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Sum of angles in n sided polygon=(n-2)*1806 right angles=6*90=540Remaining angles=(n-6)*200540+(n-6)*200=(n-2)*180540+200n-1200=180n-36020n=300n=15

Number of sides are 15

x/2 - 1/5 = x/3 + 1/4

x/2 - x/3 = 1/4 + 1/5

(3x-2x)/6 = (5+4)/20

x/6 = 9/20

x = 6×9/20

x = 27/10

2x+3y=13----------(i)5x-3y=22 ------------(ii)-----------------7x = 35, x=5putting the value of x in eq 12x+3y=132(5) + 3y=1310-13=3y-3=3yY=-1

2x+3y=13___________(i) 5x-3y=22___/___________(ii) __________________7x=35; x=35/7=5, 2(5)+3y=13, 3y=13-10=3; y =3/3=1; x=3; y=1

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Given quadratic equation is=x² + 5px +16 = 0

On comparing with standard form of quadratic equation i.e ax² + bx + c =0,Here, a = 1 , b= 5p, c= 16

D(discriminant)= b²-4ac= (5p)² - 4× 1 × 16= 25p² - 64

Since, roots of given equation has no real roots. D < 0.

25p² - 64 <05p² - 8² < 0(5p +8)(5p -8)< 0[ a² - b² = (a-b)(a+b)]5p +8 <0 or 5p - 8< 0k > -8/5 or k < 8/5

-8/5 < k < 8/5

Hence, the required value of k is -8/5 < k < 8/5.

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multiplying x+√3 and x-√3 i.e.x^2-3now, dividing the equation with x^2-3we get x^2-3x-2 whose that roots are x-1 and x-2

thanks

I think the answer is 6135.8cm2

My both pairs of opposite sides are parallel is parallelogram

My all angles are right angles it can be rectangle.

My all side are equal in length is rhombus

My all angles are equal and side are equal is square.

Coordinates of P=3(a)+1(b)/3+1=3a+b/4Coordinates of Q=(3b+a/4+a/2)=3b+5a/8Position of Q=3b+5a/8

x²-3x-10=0x²-5x+2x-10=0x(x-5)+2(x-5)=1

x²-3x-10=0x²-5x+2x-10=0x(x-5)+2(x-5)=0(x+5)(x+2)=0x+5=

x²-3x-10=0x²-5x+2x-10=0x(x-5)+2(x-5)=1

x= -2 or 5 is the correct answer for this question

5,-2 is the correct answer of the given

the correct value of x in this question is _2and 5

x^2-3x-10 = x^2-5x+2x-10=0; x(x-5)+2(x-5)=( x+2)(x-5)=0; x=-2; x=5

x^2-3x-10=0x^2-5x+2x-10=0x(x-5)+2(x-5)=0(x-5)(x+2)=0either x-5=0 , x= 5or x+2=0 ,x= -25, -2 are the zerosif a,b be zerossum of zerosa+b= -(-3)/1=3product of zerosa -10/1= -10

(5x-2)/10=(4x+3)/1260x-24=40x+3060x-40x=30+2420x=54x=54/20=27/10

thanks

Part 2

Part 1

Roots will be -1 and +1√5/3and -√5/3

The curved surface area of a cylindrical pillar is 264m2 and its volume is 924m3.find the diameter and height of the pillar.

Solution:-Given : CSA of cylinder = 264 m² and volume of cylinder = 924 m³CSA of cylinder = 2πrh264 = 2*22/7*r*hr*h = (264*7)/44r*h = 1848/44r*h = 42h = 42/r ......(1)Now,volume of cylinder =πr²hPutting the value of h = 42/r in the below, we get924 = 22/7*r²*42/r924r = 924*7r = 7 mSo, Radius is 7 m and the diameter will be 7*2 = 14 m.And the height of the cylinder = 42/7 = 6 m

this was the solution for similar question.

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P(x) = 3x^2 - 5x + 6

Then,P(2) = 3*(2)^2 - 5*2 + 6 = 3*4 - 10 + 6 = 12 - 4 = 8

P (2) = 3*(2)2- 5*2+6 = 3*4-5*2+6 = 12-10+6 = 2+6 = 8Here is your ans. 8

Yes because square of 1 side is equal to sum of square of other two side.

180 is correct answer