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2.5 litres of paint can cover 725 m² of area

1 litres of paint can cover 725/2.5 m² of area

4.75 litres of paint can cover (725/2.5)*4.75 m² of area

Therefore, 4.75 litres of paint can cover 1377.5 m² of area

suppose the length of tangent is x cmthen (9.1^2 = X^2 + 8.4^2)according to Pythagoras theorem)x =3.5m

Intregal sin2x=-(cos2x)/2+ cthanksplease like the solution 👍 ✔️

but I didn't understand

thanks

the minute hand is always at 3 position.

at the mid point of hypotenuse

Let, 150 men would have completed the work in 'n' days working all days.

Now no. of men & no. of days are inversely proportional. So, we get,

150n = constant ----------->(1)

But, from 2nd day, 4 men left and so on and it took 8 days more than the normal to finish the work, ie, (n + 8) days. Consequently,

150 + 146 + 142 +.......to (n+8) terms = constant

Left hand side is an A.P, with 1st term =150, common difference = -4

So, using formula,

(n+8)*1/2*[2*150+(n+8-1)(-4)]= constant ------->(2)

From equations,

(n+8)[300+(n+7)(-4)]=300n

Solving the quadratic equation, we get,

n = 17, or -32(neglected)

Hence, work is completed in,

n+8

= 17 + 8

= 25 days

Let the number be 10x+y

Given,x × y= 18..........(1)10x + y - 63 = 10 y + x9x - 9y - 63= 09x - 9y = 63x-y = 7..........(.2)x= 7+yput value of x in eq 1 we get( 7+y ) y = 18y² + 7y = 18y² +7y-18=0 y² +9y -2y -18= 0y(y+9) -2 ( y +9) =0( y+9) (y-2) = 0y=-9 , y = 2y= 2.so, x= 7+2=9

therefore the two digit number is 10(9)+2= 92.

90+3 of 15 +(19-8)-7×8=9+45+11-56=9

please like the answer if it helps

³√8=2³√27=3³√8׳√27=2×3=6³√(8×27)=³√216=6LHS=RHS

Twolinesthatmeet in apointarecalledintersecting lines.

Speed of man = 45/9 = 5km/hrIf speed increased 3 times then new speed = 5*3 = 15 km/hr

Distance = speed x time60 = 15 x timeTime = 60/15 = 4 hrs

A is correct option

At quarter past the hour, the minutes hand is at 9

SinA* SInB= 1/4meanssinA= 1/2cosB= 1/2angle A= 30°angle B= 60°so it would be an 90° at angle C

1. 8 day is the correct answer

4) is the correct answer

In trapezium BC || ADso extend AB line we can find corresponding angle similarly for CDA + 144° = 180° A = 180° -144° = 36°D + 106° = 180°D = 180° - 106° =74°

A Line segment have one end point

A line segment have one end point

(b) A ray .A ray has one end point

a line segment have one end point

A Ray has one end point

Ray is one end points

answer of this question is a

a ray has one end pointhope this answer helps you out

01:55 pm is the answer of the given questions

01:55 is the right answer of given questions

01:55pm is the right answer

10 15 + 3 40 ____________ 13 55therefore the seminar end at 1:55 pm.

1:55 pm is the right answer

1:55 IS YOUR RIGHT ANSWER

The seminar concluded at 1:55 pm

1:15 is the answer of the following

hm= 100So,7hm= m=700metres

Number of rows = 53

Number of equal saplings on each row:

Number on each row = 15,019 ÷53 = 283 remaining 20

Find the number of saplings he need to buy to make another row:

Number of saplings = 53 - 20 = 33

Answer: He should bring in 33 more saplings to have 284 equal rows.

2)20 daysis correct answer

hm= 100So:-8.256hm= m=825.6metres

Given time needed by the minutes hand show (t^2/4) – 3Hence the quadratic equation becomes, (t^2/4) – 3 = 60 – t(t^2– 12)/4 = 60 – t(t^2– 12) = 240 – 4 tt^2– 12 – 240 + 4 t = 0t^2+ 4t – 252 = 0t^2+ 18t – 14t – 252 = 0t(t + 18) – 14(t + 18) = 0(t + 18)(t – 14) = 0(t + 18) = 0 or (t – 14) = 0∴t = - 18 or t = 14Since t cannot be negative, t = 14