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Area of trapezium=(1/2)(Sum of parallel sides)*altitude

5.25=(1/2)(6)*altitude

5.25=(3)*altitude

altitude=5.25/3=1.75cm

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itna gussa wala qustion kyon upload krte jiii

12m 25cm - 65cm=12.25-0.65=11.6=11m 60cm

Let height of room = xThen length of room = 3xbreadth of room = (3/2)x

Area of four walls= 2(length*height + breadth*height)= 2(3x*x + (3/2)x*x)= 6x^2 + 3x^2= 9x^2

Cost of white washing = 2169x^2 * 1.5 = 216x^2 = 240/15 = 16x = 4 m

Dimensions of room:Length = 3x = 3*4 = 12 mBreadth = (3/2)x = (3/2)*4 = 6 mHeight = x = 4 m

We havea2+ 8a + 16 = (a)2+ 2(a)(4) + (4)2 = (a+4)2= (a + 4)(a + 4)∴a2+ 8a + 16 = (a + 4)2= (a + 4)(a + 4)

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Given equation : 9x² + 3kx + 4 = 0For real distinct roots discrimanat will be greater than 0So, (3k)² - 4 × 4 × 9 > 09k² > 16×9k² > 16k > √16 = + or - 4 For -4 it does not hold so, k > 4

Given quadratic equation is = 9x² + 3kx + 4 = 0

On comparing with standard form of quadratic equation i.e ax² + bx + c =0,a≠0Here, a = 9 , b= 3k, c= 4

D(discriminant)= b²-4ac

= (3k)² - 4× 9 ×4= 9k² - 144

Since, roots of given equation are distinct. D > 0.

9k² - 144 > 09(k² - 16) >0(k² - 16) >0 (9≠0)k² -4²>0(k-4) (k+4) >0[ a² - b² = (a-b)(a+b)]

k > 4 and k< -4

Hence, the value of k is k > 4 and k< -4.

If 1 and - 1 are roots of equation x^2 + 4x - 5 = 0

Sum of roots = - b/a = - 4/1 = - 4Verify = - 1 + 1 = 0

Therefore,-1 and 1 are not roots of given equation

A = 1/2 × 6.5× h =266.5×h=52h=52/6.5h= 8cm

Area= 1/2* base * altitude0.5* 100*2/10= base= 10 cm

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a*a+4a+4a+16=(a+4)(a+4)

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3y^2+(6+4a)y+8a; a=3; b=6+4a, c=8a, y=-b+-Vb^2-4ac/2a; y=-(6+4a)+-V(6+4a)^2-4(3)(8a)/2(3)= -6-4a+V36+48+a^2-96a/6= -6-4a+-V36+48a+a^2-96/6= y=-6-4a+-V6^2-48a+36/6; y=-6+4a+22a-36; y=-6+4a-22a-36=126, y=-2 (or)-4a^3

Since a Rhombus is also a parallelogramThus,Area of rhombus = base *height320 = 5 * altitudeAltitude = 64 m.

find the altitude of a rhombus whose area is 320m and side is 5m

All sides of rhombus are sameso perimeter = 4 × side140 .=4 × side140/4=side35= side

area = Base ×height420 = 35 × h420/35 = h12 cm = height

Area = height × base168 = height × 21height = 168/21height = 8 dm

1dm = 10 cm8 dm = 8 × 10= 80 cm

A square field side 65mSo, perimeter of square=4×65=>260m

Perimeter of square=Perimeter of rectangle260=2(l+b)130=l+b130=75+b130-75=b55m=b

Area of square=S×S=>65×65=4225m²Area of rectangle=l×b=>75×55=4125m²

Square has larger area and by =4225-4125=>100m²

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so what we have to do

8a*a*a + b*b*b + 12a*ab + 6ab*b = 2a*2a*2a + b*b*b + 3*2a*2a*b + 3*2a*b*b

(x+y)(x+y)(x+y) = x*x*x + y*y*y + 3x*xy + 3xy*y comparing with above formula we can write like following = (2a+b)(2a+b)(2a+b)

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8a*a*a + b*b*b + 12a*ab + 6ab*b = (2a)(2a)(2a) + (b)(b)(b) + 3(2a)(2a)(b) + 3(2a)(b)(b)

compare it with following formula (x+y)(x+y)(x+y) = x*x*x + y*y*y + 3x*xy + 3xy*y x = 2a and y = b

= (2a+b)(2a+b)(2a+b)

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a^2+6ab+ab^2=a^2+3ab+3ab+ab^2=a(a+3b)+ab(3+b)

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Surface area= 2(80*50+50*25+80*25)=2(4000+750+2000)= 6750*2=13500cm^2number of paint box= 13500/100= 135 please share the feedback and the like 👍 ✔️

option 2) is the correct answer