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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 69951. |
Factorise: 2 a-4 b-x a+2 b x |
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| 69952. |
le product of the greatest and the smallesrs made with the digits 5, 2 and 9. |
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Answer» greatest no =952smallest no=259 greatest number is 952smallest number 259 greatest number is 952and Smaller number is 259 |
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| 69953. |
If the CP of 10 articles equals the SP of 8 articles, find the profit or loss per cent. |
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Answer» let CP of one article be = 10CP of 10 articles = 100 SP of 8 articles = 100SP of one article = 100/8 = 12.5 So thegain= (2.5/10)*100 =25%. |
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| 69954. |
If the CP of 10 articles is equal to the SP of 12 articles. Find the gain or loss %. |
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Answer» CP of 10 article = x CP of 1 article = x/10 SP of 12 article = x SP of 1 article = x/12 loss%= loss/CP*100 =(x/60)/(x/10)×100 =100/6=16.6666% |
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| 69955. |
3*(n - 5)=-15 |
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Answer» 3( n-5)=-15; 3n-15=-15; 3n=-15+15=0; n=0/3=0 |
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| 69956. |
if a=9,b=8 and c=x satisfies 3 cosC=2,then -a)x=5b)x=6c)x=4d)x=7 |
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Answer» So Cos C = 2/3 So, C = cos inv( 2/3) nearly equal to 5 so x= 5 |
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| 69957. |
\begin{array}{l}{\text { (i) } \tan 48^{\circ} \tan 23^{\circ} \tan 42^{\circ} \tan 67^{\circ}-1} \\ {\cos 38^{\circ} \cos 52^{\circ}-\sin 38^{\circ} \sin 52^{\circ}-0}\end{array} |
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Answer» tan 48 cot 23 tan 42 cot 421*1=1since cot A. tan A=1 |
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| 69958. |
4 x ^ { 2 } + 4 b x - ( a ^ { 2 } - b ^ { 2 } ) = 0 |
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Answer» but we are supposed to factorize it |
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| 69959. |
203×204 BY SUTR NIKHILAM |
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| 69960. |
\operatorname { tan } ^ { 4 } 38 ^ { \circ } \operatorname { cos } 52 ^ { \circ } - \operatorname { sin } 38 ^ { \circ } \operatorname { sin } 52 ^ { \circ } = 0 |
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| 69961. |
Strategy to solve1) The formula for area of circle is...2)Second, I will substitute numbers for Variables3) Thirds, I will multiply the numbers to findthe AREA |
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Answer» a=π r2 is the formula of circle |
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| 69962. |
Then the ratio of the lergiit aid m(d) 4:1. (vi) If the mean of 6,7, x-2, x, 17, 20 is 16 then, the value ofx is-(a)24 (b) 48 (c) 50 (d) 21.|P81x5-5 | |
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Answer» For given dsts 6, 7, x-2, x, 17, 20 mean is average of(6/2)th and [(6/2) + 1]th term Thus, mean = (x - 2 + x)/216 = (2x - 2)/22x = 32 + 2x = 34/2 = 17 Value of x is 17 |
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| 69963. |
EXERCISE 81. ) The angles of quadrilateral are in the ratio 3:5:9:13. Find all the angles of of thequadrilateral.(2.) If the diagonals of a parallelogram are equal, then show that it is a rectangle. |
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Answer» 3x+5x+9x+13x = 360° x = 360/30 x = 12° The angles are 36°, 60°, 108° and 156° |
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| 69964. |
1221. Express each of the following rat(i) 28 : 631 1EXERCISE 8 (A)(iii) 0.4: 0.6press each of the following ratios in the simplest form:1 1 1(ii) 105: 133(vii) 4. 8 10(xi) 36 minutes(x) 4 days : 2 weeks(ix) 125g: 1 kg |
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Answer» i) 28: 63 =4:9; ii)105:133=7x19; 7x15=19:15; iii)0.4:0.6=0.2:0:0.3, iv)1/4:1/9=1/2:1/3, v)7/2:9/4=7/1:9/2 |
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| 69965. |
Exercise 8 (C)1. What amount of money should Mohan invest in a bank in order to get 1323 in 2 yerar" compounded annually? |
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Answer» answer is 1200 |
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| 69966. |
Suggested Exercise1. Sketch the graph ofx +4y8. |
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| 69967. |
Q. 3. If 24x is a multiple of 3, where x isa digit, what is the value of x?20Since 24x is a multiple of 3, its sum oftsle8lydigits 6 +x is a multiple of 3; so 6 +x is one ofthese numbers: 0, 3, 6, 9, 12, 15, 18, .Butsince x is a digit, it can only be that 6 + x=6 or9 or 12 or 15. Therefore, x -0 or 3 or 6 or 9.Thus, a can have any of four different values.) |
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| 69968. |
Three items are purchased at Rs.450 each. One of them is sold at a loss of 10%. At what priceshould the other two be sold so as to gain 20% on the whole transaction? What is the gain % onthe transaction? |
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Answer» Total cost for three items purchased =3×450=1350.SP of first item =450-((10/100)×450)=Rs.405Total SP when gained 20%=1350+((20/100)×1350)=Rs.1620price for each of the two of items to gain 20%on the whole transaction=(1620-405)/2=Rs.607.5gain% on the two items =((1215-900)/900×100)=35% |
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| 69969. |
CP of 10 article is equal to Sp 0410articles, then in the whole transactionthere is a profit in % of |
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| 69970. |
tuA53Prove thatin is a natural number for all n e N5 3 15 |
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| 69971. |
If 'A' denotes "divided by", 'B' denotes "added to", 'X' denotessubtracted from", 'R denotes "multiplied by", then 18 R 12 A 4 X 8 B 63(B) 102(A) 52(C) 45(D) 32 |
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| 69972. |
3 a x - 6 a y - 8 b y + 4 b x |
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| 69973. |
\left. \begin{array} { l l } { x ^ { 2 } + 4 + 3 x ^ { 3 } - 7 x } & { ( b ) ( x ^ { 2 } - 1 ) ( x ^ { 2 } + 4 ) } \\ { ( x + \frac { 5 } { 6 } ) ( x + \frac { 6 } { 5 } ) } & { ( d ) ( x ^ { 3 } - 7 ) ( x ^ { 3 } - 8 ) } \end{array} \right. |
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Answer» a ka answer wrong h give statement also statement also sir said statement is where |
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| 69974. |
| सानित 53 3 3 +52 -यमेथ छे, |
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Answer» લેટ 3 - √2 = (એ / બી) એક પરિમાણીય સંખ્યા છે. બંને બાજુથી બેઠા પર મળીને મળે છે 2 + 3 - 2 +6 = (એ 2 / બી 2) તેથી, 5 - 2, 6 = (એ 2 / બી 2) એક રજિસ્ટિક સં. તો, 226 = 5- (એ 2 / બી 2) કારણ કે, 2 થી 6 એક અપ્રમાણિક સં. અને 5 - (એ 2 / બી 2) એક પરિમાણીય સંખ્યા છે. તેથી, મારો વિરોધાભાસ ખોટો છે. તેથી, (, 3 - √2) એક અદ્રશ્ય સંખ્યા છે. |
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| 69975. |
URMultiply using Nikhilam formula-51 x 52 x 53 |
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| 69976. |
-sin(37^circ)*1/(2*cos(53^circ)) %2B (2*sec(52^circ))/((3*(38^circ*cosec))) |
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| 69977. |
\left. \begin{array} { l } { \text { If } 5 ^ { x - 3 } \times 3 ^ { 2 x - 8 } = 225 } \\ { \text { If } ( \frac { 3 } { 4 } ) ^ { 6 } \times ( \frac { 16 } { 9 } ) ^ { 5 } = ( \frac { 4 } { 3 } ) ^ { x + 2 } } \\ { \text { If } ( \frac { a } { b } ) ^ { x - 1 } = ( \frac { b } { a } ) ^ { 2 x - 8 } } \end{array} \right. |
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| 69978. |
pouIls(8,12)aid(,24).FindthevalueolxFind the value of x for which the points (-I)(2. 1) and (4.5) arecollinear.] |
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| 69979. |
NE G g Ry & -5. Given 2a - = = 4 find Qa° + =2!,‘? r._"'(l‘5— जि e P on & N SRR Y g 5 R s % न |
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| 69980. |
कक /o 113} b Ne /0L o)k N\ ////—\\5 8. g |
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Answer» x +(10/100)x = 35211x/10=352x=320 |
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| 69981. |
16.2.7 3.5" -5 is divisible by 24, for all n e N. |
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| 69982. |
Exercise 81. Jose has 4 chocolates.Tara has 3 chocolates.How many more chocolatesdoes Jose have? |
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Answer» the correct answer is 0 1 chocolates Jose has |
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| 69983. |
Multiple CIU12, Rahul bought a motor cycle for45000 andaid 200 for its cartage. He sold it at a gain of10%. What was Rahul's profit ?(a) 4500(b)4520 |
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| 69984. |
The list price of a DVD player is Rs. 13,500. If the rate of VAT is 11%, find the selling price of theDVD player.5. |
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Answer» Let list price is LP = 13500ce Selling price is SPGiven VAT = 11% SP = LP + VAT = LP + (11/100)LP = LP(111/100) = 13500(111/100) = 135*111 = 14985 Selling price is Rs 14985 |
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| 69985. |
a 21. A DVD player and TV were bought for Rs 8,000 each. The shopkeeper made apercentloss of 4% on the DVD player and a profit of 8% on the TV. Find the gain or losson the whole transaction. |
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| 69986. |
1.Simplify combining like terms:0 21b- 32+ 7b-20b |
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Answer» 21b-32+7b-20b =21b-20b+7b-32 =(21-20+7)b-32 =8b-32 =8(b-4) |
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| 69987. |
A.Simplify combining like terms :1.2lb -32 + 7b-20b |
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Answer» 21b-32+7b-20b21b-20b+7b-328b-32 |
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| 69988. |
8 छा) न 6395 [-6 $00 4 g uls ;R R1 1+ 68०5 - 8 फूड X |
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Answer» LHS = (sinθ - cosθ + 1)/(sinθ + cosθ - 1) dividing by cosθ both Numerator and denominator = (sinθ/cosθ - cosθ/cosθ + 1/cosθ)/(sinθ/cosθ + cosθ/cosθ - 1/cosθ)= (tanθ + secθ - 1)/(tanθ - secθ + 1) Multiply (tanθ - sec) both Numerator and denominator = (tanθ + secθ - 1)(tanθ - secθ)/(tanθ - secθ + 1)(tanθ - secθ)= {(tan²θ - sec²θ) - (tanθ - secθ)}/(tanθ - secθ + 1)(tanθ - secθ)= (-1 - tanθ + secθ)/(tanθ - secθ + 1)(tanθ - secθ) [ ∵ sec²x - tan²x = 1 ]= -1/(tanθ - secθ) = 1/(secθ - tanθ) = RHS |
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| 69989. |
EXERCISE 12.2Simplify combining like termso 21b 32 +7b- 20b |
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Answer» 28b-32-20b=8b-32=8(b-4) |
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| 69990. |
3.Powers and Exponentsnplify(ii) _252492 - 1615353,5,7874,85 R(iv)153 , 18235 , 54 / 122he value of x3=(*) (ii) 7 + 73 = 73(i) 42+1e value |
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| 69991. |
Find the following using the law of powerswith the same baseA. 52 x 533.C. 74+73D. 99 92 |
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| 69992. |
\left| \begin{array} { r r r } { 6 i } & { - 3 i } & { 1 } \\ { 4 } & { 3 i } & { - 1 } \\ { 20 } & { 3 } & { i } \end{array} \right| = x + i y , |
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| 69993. |
Q6. If 'A' denotes "divided by", 'B' denotes "added to", 'X' denotes"subtracted from", 'R' denotes "multiplied by", then 18 R 12 A 4 X 8 B 6 ?(A) 52(C) 45(B) 102(D) 32 |
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Answer» 18*12÷4-8+618*3-8+654-8+660-852 |
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| 69994. |
(6) Write all the twin primes from 1 to 30. |
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Answer» The twin pair primes between 1 and 30 are (3, 5), (5, 7), (11, 13), (17, 19), The twin prime pairs are: (3, 5), (5, 7), (11, 13), (17, 19) |
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| 69995. |
16. Express each of the following numbers as the sum of twin primes |
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Answer» 2650 answer...... ........ |
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| 69996. |
8ab X+4a x+4bन जार मेa+b x—4a x-4b x = -3 भोन निर्श काला । |
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Answer» Given : x = 8ab / (a + b) ==> x = 4a * 2b / (a + b)=> x / 4a = 2b / (a + b) - - - (1) Similarly, x / 4b = 2a / (a + b) - - - -(2) Now, using Componendo & Dividendo in (1) & (2)and adding left to left and right to right we get,(x + 4a) / (x - 4a) + (x + 4b) / (x - 4b) =. . (2a + a + b) / (2a - a - b) + (2b + a + b) / (2b - a - b) => (x + 4a) / (x - 4a) + (x + 4b) / (x - 4b) = (3a + b) / (a - b) + (3b + a) / (b - a )=> (x + 4a) / (x - 4a) + (x + 4b) / (x - 4b) = (3a + b) / (a - b) - (3b + a) / (a - b )=> (x + 4a) / (x - 4a) + (x + 4b) / (x - 4b) = (3a + b - 3b - a) / (a - b)=> (x + 4a) / (x - 4a) + (x + 4b) / (x - 4b) = (2a - 2b) / (a - b) = 2(a - b) / (a - b) => (x + 4a) / (x - 4a) + (x + 4b) / (x - 4b) = 2 . . . . |
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| 69997. |
UULLUTUU LIIuuuulil PUNTEN5. If sum of the squares of zeros of the quadratic polynomial f(x) = x2 -8x + kis 40, find the value of k.1.2. |
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| 69998. |
. Simplify combining like terms:21b- 32+7b-20b |
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Answer» 21-32+7b-20b=08b=32b=32/8b=4 |
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| 69999. |
12 chocolates. Anil, Sunil and Neel need to share the chocolates in ratio of 1 : 2:3. How many each one will get? |
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Answer» let the ratio be x so share will be x, 2x, 3xAccording to question,x + 2x + 3x = 126x = 12 x = 12/6 x = 2so anil will get 2 sunil will get 4neel will get 6 |
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| 70000. |
1 meu can need 63 m long trenchin one day . How many mech should beemployed for digging 27m cong trendsof the same type in 1 day. |
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