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66851.

ind anoMaint pesitive prime such hat

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(a)^[6/3]*b^[-4/3] = a^x*b^[-2y]Base are same power will be equal

Therefore, x = 6/3 = 2 - 2y = - 4/3 y = 2/3

x = 2, y = 2/3

66852.

VOLLEWhat is the measure of the angle x in the figure bel-35259anmnh helo v indicates the number of girls ar

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As, shown in figure 35+x+25= 180 ( linear pair) x = 180-60x= 120

66853.

2si—39~tan? A — tan’ B =s S o LT e

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66854.

0) 2x2-7x +3 0

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66855.

Sr-43' + 8-07x +6y-9-0(i)

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66856.

Two Items A& B are sold at a profit of 10% & 15% respectively. If the amount of profit received is thesame, then the cost price of A & B may be

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66857.

4. Santosh purchased a watch at 20% discount on its marked price but sold it at the marked price. Findthe profit percent of Santosh on this transaction.

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Let P be the marked price,

then the cost to santosh was (0.8)P, which represents a 20% discount.

When he sold the watch, his profit was P - .8P = 0.2 P

The percent gain = (Profit/Cost)* 100 = (.2p/.8P)*100 = 25%

If the marked price is $100, he spends $80. He sells it for $100, so he makes $20 on his $80 investment, and $20 is 25% of $80, so this answer makes sense.

66858.

सच urs — |v um%v 395 Vi

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66859.

onesilodiscriminant (b) nature of roots and (c) root using binomial fof the quadratic equation 2r 2v2 x1 0.)

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please like my answer if you find it useful

66860.

6x-5y-16=07x-13y+10=0

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66861.

17. Find the remainder when the polynomial p ()-12y-13y-idedby 3y-2

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66862.

\begin{array} { l } { \text { Evaluate without using trigonometric tables: } } \\ { \frac { 3 \cos 55 ^ { \circ } } { 7 \sin 35 ^ { \circ } } - \frac { 4 \left( \cos 70 ^ { \circ } \csc 20 ^ { \circ } \right) } { 7 \left( \tan 5 ^ { \circ } \tan 25 ^ { \circ } \tan 45 ^ { \circ } \tan 65 ^ { \circ } \tan 85 ^ { \circ } \right) } } \end{array}

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66863.

Evaluate without using trigonometric tables:3 cos 55°7 sin 35°7 (tan5° tan 25° tan 45 tan65° tan859)4 (cos70° cosec 20°)

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66864.

\frac \operatorname cos 70 ^ \circ \operatorname sin 20 ^ \circ %2B \frac \operatorname cos 55 ^ \circ \cdot \operatorname cosec 35 ^ \circ \operatorname tan 5 ^ \circ \cdot \operatorname tan 25 ^ \circ \cdot \operatorname tan 65 ^ \circ \cdot \operatorname tan 85 ^ \circ = 2

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66865.

\frac \operatorname cos 70 ^ \circ \operatorname sin 20 ^ \circ %2B \frac \operatorname cos 55 ^ \circ \operatorname tan 5 ^ \circ \cdot \operatorname tan 25 ^ \circ \cdot \operatorname tan 65 ^ \circ \cdot \operatorname tan 85 ^ \circ = 2

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66866.

x 3) Expand the binomial

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your ans is correct . thank you so much

66867.

e the greatest number of 9 digits by the greatest nurnber of 3 digroduct of two numbers is 1 27 008.One of them is 882. Findhe product of the least number and the greatest number of thed with the digits 9, 3 and 5.the dividend when the divisor 241, quotient 135 and wbooks contain 1 395 and 2 232 pages respectively. The boochapter of the first book has 93 pages and that of the secondy more chapters are there in one book than the other?cklace has 3 strings of pearls. Each string has 100 pearls. Tcontaining 120 pearls. How many packets of pearls w22 such necklaces?

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please clarify the question

divide the greatest number of 9 digit by the greatest number of 3 digit

66868.

E PRODUC

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66869.

(vii) 13x + 1 ly = 70;1 1x + 13y74

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66870.

4(cos 70° cosec20”) _(tan 5° tan 25" tan 45" tan 65° tan 85°)- OR’

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66871.

Q: -What is National Income Accounting?

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National income accountingis a bookkeeping system that a government uses to measure the level of the country's economic activity in a given time period

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66872.

7 25203(¢} Evaluate: PSR Oko ‘tan5°.tan 25°.tan 45°. tan 65°.tan 85°

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66873.

tan 73193. sin 5째 tan 22째 sec 60째 tan 68째 sec 852

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66874.

An aeroplane flying horizontally 1 km abovethe ground is observed at an elevation of 60°.After 10 seconds the elevation is observed tobe 30° then the uniform speed per hour of theaeroplane is

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66875.

cos 70sin 20cos 55 cosec 35tan 5 tan 25 tan 45 tan 65 tan 85

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66876.

\operatorname { tan } 5 \operatorname { tan } 25 ^ { \circ } \operatorname { tan } 30 ^ { \circ } \operatorname { tan } 65 ^ { \circ } \operatorname { tan } 85 ^ { \circ } = \frac { 1 } { \sqrt { 3 } }

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Tan 5 = tan(90-85) = cot85Tan 25 = Tan(90-65) = Cot65

Tan5 Tan25 Tan30 Tan 65 Tan85⇒ Cot85 Cot 65 Tan30 Tan65 Tan85⇒ Tan 30 = 1/√3

(Since Cot85*Tan85 = 1 and Cot65*Tan65 = 1)

66877.

44. T食an11, 12, х, 13, y, 18, 19莉耶지 13矶(A) x + y = 1 8(C) x + y = 21(B)x-y=18(D) x-y=21

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66878.

13W O SRS I सका: ) heus a2 मकर कर्यीन धर| bhis pRM MR R eSe D Epy 2 WG[ e W hIB S Sh M B dnge P Mk 9T B4N

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Given AB is the tower.

P and Q are the points at distance of 4m and 9m respectively.

From fig, PB = 4m, QB = 9m.

Let angle of elevation from P be α and angle of elevation from Q be β.

Given that α and β are supplementary. Thus, α + β = 90

In triangle ABP,

tan α = AB/BP – (i)

In triangle ABQ,

tan β = AB/BQ

tan (90 – α) = AB/BQ (Since, α + β = 90)

cot α = AB/BQ

1/tan α = AB/BQ

So, tan α = BQ/AB – (ii)

From (i) and (ii)

AB/BP = BQ/AB

AB^2 = BQ x BP

AB^2 = 4 x 9

AB^2 = 36

Therefore, AB = 6.

Hence, height of tower is 6m.

66879.

igits of a number "Xy" is such thatthefisdigit "x" is double in value than secondese digits are 12. What is the value of number?

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66880.

1.Greatest binomial coefficient in the expansion of (1+x)x e (0, 1), is equal to

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66881.

OF TERMS& PARTICULAR TERM0.The number of terms in the expansion of(1 + x)^21 . IS)20 2) 21 3)22 4)24

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66882.

11. Prove that the coefficient of.x" in the expansion of (1+x), is twice the coefficient21 -1of x" in the expansion of (1x)-1.

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66883.

Calculate following determinants using minor expansion method:\left| \begin{array}{rrr}{1} & {7} & {3} \\ {7} & {6} & {0} \\ {-5} & {3} & {4}\end{array}\right|

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Yeah I completed my homework 🙂

66884.

the distance Betweeil icm3. Find the altitude of a trapezium, the sum of thelengths of whose bases is 6.5 cm and whose area is26 cm2.sofa trapezium

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66885.

sqrt(-cos(40)^2 %2B 1)/sin(40)

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sin^2A+cos^2A=11-cos^2A=sin^2Ahence√1/1=1

66886.

\frac \tan 85 ^ \circ - \tan 40 ^ \circ 1 %2B \tan 85 ^ \circ \tan 40 ^ \circ = 1

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tan(85°-40°)=tan45°=1

using identity tan(A-B)=(tanA - tanB)/(1+tanAtanB)

66887.

Find the equation of the line which cuts off an intercept 7 on y-axisand has the slope 3.1.

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An equation of a line is:y = mx+b

Where:m is the slope, andb is the y-intercept

in the equation y=mx+b.Put m = 3, b = 7

Equation of line isy = 3x + 7

66888.

Write any five examples of angles that you have observed arround.Example : The angle formed when a scissor is opened.

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1 angle b/w the door and the wall2 angle b/w the corners of a room3 the angle b/w the table and the ground4 the angle b/w the two books in a bag5 the angle b/w the tyres and the spokes of a bike

66889.

25. Which is the smallest number to be added to the denominator of 12/5 toget a proper fraction ?

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in proper fraction denominator is larger than numerator, so the smallest no. is 8 as 8+5 = 13 so 13 > 12.

66890.

EXERCISE 8.3Which is greater?(a) 0.3 or 0.4 (b) 0.07 or 0.02(e) 1.23 or 1.2 ( 0.099 or 0.19d) 3.3 or 3.300 G) 5.64 or 5.603Make five more examples and find the g8.5 Usi(i)Write 2 rupees 5 paise50 naise

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0.40.071.230.19both are equal5.64

66891.

Convert decimal fraction of07 to proper fraction0.95

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66892.

Exerciuollowing as proper fraction, improper fraction or mixed tractionClassi1.Classify the followin(a) &(b) 65(c) 23(11 12 13() 19b of the following improper fractions into mixed(h) 5181Convert each of the(1) 26wn-(b) 11

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1. proper fraction2.improper fraction 3. mixed fraction 4. improper fraction5.proper fraction6. mixed fraction7.improper fraction 8.proper fraction 9.improper fraction10.improper fraction

66893.

¥दे 2दी A / 11526 lifle] कीच B5-X 20 2 0T नि ८ कट

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|3x 7|=10| 2 4|

12x-14=1012x=24x=2

66894.

ese questions mentally(a) How many forties are there in four hundred(b) What is two thirds of ninety nine?

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(a) To answer this question, you need to divide 400 by 40.

400 / 40 = 10

There are 10 forties in 400.

66895.

3. Using a suitable identity, determine the product: X

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As(a+b)^2= a^2+b^2+2ab(x^2+9/16+2x*3/4)

66896.

४ , ही . 3 R S B s e L e अनल्कपवनकका:g 2 W o ¢My 0T X L'T IR. Lok किन03 Sl 1% ue' =g R .) "88224

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66897.

(1) Evaluate the following determinants, by the process of expansion21 0(a) 7 2 5(b) 1 3 -4(c) 35-3 4

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a) 1(2×6-4×5)+6(4×7-2×3) = 1(12-20) +6(28-6) = 1(-8) +6(22) = -8+132 = 124

b) 2(3×4-(-4)(-3))-(-1)(4×1-(-4)(5)) = 2(12-12)+1(4+20) = 24

66898.

3 Describe the Distributive Property.Use the Distributive Property to expand the expression -3(6.3x+ 1.5y).Lalwhat expression is equivalent to "37.5% of R "?37.5A 10037.5rectangle?В 100C 37.5RD R+37.5Ra tin. If the meal c

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3. Distributive law

-3 (6.3x + 1.5y)

-3 × 6.3x + (-3) × (1.5y)

-18.9x - 4.5y

4.

37.5 % of R

37.5------- × R100

37.5 R---------- 100

option (B) is correct.

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66899.

find the product using identities (5x -9) (5x -9)

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Use (a-b) ( a-b) = (a-b)² = a² + b² - 2ab

(5x-9) (5x-9) = (5x-9)²

= (5x)² + 9² - 2 × (5x) × 9

= 25x² + 81 - 90x

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66900.

find the product using identities (2.5-1.4) (2.5+1.4)

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Use a² - b² = ( a-b) ( a+b)

(2.5 - 1.4) ( 2.5 + 1.4)

2.5² - 1.4²

4.29