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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 64551. |
A fruit seller had some apples. He sells 40% of them and still has 420 apples. How many applhad he in all |
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| 64552. |
A bag contains 2 white and 3 red balls. 2 ballsare selected at random. Find the probability ofgetting 1 white and 1 red ball. |
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| 64553. |
Express 75000 gram in kilograms |
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Answer» 1000g=1kg1g=1/1000kg75000g=75000/1000=75kg |
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| 64554. |
-LXS- Q 3 - 5kg01- TINGS-OX..."}। -SKR |
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Answer» 3×7=21 itz easy |
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| 64555. |
गए कि झट चिट = jfl\«’&oor-&& o oEhyx b one i~| polynommiad. \ ot olHe sclfo लक : था « Them _ दर िाट ) “—_—J:—_{ 4_,____#_\/& ot |
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Answer» Please like the solution 👍 ✔️ |
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| 64556. |
Provg the following identities (1-16)ectr-sec2x-tan 4.x + tan 2 x.sino+ coso Ď1-3 sin 2 Ď cos |
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| 64557. |
(b) 345 kg from 604 kg 345 g(d) 340 ml from 1 litre |
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| 64558. |
5]COS A Cos BCOS B.CoScCOS C COS A |
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| 64559. |
Value of cos 0°. Cos 30° cos 45º. cos 60° . cos 90° is |
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Answer» since cos90°= 0 hence on solving the answer is 0 is the correct answer of the given question 0 will be the final answer because cos 90 is equal to zero cos 0=1cos 30=√3÷2cos 45=1÷√2cos 60=1÷2cos 90=0 |
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| 64560. |
in any triangle prove that a^ ( cos^ b - cos^ c) + b^ ( cos^ c - cos^ a) + c^ ( cos^ a - cos^ b ) = o |
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Answer» what is your question |
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| 64561. |
If 152x-378y = -74 and-378 x + 152 y =-604, find x+y: x-y |
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| 64562. |
6. By how much is the difference of 604 and 406.65 less than their sum?!are on Bc 50 to the |
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Answer» (604+406.65)-(604-406.65)=813.30 is the right answer 813.30 is correct answer 813.30 is the correct answer 813.30 is the correct answer 813.30 is correct Ans |
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| 64563. |
Find out the value of (a , , where n is any pos)me meie, |
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Answer» Please post a clear image with proper lighting. We cannot provide a solution without a clear image of question. |
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| 64564. |
xiomsIN EACH MATHS-AN0SLLEIUE THO EXAMPLES Fr APPLICATIDNG OF POS TULATE |
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Answer» 1)Maths - euclid axioms :the whole is greater than the partfor.eg indian is a part of asia,but the whole asia is greater in size than india example for application of axioms in science |
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| 64565. |
() 36 kg 285g -12kg 578g |
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Answer» by basic subtraction 36.285 - 12.578 = 23.707 kg |
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| 64566. |
x+yx-y15he following pro |
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| 64567. |
2. Alice has 6 bags of flour. Each bag contains 2 kilograms 250 arongramflour. What is the total weight of flour that Alice has? |
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| 64568. |
eleven bags of wheat flour. Each marked 5kg actually contained the following weights of flour in kg?4.97,5.05,5.08,5.03,5.00,5.06,5.08,4.98,5.04 5.07,5.00find the probability that any of these bags chosen at random contains more than 5 kg of flour? |
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| 64569. |
= LHS = (sino - cose) (1 - 2 sino cos? e) = RHSEXAMPLE 27 Prove the following identities:(1) (1 + tan A tan B) + (tan A-tan B)2 = sec? A sec B(ii) (tan A + cosec B) 2 - (cot B - sec A) = 2 tan A cot B(cosec A + sec B) |
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| 64570. |
SE20721JUIot ofFind the least number which must be subtracted from 250g to make it perfect square. |
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Answer» If we remove25 gmso it will be 225 gm that is a square of 15 gmthanks |
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| 64571. |
न कक | ला b2 BLafoy ARA o B |
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| 64572. |
If /3 sine- cose, find the value of S\frac{\sin \theta \cdot \tan \theta \cdot(1+\cot \theta)}{\sin \theta+\cos \theta} |
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Answer» 😊☺ Thanks Thanks |
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| 64573. |
Calculate the molality and mole fraction of a solution cntain 3 g of urea in 250g of H20 |
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| 64574. |
5. For any angle 0. state the value of sino +cos'.(ICSE) |
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| 64575. |
Dhind b2 22-८८ of ar g “लक - il ८ ८८22 2,7 G(-5.27 ५८०9४ |
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| 64576. |
4find value ofcos Go x sino atanus x cotuto |
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Answer» cos60= 1/2 sin 30 = 1/2tan 45= 1 = cot 45after putting values= 1/2*1/2/1*1= 1/4 answer cos60"sin30/tan45*cot45= 1/2*1/2/1*1=1/4 1/2*1/2/1*1=1/4 is right answer 1/2×1/2=1 is answer of above question |
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| 64577. |
7. Solye the following pair of linear equations(i)px+qy = p-q(ii) ar + by=cbr + ay = 1 +c( + b) y = d-2ab-Fiv) (a-b)x+ (aqx-py = p + q(ii) a b0(a+ b)(r +y)-a+bax+by = a2 + b2.152-378y-74378x+152y =-604(v) |
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Answer» 152×-378y=-74,-378x+152y=-604 |
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| 64578. |
ress 52 in the form f,whereesent 3 on the number line.81ate |
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Answer» 2nd quetion |
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| 64579. |
c id) 0 are equal, prove that b da CIf the roots of the equation: (a2 + b2)X2-2(ac + bd)x + (c4 aă= 0 ar |
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| 64580. |
TyPos a brime number than Brooke that Up is wirational- |
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| 64581. |
18yIf α, β, γ are the zeros of the polynomial f(x)-ar' + bx2 + cx + d, then α2 + β2 + γ2- acb2 -2ac(b)(c)h62(d) |
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| 64582. |
if (-5/7)³ (-5/7)6=(-5/7)2x-1 then x is equl to |
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Answer» (-5/7)^3(-5/7)^6 = (-5/7)^2x-1 ; 3 + 6 = 2x -1; 9+1= 2x ; x = 10/2=5 x=102=5the answer is correct |
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| 64583. |
d the value ofSino and coto |
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| 64584. |
a flour packet weighs 12kg 250g. how much flour is there in15such packet |
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Answer» 1kg=1000gtherefore, 12kg250g =12250gand 15 packets weight is 12250g*15=183750g and 183750g = 183kg750g this is right answer |
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| 64585. |
Prove that secesinecotsinoCose = coto |
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Answer» secx/ sinx - sinx/ cosx= 1/ cosxsinx/sinx - sinx/ cosx=/1-sinx^2/ sinxcosx= cosx^2/ sinxcosx=cosx( cosx)/ sinxcosx= cotx secx/ sinx - sinx/ cosx=1/ cosxsinx- sinx/ cosx=1- sinx^2/sinxcosx= cosx^2/sinxcosx= cosx( cosx)/sinxcosx=cosx/ sinx= cotx |
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| 64586. |
draw a parallel line to a line at 5 cm |
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Answer» I don't understand your question. Please elaborate |
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| 64587. |
UNIT 6.1PRACTICAL GEOMETRYWORKQ,1. From theglven point, draw a line paralleltothe eiven lime0.4Q.2. Determine in each figure whether the lines are parallel or not.Inot, take a point on the second line and draw a parallel line. |
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Answer» make a line intersecting the given line such that angle A = angle B , therefore corresponding angle must equal giving us a parallel line |
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| 64588. |
(vii) What is the value of coto-sin- o |
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Answer» 1/sin²A = cosec²A 1 + cot²A = cosec²A Now,cot²A - (1/sin²A) = cot²A - coesec²A = cot²A - 1 - cot²A = -1 |
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| 64589. |
27. If tano + coto = 2, then the value of O is |
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| 64590. |
a + i b = \frac { ( x + i ) ^ { 2 } } { 2 x ^ { 2 } + 1 } , \text { prove that } a ^ { 2 } + b ^ { 2 } = \frac { ( x ^ { 2 } + 1 ) ^ { 2 } } { ( 2 x ^ { 2 } + 1 ) ^ { 2 } } |
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| 64591. |
a x + b y = 1 ; b x + a y = \frac { ( a + b ) ^ { 2 } } { a ^ { 2 } + b ^ { 2 } } - 1 |
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| 64592. |
Page No.Ifb=Cos Ot sino = J2J2and(sino tcoso) thensino.cosoequal toB) 2bis673D) 4 |
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Answer» Let theta = xcos x + sin x = root(2)Squaring both sides (cosx + sinx)^2 = 2cos^2 x + sin^2 x + 2sinx.cosx = 21 + 2sinx.cosx = 22sinx.cosx = 2 - 1sinx.cosx = 1/2............(2) Therefore, Value of b = root(2)*[cosx + sinx]/ sinx.cosx Using eq(1) & eq(2) = root(2)*root(2)/ (1/2) = 2*2 = 4 (D) is correct option |
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| 64593. |
In Fig. 6.17, POQis a line. Ray OR is perpendicularto line PQ. OS is another ray lying between raysOP and OR. Prove thatZ ROS (Q0S - Z POS). |
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| 64594. |
In Fig. 6.15, PQR<POS = < PRT.Z PRQ, then prove thatFig. 6.15 |
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Answer» ∠PQR = ∠PRQTo prove:∠PQS = ∠PRTProof:∠PQR +∠PQS =180° (by Linear Pair axiom)∠PQS =180°– ∠PQR — (i)∠PRQ +∠PRT = 180° (by Linear Pair axiom)∠PRT = 180° – ∠PRQ∠PRQ=180°– ∠PQR — (ii)[∠PQR = ∠PRQ]From (i) and (ii)∠PQS = ∠PRT = 180°– ∠PQR∠PQS = ∠PRTHence, ∠PQS = ∠PRT |
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| 64595. |
Find the value of x and y suc that(2x+y,5)=(7,3x+2y |
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Answer» Find the value of x and y such that(2x+y)=(7,3x+2y) 2x+y = 7 ---(1)3x+2y = 5 ---(2) 2*(1) - (2) ==> 4x+2y - (3x-2y) = 2*7 - 5 ==> x=9,y= -11 |
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| 64596. |
-1) is a factor aj me piPRI.In the given fig,POR = Z PRO, then prove that POS - |
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Answer» Given- ln triangle PQR ,TO PROVE- ANGLE PQS=ANGLE PRT.PROFF- angle SQP+ANGLE IS PQR=180'---'-----(1)LINEAR PAIRSANGLE PRT+ANGLE PRQ=180'--'----(2)LINEAR PAIRS FROM EQ.(1)&(2)ANGLE SQP+ANGLE PQR=ANGLE PRT+ANGLE PRQANGLE SQP=ANGLE PRT+ANGLE PRQ__ANGLE PQRANGLE SQP=ANGLE PRT+ ANGLE PRQ__ANGLE PRQ FROM PRQ ,PRQ IS CANCELLED. SO, IT IS PROVED THAT. ANGLE SQP=ANGLE PRT I HOPE IT CAN HELP YOU |
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| 64597. |
4. In figure, O is the centre of a circle, PQ is a chord and the tangent PR aInthe gmakes an angles of 50° with PQ. Find ZPOQ.5082Mathematics-X athem |
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| 64598. |
Suc packet?30. A rope of length 10 m has been divided into 8 pieces of the same length. Whieach piece?pieces of the same length. What is the length of |
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Answer» 12.5mm is the lenght of each piece 125mm per piece lenght |
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| 64599. |
2 If the straight line through the point P (3, 4) makes an angle T/6 with the x-axis and meetsthe line 12x +5y +10 0 at Q, find the length PQ |
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| 64600. |
9. ABCo is a trapezium in which AB Il DC and itsoals intersect each other at the point O. Show·C-Qo COO DOthatFig. 6.21t the noint O suc |
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