Explore topic-wise InterviewSolutions in .

26 = 2 x 1391=7 x 13HCF = 13LCM =2 x 7 x 13 =182Product of two value 26 x 91 = 2366Product of HCF and LCM 13 x 182 = 2366

ii. 510 = 2 x 3 x 5 x 1792 =2 x 2 x 23HCF =2 LCM =2 x 2 x3 x 5 x 17 x 23 = 23460Product of both values 510x92 = 46920Product of HCF and LCM 2x23460 =46920Hence, product of two numbers = product of HCF × LCM.

Let a = 336 ,

b = 54

Expressing a and b as a product of

prime factors

336 = 2 × 2 × 2× 2 × 3 × 7 = 2^4 × 3 × 7

54 = 2 × 3 × 3 × 3 = 2 × 3^3

HCF ( 336 , 54 ) = 2 × 3 = 6

LCF( 336 , 54 ) = 2^4 × 3^3 × 7 = 3024

We know that ,_____________________________

For any two positive integers a and b .

HCF( a , b ) × LCM( a , b ) = a × b

Verification :

HCF( 336 , 54 ) × LCM( 336 , 54 )

= 6 ×3024= 18144 -----( 1 )a × b = 336 × 54 = 18144 ----( 2 )

Therefore ,( 1 ) = ( 2 )

thanks for all answers

AC and BD are the diagonals of the parallelogram.

Each diagonal of the parallelogram divides the parallelogram into two congruent triangles.

ΔADC ≅ ΔABC

∴ Corresponding sides of congrunt triangles are equal.⇒CD = AB⇒ AD = BC

Hence the opposite sides of the parallelogram are equal.

26 = 2*1391 = 7*13Hence H.C.F = 13L.C.M = 13*7*2=13*14=182H.C.F * L.C.M = 13*182 = 2366Product of the two numbers = 26*91 = 2366

Hence H.C.F * L.C.M = product of the two numbers..

square root of 559504 is 748.

DIDI how can you find it

I tried more but , I can't find it

Thanks for the answer

We are assuming that the roots ofx^2 + px + q = 0areα, βwhile roots ofx^2 + lx + m = 0areγ, δ. So, as we're given,

α/β=γ/δ

By using the sum and product of roots formulae, we can say that

α + β = -p;αβ = qγ + δ = -l;γδ = m

We have to prove that m.p^2 = q.l^2.

We are given thatα / β = γ / δ ------------(1)Reciprocating both the sides, we'll getβ / α = δ / γ -------------(2)

Adding(1)and(2), we'll get

=> (α / β) + (β / α) = (γ / δ) + (δ / γ)=> (α^2 + β^2) /αβ = (γ^2 + δ^2) /γδ

Adding 2 on both the sides,

=> [(α^2 + β^2) /αβ] + 2 = [(γ^2 + δ^2) /γδ] + 2=> (α^2 + β^2 + 2αβ) /αβ = (γ^2 + δ^2 + 2γδ) /γδ=> (α + β)^2 /αβ = (γ + δ)^2 /γδ

Now, using α + β = -p, αβ = q, γ + δ = -l, γδ = m,

=> (-p)^2 /q = (-l)^2 /m=> m.p^2 = q.l^2

Hence Proved.

In triangle ADE and triangle ABC

angle A = angle A ( common )

angle ADE = angle ABC ( corresponding angles, DE is parallel to BC)

therefore, triangle ADE is similar to triangle ABC ( by AA corollary of AAA)

area of triangle ADE / area of triangle ABC = (DE) / (BC)

area of triangle ADE / 81 = (2/3 BC)/ (BC)

area of triangle ADE = 2/ 3 * 81

area of triangle ADE = 54 cm^2

it's not answer

answer is 54

Cost of one tube = ₹57Number of tubes = 19893/57 = 349

Ohm's lawequation(formula): V = I × R and thepowerlawequation(formula): P = I × V.

I = V/R from ohm's law

Substituting I in P, we get,

P = V/R * V

P= V²/R

like my answer if you find it useful!

C=180-(80+55) =180-135 = 45

A is equal to C (because PQ and RT are parallel)A=45

B=55 (because PQ and RT are parallel)

c+80°+55°=180°.... {sum of angles of triangle is 180c=180°-135°=45°b=55°...... {alternate anglesa=c=45°..... {corresponding angle

80+55+c=180135+c=180C=180-135C=45

A equal c (beace ac is a corresponding angle) C=45

B equal q( because bq ias alternate angle) Hence b=55

It's wrong

in the apa=1/3d=4/3-1/3=3/3=1n=18henceSn=n/2(2a+(n-1)d)henceS18=18/2(2*1/3+17*1)=9(2/3+17)9(2+51/3)3(53)=159

Area of a trapezoid/trapezium is the height multiplied by the sum of parallel sides and this whole equation divided by 2.

1 minute=60 seconds

60 seconds=1 minute1 second=1/60 minute18 seconds=1/60 * 18=3/10 minutes

∆ ADC is congurent to ∆BDCby SSS rule , so angle C = angle Dsimilarly∆DBA is congurent to ∆CBA by SSS ruleso angle A = angle B

By remainder theorem put x= -5/23(-5/2)^2+5(-5/2)-113(25/4)-25/2-1175/4-25/2-1175-25-88/4= -38/4= -19/2=- 9.5

Please hit the like button

Mean of p and t = r => r*r = ptMean of q and s = r => r*r = qsTherefore, pt = qs. Option D is the answer.

In mathematics, thePythagorean theorem,alsoknown asPythagoras'theorem, is a fundamental relation in Euclidean geometry among the three sides of aright triangle. It states that the square of the hypotenuse (the side opposite theright angle) is equal to the sum of the squares of the other two sides

AC^2=AB^2+BC^2