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61551.

Market value of a share is 200. If the brokerage rate is 03%thente purchase value of the share.

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Let purchase value of share = nGiven,Brokerage =.3%Market value = 200

Purchase value = Market value + brokerage

Purchase value= 200 + 200*(.3/100)= 200 +.6= 200.6

61552.

e diagonals of a quadrilateral ABCD are equal. Prove that thequadrilateral formed by joining the midpoints of its sides is a rhombus.16. Th

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61553.

नुध 1७ 14 पास कु V500 e 1 Dl BRI

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61554.

8Four sides of quadrilateral are equal, prove that its angles are bisected by the diagonalsABCD is a quadrilateral in whishAR CD A

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61555.

का चेन=0 Dl B g oo (4 Dy रह e लत ही 6

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61556.

644B) In the adjacent figure, DE Il BC2ADE-600 andくCz70% Findthe values of x°, yo and zo700

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only short

61557.

(A) 18 e48. Quadrilateral ABCD circumscribes a circle as shown in Fig. The side of thequadrilateral which is equal to AP+ BR is:Fig.3(A) AD(B) AC(C) AB(D) BC

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61558.

6 (a) In the figure () given below, CD Il LA and DE Il AC. Find the length of CL if BE=4cm and EC = 2 cm.(b) In the figure (ii) given below, <D = ZE and DB-EC. Prove that ABC is anisosceles triangle.

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Consider triangle ABC in which BD is perpendicular to AC and EC perpendicular to AB.

in triangle ABCangle D = angle E = 90 degree ( angle D and angle E are perpendicular to AC & AB) (GIVEN)

AD/DB = AE/EC (GIVEN)==> BD = EC.And AB = AC.therefore triangle ABC is an isoceles triangle

how they are perpendicular?

this is based on parallel

61559.

S.In Fig.9.17, PQRS and ABRS are parallelogramsand X is any point on side BR. Show tha(i) ar (PQRS)ar(ABRS)

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61560.

2 30X36. Draw the picture of minor sector clearly

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61561.

pointCliesbetwentwopointsAandBsuchthatACen provethat ACAB. Explain with figure.

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61562.

how many rational number lies between 5 and 6 ?

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The answere is infinity

61563.

2. Find out the missing terms.0, 2, 6, 11,20, L 142.(a) 15,18 D (b) 12,30(c) 16,25 D (d) none of these

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the answer is (b) 12,30

the answer is (b) 12,30

0,2,2+4,6+6,12+8,20+10,30+12b .12,30 is the right answers

B)12,30 is the right answer

b=12,30 is right answer

61564.

tulPentlowner itMonday. the value of'a company's shares was 7.50. Thelua afeach share when trade opened on Fridahow much will be the rent after 2 years?prieed by 1.5% on Wednesday, and decreased by 2% onThursd

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61565.

Asum of money amounts to? 7833.71 in 3 years andて7303.14 in 2 years, pint the rat.of interest if the total interest is8.2652.85 in the end.

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Any short way u can do it

61566.

180° What 15 DE JUis a1. In the figure, ABC is a triangle andpoint in it. OP and OQ are drawnperpendicular to the sides AB and BCrespectively. If ZB = 65 find ZPOQ13)805

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In given fig. POBQ is a quadrilateral

We know sum of all angles of a quadrilateral is 360°

Thus,65 + 90 + 90 + <POQ = 360<POQ = 360 - (180 + 65) = 360 - 245 = 115°

61567.

(65०० - 0(6 8०० + 1) g /l७३०० 00. टिक ना (1) :amEn[EAd 810241 ३.

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2) cot^2 theeta= (7/8)^2= 49/64

61568.

(xe-i25 w eDl BE LI ey Ejl

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61569.

2 lota ben borroioed some money from a bone atthe rate of 12 pcipia simple interest for 25 yearsto start a collage industry. She pard 30,000 astotal interest . How much money had she borraced

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answer of this question 100000

61570.

Hence find the lengths of its sides.ORif A- 5, 7), B4, 5), C-1, -6) and D4, 5) are the vertices of a quadrilateral, find the area of thefl for which the quadratic equation kx2+1-2(k-1)x+x2= 0 has equal rootsquadrilateral ABCDlua o

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By joining B to D ,you will get two triangles ABD,BCD.

The area of triangle ABD

=1/2[-5(-5-5)+(-4)(5-7)+4(7+5)

=1/2(50+8+48)=106/2=53 square units....

Also,

The area of triangle BCD =1/2[-4(-6-5)-1(5+5)+4(-5+6)

=1/2[44-10+4]=19 square units...

Area of Triangle ABD + area of triangle BCD

so,

the area of quadrilateral ABCD=53+19=72 square units..

61571.

5. In Fig. 6.20, DE Il OQ and DF I| OR. Show thatFl QR.

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∆PQR s ED || QO

.°. PD/DO = PE/EQ ( from formula )-------(1)

∆POR s DF || OR

.°. PD/DO = PF/FR ( from formula )........(2)

from (1) and (2) we get

PE/EQ = PF/FR

.°. EF || QR

Like my answer if you find it useful!

61572.

6.20, DE Il OQ and DF || OR. Show that5.EF|| QR

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61573.

Shri Ram paid 200 for a machine. At the end of 7th year it was valued at 95. Assuming the yearly depreciationa constant amount, find the annual depreciation.

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Let the Annual depreciation be x.

We know that,

95 = 200 - 7x

7x = 200 - 95 = 105

7x = 105

x = 15 .

Therefore, The yearly depreciation is 15

61574.

GMAT(K-8)(Questlons 78-81)Directions : In the following questions,( 78-81)od ar exprtond ecn gadloont: da-zineg. eua part of the figure is missing. ldentihy themissing part from among the tour altenativesgiven under each question.78.803)凹,因4)因4)791)2)3)

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8q question that will be opposite I think the answer is2

yes option 2 is the correct answer for 81

61575.

vi) log log log(i) logo3 lies between 1/3 and 1/2 (i) log,70 lies betwen 6 and ahat logs is irrational.1s. Show thatfr such that logos xsinx +1ogsnacos x=2

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61576.

3. In the following APs, find the missing terms0) 2, 26

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61577.

3. In the following APs, find the missing terms in the boxes:0 2,26

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61578.

5. In Fig. 6.20, DE || OQ and DF II OR. Show thatEFIIQR.

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61579.

473× 84

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39,732is the correct answer

39,732 is the correct ans

473*84=39,732 is the answer

39732 is the correct

39732 is the correct

39,732 is the correct answer

39,732 is correct answer

61580.

soham deposite 85,000 rupees for30 month at 7 p.c.p.a in a saving bank amount. what is the total interest recive at the end of the period

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As SI =P*R*T/100So,85000*30months*7/100*12therefore , as I solve ₹14875 will be our answer(if there are months we multiply 100 by 12)

61581.

Q. 12. Shri Ram deposited Rs. 20,000 for2years in fixed deposite account. If the rate ofinterest is 6% per year and interest is compounded half yearly, then how much wil heuch will hereceive the amount after the fixed date?

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Compount interest = 20000(1+6/100)^2*2

= 2000(106/100)⁴

= 2000*1.26247696

= 2,524.95392

Amount = 22525.95

61582.

cNGLES. In Fig. 6.20, DE |l 00 and DF II OR. Show thatEFIQR.

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∆PQR s ED || QO

.°. PD/DO = PE/EQ ( from formula )-------(1)

∆POR s DF || OR

.°. PD/DO = PF/FR ( from formula )........(2)

from (1) and (2) we get

PE/EQ = PF/FR

.°. EF || QR

61583.

\left. \begin array l \frac ( 3 \cdot 473 %2B 598 ) ^ 2 %2B ( 3 \cdot 473 - .598 ) ^ 2 3.473 \times 3 \cdot 473 %2B .598 \times .598 = ? \\ ( a ) 4.071 \end array \right.

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61584.

\left. \begin array r 323 \\ %2B 473 \end array \right.

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796 is answer so easy question

61585.

\left. \begin array r 323 \\ %2B 473 \\ \hline \end array \right.

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796 because if we +323 and 473 so the answer coming this 796

61586.

6. In the given figure, the chord AB othe larger of the two concentric circleswith centre O, touches the smallercircle at C. Prove that AC CB.

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How to say that oc is a tangent???

61587.

Type I. Problems based on representation of integers on number line :1. Following number line shows the temperature in degree celsius (°C) at different places on a particular day.Lahulspiti Srinagar ShimlaOotyBangalore-105010 15 20 25(1) Observe this number line and write the temperature of the places marked on it(ii) What is the temperature difference between the hottest and the coldest places among the above ?(iii) What is the temperature difference between Lahulspiti and Srinagar?(iv) Can we say temperature of Srinagar and Shimla taken together is less than the temperature at Shimla ? Is it also lesstemperature at Srinagar?

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61588.

7.1. Foilow ing number line shows the temperature in degree celsius (C) at different placeon a particular day.Lahelspitis Srinagars ShimlaOotyBengaluru-5010152025-10Observe this number line and write the temperature of the places marked onitWhat is the temperature difference between the hottest and the coldest placesamong the above?What is the temperature difference between Lahulspiti and Srinagar?(a)(b)(c)(d) Can we say temperature of Srinagar and Shimla taken together is less than thetemperature at Shimla? Is it also less than the temperature at Srinagar?

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whaaa

61589.

wing is the list of temperatures of five places in India on a particular day of theyearPlaceSiachinShimlaTemperature10°C below 0°C2°C below O°Cedabad 30°C above 0°CDelhiSrinagar(a) Write the temperatures of these places in the form of integers in the blank column.(b) Following is the number line representing the temperature in degree Celsius.Plot the name of the city against its temperature.20°C above 0°C n5°C below 0°Cny-25 20-15 10 5 0 5 10 15 20 25 30 35 40(c) Which is the coolest place?(d) Write the names of the places where temperatures are above 10°C.

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61590.

g कारण3. In the figure given below; AB | DF and AC || DF, prove that ZBAC =o SRS के. i

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Given :-

AB||DE and AC||DF

so if lines are parallelthen

angle BAC = angle EDF

61591.

amabhi deposite 7500 in a finance company which pays 15% per annum. Find the amount Surais expected to get after 5 4 years.bhi

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Principal=7500Rs.Rate=15%.Time=23/4years.

SI= (P*R*T)/100.

= (7500*15*23)/(100*4).

= 2587500/400.

=6468.75Rs

Amount= SI+Principal.

=6468.75+7500.

=13968.75Rs

thankyou

61592.

1. दर्शाइए कि /5 एक STREA HET (irrational number) =i 2 b

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To prove that√5 is irrational numberLet us assume that√5 is rationalThen√5 =a/b(a and b are co primes, with only 1 common factor and b≠0)⇒√5 = (cross multiply)⇒ a =√5b⇒ a² = 5b² ------->α⇒ 5/a²(by theorem if p divides q then p can also divide q²)⇒ 5/a ----> 1⇒ a = 5c(squaring on both sides)⇒ a² = 25c² ---->βFrom equationsα andβ⇒ 5b² = 25c²⇒ b² = 5c²⇒ 5/b²(again by theorem)⇒ 5/b-------> 2

we know that a and b are co-primes having only 1 common factor but from 1 and 2 we can that it is wrong.This contradiction arises because we assumed that√5 is a rational number∴ our assumption is wrong∴√5 is irrational number

61593.

In the figure, ABCD is a parallelogram in which E is midpoint of AD. DF II EB, meeting AB produced in F and BC at L. Prove that DF=2DL.

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Given: ABCD is a parallelogram. E is the midpoint of AD and DL is parallel to EB. meets AB produced at F.

TPT: B is the midpoint of AF and EB = LF

proof:

in triangle ADF ,

E is the midpoint of AD and EBDF

therefore by the converse of mid point thm.

B is the mid point of AF.

in triangle ADF,

E and B are the mid points AD and AF respectively

by the mid point thm EB = 1/2 DF.........(1)

since EB is parallel to DL and BL is parallel to ED.

EBLD is a parallelogram .

EB =DL......(2) [opposite sides of a parallelogram are equal]

DL = 1/2 DF i.e. L is the midpoint of DF.

61594.

3. AABC is an isosceles triangle in which ABAC. D, E and F are the mid-points of thesides BC, AC and AB, respectively. Prove that DE DF

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61595.

a4cb5c6d t axbxcxd IT HET7

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I think the answer is 840

A*B*C*D KA MAAN HE 1

a into b into C into d ka mann Hai Ek

61596.

ली AR R b Ab qh S4BT R R5 Ovd el

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x^2 - (a + b)x + ab = 0x^2 - ax - bx + ab = 0x(x - a) - b(x - a) = 0(x - a)(x - b) = 0x = a, b

Roots of given quadratic equation is a and b

61597.

“या 2 : 0२रा cout 2 425ij चार) का):(0 Gk जय e

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it is 195 or 595

61598.

If $R,$ is a relation in set $N$ given by $R=\{(a, b) : a=b-3, b&gt;5\},$ then does elements $(5,7) \in R ?$

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61599.

S. Check whether the relation R in R defined by R [(a, b) :a S b] is reflexive,symmetric or transitive.R is bnanshuenela tioo

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61600.

DE, ABDE, BCEF11. In Δ ABC and Δ DEF, ABand BC I EF. Vertices A, B and C are joined tovertices D, E and F respectively (see Fig. 8.22)Show thatquadrilateral ABED is a parallelogram) quadrilateral BEFC is a parallelogram(iii) ADI CF and AD-CF(iv) quadrilateral ACFD is a parallelogram(v) AC-DF(vi) Δ ABC0E.Fig. 8.22Δ DEF

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