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Sol:Given that triangle ABC right angled at A.Base = AB = 5cm, Height = AC = 12 cmTherefore, Area of the triangle = Base x Height.Area = AB x AC = 5 cm x 12 cm⇒ Area = 60 cm2.Now, consider BC = Base, Height = AD.Area = Base x Height.⇒ 60 cm2= 13cm x ADAD = 60 / 13⇒ AD = 4.615 cm

10cm is the perimeter of triangle apq pls mark as best

27+44/30 kaise

Sqaure of maximum size will be of side=2mPerimeter of square=4*side=4*2=8mCost =25*8=200 RsLeftover glass is in rectangle shape.Perimeter of leftover glass=2(1.5+3.5)=2(5)=10mCost =10*25=250Rs

answer rectangle 2m by 1.5m;₹375

as an is a rational number - 100 cannot be the term of the given AP.

we calculate the area total the acquarium:Atot=2(ab+ah+bh)=2(80×30 +80×40 + 30×40); =2×(2400+3200+1200); =2×6800=136000 cm²we calculate the area of front face:Af=a×h=80×40=3200 cm²we calculathe the area of the top:At=a×b=80×30=2400 cm²we calculate the area of paper needed:A=Atot-(Af+At)=136000-(3200+2400)=136000-5600=8000 cm²

therefore answer is (B) 8000 cm²

For finding the area of the paper used determine the area of each part separately and then find the sum of the areas to get the area of used paper.

For region I (Triangle)

Length of the sides of the triangle section I = a=5cm, b=1cm and c=5cm

Semi Perimeter of the triangle, s =( a+b+c)/2s=(5 + 5 + 1)/2= 11/2cm

Semi perimeter = 11/2 cm = 5.5cm

Using heron’s formula,Area of section I = √s (s-a) (s-b) (s-c)

= √5.5(5.5 – 5) (5.5 – 5) (5.5 – 1) cm2

= √5.5 × 0.5 × 0.5 × 4.5 cm2

= √5.5 × 0.5 × 0.5 × 4.5 cm2

= 0.75√11 cm²= 0.75 ×3.32 cm²= 2.49 cm² (approx)

Section II( rectangle)

Length of the sides of the rectangle of section II = 6.5cm and 1cm

Area of section II = l ×b= 6.5 × 1= 6.5cm²

Section III is an isosceles trapezium Figure is in the attachment:

In ∆ AMDAD = 1cm (given)AM + NB = AB – MN = 1cmTherefore, AM = 0.5cmNow,AD² =AM² +MD²MD²= 1² – 0.5²MD²= 1- 0.25= 0.75MD = √0.75= √75/100=√3/4cm

Now, area of trapezium = ½(sum of parallel sides)×height

=1/2×(AB+DC)×MD

=1/2×(2+1)×√3/4

= ½(3)×√(3/4)= ½×3×√3×2=(3/4)√3

= (3/4)×1.73= 1.30cm²(approx)[√3=1.73....]

Hence, area of trapezium = 1.30cm²

Section IV and V are 2 congruent right angled triangles with base 6cm and height 1.5cm

Area of region IV and V = 2 × 1/2 × 6 × 1.5cm² = 9cm²

Total area of the paper used = (2.49+ 6.5 + 1.30 + 9)

= 19.3 cm² (approx).__________________

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We know that ,******************************************If a : b = c : d then a, b , c ,d are in

proportion.

a × d = b × d

or

Product of extrems = product of

means**********************************************

Now ,

( 4x² - 3y²) : ( 2x² + 5y² ) = 12 : 19

( 4x² - 3y² ) 19 = ( 2x² + 5y² )12

76x² - 57y² = 24x² + 60y²

76x² - 24x² = 60y² +57y²

52x² = 117y²

x² / y² = 117 / 52

( x/ y )² = ( 13 × 9 ) / ( 13 × 4 )

= 9 / 4

( x / y )² = ( 3 / 2 )²

Therefore ,

x / y = 3 / 2

x : y = 3 : 2

= Let length of bridge be x.= Distance traveled by train = 50 + x

= Speed = Distance / time

= Speed = 90 km/h = 90 * 5 / 18 = 25 m/s

= 25 = (50 + x) / 26

= 650 = 50 + x

= x = 600 m.

Given two forcesPandQ, such that |P | =P,| Q | =Q, and P = Q, acting at a point, such that square of magnitude R of resultantRofPandQis 3 P² = 3 Q². We are required to find the angle betweenPandQ.

Let the angle betweenPandQ is ∅.Then by parallelogram law of vectors we have for the resultant,that,

R² = P² + Q² + 2 P Q Cos ∅ = P² + P² + 2 P P Cos ∅= 2 P² + 2 P² Cos ∅. ……..(1)

We are given that R² = 3 P². Substituting for R²in equation 1, we get,

3 P² = 2 P² + 2 P² Cos ∅, or Cos ∅ = ½ or ∅ = 60° .

The angle between the two forces is 60° .

The area of an object is the amount of surface that the object occupies.

Area formula== length width = l × w

Area of the sheet =l × w =20×30

=600cm²

Area of remaining sheet

= (20-2 (4))×(30-2(4))

=12×22

=264 cm²

OM=6cm and at(OPQ)=48cm

if pq is 16 thenom is bisector of seg pq so, pm=qm2pm=pqpm=8by p.g.t(16)square+(om)square=(10)square256+om=100(om)square=100-256 156 under root 39*4 2 root 39

OM = square root(100 - 64) = 6 cmAr(OPQ) = (1/2)(16)(6) = 48 sq.cm

height of OM=4 cm and area is=32cmsq.

thanks

Complement angles have sum 90°

i) Complement is 90° - 20° = 70°

ii) Complement is 90° - 63° = 27°

average runs will be total runs/10=421/10=42.1

thanks

Volume of metal parallel piped Vp = length * breadth * height = 16*11*10 = 1760 cm^3

Given, coin thickness h = 2 mm =.2 cmcoin diameter d = 2 cm

Let number of coins made = n

Then, volume of one coin Vc = pi*r*r*h = 22/7*1*1*.2 = 4.4/7

Now,n*4.4/7 = 1760n = 1760*7/4.4 = 1600*7/4 = 400*8 = 2800

Therefore number of coins made = 2800

F is 6th alphabet and P is 16th alphabet so 16+6=22G is 7th alphabet and N is 14th alphabet so 14+7=21E is 5th alphabet and J is 10th alphabet so 10+5=15now K is 11th alphabet so 27-11=16th alphabet that is Pso answer is P

thank

Total time = sum of the time of each lap = 54.75+54.56+54.32+54.54 = 218.17 sec

Runs scored by running = 110 - 3*4 - 8*6= 110 - 12 - 48= 50. Percentage of runs scored by running = 50/110 * 100= 45.45 %Option c is correct.

Option "c" is answer

Circumference = 220 C= 2πr220= 2×22/7×r220×7/44= r RV= 35cmArea = πr² = 22/7 × 35² = 22 × 5 × 35 = 3850 cm²

123 is the answer of the following

123 is the correct answer

please like my answer if you find it useful

The first line says when A and B both work together.. then they take 6 days

and questions is also asking for the same.. when they both work together..

answer should be 6 days only..

Thanku

125

250/(30-20) = 250/10 = 25 second ANSWER.

Thanks

LHS = (sinθ - cosθ + 1)/(sinθ + cosθ - 1) dividing by cosθ both Numerator and denominator = (sinθ/cosθ - cosθ/cosθ + 1/cosθ)/(sinθ/cosθ + cosθ/cosθ - 1/cosθ)= (tanθ + secθ - 1)/(tanθ - secθ + 1)

Multiply (tanθ - secθ) with both Numerator and denominator

= (tanθ + secθ - 1)(tanθ - secθ)/(tanθ - secθ + 1)(tanθ - secθ)

= {(tan²θ - sec²θ) - (tanθ - secθ)}/(tanθ - secθ + 1)(tanθ - secθ)= (-1 - tanθ + secθ)/(tanθ - secθ + 1)(tanθ - secθ) [ ∵ sec²x - tan²x = 1 ]= -1/(tanθ - secθ) = 1/(secθ - tanθ) = RHS

a) 21 % is the correct answer

21% is correct answer

a) 21% is the correct answer

21% is the following question answer

a) 21% is the correct answer

a is the correct answer

a) 21% is the right answer of the following

I think you've like answered a similar question but unfortunately not this one🙄

Write 13:39 in ratio