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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 64901. |
3+5+7+.... + n terms5+ 8+ 11 +..+10 termsIf= 7, then the value of n is |
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| 64902. |
(b) 0.4420. The decimal equivalent to 30.4 is(by 30.4(a) 30.04 |
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Answer» 30.4= 304/10= 30.40 please like the solution 👍 ✔️ |
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| 64903. |
Find three equivalent ratio of 9\12 |
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Answer» 9/12=15/20=18/24 |
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| 64904. |
\left( \cos ^ { 2 } 28 ^ { \circ } - \sin ^ { 2 } 62 ^ { \circ } \right) |
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Answer» cos² 28° - sin²(62°)cos²(90° - 62°) - sin²(62°)sin²(62°) - sin²(62°)0 |
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| 64905. |
2+9×4÷3_6= |
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Answer» 2+9×4÷3-6=. 104 how? 104 answer hoga . |
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| 64906. |
6. 59 6.33 &%, PQ जाक RS माद्वान मूथनकAT TGS I (TR 9 खाथऊिज वृद्धि <<=३0 मांटनानव 3 विन्दू शविंदक खाक थंऊिकलिऊ oz0 शदथटव टन 1२५ मादशागव ( विन्मूऊ शविटडू। थेवश्धचि खांटकी (71) निटगएव विधगीजकमऊ धंडिकनिऊव्इदडष। थमाग कवां (य 28 || (01A |
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Answer» Apologies but we are currently providing answers to questions in English only. We are going to include other languages very soon. So keep checking this app in the coming months. |
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| 64907. |
7. In the given figure, QT-RS, QT L PR and RSderHOTSPQ. Prove that.SQ = TR |
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Answer» In triangles QSR and RTQ, angle QSR = angle RTQ = 90°QR = RQ = common sideSR = TQ ( given) So, the trianlges are congruent by RHS rule.So, QS = RT ( c.p.c.t.) |
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| 64908. |
6. The radii of the circular ends of a solid frustum of a cone are 33 cm and27 cm, and its slant height is 10 cm. Find its capacity and total surface[CBSE 2005)area. [Take π = 227 .] |
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| 64909. |
. If the ratio of the 11th term of an AP to its 18w term is z:3,find the ratio of the sum of thefirst five terms to the sum of its first 10 terms. |
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| 64910. |
An AP consists of 50 terms of which 3d term is 12 and the last term is 106. Find the 29term. |
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Answer» Let a , d are first term and common difference of an A.P nth term = Last term = a + ( n - 1 )d an = a + ( n - 1 )d Now , It is given that , Third term = 12 a + 2d = 12 ------( 1 ) Last term = 106 a + 49d = 106 ---( 2 ) Subtract ( 1 ) from ( 2 ) , we get 47d = 94 d = 2 Substitute d value in equation ( 1 ) , We get a + 2 × 2 = 12 a = 12 - 4 a = 8 29th term = a + 28d a29 = 8 + 28 × 2 = 8 + 56 = 64 |
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| 64911. |
126Theorem 6.2: If a line divides any two sides of atriangle in the same ratio, then the line is parallelto the third side. |
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| 64912. |
distinct points, then the other two sides are divided in the same ratioS. If a line divides any two sides of a triangle in the same ratio, then the line is paraldss21 Inthird side |
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Answer» just a trual |
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| 64913. |
luvethalpTS.Q.8 n terms lie between 7 and 49 in an AP. Ifratio of the fourth termthe (n - 1)term is 5:4, then find the value ofn. |
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Answer» The process and the calculations are correct...but i dont know why the value of n is not integer here video video please given and term lie between 7 and 49 in an ap if ratio of the fourth term and the and -1 term is 5 ratio 4 then find the value of an please given the video also and return is also and then it is given the answer and is equal to 5 and is equal to 5 |
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| 64914. |
which of the following ratios is not equivalent to the other three |
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Answer» Where are the options? |
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| 64915. |
write 0.50 in three equivalent decimal |
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Answer» 0.50=50/100=50*2/100*2=100/200=50*3/100*3=150/300 |
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| 64916. |
2. Write three rational numbers equivalent to: (a) and (b) |
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Answer» -5/3, -4/3, -2/3 three rational ni equivalent to -1/3 = -2/6, -3/9,-4/122) -5/3= -10/6, -20/12, -45/27 |
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| 64917. |
6. Give four equivalent ratios of 12: 15, |
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Answer» four equivalent ratios12*2/15*2=24/3012*3/15*3=36/4512*4/15*4=48/6012*5/15*5=60/75 |
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| 64918. |
and ABORRF & RR-410 |
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| 64919. |
6. Give four equivalent ratios of 12:15. |
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| 64920. |
If \left[ \begin{array}{rr}{x-3} & {2 y-8} \\ {z+2} & {6}\end{array}\right]=\left[ \begin{array}{rr}{5} & {2} \\ {-2} & {a-4}\end{array}\right], then find the values of x y,z and a. |
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Answer» comparing both sides we getx - 3 = 5x = 82y - 8 = 22y = 10y = 5z + 2 = -2z = -4a - 4 = 6a = 10 |
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| 64921. |
ow that rr- |
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| 64922. |
9Given A=\left[ \begin{array}{rr}{2} & {-6} \\ {2} & {0}\end{array}\right], B=\left[ \begin{array}{rr}{-3} & {2} \\ {4} & {0}\end{array}\right] \text { and } C=\left[ \begin{array}{ll}{0} & {2}\end{array}\right]Find the matrix X such that A + 2x = 2B + C |
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| 64923. |
PaRRS TRas PaRR QT |
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Answer» The solution is correct. That is the proof |
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| 64924. |
integer question(2)+(+9)-(-4) |
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Answer» (2)+(+9)-(-4)=2+9+4=15 (Two negative signs when multiplied, form a positive number) |
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| 64925. |
Find the i1'h term from the last term towards the firstterm of the AP 10, 7, 4,. (-62) |
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| 64926. |
h termof an AP is zero. Prove that its 25th term is triple its 11th27. The 4th teCBSE 2005 |
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| 64927. |
If m times the mth term of an A.P is equal to n times its nth term, find the (m+n)h termof the A.P |
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| 64928. |
The statement "If a line divides two sides of a triangle in the same ratio, then the lineis parallel to the third side" is |
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Answer» Ans :- If a line dividesthetwo sides of a triangle in the same ratio, then thatlinemust be parallel to the third side(of the triangle). which theorem |
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| 64929. |
The sum of first Z terms of an A.lP. is 63 and the sum of is hterm is 161Find the 28th term of this A.P.riz |
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| 64930. |
n terms lie between 7 and 49 in an AP. Ifratio of the fourth term and the (n-1)hterm is 5: 4, then find the value ofn. |
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| 64931. |
12. The fourth term of an A. P. is 11th term of an A.P. is Il. The sum of the fifth and seventh terms of the A.P. is s4. h. Theits common difference. |
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Answer» common difference is 3 |
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| 64932. |
5 In an A.P, if pth term isand h term is , prove that the sum of first pqterms is(pq +1), where p# q.mher of terms of the A.P. 25, 22, 19,is 116. Find the |
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| 64933. |
8. Write three equivalent ratios of the ratio 9:15 |
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Answer» 9/15 1) 9÷3/15÷3=3/52)3*2/5*2=6/103)3*4/5*4=12/20 Write 13:39 in ratio |
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| 64934. |
45Write an equivalent fraction ofwith denominator 18 |
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Answer» 35/42= the answer for this question is 15 |
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| 64935. |
7) Write the following information in mathematical form.The length of a rectangle is twice its beradth and its perimeter is 52. |
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Answer» photo can not clear |
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| 64936. |
Round off nearestten814 |
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Answer» 810 is the correct answer 810 is the correct answer 810 is a correct answer.... in given question is The right answer is 810. 810 is correct answer 810 is the right answer 810 is right answer for this question 810 is the right answer. 810 is the right answer 810 is the correct answer 810 is the right answer |
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| 64937. |
ittg RR defined by tx)x*1 and gx)x then find (og) (3) |
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| 64938. |
Question 2Round 16281482 to the nearest ten thousand |
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Answer» 630000 is the right answer SoOption-B630,000is the answer Nearest ten thousand for 628,482 is Option B630,000 |
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| 64939. |
0 (2)६ (q) 9 (४)20[४८/pg6x 28.१ Elh 1# 9x gx pz6xpg८ |
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Answer» 2^3a * 3^2a * 5^a * 6^a/8^a * 9^3a/2 * 10^a = 2^3a * 3^2a * 5^a * (2*3)^a/ 2^3a * (3)^3a * (2*5)^a = 2^[3a + a - 3a - a] * 3^[2a + a - 3a] * 5^[a - a] = 2^0 * 3^0 * 5^0 = 1*1*1 = 1 1 is correct answer |
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| 64940. |
Exercise 1.41. Round off the nearest ten :(i) 341(ii) 3556(iii)55Ń (iv) 2467 |
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Answer» Rounded off to nearest 10 (1) 341 ----> 340(2) 3556 ----> 3560(3) 55 ----> 60(4) 2467 ----> 2470 |
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| 64941. |
Estimate the sum (64 + 79) to the nearest ten. |
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Answer» the sum will be 64+79=143to the nearest ten will be 140as the units place is less than 5 hence it can be rounded off to zero |
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| 64942. |
”दरघुदमसथिकटमक — T साम उेनेपपरुझागिकत तथा शेवर्फ्त शिर= At NP o) = oel-BorteSx o3 =gx=ats |
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| 64943. |
If 7 times the 7th term of an AP is equal to 11 times its 11 hterm, then find its 18h term. |
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Answer» nth term of an AP = a + (n-1)d where a is a first term and d is a common difference 7*7th term = 11*11th term 7(a+6d) = 11(a+10d) 7a + 42d = 11a + 110d 4a = -68d a = -17d a + 17d = 0 which is 18th term so 18th term is 0. If you find this answer helpful then like it. |
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| 64944. |
ORIf 7 times the 7th term of an A.P is equal to 11 times its II'h term, then find its 18h term. |
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| 64945. |
ORX If 7 times the 7th term of an A.P. is equal to 11 times its 11th term, then find its 18th term. |
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Answer» Like if you find it useful |
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| 64946. |
If 7 times the 7th term of an A.P is equal to the 11 times its 11th term, show that its 18th termis zero.OR |
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Answer» 7×t7 = 11×t11 tn=a+(n-1)dt7=a+6d t11=a+10d 7(a+6d)= 11(a+10d) 7a+42d=11a+110d 4a+68d=0 a+17d=0 a=-17d t18=a+17d =-17d+17d =0 |
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| 64947. |
\lim _{x \rightarrow 0} \frac{x^{2}}{e^{x}+e^{-x}-2} |
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| 64948. |
Q 9 Write three equivalent fraction of 2 |
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Answer» Three Equivalent Fractions for 13/5 are: 26/10, 39/15, 52/20 |
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| 64949. |
Write the equivalent fraction of with numerator 48. |
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| 64950. |
5. List all the numbers which when rounded off to the nearest ten become 240 |
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Answer» 244,243 ,242,241is you answer 244243242241 is the answer of the following |
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