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p(a) ={1, 2,(1, 2), {}}

then power set is 4

p(a) = ¢, [a],[b],[a,b]

The set B-A is the set containing elements which are in B but not in A. So the set is(Trapezium).

Let ABCD be a parallelogram which circumscribes the circle.AP = AS [Tangents drawn from an external point to a circle are equal in length]BP =BQ [Tangents drawn from an external point to a circle are equal in length]CR= CQ [Tangents drawn from an external point to a circle are equal in length]DR = DS [Tangents drawn from an external point to a circle are equal in length]Consider, (AP + BP) + (CR + DR) = (AS + DS) + (BQ + CQ)AB + CD = AD + BCBut AB= CD and BC = AD [Opposite sides of parallelogram ABCD]AB + CD =AD + BCHence 2AB = 2BCTherefore, AB= BC Similarly, we get AB= DA and DA = CDThus, ABCD is a rhombus.

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I didn't understand your answer

thanks again

ok thanks for your help and support

I am not sure what to do it for

I will send it back on the phone to call the number yet to be in a few minutes late please yet to be in a few minutes ago and I will send it out and about in class on Tuesday and then delete it

I have to be able to do it e a good time re yreeuutrrrwttuutyyy and I will be in the future of weed out to me so that I have a great day today thanks for the first time in a way to get to see

I have to be able to do it e a good time re yreeuutrrrwttuutyyy and I will be in the future of weed out to me so that I have a great day today thanks for the first time in a way to get to see

Option 1 is the correct answer

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CMP DMP dp is b skywalk you have a great day and I

GIVEN: Triangle ABC , AB = AC => < B =< ABD = < ACD In triangle ABD & triangle ACE < ABD = < ACE ( proved above)tri ABD ~ tri ACE ( by AA similarity criterion) => AB/AC = AD/AE ( csst) But AB = AC ( given) …….. (1) => AD = AE ………(2) => AB - AE = AC - AD => BE = DC …….. (3) By (2) & (3) ED // BC ( by converse of Basic proportionality theorem) Plz like my answer and accepted as best plz

CMP DMP dp is b sky walk you have agreat day andI

If ∆ABD~∆ACE ,then we can prove AB/AC=AD/AE..but AB=AC .....1) AD=AE...2) AB-AE=AC-AD, that employes BE=DC...3)by 2&3 ED//BC...

GIVEN: Triangle ABC , AB = AC => < B =< ABD = < ACD In triangle ABD & triangle ACE < ABD = < ACE ( proved above)tri ABD ~ tri ACE ( by AA similarity criterion) => AB/AC = AD/AE ( csst) But AB = AC ( given) …….. (1) => AD = AE ……(2) => AB - AE = AC - AD => BE = DC …….. (3) By (2) & (3) ED // BC ( by converse of Basic proportionality theorem) Plz like my answer and accepted as best plz

GIVEN: Triangle ABC , AB = AC => < B =< ABD = < ACD In triangle ABD & triangle ACE < ABD = < ACE ( proved above)tri ABD ~ tri ACE ( by AA similarity criterion) => AB/AC = AD/AE ( csst) But AB = AC ( given) …….. (1) => AD = AE ………(2) => AB - AE = AC - AD => BE = DC …….. (3) By (2) & (3) ED // BC ( by converse of Basic proportionality theorem)

: Triangle ABC , AB = AC => < B =< ABD = < ACD In triangle ABD & triangle ACE < ABD = < ACE ( proved above)tri ABD ~ tri ACE ( by AA similarity criterion) => AB/AC = AD/AE ( csst) But AB = AC ( given) …….. (1) => AD = AE ………(2) => AB - AE = AC - AD => BE = DC …….. (3) By (2) & (3) ED // BC ( by converse of Basic proportionality theorem) Plz like my answer and accepted as best plz

AB = AC => < B =< ABD = < ACD In triangle ABD & triangle ACE < ABD = < ACE ( proved above)tri ABD ~ tri ACE ( by AA similarity criterion) => AB/AC = AD/AE ( csst) But AB = AC ( given) …….. (1) => AD = AE ………(2) => AB - AE = AC - AD => BE = DC …….. (3) By (2) & (3) ED // BC

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i dont know answer please send me correct option

(i) 256 + (-312) = 256 - 312 = -56(ii) -319 + (-136) = -319 - 136 = -455

256+(-312)=256-312=-56

Proof: Draw three non-collinear points. Name them A, C, B respectively. Construction: Draw circle through the non-collinear points. Repeat this activity. You will get the same answer

Option (3)

Angles AEB and BEC are adjacent angles as they share a common vertex E as well common arm BE.

Then what letter would the answer be?

I have written... option (3) is a false statement. If the options are in alphabetical order, then option (c) is the false statement

Please send answer in steps. I have not understood

above we have found AEB ( sorry for writing wrong) below you can find AED

( a - 1/ a)^2= a^2 + 1 / a^2 -2,; (5)^2 + 2 = a^2 + 1 /a^2 ==25+2=27

27 is the correct answer for this question Thank you

a²+1/a²=27 is answer

the correct answer of this question is 27

27 answer hoga iska samjha

27 is the correct answer of your question.

= 20000(1+5/100)^6

= 20000*21*21*21*21*21*21/20*20*20*20*20*20

= 26,801.9125

CI = 26801.91 - 20000

= 6801.91

What is star there

(-9/25) * (10/9)

= - 10/25

= - 2/5

the answer is (-9/25) * (10/9)= -10/25= -2/5

9 * 2 = 18 -1 = 17160 *2 = 320 -1 = 319475 * 2 = 950 -1 = 949

ty bhai

Option (3)

Angles AED and BEC are vertically opposite angles as they are on the opposite sides of the common vertex E.

Thanks!

I just posted a similar question. can u answer it for me?

i) the sum of adjacent angle is 180° i.e. angle AOC + angle BOC = 180°

Like my answer if you find it useful

ABCE is a quadrilateral in which AC is its diagonal and AB || EC, AB = AC BA is produced to D AE bisects ∠DAC To prove: (i) ∠EAC = ∠ACBRead

hope you understand

Simple interest=PRT=10000*8*2.5/2=100000

Give full answers

Rombus all 4 side are equal

X+x+x+x = 104

4x= 104

X= 26 cm

Now diagonals of rombus bisect each other at 90 then

26² = (5x)²+(12x)²

676 = 25x² + 144x²

676 = 169x²

X² = 676/169

X²= 4

X = 2

Hence 5*2 = 10 and 12*2= 24 …Hence full length of diagonals are 10+10 = 20 and 24+24=48