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Let two numbers are x and yx+y=200025%x=(1/6)y25x/100=y/6x/4=y/6x/2=y/33x=2y

2y/3+y=20005y=6000y=1200

x=2y/3x=2(1200)/3=800

Let the two numbers be x and (50-x).

∴(50-x)/x=2/3=>2x=150-3x=>5x=150=>x=30

∴The numbers are 30 and 20.

let the denominator be x, therefore the numerator will be (x-4)(x-6)fraction =(x−4)(x−6)/x

what does (x-4)(x-6) tell you1) It tells us that x<4 and x>6, both terms will be negative and the value will be positive.2) At 4 and 6 it will be 03) AND at x as 5, the value will be NEGATIVEso lowest value will be at x = 5

(x−4)(x−6)/x

=(5−4)(5−6)/5

=−1/5

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answer option is [D] that is ADE

d option is the answer of this question

answer dis that is ade

option d is the correct answer of the given question

d is the correct answer

GivenAB and AC are two equal words of a circle, therefore the centre of the circle lies on the bisector of ∠BAC.

⇒ OA is the bisector of ∠BAC.

Again, the internal bisector of an angle divides the opposite sides in the ratio of the sides containing the angle.

∴ P divides BC in the ratio = 6 : 6 = 1 : 1.

⇒ P is mid-point of BC.

⇒ OP ⊥ BC.

In ΔABP, by pythagoras theorem,

AB^2= AP^2+ BP^2

⇒ BP^2= 6^2- AP^2.............(1)

In right triangle OBP, we haveOB^2= OP^2+ BP^2

⇒ 5^2= (5 - AP)^2+ BP^2

⇒ BP^2= 25 - (5 - AP)^2...........(2)

Equating (1) and (2), we get

6^2- AP2= 2^5 - (5 - AP)^2

⇒ 11 - AP^2= -25 - AP^2+ 10AP

⇒ 36 = 10APAP = 3.6 cm

putting AP in (1), we get

BP^2= 6^2- (3.6)^2= 23.04

⇒ BP = 4.8 cm

⇒ BC = 2BP = 2× 4.8 = 9.6 cm

⇒ AP = 3.6 cm

putting AP in (1), we get

BP^2= 6^2- (3.6)^2= 23.04

⇒ BP = 4.8 cm

please post clearly

Please post clear images

- 1 is the correct answer of the given question

thanks a lot

Tangents drawn from an external point to a circle are equal.⇒ AD = AF, BD = BE, CE = CF.Let AD = AF =aBD = BE =bCE = CF =cAB = AD + DB =a+b= 8 -------- (1)BC = BE + EC =b+c= 10 -------- (2)AC = AF + FC =a+b= 12 -------- (3)Adding (1), (2) and (3), we get2 (a+b+c) = 30⇒ (a+b+c) = 15 -------- (4)Subtracting (1) from (4), we getc= 7Subtracting (2) from (4), we geta= 5Subtracting (3) from (4), we getb= 3Therefore, AD =a= 5 cm, BE =b= 3 cm, CF =c= 7 cm

1. 1156 2. 1244 4. 3444

Join OC

In Δ OPA and Δ OCA

OP = OC (radii of same circle)

PA = CA (length of two tangents)

AO = AO (Common)

Therefore, Δ OPA ≅ Δ OCA (By SSS congruency criterion)

Hence, ∠ 1 = ∠ 2 (CPCT)

Similarly ∠ 3 = ∠ 4

Now, ∠ PAB + ∠ QBA = 180°

2∠2 + 2∠4 = 180°

∠2 + ∠4 = 90°

∠AOB = 90° (Angle sum property)

cos1 cos2 cos3........cos89 cos90put cos90=0cos1 cos2 cos3.......cos89 *0=0

a+b=4/2=2ab=1/2(a+b)^2=4a^2+2ab+b^2=4so a^2+b^2=31/(a+2b)+1/(2a+b)=(2a+b+a+2b)/((a+2b)(2a+b))=(3a+3b)/((2a^2+5ab+2b^2)=3(2)/((2(3)+5(1/2))=6/(6+2.5)=6/8.5=12/17

since C lies between A and B AB = AC + BCAB = AC + AC (AC=BC)AB = 2AC AB/2 =AC AC = 1/2AB.

Circumference of a circle =2πra) C=2πr=2(22/7)(14)=88cmb) C=2(22/7)(28)=176mmc) C=2(22/7)(21)=132cm

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please step to step

Substitute x = -1 in the given function as shown in the answer.

Circumference = 2*(22/7)*28 Distance covered in 1 rotation = CircumferenceNumber of rotations = Distance covered / Circumference= 352/88= 4

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35000/6500350/6570:13

there 6500 is in gram so 6500gram =65kgso 35:65= 7:13

70:13. convert kg into gram

1kg=1000gso 35×1000/65003500/6500

A / (x - a) + b / (x - b) = 2c / (x - c)=> [a(x - b) + b (x - a)] / (x - a) (x - b) = 2c / (x - c)=> [(a + b) x - 2ab] (x - c) = 2c [x^2 - (a + b)x + ab]=> (a + b) x^2 - [2ab + c(a + b)]x + 2abc = 2cx^2 - 2c(a + b)x + 2abc=> (a + b - 2c) x^2 = (2ab + ac + bc - 2ca - 2bc) x=> (a + b - 2c) x^2 = (2ab - ca - bc) x=> x = 0or x = (2ab - ca - bc) / (a + b - 2c)

tuzhe pata nhi kya ans

Abe solution de

Iska answer to terko pata hi hai to solution khudh karle

your answer will be zero after divide by both

Please check the question.Here I have given the correct solution.

Let the number be x

Now,

(28 - x) = 160 / x

28x - x²= 160

x²- 28x + 160 = 0

x²- 20x - 8x + 160 = 0

x(x - 20) - 8(x - 20) = 0

(x - 8)(x - 20) = 0

x = 8 , 20

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2p-1, 3p+1, 11 are in AP

2(3p+1)=2p-1+116p+2=2p+106p-2p=10-24p=8p=8/4=2