Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

ABC is a triangle in which LB 2 LC. D is a point on BC such that ADbisects (BAC and AB-CD Prove that LRAC = 72°.

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2.

Iwo adjacent angles of a parallelogram areand (3x-5)o. The value of x is

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(2x+25)+(3x-5)=180[sum of adjacent sides of ||gm is 180.]-> 5x+20=180-> 5x=160-> x=32

NOW,... (2x+25)=(2*32+25)=89(3x-5)=(3*32-5)=91

TO check-89+91=180

3.

19. A diagonal of a quadrilateral is 26 cm and the perpendiculars drawn to it from the oppostevertices are 12.8 cm and 11.2 cm. Find the area of the quadrilateral.

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*72* is the largest size

4.

E is the mid-point of side BC of a ΔABC, such that the perpendicular from E on the sides AB and AC are equal. Show that AE bisects Angle BAC

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5.

Fig. 11.33ABCD is a parallelogram. AP bisects ZA and CQ bisects C. P lies on CD and olies on AB. Show that-(i) AP CQ(ii)AQCP is a parallelogram.

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can you give me a detailed and proper solution

6.

le23sp is a pointe elintant from two lines lend m intersecting atpuntEvaExample 8:238). Show that the line AP bisects the angle betwcen them

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7.

AC. ProveIn AABC, D is any point in the interior of AABC such that DBC <DCB and ABthat AD bisects <BAC.CB and AB

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Given ∠DBC = ∠DCB .....(1)so, BD = DC .....(2)

Given : AB = ACSo, ∠ABC = ∠ACB ....(3)

Consider (3) - (1)So,∠ABD = ∠ACD .....(4)

In ∆ ABD and ∆ ADC,AB = AC∠ABD = ∠ACD from (4)BD = DC from (2)

By SAS rule ∆ ABD and ∆ ADC are congurent so ∠BAD = ∠CAD .So, AD bisect ∠ BAC

Thx

8.

1, tanl°tan2°tan3°tan 4° ... (870 89% का मान होगा : . (b) 0. © L

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Let's take tan 89 and tan 1 in the first case and Let's take Tan 2 and tan 88 in 2nd case:-By the Problem,[1st case]:-=) tan(90-89)tan89=) cot89 x tan89=) 1/tan89 x tan89 [tan89 will be canceled onboth the sides by multiplying]=) 1. Ans.

By the Problem,[2nd Case]:-=) tan(90-88) tan88=) cot88 x tan88=) 1/tan88 x tan88 [tan 88 will be canceled onboth the sides by multiplying]=) 1.Ans.

Therefore, if we go on doing this for every ratios...we will come to the answer 1 for each case.Hence, Answer = 1.

9.

(c) 3The value of (sin? 10 + sin? 3° + sin sºsin-85° + sin 870-sin89°)

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(sin^2 1° + sin^2 3° + sin^2 5° + sin^2 85° + sin^2 87° + sin^2 89°)

Using, cos(90 - x) = sin xsin^2 x + cos^2 x = 1

= (sin^2 1° + sin^2 3° + sin^2 5° + cos^2 (90 - 85) + cos^2 (90 - 87) + cos^2 (90 - 89))

= (sin^2 1° + cos^2 1° + sin^2 5° + cos^2 5° + sin^2 3° + cos^2 3°)

= 1 + 1 + 1

= 3

10.

2000 from a bank for 2 years at 12% per annum and? 3000 frorn his friend for2Sunil borrowedyears at 15% per annum. How much total interest did he pay?3,

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690 is the total intrest

I = P*R*N/100so I1+I2=2000*12*2/100 + 3000*15*2/100=480 + 900 = 1380

11.

A diagonal of a quadrillateral is 26 em and the perpendiculars drawn to it from the opposttevertices are 12.8 cm and 11.2 cm. Find the area of the quadrilateral.19.

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12.

Use Euclid's division algorithm to find H.C.F. of 870 and 225.

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13.

Ravi's car travels 174 km on 120 litre of petrol. How much petrol is needed for travelling870 km?

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14.

olve the following questions: (Any iwo)) If 3x +5y 9 and 5x +3y 7, then what is the value of (x + y)?

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15.

pnuionm22by14m.Findtheheightof the platform.. Iwo cubes of volume 64cm2 are joined end to end. Find the volume of the sphere.

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16.

20. The outer and the inner circumference of two concentric circles are 880 cm and 3082. Iwo croangles tof lenrespectively. Find the difference between their radii.cm

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17.

How much is the simple interest earned on R 75 for 3 months at 8 p.c.p.a.?(1) 1.05 (2) 18 (3) 15 (4) 1.503.

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Principle is Rs 75Rate is 8% p. aTime is 3 monthsSo, Simple interest = P*R*T /100S. I. = 75 * 8 * 0.25 /100S. I. = 150/100S. I. = Rs 1.50

18.

Show that the perpendiculars drawn from the vertices of the base of an isosceles triangle to the opposite sides are equal.

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19.

8. If AP bisects angle BAC and M is any pointon AP, prove that the perpendiculars drawnfrom M to AB and AC are equal.

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20.

Which is the greatest among\sqrt{2}, \sqrt[3]{4} \text { and } \sqrt[4]{3}

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21.

Prove that the length of the perpendicularsdrawn from vertices of equal angles of anisosceles triangle to the opposite sides are equal.

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22.

Which is the greatest among \sqrt{2}, \sqrt[3]{4} \text { and } \sqrt[4]{3} ?

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23.

Which is the greatest among \sqrt { 2 } , \sqrt [ 3 ] { 4 } \text { and } \sqrt [ 4 ] { 3 }

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24.

tnat.8. If AP bisects angle BAC and M is any pointon AP, prove that the perpendiculars drawnfrom M to AB and AC are equal.

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25.

. 4.PORS is a parallelogram, and PI and RM areand Rperpendiculars drawn from the vertices Pof the parallelograim on diagonal sQ. Show that

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26.

27. The probabilities of a problem being solved23by two students are Then the probabilityof the problem being solved is23 (b)43 (d) 1

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first case if both will solvethen 23/90=25 percentageif one will solve then probability

23/90(1-23/90)+(1-23/90)*23/90+23/9023/90*67/90+0.250.38+0.250.63

27.

fone diagonal of a quadrilateral is 40 cm, and perpendiculars drawn to it fromThe lensre 12 cm and 9 cm. Find the area of the quadrilateral.care IE

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Let abcd is the quad.Then ac=40Broke the quad. into two ∆So ar(abc)=0.5*40*12=240cmAnd ar(ADC)=0.5*40*7.5=180cmAr(abcd)=240+180=420cm

28.

Sandeep borrowed 3000 for 4 years and 800 for 2 years ftat the same rate of interest. The total interest earned by SoFind the rate of interest.

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2880=(3000×4×r)/100+(8000×5/2×r)/1002880=120r+200r=320rso r=2880/320=9%

29.

89 : The line segment joining the mid-points of two sides of a triangto the third side.

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30.

The line segment joining the mid-points of two sides of a triangle is parallel to the third side

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31.

95. The H.C.F. of two numbers is 12 and their difference is also 12. Thenumbers are

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Let numbers be12xand12ywherexandy are both co-prime numbers.

∴|12x-12y|=12

=>12|x-y|=12=>|x-y|=12/12=1

So there can be many possibilities,

x = 2 , y = 1So they can be 24 and 12.

x = 3 , y = 2So they can be 36 and 24.

x = 5 , y = 4So they can be 60 and 48.

32.

. Are the numbers 12, 18, 26, 39 in proportion ?

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Yea they are in same proportionas12/18= 6/9= 2/3and26/39= 2/3so yesthanks

33.

The HC.F of iwo numbers is 12 and their difference is also 12. Thenumbers areA) 66, 78(C) 94, 106(B) 70, 82(D) 84.96

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HCF is 12 so numbers should be multiple of 12 and difference is 12 so only possible pair among options is 84 and 96.

34.

26. 24, 36 और 40 का ल० स० निकालिए -(a) 120 (b)240 (c) 360[RRB मुम्बई (Group 'D')-2003](d) 480 ।

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360 is the right answer

360 is the correct answer of the given question

2|24|36|402|12|18|202| 6 | 9| 103| 3 | 9| 53| 1| 3| 55| 1| 1| 5LCM =2×2×2×3×3×5=360

360 is the answer.....

360 is the right answer.

plz like my answer

360 is the correct answer

35.

Are the numbers 12, 5 and 13 form a Pythagorean Triplet?

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Yes they doas12^2+5^2= 13^2= 144+25= 169

36.

The greatest decimal among 3.109, 3.019,3.099and3.19

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Out of these numbers, 3.19 is the greatest.

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37.

41 I3. The greatest among 41, 82, 36, 43, is

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The greatest number among 41 82 36 43 is 82.

38.

व कर लिन को & W 0 CRMTF 4 e A1. .... द्विधात समीकरण (» + 5)4 > 2 (5: - 8) F1 HEHH (discriminant) fafam |Write the discriminant of the quadratic equation (x + 5)% =2 (5x-3),

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39.

दड्े [2५ IPRRLIC kB12 112 2P I %8 RIS ‘I3 0000/ Lmikaic | 2312 1 "G

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40.

10. Mr. Britto deposits a certain sum of money eachmonth in a Recurring Deposit Account of a bank. Ifthe rate of interest is 8% per annum and Mr. Brittogets 8088 from the bank after 3 years, find thevalue of his monthly instalment. aCSE 2013)Hint. Type Solved Ex. 4]Mohfor 213.120

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41.

1. Find the vector in the direction of the vector i - 2 j that has magnitude 7 u

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42.

5. Find the area of a quadrilateral one of whose diagonals is 40 cm and the lengths of thperpendiculars drawn from the opposite vertices on the diagonal are 16 cm and 12 cm.

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43.

2. What will be the simple interest earned on an amount of Rs. 16,800 in 9 months athe rate of 6-% p:a. ?(a) Rs. 787.50 (b) Rs. 812.50 (e) Rs. 860(d) Rs. 887

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44.

The perimeter of a rhombus is 180 cm and one of its diagonals ls 12 ll.Tliof the other diagonal and the area of the rhombus.3.

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45.

Find the area of the fig., formed by joining mid points of adjacent sides of a rhombus withdiagonal 12 cm and 16 cm

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46.

-CONILIULUI 1110017. Find the least square number which is exactly divisible by each of the numbers 6, 9, 15and 20.

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47.

9. Find the least number which is exactly divisible by each one of the numbers 12, 16 and 24.-Lanthanne of 15 20 and 20toner

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48 will be the right answer of this question

12/2=6/2=3; 16/2=8/2=4/2=2; 24/2=12/2=6/2=3; 3x3x2=18

48.

240()360() 440 i

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49.

Question 12:Let f: X - Y be an invertible function. Show that the inverse of f1 is f, i.e.,(F1)-1 = f.

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50.

ika Golden Solved Question Bank(Check the continuity of the function defined asunder atx-J.)x+3f(x)-2x36x +2 x23

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