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69251.

Cias XSub-MathTime-2 HrsFull Marks - 401. Answer all the questions.(1x51(1) Ifa, Bare the zeroes of the polynomial f(x) = x² + x + 1, then findthe value of+?ii) Find the HCF of96 and 404 by prime factorization method?iii) If x = 1is zeroes of the polynomialf(x) = x-2x2 + 4x + k, writethe value of k?Vivi Given that HCF (306, 657) = 9, find LCM (306,657)(v) Find the value of kfor which the system of equations 2x + 3y =5 and 4x - ky = 10 has infinite number of solutions?122. Answer all the questions.Show that 5 - VŽ is irrationaldi Use Euclid's division algorithm to find the HCF of 196 and 3822

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iii) 96 and 404; 96/2=48/2÷24/2=12/2÷6/2=3: 404/2=202/2=101; lcm=2×2×2×2×2×3=2×2×2=8; lcm 404=2×2×101=2×101

x^3-2x^2+4x+k; x=1;; (1)^3-2(1)^2+4(1)+k=1-2+4+k=-1+4+k; ; k=-3

69252.

There were 56 apples in thebasket. The children ate 39apples. How many applesare left?

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Total apples in the basket:56Apple's ate by children's:39Apple's left=56-39 =17

69253.

2 It the zeroes of the quadratic polynomial)N bare 2 and 3, then find thevalues of a and b

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69254.

EXERCISE 10nd the later surface area and total.14 cm.

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Lateral Surface Area = 6*a^2= 6*4*4= 96 sq cm

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69255.

2. If 1680 Apples are packed in 12 cartons. Howmany Applesthere in each carton?

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12 cartoon have 1680 applesso each cartoon have 1680/12 = 140

69256.

the ratio in which the line segment joining the1, 6).points (-3, 10) and (6, -S) i

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69257.

Find the ratio in which the line segment joining the points (-3, 10) and (6,- 8) is dividedby (- 1, 6)

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why we let k:1

69258.

Draw the perpendicular bisector of a given line segment AB of length 6 cm

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Thank You!

69259.

ind the coordinates of the points which trisect the line segment joining(4, 2,-6) and Q (10,-16, 6).Miscellaneous Examples

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69260.

6.Draw a line segment of a given length. Divide it into four equal parts.

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Answer:First we draw a line with length of 10 cm let say AB = 10 cmThen divide it into half as take arc of more than half length of the line and place point at A and make two arc on both side of the line , Now do the same for poin B and both arc intersect At C and D As:

That gives us AE = EBNow we divide section AE and EB to get four equal parts of our line AB = 10 cmSo , place point at A and take arc of more than half of AE and make two arc on both side of the line , and do same for placing point at E , that gives two point F and G .Do above step for line segment EBand get two point H and I As:

Nowlength of all four sectionAJ = JE = EK = KB = 2.5 cm

69261.

What is the smallest number that is divisible by 20, 48 and 72?

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LCM of 20,48,72=1220

1220 is divisible by 20,48,72

69262.

Q.11. If a and Bare zeroes of p(x) = x2 - p(x + 1) + C, such that (a + 1)(then find the value of c.+ 1) = 0,

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Secondary School

Math

13+7 pts

If alpha,beta are the zeros of the polynomial x2-px-1)+c such that (alpha + 1)(beta +1)=0,then find the value of c

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byBarlacktr778616.10.2018

Answers

TheGreatStudent01

Maths AryaBhatta

hey gd aftrnhere is your answerGiven that alpha and beta are the roots of the quadratic equation f(x) = x^2-p(x+1)-c = x^2-px-p-c = x^2 -px-(p+c), comparing with ax^2 + bx + c, we have, a =1 , b= -p & c= -(p+c) alpha+beta = -b/a = -(-p)/1 = p & alpha*beta = c/a = -(p+c)/1 = -(p+c) Therefore, (Alpha + 1)*(beta+1) = Alpha*beta + alpha + beta + 1 = -(p+c) + p + 1 = -p-c+p+1 = 1-c or c=1hope its help you plz mark as brainlist answer and follow me for more brainlist answer thanxx and be brainly.................................

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BrainlyQueen01

Brainly Warrior

Correct question : If α and β are the zeros of the polynomial x² - p ( x + 1 ) + c such that, ( α + 1 ) ( β + 1 ) = 0 then find the value of c. Answer:

c = - 1

Step-by-step explanation:

x² - p ( x + 1 ) + c

⇒ x² - p x - p + c

⇒ x² - p x + ( c - p )

Comparing with ax² + bx + c, we get :

a = 1

b = - p

c = c - p .

Given :

( α + 1 )( β + 1 ) = 0

⇒ αβ + α + β + 1 = 0

Note that, sum of roots = - b/a

α + β = - b / a

But b = - p

a = 1

So α + β = - ( - p ) / 1 = p

Product of roots = αβ = c / a

⇒ αβ = ( c - p )

Hence write this as :

αβ + α + β + 1 = 0

⇒ c - p + p + 1 = 0

⇒ c + 1 = 0

⇒ c = -1

Hence, the value of c is - 1.

c is -1 is a correct answer.....

c= -1 is the correct answer of the given question

69263.

1.Using appropriate properties find.3525、'6

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69264.

honts to, o) nd (, 4).A andBare (1, 4) and (5, 2) respectively,find the coordinates of P when AP/BP-3

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69265.

17. There are 4 shelves to keep apples in thefruit shop of Ms. Bendick. Each shelf hasroom for 15 apples. If Ms. Bendick has 72apples, how many apples will not be able tofit on the shelves?(6) 60(c) 15(a) 72d) 12

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d is the correct answer

69266.

If a>b>0,√a+√b=17 and √ab=72,find the value of √√a-√b?

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question of which book

sample paper

of what

vmc admission test

can you send pic of this question

thanks

you re from which state

Delhi

what's the answer???

as you know a plus b ka whole square is equal to a minus b ka whole square + 4 a b Teri

sorry

send mare questions

69267.

02031 न तण२ 0001) ८ ek lie (i 2288 el sy ite 553 WD €7 B |bhe Yo WO 76T Rh L Mkl b Db Hblkbe कप,

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69268.

Draw a line segment Pg 6.2 cm. Draw the perpendicular bisector of Pg

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69269.

6. Draw a line AB. Take a point P on it. Draw a line passing through P and perpendicularto AB.

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69270.

EXERCISE 14A1. Draw a line segment P9 6.2 cm. Draw the perpendicular bisector of P9.

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69271.

Reetu's school starts at 8:15 a.m. and closes at 3:40 p.m. Find the working hours of her school.

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Starts at 8:15 am Closes at 3:40 pm Total working hours = 7 hr 25 min

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69272.

e The value of(Ag72-72-72-......20(B) 12(C) 4(D) 6

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69273.

12. Find the angle in radian through which a pendulum swings if its length is75 cm and the tip describes an arc of length:(i) 10 cm(ii) 21 cm(iii) 15 cm | use π

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69274.

If √3/4a²=21a/2, find the value of a

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V3/4a^2= 21a/2; = 2 V3 =21a(4a^2) = 2V3 = 21×4( a^3) = a^3 = 2V3/84=V3/21

ve/4a^2=21a/2;=2v3=21a(4a^2)=2v3=21×4(a^3)=. a^3=2v3/84=ve/21

69275.

12. If x 2, y 3, thenis equal to1772724) 17(1) 7231(3) 108

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X= 2y= 3then1/2^3+1/3^21/8+1/917/72 answer

69276.

EXERCISE 1.1Bare properties find--*

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2/5 * (-3/7) - 1/6 * 3/2 + 1/14*2/5

= - 6/35 - 1/4 + 1/35

= (-6 + 1)/35 - 1/4

= - 5/35 - 1/4

= - 1/7 - 1/4

= (-4 - 7)/28

= - 11/28

-11/28 is the answer

-11/28 is the answer

69277.

d 20121a

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69278.

wo Pais l adjacent angies.2. Draw a parallelogram ABCD in which AB= 6.5 cm . AD= 4.8 cm andBAD:7Measure its diagonals.

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69279.

1. (-216x1728)3 का मान होगा।(a) -72 | (b) 27(c) 72(d) -27

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Given cubic root is ( -216 * 1728 ) ^ 1/3 = -72.

A is correct answer (-72)

-27 right answer bhai

69280.

15. The value of cos2 135 -2sin2 180° +3cot2 1500-4 tan2 120° isIS(2) /23(3) 725(4) 72

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69281.

4. Prove that theperpendicular drawn,to the base of an isosceles triangle from the vertex bisects the base

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U can use RHS congruence rule.In ∆ADB and ∆ADCangleADB=angleADC=90° (since AD is perpendicular to BC)

AB=AC( since it is an isos triangle)AND. AD=AD (common)therefore the triangles are congruent. BD=DC(by cpct)

69282.

A boy go to his school which is 12 km from his home . if boy increased his speed by 1 km/hr he reaches the school 1 hours before. find his speed of walking.

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distance = 12kmlet original velocity and time be v,t=> distance = velocity * timechanged velocity = v+1changed time = t-1v*t = 12 = ( v+1)*(t-1)=>t-v-1 = 0 => t-v = 1t+v = 5 by solving we get velocity = 2 kmph

69283.

ORThe length, breadth and height of a room are 8 m 50 cm, 6 m 25 cm and 4 m 75 cm rlength of the longest rod that can measure the dimensions of the room exactlyespectively. Find the2

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69284.

2.The length and breadth of our school hall is 2000 cm and 1600 cm. Let's find the length ofthe longest tape which can measure both length and breadth in exact whole numbers.

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the length and breadth of our school is hall is 2000 cm and 1600cm. Let's find the length of the longest tape which can measure both length and breadth in exact whole number

Length of school hall = 2000 cmBreadth of school hall = 1600 cm

The length of longest tape os equal to HCF of 2000 and 1600

Factors of 2000 = 2, 2, 2, 2, 5, 5, 5Factors of 1600 = 2, 2, 2, 2, 2, 2, 5, 5

HCF = 2*2*2*2*5*5 = 400

Therefore length of longest tape to measure length and breadth of hall= 400 cm

400 cm is the right answer

400 is the correct answer

69285.

(f) 16.5 ÷15(g) 0.077 ÷ 7(h) 8888 ÷22(i) 35.49 ÷ 13(j) 57.5 ÷25

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69286.

Find the value of λ for which the following lines are perpendicular to eachother:x-55λ + 2x-y+2 = 2-112-y1-z:-1,52λHence, find whether the lines intersect or not.

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69287.

The breadth of a rectangle is 6 cm and each of its diagonalsmeasure 10 cm. Find its length

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Diagnols are hypotenuse.So length=(10^2 - 6^2)^(1/2)=(100-36)^(1/2)=64^(1/2)Length=8cm

69288.

EXERCISE 21AFind the perimeter of a rectangle in which:(i) length 16.8 cm and breadth 6.2 cmii) length = 2 m 25 cm and breadth 1 m 50 cmiii) length 8 m 5 din and breadth = 6 m 8 dmind the cost of fencing a reeto

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69289.

." (a) 40:10=80:20 (b) 9:18=36:72)(d 3:42=7:98 (e) 15:20=45:60

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69290.

Divide the Px)-3x5x-3 by xJ2 i llquotient and remainder.18. Solve the following pair of linear equation by the substitution04method3x -y 3OR24 ond hence find the value

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3x - y = 3 .....(1)

9x - 3y = 9 ......(2)

From (1), y = 3x - 3

Put in (2)

9x - 3 ( 3x - 3) = 9

9x - 9x + 9 = 9

9 = 9

So, there are infinite solution.

thanks bhai

69291.

It is required to make a closed cylindrical tank of height 1 m and base diameter 140 cmfrom a metal sheet. How many square metres of the sheet are required for the same?

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69292.

In Δ ABC, LACBof ACB.Prove that90°. seg CDside AB and seg CE is angle bisectorAD AE2BD BE

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69293.

23. t is required to make a closed cylindrical tank of height 1 m and basediameter 140 cm from a metal sheet. How many square metres of thesheet are required for the same?

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69294.

a)In Δ ABC, LACB-20°, seg CDof ZACBProve that :side AB and seg CE is angle bisectorAD AEBD BE

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69295.

base 4, the number is ifi What is the same number in base 10?7. Written inase 4, the number is 111. What is the same number in base 10?

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69296.

solid cylinder of copper 8 cm high and 3 cm in radius is melted and recastblid cylinder of copper 8 cm high and 3nto a cone of radius o em Caculde the height of the conemelted and recast

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Thank u so mch

69297.

VİI. (i) The teacher said to the boys, "Sit properly an(ii) My friend said to me, "Why do you not read th(iii) The boy said, "Let us go to our playgroundlook at the diagram on the blackboard."book given by him?'"adho hoys to sit nroperly an

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1.the teacher told/ordered the boys to sit properly and look at the diagram on the black board.2 My friend asked me why he was not read the book givan by him.

69298.

A right circular cone is 8 cm high and the radius of its base is 2 cm . The cone is nma sphere. Determine the diameter of the sphere.

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Height of cone, h = 8 cmRadius of cone, r = 2 cmLet radius of sphere be “R” cmSince cone is melted and made into a sphereVolume of sphere = Volume of cone(4/3)πR^3= (1/3)πr^2hThat is, 4R^3= r^2h4R^3= (2)^2x 8R^3= 8 = 2^3Therefore, R = 2Thus diameter of sphere is 4 cm.

69299.

(C) 1570z(D) 15.7 Z. What is the height of a cuboid of volume216 cm3 if its length and breadthmeasure 8 cm and 6 cm?(A) 45m(C) 4.8m(B) 6m(D) 9 m

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Volume=length*breadth*height216=8*6*height216/8*6=heightheight=9/2=4.5cm

69300.

3) Linear Measure1) Find the length of the fish. 2) Find the length of the 3) Find the measurement ofButterflyeach segment. Assume thatcach figure is not drown toscale. AC4.9 cm5.2 cm5.74) Find the measurement of 5) Find the value of x and YZ 6) Determine whether eachcach segment. Assume that if y is beach figure is not drown toscale. Gibetween X and Zpair of segments is congruentBE, COX, and Xy : 25GH3 m5 mark7) Find the value of x and YZ8) Determine whether eechif y is between X and Z.

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