒n=77th term is negative.a7\u200b=25+(7−1)(−5)=25−5×6=−5 | |
| 418. |
Find the domain of f(x)=√x+2 +1/√10-x |
| Answer» In this type of equations ,if we have to find out domain we have to solve the denominator-So,=> √10-x=0=> [x=√10]Domain=set of real no.s except √10. | |
| 419. |
ꜰɪɴᴅ ᴛʜᴇ ɴᴜᴍʙᴇʀ ᴏꜰ ꜱᴜʙꜱᴇᴛꜱ ᴏꜰ ᴀ×ʙ ᴡʜᴇʀᴇ ᴀ ={3,6,9} ᴀɴᴅ ʙ={x,ʏ,ᴢ} |
| Answer» No of relation=3×3=9,and no of subsets of A×B is 9^2=81 | |
| 420. |
What is property of modolus function. With example |
| Answer» The graph of modulus function is continuous having a corner at x=0. It means that graph is differentiable at all points except at x=0 (we can not draw a tangent at a corner). Since graph is symmetric about y-axis, modulus function is even function. We also see that there are pair of x values for non-zero values of y. | |
| 421. |
Value of tan pi/8 |
| Answer» Pi=180 so ans is180/8<br>(Square root of 2)-1<br>_/2-1 | |
| 422. |
Find the domain of f(x)=√x+2+1/√10-x |
| Answer» | |
| 423. |
Evaluate cosec (-1200°) |
| Answer» | |
| 424. |
. Sn denotes the sum of the first n terms of AP. If S2n = 5 Sn, thenprove that ?????? =??/4 |
| Answer» | |
| 425. |
Deleted topics of maths?please koi points Mai likh ke dedo |
| Answer» Yes Gaur saab?<br>Gaur saab..???<br>Thanks Aadya<br><a href="https://ibb.co/SBLpJkz"></a> | |
| 426. |
What is deleted syllabus of maths???please reply!! |
| Answer» Oh Bhai usme deleted topics kha hai<br>Mujhe toh mila nhi<br>Where | |
| 427. |
If tan(a-b)=sin2b/5-cos2b, then find tan a : tan b |
| Answer» | |
| 428. |
Derivative of secx |
| Answer» You will get tanx*secx<br>Chain rule*<br>Put secx=1/cosx, the apply chai rule | |
| 429. |
Integration of tan4x is |
| Answer» | |
| 430. |
Y=(1÷3)^2 curve sketching |
| Answer» | |
| 431. |
Prove that cot (x+y)=cotx coty -1/cotx+coty? |
| Answer» | |
| 432. |
Find the derivatives of 1/x |
| Answer» 1/x=x–¹=-1x–¹–¹=-1x–² | |
| 433. |
tan(X+Y)=sin(X+Y) /cos(X+Y)write a passion yes or no ? |
| Answer» | |
| 434. |
Activity 4 observations solutions |
| Answer» | |
| 435. |
Derive the formula ^n+r-1C r |
| Answer» Nahi ata yaar muja bi | |
| 436. |
1. Find the number of solution for the function fx) = sinx andy =; 1/3 ifx E [-T,T] |
| Answer» | |
| 437. |
find the sum of the values of x and y satisfying the equations 3x - 4y=77 and 3 x/2-2y =7 |
| Answer» | |
| 438. |
find the sum of the values of x and y |
| Answer» | |
| 439. |
If |x+2|≤9 then x=? |
| Answer» | |
| 440. |
The minute hand of the clock is 42 long. Find the distance of its tip cover in 20 minutes |
| Answer» In an hour or 60 minutes, the large hand performs a complete circle of 360 degree. Therefore, in a time span of 20 minutes or One third of one Hour, you will get 120 degree or\xa0To find the count of centimeters it is required to move the hand, we first frame the formula i.e. to find the length of the “arc” formed by circular movement of the handTherefore, the extremity moves 88 cm in twenty minutes. | |
| 441. |
Find real part of 5+2i |
| Answer» 5 | |
| 442. |
find the value of tan pie/8 |
| Answer» | |
| 443. |
If X and Y are two sets such that n(X)=17,n(Y)=23 and n(X u Y ) = 38, find n(XU Y) |
| Answer» It is given that:n(X)=17,n(Y)=23,n(X∪Y)=38n(X∩Y)=?Using the formulan(X∪Y)=n(X)+n(Y)−n(X∩Y)∴38=17+23−n(X∩Y)⇒n(X∩Y)=40−38=2∴n(X∩Y)=2 | |
| 444. |
$$0^{+0^{+}}=?$$ |
| Answer» Wrong<br>0Because if we multiply dividend by 0 so the answer will come 0 only | |
| 445. |
Sin(A+B) proof |
| Answer» Sin(A+B)=sinAcosB+cosAsinB | |
| 446. |
Find (x+1)^6+(x-1)^6.hence Or evalute (root 2+1)^6+(root2-1)^6 |
| Answer» | |
| 447. |
Multiple inverse of 3-2i? |
| Answer» Answer | |
| 448. |
Using binomial theorem,indicate which number is larger (1.1)^10000 or 1000 |
| Answer» (1.1)^(10000) = (1 + 0.1)^(10000)use formula,(x + y)^n = nC0.x^n + nC1.x^(n-1)y + nC2.x^(n-2)y^2 + ........+nCn.y^n(1 + 0.1)^(10000) = 10000C0.(1)^(10000) + 10000C1.(1)^9999(0.1) + ....... other terms= 1 × 1 + 10000 × 0.1 + ......... other terms .= (1 + 1000 + .......other terms ) > 1000hence, (1.1)^(10000) > 1000<br>(1.1)^(10000) = (1 + 0.1)^(10000)use formula,(x + y)^n = nC0.x^n + nC1.x^(n-1)y + nC2.x^(n-2)y^2 + ........+nCn.y^n(1 + 0.1)^(10000) = 10000C0.(1)^(10000) + 10000C1.(1)^9999(0.1) + ....... other terms= 1 × 1 + 10000 × 0.1 + ......... other terms .= (1 + 1000 + .......other terms ) > 1000hence, (1.1)^(10000) > 1000 | |
| 449. |
Find the sum to n terms of an A. P whose k^th term is 5k+1 |
| Answer» As, it is given that k th\xa0 term of the A.P. is 5k + 1.therefore, ak = a + (k – 1)d⇒ a + (k – 1)d = 5k + 1⇒ a + kd – d = 5k + 1now, on comparing the coefficient of k, we get,d\xa0= 5and\xa0\xa0a – d = 1⇒ a – 5 = 1⇒ a = 6 | |
| 450. |
General equation of line? |
| Answer» Hi<br>Ax+By+C=0<br>We know that graph of general equation of first degree in two variables, Ax + By + C = 0, where A, B and C are real constants such that A and B are not zero simultaneously is a straight line.Thus General Equation of Straight line is Ax + By + C = 0, where A, B and C are real constants such that A and B are not zero simultaneously. | |