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Then it is to be known as addition

let, First number add.xsecond number add. y= x and y adding =x+y is the best answer

Then it is to be known as addition

let numbers be x and y according to the condition the equation becomes x+y

is the best answer.

x+y is the required equation.

where is the answer

Six rational numbers are

3.1, 3.2, 3.3, 3.4, 3.5, 3.6

18 and 27 is correct as me

broken= 500 of 3/25 = 20×3= 60balance= 500-60= 440sold = 440 ×4/5 = 88×4 = 352balance= 440-352 = 88

Total eggs =500No of broken eggs = (3/25)×500 = 60eggs left =500-60=440No of eggs sold = (4/5)×440 =352 No of eggs left = 440-352 = 88

initial eggs = 500broken = (3/25) × 500 = 120remaining unbroken = 380

sold from unbroken= (4/5) × 380 = 304

left at the end unbroken and unsold = 380 - 304 = 76

total initial eggs = 500broken eggs = (3/25) × 500 = 60 eggs

remaining unbroken eggs = 500 - 60 = 440 eggs

sold eggs = 4/5 th of remaining = (4/5) × 440 = 4 × 88 = 352 eggs

now remaining eggs = 440 - 352 = 88 eggs

Total eggs=500no of broken eggs =3/5*500=60eggs left=500-60=440no of eggs sold =4/5*440=352no of eggs left =440-352=88

(5/7)x - (7/11)x = 6 (55x - 49x)/77 = 6 6x/77 = 6 x = 77

(5/7)x-(7/11)x=6 (55x-49x)/77=6 6x/77=6 6x/6=77, x=77 please like my answer

option (3)77 is the right answer

x=77 is correct answer

answer number (3). 77 is right

77 is the correct answer

77 is the correct answer me

(3) 77 is the right answer

c is right. answer

77 answer your question

77 is correct answer

प्रश्न के अनुसार

पाइप का व्यास = 7 सेमी

इस प्रकार

पाइप का त्रिज्या = आर = 7/2 सेमी

पाइप की लंबाई L होने दें

पाइप के माध्यम से पानी के प्रवाह की दर = प्रति सेकंड 72 सेमी

इस प्रकार

1 सेकंड में पानी का बहाव = 72 सेमी

इस प्रकार

60 सेकंड में = 72 * 60

1 घंटा में = 72 * 60 * 60

तो स्पष्ट रूप से

बहता पानी की मात्रा = πr^2 *h

= 22/7 * 49/4 * 72 * 60 * 60

= 9979.2 liter

what is this

6 digit number is 456361on reversing, 163654

Of these 2 6- Digit number456361 is greater

Solution

Sample space = (26,24,42,46,62,64)Total possible cases = 6Total favorable cases = 2then probability (greater then 46) = 2/6 = 1/3

thank you

but where is 1/6 ?

what is the value of x

We know that a number is divisible by 6 if it is:

Even

Divisible by 3 (for which the sum of digits should be divisible by 3)

Both of these facts can be checked by having a look at the prime factorization of 6, i.e., 2×3.

So we have to make numbers ensuring the above mentioned condition.

For a number to be even, the only simple condition is that the units place should be even. So we can have either 0, 2 or 4 at units place. That means the units place can have only 3 possible numbers.

Next up, we can have a case by case study of the remaining three numbers to see in what ways can we make the number a factor of 3.

If the units place is 0, then the required number should be in the form 3n or 3n + 0. Which means we have to pick numbers up from our list so that we end up getting the sum of those numbers as 3n. (n is any arbitrary non negative integer)

If it is 2, then we require the sum of the remaining numbers to be 3n-2 or 3k+1, for the sum to be divisible by 3.

If it is 4, then we require the sum of the remaining numbers to be 3n-4 or 3k+2 for the same.

But wait, haven't we covered all the possible forms in which a number could be? Any integer can be expressed in the form 3n, 3n+1 or 3n+2, all of which are obtained in the three cases above.

This means we can have any configuration of numbers and their sum would definitely land up in one of the three cases.

That means we can any of the 6 numbers in the thousands, hundreds and tens place.

Therefore, by the multiplication theorem, the total number of cases are: 6×6×6×3 = 648.

Find quatest 6 digit formed by using 2.05 with repetition

Please hit the like button if this helped you out

putting x=0 in log(x+1), we get log(0+1) = log 1 =0

751 , 157 , 517 , 715 , 175 , 571hope it helped.....thanks

mam (-251×21×-21) is divide by x to ye us side jakar multiply nahi hoga

(x-1/x)(x+1/x) (x²+1/x²)(x²-1/x²) ( x²+1/x²)(x⁴-1/x⁴)

1/logab[abc] +1/logbc[abc] +1/logca[abc]

= logab/log[abc] + logbc/log[abc] + logca/log[abc] = log(ab*bc*ca)/log[abc]= log(abc)²/log[abc]= 2.

10,000 makes a crore of the answer...

10,000 crore makes 1 crore ..........

10,000 makes 1 crore.........

10,000 makes 1 crore...........

10,000 make it 1 crore.........

10,000 make it 1 crore........

10,000 complete it to become 1 crore

10,000 makes a crore......

10,000 makes it 1 crore.....

·A crore is 10,000,000 so there are 10,000,000/100,000 = 100 x hundred thousands in a crore.

1 is the correct answer of the given question