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180-140=y40=ysum of angle of triangle =180third side of triangle =180-40-30 =110180-110=x90=x

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Let the sum of money be Rs P and the rate of interest be r % p.a.Amount at the end of 8 years = Rs 3PFormula for amount= P(1+(r/100))^nwhere n=time,p=principal and r=rate3P=P(1+(r/100))^83=(1+(r/100)^8 .............1Let the money becomes 27 times in n years 27P=P(1+(r/100))^n27=1+(r/100))^n(3)^3=1+(r/100)^n(1+(r/100))^8)^3=1+(r/100))^n from 11+(r/100))^24=1+(r/100)^nComparing bases we getn=24 years

Mriganko Shekhar Mukhopadhyaya was a famous and popular writer of Calcutta. He was invited by a club in Durgapur in order to felicitate him in a cultural function. Now he was on his way back to Calcutta by car. As they were about to reach Panagarh, his car went out of petrol. The driver walked to Panagarh which is three miles away to fetch petrol. Mriganko Babu got out of the car and found himself stranded in the middle of nowhere.

1 glass = 250 mL

9 class = 9 * 250 = 2250 mL

Given:- one glass holds 250 ml of juice.∴9 such glasses holds= 250 ml×9=2250 ml

(a+b)²(a+b) ( a + b)a² + ab + ba + b²a² + b² + 2ab So, RHS = LHS

Resistance ‘R = 10 ohm’ is related to length ‘L’, area of cross-section ‘A’ and resistivity ‘ρ’ as,

R = ρL/A

When L is tripled ,

As we know that the volume of the wire remains same.

old volume = new volume

AL = A'L' ....(i) ( as volume = area x length )

L' = 3L

So, from (i)

A' = A/3

So the new resistance is ,

R' = ρL'/A'

or

R' = ρ(3L)/(A/3) = 9 (ρL/A)

=> R' = 9R

so, the new resistance increases nine fold.

Now,

R' = 9 x 10ohms

thus,

R' = 90 ohms

as Resistance is directly proportional to length so if length of wire becomes 3 times then new Resistance will also become 3 times the original resistance.

Let ,

O is the centre of the given circle.

A tangent PR has been drawn touching the circle at point P.

Draw QP ⊥ RP at point P, such that point Q lies on the circle.

∠OPR = 90° (radius ⊥ tangent)

Also, ∠QPR = 90° (Given)

∴ ∠OPR = ∠QPR

Now, above case is possible only when centre O lies on the line QP.

Hence, perpendicular at the point of contact to the tangent to a circle passes through the centre of the circle.

In each day she consume = 150 × 2 = 300mlIn 30 days, she consume = 300×30 = 9 litres

A container holds 3 litre 350 mili liter of milks. How much milk can be measured by using this container 15 times

Numbers in ascending order are8, 11, 12, 2x-8, 2x+10, 35, 42, 50There are even no. Of observationsThen median is average of midd two terms Median = 1/2(n/2 + (n/2) +1) terms = 1/2(4th + 5th) terms 25 = 1/2(2x-8 + 2x+10) 50 = 4x+24x = 48x = 12

Value of x is 12

If one cup can hold 1/3 litre of milk, 2 cups can hold1/3+1/3=2/3 litre of milk.

2/3 liter in two cups

2/3 litre of two cups is the correct answer of the given question

2/3 litre of milk we can pour in two cups

2/3 litre milk can hold

one cup can hold 1/3 L of milk.then 2 cups can hold = 1/3 ×2 = 2/3 L of milk.

2/3 litre is th answer

2/3 is the correct answer. please like as best

2/3 lit. is the right answer.

1 cup can hold 1/3 of milk.then 2 cups can hold= 1/3 × 2 = 2/ 3 L 2 / 3 of milk

for that question answer is proper fraction

proper fractions is the answer

Proper is the right answer

proper is the correct answer of the given question is

the answer is propre

proper is the correct answer

As machine bought for Rs 15800

Then,Cost of machine after first year= 15800 - 1500= 14300

Cost of machine after second year= 14300 - 1500= 12800

Cost of machine after third year= 12800 - 1500= 11300

Cost of machine after fourth year= 11300 - 1500= 10800

Cost of machine after fifth year= 10800 - 1500= 9300

Therefore, Cost of machine after 5 years= Rs 9300

But answer 2 minute 15 second aa raha please tell me

Original price = 1500000Decrease price = 1200000

Percentage of Decrease= [(Original price - Decrease price)/]*100 Decrease price= [(1500000-1200000)/1500000]*100= (300000/1500000)*100= (1/5) *100= 20%

answer

These are the important rivers

The Satluj Basin: The SatlujRiveralong with itsmaintributary, the Beas, flows towards the south-west. It joins theriverIndus in Pakistan. ...

The Ganga Basin: The Ganga is the mostimportantriverin theNorthernplains. ...

The Brahmaputra basin: The BrahmaputraRiverrises in Tibet and enters India from the east.

Total amount = 1560Let C gets = Rs xThen B gets = (20/100)xA gets = (50/100)(20/100)x

According to the given condition

(50/100)(20/100)x + (20/100)x + x = 1560x/5 + 2x/5 + x = 15608x/5 = 15602x/5 = 390x = 195*5 = 975

Therefore, A gets = x/5 = 975/5 = 195B gets = 2x/5 = 390C gets = x = 975

perimeter of that triangle = 60cm

the measure of hypotaneous = 25cm

then the rest sides must measure = 60-25= 35

Let one side be xthen, thw measure of the third side must be 35 - x

Using pythagoras theorem

(25)^2 =(x)^2 + (35-x)^2625 = x^2 + x^2 - 70x + 1225

x^2 + x^2 - 70x + 1225 = 625

x^2 + x^2 - 70x + 1225 -625 = 0

2 x^2 - 70x + 600 = 02x^2 - 40x - 30 x + 600= 02x (x-20) -30 ( x - 20) = 0(x-20)(2x-30)=0

x -20 = 0x = 20

2x -30 =02x =30x = 15

so,one of the side measure either 20 cm 15 cm

if one side measure 20cm then the other must measure 35 -20 = 15cm

and if it measured 15 cm then the other side measure 35-15 = 20 cm

so,we will get 20cm and 15 cm as our remaining sides.

one of then will be height and the other misy be the base,now apply the formula of area of triangle i.e (1/2) (height)(base)= (1/2 )(20)(15)

= 150 cm^2

So, the area of that triangle will be 150 cm^2

thans

The given figure is a trapezium are the points B and Q mid points of their respective sides.

We know that sum of parallel sides is equal to twice of the line joining the mid points of non parallel sides.

You can use the mid point theorem and its conversefor solving the question.

In triangle ACP,X is mid point of PC [converse of mid point theorem]

Also BX =1/2 AP [mid point theorem].(1)

​Similarly by using both theorems in triangle CRP,We can prove

XQ = 1/2 CR .(2)(1) + (2) = BX + XQ = 1/2(AP + CR)​This implies AP + CR = 2 BQ

the question is maximum error ....its should be in percentage right??

ACardinal Numberis anumberthat says how many of something there are, such as one, two, three, four, five. AnOrdinal Numberis anumberthat tells the position of something in a list, such as 1st, 2nd, 3rd, 4th, 5th etc. Mostordinal numbersend in "th" except for: one ⇒ first (1st)

ACardinal Numberis anumberthat says how many of something there are, such as one, two, three, four, five. AnOrdinal Numberis anumberthat tells the position of something in a list, such as 1st, 2nd, 3rd, 4th, 5th etc. Mostordinal numbersend in "th" except for: one ⇒ first (1st)

d. -10x

AnOrdinal Numberis anumberthat tells the position of something in a list, such as 1st, 2nd, 3rd, 4th, 5th etc.

I want to know succeeding and preceding number

Succeeding number is the number which comes after a number.Preceeding number is the number which comes before a number.

can you solve 3 more please

solve by foctorization :3p2+8p+5=0

the answer of this quetion is 46790

tn=a+(n-1)d35=a+(9-1)d35=a+8d. (1)Also,75=a+(19-1)d75=a+18d. (2)Subtracting 1 and 2,40=10dd=4a=75-18(4)a=3

Ans :- r is radius , l is slant height of the cone

l = length, b = width, and h = height.

a1=64a2=64×3=192a3=64×3²=576a4=64×3³=1728a5=64×3⁴=5184so tell series is 64,192,576,1728,5184........

If radius is 9cm,thendiameter 9cm+9cm=18cm

3/5 and 6/10

3/5 = 0.6

6/10 = 0.6

Both are equal