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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 75051. |
If twice the number of books in the library is 5200how many books are there in the library? |
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Answer» suppose number of books are x so 2x = 5200 so x = 2600 |
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| 75052. |
23. Which of these is false?anan-1(A) If a1, a2, аС A, i(B) If a, a + d, a+d.terms are in A.P then S, 2[2a+(n-1)d(C) If 0.07, 0.007, 0,0007..are in G.P then r 0.1(D) If a 1 and d 0 then 2017th element of A.P is 2016a, d2, a.ais in G.P then |
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Answer» (D) is false. If a=1, d=0, tn =a+(n-1)d t2017=1+0 =1 So the 2017th element is 1. |
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| 75053. |
exampleWrite the set of letters of the following words in Roster form(0) ASSESSMENT () PRINCIPAL |
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Answer» Roster form: {A, S, E, M, N, T} : {P, R, I, N, C, A, L} |
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| 75054. |
ic ru plupl cionalt änd x, ind the value of x.8. If 18, x, 50 are in continued proportion, find the value of x. |
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| 75055. |
scored 40, 60, 25, 45 and 15 runs in five matches respectivelyFind the average score of five matches |
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| 75056. |
Show that log 6 log I+ log 2.+ log 3, |
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Answer» RHS=log 1+ log 2+ log 3= log(1*2)+ log 3= log 2*3=log 6=LHS Hence Proved. |
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| 75057. |
\frac { 1 } { 2 } \operatorname { log } 9 + 2 \operatorname { log } 6 + \frac { 1 } { 4 } \operatorname { log } 81 - \operatorname { log } 12 = 3 \operatorname { log } 3 |
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| 75058. |
Answer the following questions;. Name the reasoning centre of the brain. |
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Answer» The part of the brain that is responsible for complex thinking is the Frontal Lobe—Located under the forehead, the frontal lobe controls reasoning, planning, voluntary movement, and some aspects of speech. |
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| 75059. |
5.A simple pendulum attached to the ceiling of a stationary lifthas a time period T. When the lift moves upward with distancecovered as y = kt, where k = 1 m/s, the time period of thependulum will be equal to(A) 4/5T(B) 5/6 T(C) 5/4 T(D) V6757(Take g = 10.0 m/s) |
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Answer» a) is the correct answer |
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| 75060. |
A lending library gives books on rent for reading. It takes a fixed charge for the firsttwo days and an additional charge for each day thereafter. Latika paid ? 22 for abook kept for 6 days, while Anand paid 16 for the book kept for 4 days. Find thefixed charges and the charge for each extra day. |
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Answer» Let X be fixed charge for 2 days and Y be additional charge for each day....Lathika used for 6 day......that is she was charged with 2 days+4 additional days and paid 22so X+4Y=22_______(1)Anand used for 4 days.....that is 2 days+2 additional days and paid 16so X+2Y=16_______(2)by solving (1) & (2) we getX=10 and Y=3that is fixed charge for days is $10 and additional charge for each day is $3......thats it...If u want fixed charge for one day.....divide fixed charge with 2=>$5 per each fixed day. |
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| 75061. |
e Cinema uns iits movies in scUgo min.3 secend one susns. en ioonin.Bsthuhenime |
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Answer» 10 8,124 2,323=240 after 240 minutes |
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| 75062. |
इट न (इ६+रूट+ रू) (A1) |
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| 75063. |
422MATHEMATICS-(12. Find the number of arrangements of the letters of the word INDPERENDEThow many of these arrangements,(a) do the words start with P?(i) do all-the vowels always occur together ?ti |
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Answer» No. of letters in INDEPENDENCE : 12 repetitions : 4 Es, 2 Ds, 3 Ns. therefore no. of ways of arranging the letters of the word INDEPENDENCE is12! / (4!*3!*2!)since there are twelve letters in total and 3 letters are repeated 4 times,3 times and 2 times respectively. 1)WORDS START WITH P P is fixed for first place. remaining no. of letters is 11 and here also there are 4 Es, 2 Ds, 3 Ns. therefore , no. of ways of arranging is11! / (4!*3!*2!). 2)ALL VOWELS OCCUR TOGETHER vowels present in the INDEPENDENCE are i and e. But e occurs 4 times. so, totally we must consider 5 vowels.remaining no. of letters is 7 whre there are 3 Ns and 2 Ds. as the 5 vowels are always together , we must consider them as one object. therefore , there are 8 objects totally (7 letters and one set of vowels). these 8 objects can be arranged in8! / (3!*2!) * 5! / 4! wayssince, in 8 objects , n and d are repeated 3 times and 2 times respectively and we multiply by(5! / 4!) since the vowels can be arranged internally in that many ways. |
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| 75064. |
write 4 letters of English alphabet that have both vertical and horizontal line of symmetry |
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Answer» H I X have two lines of symmetry. thanks |
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| 75065. |
(ii) Quadrilateral TRUETR = 3.5 cmRU = 3 cmUE = 4 cm< R = 75° |
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| 75066. |
iind invease of elenentouA1 23 |
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Answer» 1st 2nd |
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| 75067. |
Given log 2=30103, log 3=0.47712, log find the value of\log _{6} 6, \log 1.5, \log \frac{x}{25} |
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Answer» log6=log(2×3)=log2+log3=0.30103+0.47712 =0.77815log1.5=log(3/2)=log3-log2=0.47712-0.30103 =0.17609log(1/2.5)=log(2/5)=log2-log5 =log2-log(10/2)=log2-log10+log2 =2log2-log10=2×0.30103-1 =-0.39794 |
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| 75068. |
at the rateSweety rupurk with IWhat is thehe answers25 |
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Answer» the photo is not clear post the photo of Gain and then I will answer your question |
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| 75069. |
How many triangles are there in the following figure?A) 7B)8C)9D)10LOGICAL REASONING |
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Answer» 8 triangle in figure |
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| 75070. |
If x is added to each of numbers 3,9,21 so that the resulting numbers may be in GP, then the value of x will be |
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| 75071. |
(८८ 7. glFHW T EL: . हा - |
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| 75072. |
charge for first three daystional charge per extra daye the following for x andc-3y = 13, 3x+2y = 824+2b)x + (2a - by 2, (aoss-multiplication Me |
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Answer» please post an perfect image the image u have posted doesn't contain full question. |
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| 75073. |
In a random arrangement of the letters of the wordMATHEMATICS', find the probability that all the vowelscome together. |
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| 75074. |
A letter of English alphabets is chosen at random. Find the probability that it is aletter of the word 'MATHEMATICS |
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Answer» No of distinctalphabet onMATHEMATICS=8total outcomes=26∴probability = favourable outcome/total outcome probability= 8/26probability= 4/13 |
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| 75075. |
MPLE 8 How many uords can be formed by taking 4 letters at a time out of the letters of the wordMATHEMATICS |
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| 75076. |
A1)हा 4 _॥ .. वा 45%? |
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| 75077. |
िकर्त 0=4—-x (A1) |
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Answer» x-y= 0 so x= yy+3= 0 so y= -3 so x= -3 as wellplease like the solution 👍 ✔️👍 |
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| 75078. |
0001 > 881 (A1) |
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Answer» 4.38 x 1000= 438/100 x 1000= 438 x 10= 4380 |
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| 75079. |
की (सनकी a1 o Do 62002 |
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Answer» hit like if you find it useful |
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| 75080. |
stick (2.5 RgA stick of square cross-section (5 cm x 5 cm) and length 4mweighs 2.5 kg is in equilibrium as shown in the figure below.Determine its angle of inclination in degree) in equilibriumwhen the water surface is 1 m above the hinge1m |
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Answer» The length of the rod is 4m. The depth of water is 1m Then tan Ѳ = Depth of water/ length of rod tan Ѳ = ¼ Ѳ = tan-1(1/4) Then Inclination angle (Ѳ) = tan-1(1/4) |
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| 75081. |
Category: Reasoning8 4 10 720123 |
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Answer» 21 21 |
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| 75082. |
Do THISs1. Take any Arithmetic Progression.2. Add a fixed number to each and every term of AP. Write the resulting numbers as alist.3. Similarly subtract a fixed number from each and every term of AP. Write the resulting4. Multiply and divide each term of AP by a fixed number and write the resulting numbers5. Check whether the resulting lists are APin each case.numbers as a list.as a list. |
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| 75083. |
A lending library has a fixed charge for the first three days and an additional chargefor each day thereafter. Aarushi paid for 27 Rs. For a book kept for 7 days. If fixedcharges are x Rs. And per day charges are Rs. Y. Then write the equation and drawthe graph? |
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Answer» please draw graph |
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| 75084. |
A135°ме1. In fig. 9, if PQ | RS, MXQ = 135º and Z MYR = 40°, find ZXMY.2. If a transversal intersects two lines such that the bisectors of a pair ofcorresponding angles are parallel, then prove that the two lines are parallel.3. In fig. 10, AB CD and CD || EF. AlsoEAI AB. If ZBEF = 55°, find the values of x,40°E |
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Answer» interior angle are also equal........ interior angle are also ewual interior angle are equalis the best answer angle xmy is equal to 90° interior angle are equal interior angles are equal 85' is the right answer |
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| 75085. |
A letter is chosen from the word 'PENCIL'what is the probability that the letter chosenis a consonant?4. |
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| 75086. |
A letter of English alphabets is chosen at random. Find the probability that it is aletter of the word MATHEMATICS |
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Answer» No of distinctalphabet onMATHEMATICS=8total outcomes=26∴probability = favourable outcome/total outcome probability= 8/26probability= 4/13 |
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| 75087. |
A carton of 24 bulbs contain 6 defective bulbs. One bulb is drawn at random. What is the probabilitythat the bulb is not defective? If the bulb selected is defective and it is not replaced and a secondbulb is selected at random from the rest, what is the probability that the second bulb is defective? |
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| 75088. |
6. 1-sin 10° sin 50° sin 70°虱丽(al 1/8hi 3/9 |
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Answer» 1- sin10 sin50 sin 70= 1 - {(2sin10cos10)sin50cos20}/2cos10 = 1 - 2sin20cos20cos40/4cos10 = 1 - 2 sin40cos40/8cos10 = 1 - 2sin80/8cos10= 1 - cos10/8cos10 = 1 - 1/8= 7/8 thanks |
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| 75089. |
21. Third term of an A.P. is four times the firstterm. If 6th term is 17 then its first termwill be: |
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Answer» Let a be the first term and D be the common differencethen a3=4aa+2d =4aa-4a+2d=0-3a+2d=03a-2d=0..........(i) and a6=17a+5d=17...........(ii) solving (i) &(ii), we geta=2 & d=3therefore A.P. is2,5,8,11,....... a3=a4; a+2d=4A,;a-4a+2d=0:; -3a+2d=0; 3a-2d=0_________(1); a6=17; a+5d=17, solving (i),(ii), a=2; d=3, A.P. is 2, 5, 8, 11, 14 |
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| 75090. |
Ll el ok X 1“3 T lbiflis(kb Hp 1§ 3 By b b gole 12Me L1 ST T+ X XL '5 ६ जा (B |
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Answer» x=11 your Questions Answer |
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| 75091. |
ii 10, 35, 40Find the largest number which is a factor of each of the numbers 504,792 and 1080?iv. 32, 64, 96, 1283/ The length, breadth and height of a room are 12m, 15m and 18m respectively. Determinethe length oflongest stick that can measure all the dimensions of the room in exact numberof times ? |
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Answer» I am not asking 2 one I am asking 3one |
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| 75092. |
Q55A man starts his job with a certain monthly salary and eams a fixed increment every ysar f hie slryRs.1500 after A years of service and Rs. 1800 after 10 years of service, wihat was his stantsing salary andthe annual increment? |
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| 75093. |
SECTION-A1. Write the names of number 87595762 according to Indian System of Numeration.2. Find the common factors of 20 and 283. What does the angle made by the hour hand of the clock look like when it moves from 5 to 74. What fraction of a day is 8 hours?5. Write the following numbers with appropriate signs: (a) 100 m below sea level. (b) 25°C above0°C temperature6.Write each of the following as decimals: (a) Two ones and five-tenths (b) Thirty and one-tenthSECTION -BFind the value of the following:(a) 297 x 177.297 x 3 (b) 54279 x 928 x 54279What fraction of a clockwise revolution does the hour hand of a clock turn through, when it goesfrom (a) 3 to 9 (b) 4 to 7?8.9.What should be added to 37.28 to obtain 46.8?10. Estimate the product 5981 x 4428 by rounding off each number to the nearest (i) tens (ii)hundredsI. Narne the line given)ly wo eer a a i m thefour given.A B C D12. Represent the following numbers on a number line (a)+5 (b)-10 |
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| 75094. |
A letter is chosen at random from the word 'PROBABILITY. What is the probability that the chosen letter isa vowel? |
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| 75095. |
ORA carton of 24 bulbs contain 6 defective bulbs. One bulb is drawn at random. What is the probabilitythat the bulb is not defective? If the bulb selected is defective and it is not replaced and a secondbulb is selected at random from the rest, what is the probability that the second bulb is defective: |
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Answer» Probability of getting non defective bulbs = 18/24Probability of getting defective bulbs = 6/24 |
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| 75096. |
If a transversal intersects two lines such that the bisectors of a pair of aangles are parallel, then prove that the two lines are parallel. |
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| 75097. |
10.The third term of a G.P is 18 and its seventh term is3-. Find the tenth term of the G.P |
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Answer» Let 1st term be 'a'.So, ar^2=18.......(1)...(given)Also ar^6=32/9..(2)...(given)Dividing (2) by (1), we get,ar^6/ar^2 = 32/162r^4=16/81.r=2/3.Putting r in eqn.(1)a=81/2.So, 10th term = ar^9= (81/2) ×(512/19683)= 256/243. hit like if you find it useful |
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| 75098. |
CBSEEXAMINATION PAPER 2018MATHEMATICS(With Solutions)CLASS X(This Paper is Modified According to the Latest CBSE QuesTime Aloweds 3 HoursGeneral Instructions :Mcximum Marks 8All questions are compulsoryhis question paper consists of 30 questions divided into four seseions A, B. C and D.ct(ii) Section 4 contains 6 questions of I mark each. Section B contains 6 questeach, Section C contains 10 questions of 3 marks each and Section D cocontains 8 quest4 marks eachiv) There is no overall choice. However, an internal choice has been provided in3 marks each and three questions of 4 marks each. You have to attemptalternatives in all such questions) Use of caleulators is not permittedSection âA'Question numbers I to 6 carry I mark each1. If.r = 3 is one root of the quadratic equation x2-2kx-6 = 0, then findSolution. The given equation is x -2kx 6 0. |
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Answer» If x= 3 is the root thenafter putting x= 39-6k-6= 03= 6kk= 1/2please like the solution 👍 ✔️ |
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| 75099. |
ALTOUUU..10. The third term of a G.P is 18 and its seventh term is. Find the tenth term of the G.P. |
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Answer» We know,nth term of GPan = ar^n-1 Givena3 = ar^2 = 18.........(1)a7 = ar^6 = 32/9.....(2) ar^6/ar^2 = 32/9*18 r^4 = (2/3)^4 r = 2/3 Put value of r in eq(1)a*(4/9) = 18a = 18*9/4 Therefore, Tenth term= ar^9= (18*9/4)*(2/3)^9= (9*9)/2 * (2/3)^9= (2)^8/(3)^5= 256/243 wrong answer |
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| 75100. |
List any five consequences of drug abuse. |
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