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3.You should know how to divide a line segment in 3 equal parts & to 4 equal parts.

16/3 = 5 & 1/3.

On number line it will be between 5 & 6. It is 1/3 units ahead of (to the right of) 5.

-29/4 = -7 - 1/4.

On the number line this point lies between -7 & -8. It is 1/4 unit beyond (to the left of -7).

-3/10=-0.3-7/-5=1.49/-15=-0.618/30=0.6

ascending order

9/-15,-3/10,18/30,-7/-5(7/5)

5. 1.3 to 2 =1cm. 2 to 1=1cm. 1 to 0=1cm total 3cm × 3 =6 cm

Given: In quadrilateral ABCD,

AC = AD & AB bisects ∠A i.e, ∠CAB = ∠DAB

To prove,

ΔABC ≅ ΔABD

Proof,In ΔABC& ΔABD,

AB = AB (Common)

AC = AD (Given)∠CAB =∠DAB(AB is bisector)

Hence, ΔABC ≅ ΔABD.(by SAS congruence rule)

Then,BC= BD (by CPCT)

Thus,BC & BAD are equal.

i) Avariableis a quantity that may change within the context of amathematical problem or experiment. Typically, we use a single letter to represent avariable.

ii) A fixed value. In Algebra, aconstantis a number on its own, or sometimes a letter such as a, b or c to stand for a fixed number. Example: in "x + 5 = 9", 5 and 9 areconstants.

iii) An equation containing but one unknown quantity, and that quantity only in the first degree.

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Given : Internal diameter of hollow sphere(d)= 4 cm.Internal radius of hollow sphere (r) = 4/2= 2 cmexternal diameter of hollow sphere (D) = 8 cm.external radius of hollow sphere( R )= 8/2= 4 cm.

Volume of the Hollow sphere = 4/3π(R³ - r³)Volume of the Hollow sphere = 4/3π(4³ - 2³)Volume of the Hollow sphere = 4/3π(64 - 8)Volume of the Hollow sphere = 4/3π(56) cm³

Diameter of the cone(d1) = 8 cmradius of the cone( r1)= 8/2 = 4 cm

Let the height of the cone be h cm.Volume of the cone = ⅓ πr1²h= ⅓ π × 4² × h = 16πh/3

Volume of the cone = Volume of the hollow sphere16πh/3 = 4/3π(56)16h = 4 ×56h = (4 × 56)/16h = 56/4 = 14 cm

Hence, the height of the cone is 14 cm.

tq

5/7 the answer is correct

21/21+15/2136/2112/7

1+5/7=12/7 is the answer

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5/7 is correct answer.

14/28is a fraction form of given problem.

no. of boys = 14(given)so no.of girls = total - no. of boys = 14

so fraction of girls =14/28 = 1/2

14/28 is a fraction for boys in class

thank you

very much

thank you

The regular quadrilateral ABCDAB = aBC= bCD= xAD= yfor any regular quadrilateral like rectanglewhose opposite sides are equala=x (i)b=y (ii)from i and iia+b = x+y

The regular quadrilateral ABCDAB = aBC= bCD= xAD= yfor any regular quadrilateral like rectanglewhose opposite sides are equala=x (i)b=y (ii)from i and iia+b = x+y

thanks mam

2/7 kha se aya h

-1/2 is the correct answer

Mean = Sum of Observations / No. of Observations,

Here sum of Observations = x1+ x2 + ....... + xn,No. of observations = n,

Mean = x bar , As the bar can't be represented here I am taking it as a, i.e x bar = b, for better understanding,

Now,b = (x1+ x2 + ......+ xn)/n=> bn = x1 + x2 + x3 + ..... + xn,Multiple both the sides with a,=> abn = ax1 + ax2 + ax3 + ..... + axn ,

Now we got the value of ax1 + ax2 + ... + axn,Remember that no. of observations won't change,

Now new mean or Required mean is,

New mean = (ax1+ ax2 + ... + axn )/n=> New mean = abn/n=> New mean = ab,

Here b = x bar, As I said above , So the new mean = a * Previous mean or ,

New mean = a * x bar,

this is a diagram bisect with the PR QRS with PQ and then answer was giving

angle of rhombus is 60

4k(3y^2+2y-5)=4k(3y^2-3y+5y-5)=4k(3y(y-1)+5(y-1)=4k(3y+5)(y-1)

your answer should be wrong

According to the Quadratic Formula,x,the solution forAx2+Bx+C=0, whereA, B andCare numbers, often called coefficients, is given by :-B± √B2-4ACx = ————————2A

In our case,A= 5B=-37C=-264

Accordingly,B2-4AC=1369 - (-5280) =6649

Applying the quadratic formula :

37 ± √6649x=——————10

√6649 , rounded to 4 decimal digits, is81.5414So now we are looking at:x=(37± 81.541 )/10

Two real solutions:

x =(37+√6649)/10=11.854

or:

x =(37-√6649)/10=-4.454

Two solutions were found :

x =(37-√6649)/10=-4.454

x =(37+√6649)/10=11.854

Volume of ice cream = 3.142 x 6² x 15 = 1696.68Each child gets = 1696.68/10 = 169.668 cm³

Take radius of cone = r = radius of hemisphereHeight of cone is therefore = 4r

Volume of hemisphere + volume of cone = 169.668 cm³

2/3 x 3.142 x r³ + 1/3 x 3.142 x r² (4r) = 169.6682.09r³ + 4.19r³ = 169.6686.28r³ = 169.668 r³ = 27 r = 3 cm∴ Radius of cone = 3

Given:

For right circular cylinder

Diameter = 12 cm

Radius(R1) = 12/2= 6 cm & height (h1) = 15 cm

Volume of Cylindrical ice-cream container= πr1²h1= 22/7 × 6× 6× 15= 11880/7 cm³

Volume of Cylindrical ice-cream container=11880/7 cm³

For cone,

Diameter = 6 cm

Radius(r2) =6/2 = 3 cm & height (h2) = 12 cmRadius of hemisphere = radius of cone= 3 cm

Volume of cone full of ice-cream= volume of cone + volume of hemisphere

= ⅓ πr2²h2 + ⅔ πr2³= ⅓ π ( r2²h2 + 2r2³)

= ⅓ × 22/7 (3²× 12 + 2× 3³)

= ⅓ × 22/7 ( 9 ×12 + 2 × 27)

= 22/21 ( 108 +54)

= 22/21(162)

= (22×54)/7

= 1188/7 cm³

Let n be the number of cones full of ice cream.

Volume of Cylindrical ice-cream container =n × Volume of one cone full with ice cream

11880/7 = n × 1188/7

11880 = n × 1188

n = 11880/1188= 10

n = 10

Hence, the required Number of cones = 10

yes

Weight of dessert =2.25kgIce cream weighs 35%So, the weight of ice cream is (35/100)*2.25=.7875kg